PHP :: Populating Array With Mysql Results

Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.

Populating Form From Database, Then Passing Results To Next Page
I have a multiple select input in a form that's being populated by a row
from my database as such:
<input type="checkbox" name="subm[]" value="$row[ID]">

That part is working fine as I can check the displayed page using View
Source and see that the value is the correct row number from the
database. It is then being submitted on a form by $_POST method to
another page where I want to evaluate the checkboxes and display the
contents of the entire row that corresponds to each value="$row[ID]"
that have been checked. But I can't seem to get it to work. I'm having a
problem passing the selected value. Can someone point me in the right
direction?

$query = ("SELECT * FROM `table`");
$result = mysql_query($query);

print "<p>Data for Selections:";
print "<table border=2><tr><th>You chose:";

foreach ($_POST['subm'] as $value) {
print "<tr><td>";
print "$row[ID];
";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print "</td></tr>";
print "</table>
";
}

if (!isset($_POST['subm'])){
print "<p>No matching entry ";
}

mysql_close();

Store Mysql Results Into An Array
i just started using php. i've used it before as a maintainer. fun stuff. well now i'm the writer. i want to abstract all the DB commands away from myself and all other developers. so i'm writing a function to query the php database from all users of the database and store them into an array as a return value so that i can seperate my database code from my html creation code.

1. is there a way to put all my database functions into a php file and include that file into all my other php pages? similiarly to a #include in C++ or a import package name in Java?

2. my code to run down the fetched results and store them into an array doesn't seem to be working the way i want it to. if i print out the results from the mysql returned fetch the data is fine. however the array seems to print out "Array[elementnumber]" instead of the value. Code:

Pushing Data Into A Multi-dimensional Array From Mysql Results
First, A result array I'd want to get could look like this:

$chart['chart_data'] = array (
array ( "Region A", 10,12,11,15,20,22,21,25,31,32,),
);

The first is "Region A" and the rest is just int's that I'd pull from the db, so to set it I'd do this:

$chart [ 'chart_data' ][ 0 ][ 0 ] = "Region A";

But the problem is when I want to insert the data in the while loop (like the 10,12,11,15...), I've tried array_push but it's not working, maybe it doesn't work with multi-dimensional arrays? Anyways, here.'s what I tried, the following inside the "while" to loop the mysql results with mysql_fetch_assoc:

while($r=mysql_fetch_assoc($res)) {

$chart [ 'chart_data' ][ 0 ][ 0 ] = array_push($chart['chart_data'][0][0], $r['wght']);
// the above line is where I have problems ^^
}

What I want is on each loop to insert the fetched data inside the array so that it gives what I gave first at the top, but what I've written above doesn't work, it gives me a warning saying "first argument must be an array" which seems to be one, but anyway, anybody know how to do this?

PHP + MYSQL, Populating Drop Down Box
I am looking to generate a dropdown box from MYSQL data:

db name = h2, table = Working, Column = Home.

Populating DHTML Menu From MySQL
I have a client that would like to have drop down menus added to a nav
bar that is generated from MySQL. Is it possible to have a dynamically
driven DHTML menu from MySQL?

Populating Arrays From MySQL Query
I have the following code: http://pastebin.com/746601

The field 'material' in 'is_material' contains multiple values for each
record in 'is_details'. Because of this I have used
'is_material_lookup' as a reference lookup table containing the
'style_code' and 'material_code' which refer to their full details in
the respective tables.

Currently I have got the script outputting all the details and one
material then in the next block of data, repeating the details with a
different material. What I would like to achieve is having 1 block of
data with a list of all materials in that, instead of the repeat, but
sadly I can't know exactly how to do it.

Populating Dropdown With Mysql Entries
I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.

Sorting Sql Results In An Array Using Things Outside The Array To Sort Them?
I'm using PHP to connect to a database full of place names, and their associated post codes, latitude and longitude on the earth. A user types his or her post code into a form, plus a distance (in miles), and the script looks for other area codes (first half of the post code) within that distance.

