Populating Drop Down From A Query
I'm trying to populate a drop-down box from the results of a query. I end up with the first option coming through and then blanks in the rest. Something like this...
<option value=Acevedo>Acevedo</option>
<option value=></option>
<option value=></option>
<option value=></option>
<option value=></option> .......
View Complete Forum Thread with Replies
Related Forum Messages:
Populating Drop Down
How do I do this drop down box ? Making an edit page. I have 2 tables groups id || categoryname program id || cateogry_id I need to populate the groups in it at same time show the selected choice from program. Not showing id but needs to show categoryname with of course the values being the id of groups.
View Replies !
Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.
View Replies !
Populating Drop Down And Table
I have a database with the following fields. Name | Company | Date values in each column could be repeated, or not. as in there could be several same names with the same company with different dates, or different names with same company. How do I populate a table with this info and have drop down boxes, so that I can narrow down the search? For example: Name | Company | Date 12 | 1 | 1929 13 | 1 | 1929 14 | 1 | 1929 12 | 2 | 1929 12 | 4 | 1929 13 | 1 | 1941 12 | 6 | 1929 So if in the drop down I select '12' under name, only those entries with 12 are shown, and then I can further sort it by selecting only '1' under Company. Hope I'm clear, I manage to complicate things when I post them.
View Replies !
Auto Populating A Drop Down Box
Basically I'm setting up a website which needs an populated drop down box made up from all fields in a specific column of a table in a mysql db.... Here's the code I've made up using various tutorials.... <?php $user = ""; $host = "" $password = "" $dbName = "" /* make connection to database */ mysql_connect($host, $user, $password) OR DIE( "Unable to connect to database"); mysql_select_db($dbName); //did you forget this line? $sql = "SELECT model FROM usedVehicles"; $query = mysql_query($sql) or die(mysql_error() . "<br>$sql"); //use the or die(...) part ONLY IN DEVELOPMENT ?> <form action="action" method="post"> <select name="option"> <?php while ($row = mysql_fetch_array($result)) { echo "<option value="" . $row['model'] . "">" . $row['model'] . "</option> "; } ?> </select> <input type="submit"> </form> I've left out the connection details for obvious reasons... When I upload and try to test this, jus a blank drop down appears... there are definately fields in the column as I have tried the query on phpMyAdmin.
View Replies !
Populating A Drop Down List With Php
I am trying to get a drop down list to populate vbia php. What I have a is a script that allows a airline/user to enter airfare and price for tickets. It dumps them into a database and then allows the user to view/delete/add. I want the user to be able to edit the airfare. I have a drop down list that is set as a variable $ticket_from, $ticket_to. The list contains around 400 cities. When the user clicks 'edit' I have the price population but no the drop down list. How do you go about something like that? I have this right now: Code:
View Replies !
Populating Drop Down Lists
Could anyone help me on populating database driven drop down menus. I am trying to populate a second drop down list based on the selection of the first drop down list. I have the first drop down list running. Not sure about getting the second now.
View Replies !
Self Populating Drop Down Menus
i am trying to do is the following: I have a MySQL database that (very simplified) has a schema like this 'Students(Name, id, Course)' I would like to have a form on a web site that has 2 linked drop down menus, one 'Please select id' and one 'Please select course'. When a user of the site selects there Id from the first drop down menu, i want the second drop down menu to populate itself with the courses held in the database for the given users Id. I would like the first drop down menu to be populated from the database with a query similar to 'SELECT id FROM students'.
View Replies !
Populating Drop Down From MySQL
I am trying to populate a drop down menu of MySQL data using PHP and I have hit a snag. I think its probably something simple that a freah pair of eyes could pick out right away that I am just not seeing... For some reason only the "firstname" part of the data is populating in the drop down and I can't figure out why. When I try to make changes to the echo lines to correct this, nothing shows up including the "firstname" data. Code:
View Replies !
Populating Drop Down Menu
I use the following code snippet to build a drop down menu with the results of a query. How can I set the initial value of this input based on the result of another query? What I am trying to do is update records in the data base. The field WkEndDate is pulled along with the rest of the record and the drop down menu is built from a table of valid WkEndDate values. Code:
View Replies !
Populating Drop Down Fields
I am trying to populate a drop down menu with a mysql database. I was hoping to have a selection of months in the dropdown menu, based on date fields in my database when a user then selects a month, they will be brought to a new page that will have only the records created in that month. But in my database, the date is stored in this format: 2006-05-12 00:00:00 if you need to see my code, here it is: <? //database connection $query = mysql_query("SELECT * FROM casinocredit"); // start to print out the form echo "<form action="cats.php" method="POST"><select name="clients"><option value="" "selected">Select A Client</option>"; // loop through the records while ($row = mysql_fetch_array($query)) { echo "<option value="{$row['ID']}">{$row['ddate']}</option>"; }.........
View Replies !
Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.
View Replies !
Populating A Drop Down Via A File Directory?
I just wrote this code: $dir = "/images/news"; print "<select name='file'>"; $dir = opendir($dir); while (false !== ($file = readdir($dir))){ if (in_array($file, array(".", ".."))) continue; print "<option value='$file'>$file</option>"; } print "</select>"; But for some reason it is not populating. It instead echoes an empty drop down menu. Can anyone suggest anything?
View Replies !
Populating A Drop Down From A MySQL Table
When they click submit, I want the name dropped from "invite" and added to a table "guests" with their answer if they are coming and how many. I know the SQL to make it happen, but I am pretty sketchy about the PHP. Code:
View Replies !
Auto Populating Multiple Drop Downs.
im trying to create two dropdowns, i need the first one to be the category and the second one to be the subcategory. The category drop down autopopulates with the correct info from the database. and uses the table "category", the value of each drop down is represented by the "cat" field in the table (cat is basically and integer id number) and "Category" is used as what the user actually sees in the drop down (category is the actual word of the category). Once the category is selected i would like to have the sub category auto populate with everything that has the same values as the selected category (cat) Here is a break down of how the tables work. Table 1 Name: "category" Fields for Table 1: "cat" (the id number), "category" ( the actual name of the category) Table 2 Name: "subcategory" Fields for Table 2: "cat" (corresponds with the cat id from table 1 to pull the correct data), "subc" (the basic id of the subcategory), "subcat" the actual name of the subcategory. so the way i see it, have a normal drop down populated by a php query. then on change, populate subcategory drop down where cat = cat and display sub category.
View Replies !
Populating The Drop Down And Pressing The Submit Button
1. The first is I have two drop down menus. The first is "year" and the second is "mfr". When a user selects a year from the drop down it then populates the second drop down, mfr, from the MySQL database. Theat is working fine. But the problem I am having is the "submit" button (which I have labeled as "browse"). When I click it. Nothing happens, no action tacks place. I have looked over the code and I can't figure it out. (See Code Box 1 Below). 2. Right now the "mfr" drop down is populated by the MySQL database and reads with a list like "Acr", "Alp", etc. These are abreviations. I need to set up an array to have them instead read the entire mfr name. Example: Instead of "Acr" it needs to be "Acura". Instead of "Alp" it needs to be "Alpine". I need these full names to appear in the drop down. I know I need to do something like this (See Code Box 2 Below) but I can't get my finger on it. Code:
View Replies !
Populating Drop Down List With Selected Vaue
I have a drop down box and the "selected" value needs to be selected by a dynamic value that gets entered into the database, this is currently how im doing it: PHP Code: <?php                 if($modify_row[21] == "0") {                   print "<option value=" "></option>";                   print "<option value="1">Active</option>";                   print "<option value="0" selected>In-Active</option>";                 } elseif ($modify_row[21] == "1") {                   print "<option value=" "></option>";                   print "<option value="1" selected>Active</option>"; Its fairly straight forward, basically the option that is automatically selected needs to be the one coming from the database $modify_row[21].
View Replies !
Populating City,state,country Drop Down Menu
In the registration form I have city, state, country fields. I was wondering if there was a database available on the net which has the list of states in each of the countries. That way when a user selects a country I could automatically populate the state drop down menu ...
View Replies !
Drop Down Menu Select And Populating Data Fields
I have a PHP/MySQL Content Management System set up for the job I work at. It's basically a shift program that lets users pick up shifts, post shifts, etc. The data fields are tied to the shift ID which is selected from a dynamically populated drop down box. However, I cannot get the data fields to be updated when I select a new value and I cannot get the form to accept the new selected Shift ID. I have tried using JavaScript but cannot quite get it to work. Code:
View Replies !
Populating Multiple Drop Down Boxes From Mysql Table
Am having a problem with a dynamic, multiple drop down box query. If I run the code with only one select, it populates fine. If I run it with 2 selects then only the first drop down box populates - the second drop down box is empty. Am wondering if I need to put the query into an array and populate the boxes from there. Code:
View Replies !