I can do that fine, but the results are ordered alphabetically by postcode, and I want to order it by the distance. Problem here, is that the distance isn't part of the array taken from the database, it takes the latitude and longitude of the area it's on in the while loop, and calculates the distance between the user's post code and that one, but it's not part of the array, so I can't sort the array using it.

How can I sort it? Can I add the calculated distances to the array, and sort it using sort()? If yes, how do I add them to the array?

Here's the page, just to explain better what the script does: http://navimaker.org/ed/owain/results.php?postcode=gl15&distance=34
Mess around with the postcode and distance vars.

I'd put the source on here too but I'm doing all this over SSH and can't copy & paste very easily .

Search Results ($num_rows) Does Not Match $search Results (PHP,MySQL)?
For example, when I do a database search for a term I get 2 results but the $num_rows says there are 3 results.

I suspect it's because there are similar keywords within different search fields of the SQL statement. But I am stumped as to how I can change this. Any Suggestions? the code:

Looping Through An Array And Using The Results.
function build_menu() {
$all_li = create_list_items();
$menu = '<ul id="navbar">'
reset($all_li);
while($li = each($all_li)) {
$menu .= $li;
}
$menu .= '</ul>'
echo($menu);
}

I'm trying to move through each item in the #all_li array and add it's contents to the $menu variable. $all_links is filled with string values from the function create_list_items().

I tried (above) using each(), but the output from the function is "ArrayArrayArray" and this has me confused. I think it's giving me this because each() creates an array which includes key values (yes?), which means each() is not the method I need to use.

Can anybody advise me on a method I can use to loop through the $all_links array and add each string to the $menu variable? So far I've tried a for loop, foreach, even attempted an array_walk(), but haven't had any success.

Displaying Array Results In Table
I'd like to display the results of an array in a table format with the Alias, Alias Destination & Username as column headings & the results underneath. PHP Code:

Evaluating Array And Skipping Certain Results
I'm having a brain freeze on this. I have a script where I am reading
the contents of a file into an array. I have that up and working with no
problem. Then I'm exploding the array using

while ($line = fgets($fd, 4096))
{
$arrayData = explode("-", trim($line));
}

Works fine. But what I want to do now is evaluate arrayData[2] to see if
it contains the integers "00" (that's zero zero) and if it does, I want
it to skip that entry. I know I need to set it up with
if arrayData[2] == "00" {

But I'm drawing a blank on how to get it to skip this entire line in the
final results. There may be multiple instances of this happening in each
file and I want to skip them all.

How Do I Search Two-dimiensional Results Set Array
Here's the pertinent code to get the SQL results. It is generated by
dreamweaver adn I'm trying to learn to code php so I don't depend on DW to
do it for me.

$query_rsSummary = "SELECT sid, Count(wid) FROM plotting GROUP BY sid";
$rsSummary = mysql_query($query_rsSummary, $tableG) or die(mysql_error());
$row_rsSummary = mysql_fetch_assoc($rsSummary);

How do I search the array to see if a certain "sid" has an entry in the
array?

Building Array Of Difft Results For Return
I have 2 functions that I want to call from a subroutine, and then return their results; one result is an array, the other will be an array of arrays. The first will be the information about a product, $product, with values like $product['title'], product['id'], etc.

The second will be an array of arrays, each line of which contains information about an element of the product. I.e., $item[0]['title'], $item[2]['value'], etc. How would I best combine these so I can RETURN the total thing from the function, and then how would I refer to the parts in the calling code? For example, if I said Code:

ODBC: Fetch Results As Associative Array
Will PHP fetch the results of a query using ODBC as an associative array? I know that MySQL does that, but I couldn't find it for ODBC connections.