Populating Arrays From MySQL Query
I have the following code: http://pastebin.com/746601 The field 'material' in 'is_material' contains multiple values for each record in 'is_details'. Because of this I have used 'is_material_lookup' as a reference lookup table containing the 'style_code' and 'material_code' which refer to their full details in the respective tables. Currently I have got the script outputting all the details and one material then in the next block of data, repeating the details with a different material. What I would like to achieve is having 1 block of data with a list of all materials in that, instead of the repeat, but sadly I can't know exactly how to do it.
View Replies !
Drop Down Box Query
I am trying to do a drop drown box query where if you select a certain game type then the records in the database that have that game type are displayed in a table below. My drop boxs work fine, its the query to display the data that is troubling me. Here is my code:
View Replies !
Query Using Drop Down Menu
can i query a table based on a drop down list? i have a list of agents that i just want a simple drop down list to show the records they entered.... right now i just have the entire table showing all records in a html table format...but i want a drop down list so that if they only want to see the ones they entered, they can just select their name and poof...only theirs are shown...
View Replies !
Drop-down From Query Results
I've got a form that pulls data from a MySQL database and populates the form and allows the user to edit the info and submit the changes to the database. All works fine when I'm working with straight text boxes (which comprises the majority of the form). The problem arises when I'm dealing drop-down select boxes. Essentially, what I want to do is to populate the drop-down with all choices but have the one "selected" that was previously in the database. The MySQL tables look like this: leave_type TABLE which has leave_type_id and leave_type_name absence_actions TABLE which has absence_id, personnel_id, leave_type_id, etc... So, I'm looking at grabbing all of the results of the leave_type table to populate the dropdown and then grabbing a specific row from the absence_actions table and making the dropdown "selected" based on the leave_type_id from both tables. Does anyone have any idea on how to code something like this. This seems like a common problem but I can't find anything on google. Perhaps I don't know how to phrase my query.
View Replies !
Drop Down Population And Query
I have been working on this for a few days, but am getting nowhere. I have a client that purchased a template, had no idea what she was doing, so brought it to me. My problem is that it has a calendar feature, that she wants to use for future events, and all that I know about PHP is what I have learned in the past few days (if she had Windows host, and I could do it in ASP, I wouldn't be here). The calendar has 4 different drop downs (Month, Year, Location, Event) that she wants people to be able to pick one or more of the options to see events that correspond with the selections. I have the database set up and the table set up with a few test entries set up. I just have no idea where to go from here.
View Replies !
Dynamic Drop Down Boxes With Php Query
I need to build a dynamic page with 2 drop down boxes on it where the contents of the second drop down box are dependent upon the selection made in the first drop down box (the first box contains districts/regions and the second box contains towns/cities). The customer wants this to happen on a single screen but can this be done with PHP? The above question is already answered by many people and they want me to use Javascript. My doubt is the second box shoud query the list from a table in mysql using php. How do i do that?
View Replies !
2 Drop Down List Where Need Query Database
there is drop down list box linked to the database where it displays the state of a country and once the user clicks on the particular state, there purpose to be radio button displaying the locations available of that state, the location displayed in radio buttons are from the database. currently the source code i'm using is (which uses a submit button to query the database but i does not want the submit button it purpose to work using Code:
View Replies !
Trying To Make Populated Drop Down Box Query
My host is Godaddy, sql 4.1 - trying to create a populated drop down list that when submitted, displays the info row by row. I can populate the list, and when I post it takes me to the next page. The php on the next page makes the table header but there is no data underneath. There is data in the table cause I can display it all on another php page I have. Code:
View Replies !
Trying To Connect A Drop Box To A Mysql Query
i have this problem: i want to create a new table into an existing database. i have no problems in creating the table in a fixed database, but i want to create it into an existing database which you choose from a dropdown box. the box seems to work correctly but it doesn't i am missing something: how can i connect the highlighted item in the dropdown box to the query: mysql_select_db($nomecategoria,$db); so that the new group gets created inside the highlighted database? (sorry for italian language variables, but $nomecategoria should be the database in which i go adding the new table.) excuse me for my english, i hope you have understood my problem.. i have to do this script for a university exam ....
View Replies !
Drop Down List Based DB Query
I have a website in which I have like 20 Items. Every Item has its own distinguised Attributes. e.g Item A - Black - Solid Item B - Socks - Clothes .. etc In Database I have Two Tables. One for Items and One for Attributes. The ItemID from Items table is present in Attribute Table to link to attributes with a distinguished Item. On the basis of above, I want to make two DropDows one for Items and One for Attributes, if someone select Item A from the Items Drop Down then Automcatically ONLY the Attributes related to Item A should Appear in the Attribute Dropdown.
View Replies !
Select (drop Down) Menu Query
I have a MySql table (meat) storing the results data of on online culinary exam. One of the fields in the record is "optype". It is a drop down select field with about 12 choices. I have a separate results page, and when a user goes to that URL the results are displayed automatically. I am currently displaying the results of the MySql table (meat) using the following query:: $query = "SELECT * FROM meat WHERE optype='Country_Club'ORDER BY time DESC"; Code:
View Replies !
SQL Query Selected From A Drop Down Menu
I've got the following query which gets values $search and $furn from a form. SELECT * FROM properties WHERE description LIKE '%$search%' AND furniture='$furn' ORDER BY id ASC LIMIT $start, $display" This works almost fine. The only problem is that because $furn value is either 'yes' or 'no', selected from a drop down menu, sometimes when is not selected the query doesn't work. Code:
View Replies !
Drop Down Menu Where The Items Are From A MySQL Select Query
I am just starting programming in PHP and wonder if it is possible to have a drop down menu where the items are from a MySQL select query. I am registering people for a weekend seminar and want to have a list of valid weekends to choose from on the form. Any pointers to scripts or PHP references that will help would be appreciated. I am using the book "Build your Own Database Driven Website Using PHP & MySQL" to get me started, but also need recommendations for a general primer to php.
View Replies !
Drop Down 2 Echo Seletion On Drop Down 1
I would like to put up a list/menu drop down so when you select something it echo's something in the second drop down. Example Drop menu 1 ----------------------- course 1 course 2 Drop menu 2 ------------------- If course 1 echo course 1 dates. If course 2 echo course 2 dates Does anyone have an example for me or what do I need to search for cause I don't quit know what it is called and thus I cannot find anything on Google.
View Replies !
Populating A Select Box
What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box. I can do this on my own, but I was curious if I have to use a database in order for this to be possible.
View Replies !
Populating Dropdown Box.
I have been looking around the internet for an example of what I need to do but cant find anything was wondering if someone here might be able to help. What I need to do is to connect to a mysql db select a table and then a field from that table and put all the contents of that field into a dropdown box.
View Replies !
Populating A Webpage
I am trying to create a webpage that will allow me to view my 'email' website whilst I'm at work. The firewall blocks the page and I was hoping that there was some surreptitious way to get around this problem. My thoughts for a solution to this would be to create a variable with the website's name in pieces. Then send it to a function that opens it in a frame or something.
View Replies !
Populating Tables
I'm trying to populate an HTML table using the data in MySQL. "how to do format it to where I can make shipping labels?" There will be three lines of text for each label but I will have three columns of labels X 10 rows. Code: line A1 line B1 line C1 line A2 line B2 line C2 line A3 line B3 line C3 line D1 line E1 line F1 line D2 line E2 line F2 line D3 line E3 line F3 ....
View Replies !
Populating Two Combo Boxes
I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).
View Replies !
Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:
View Replies !
Dymanic Populating Checkboxes
i like to retrieve a value from DB, accordingly i like to display the checkbox, either checked or not. Now im able to retrieve the value from DB, i can show even show the checkbox, but i cant make it checked???? the Code i used to display as follows, #Require the database class require_once('../dbinfoinc.php'); #Get an array containing the resulting record $query = "SELECT * FROM event"; $result = mysql_query($query); $num=mysql_numrows($result); mysql_close(); $i=0; while ($i < $num) { if(($i % 2) == 0) { $c = '"TableDetail"' } else { $c = '"TableDetail2"' } $event_id=mysql_result($result,$i,"event_id"); $event_name=mysql_result($result,$i,"event_name"); $event_publish=mysql_result($result,$i,"publish"); // if(($event_publish) == 0) { $event_publish = 'No' } // else { $event_publish = 'YES' } $take_action = 'Delete' echo "<tr> <td Class='navText' align='center' class=$c>$event_id</td> <td class='navText' class=$c>$event_name</td> <td class='navText' align='center' class=$c><input type='checkbox' name='publish' if($event_publish==1){'CHECKED'}?></td> <td class='navText' align='center' class=$c><a href='delete_event.php?event_id=$event_id'>$take_action</a></td></tr>"; $i++; } ?>
View Replies !
|
TRACKER