Taking SELECT Results And Turning Them Into An Array()
Does anyone know how take a mysql select statement and have the results placed into an array? I am returning 1+ rows and want to place those rows into an array so I can run a foreach() for each row and then run another foreach() for each column for each row? Code:

How To Make An Array With Query Results? (Postgresql)
Need help making an array with query results:

$value = $_POST['text'];

$pg = pg_connect('dbname=test user=user password=secret');

$query = "SELECT column FROM information";
$result = pg_query($query);

*** how to create array with $results ***

Query Array, Sort Results And Display In Seperate Tables
The problem I have it breaking out the results and displaying them (broken out) alphabetically in seperate tables. For instance, I have generated (bookmarked) tables, one for each letter (A-Z) and want to display all recordsets with say, last name
beginning with "A" in one 2 column table, "B" in another 2 column table, and so on... each
table would have two columns (with 2 background colors alternating), each cell containing values of one recordset.

Even more tricky is if I have an odd number of cells, still generating the last cell with empty values (for asthetics). And can anyone say "sort" (yes, I am nuts)? The ability to sort the whole mess by any column value. I have looked at freeware and other third part apps, but they can only do what I already can do (mine is actually cleaner) but not as complicated.

Array Results Output On Online As Opposed On Separate Lines
How do i get to echo details on oneline as opposed to the next line.

$car=array("red", "green", "white", "blue", "orange");
foreach $car as $color) {

echo "$color<BR/>";

I dont want the results on separate lines but on the same line with commons...

MySQL Results Not Working So Hot
Ok. Here I am again....probably posing a question with a solution so easy that, after looking at it for an hour, I can't figure out. Ok. here's the deal. please review the code below. Looks simple enough, right?

If/then Within MySQL Results List
I want to list job opportunities for a facility. If there are jobs in the database, I can list them without a problem. But if there are no jobs, I'd like to echo a line something like: "No jobs right now, come back later." But I can't get that line to echo. PHP Code:

Mysql Writing Results From 51 To 100
Can someone write me a mysql_query code which will get me results from 51 to 100 from $database?

Don't suggest me working with indexes, because i'm also deleting some rows (for example #1 is filled #2 is not, #3 is...)

Show Next Results Of MySQL DB
How do I get it so that php reads in the first 10 results out of a MySQL database. Then when Next or something is hit it displays the next 10 results and so on.

MySQL Results To Return Only One Value
For example, I have a column that has three different values, 1, 2, & 3. In the database, there may be over 500+ entries with one of these values assigned to it. How can I get MySQL to return just 1, 2, & 3 only once rather than several hundred times.

Hyperlinked MySQL Results W/PHP
I was wondering how results to db querys have attached links to each individual result? I have a good grasp of basic PHP & MySQL, but don't understand how that works. For example, if you have a db of products, all with individual id #, how do you get one product from the query a <ahref>? Could someone explain?

Compiling MySQL Results
Does anyone know how to compare multiple results from a MySQL query? For example, I would like to query the database and collect all the results into a variable (perhaps $totalresults). Then, I would like to use a single statement to compare each of the results within $totalresults to the statement's conditions.

Mysql: How Do I Get The Rowcount Of The Results?
I want to execute some alternate code if the a query produces zero results, but I can't find any info on the web about how to get the number of rows in a mysql result.

Getting Results From MySQL Database In PHP
I am trying to write a php page which connects to a MySQL
Database which is supposed to get the results from a table within a
database and display the results in a table.

Below is the code that I am using:

Limit Mysql Results
I have a script which has a mysql query which returns 20 results - I want to add some validation so if my variable ($var) is empty, it only allows the user to select the first 5 results my code is: -

$sql = mysql_query("SELECT * FROM greetingcards_cards WHERE category='$cat' LIMIT $from, $max_results");
while($row = mysql_fetch_array($sql)){
$image = $row['url'];
$cardid = $row['cardid'];
echo "<br><img src="$image" /><br><a href="?function=sendmessage&cardid=$cardid">Pick this card</a><br>";}

I want it so that if the variable is empty, instead of displaying "Pick this card" it displays - "You must register to pick this card" and have a different hyperlink Is this type of validation possible? if so how is it done?

PHP MySQL Order Results
I'm using:

$sql = "SELECT * from $myTable ORDER BY `points` DESC LIMIT 5";
in a whileloop to display the top five scorers but would like to put their position next to the results (eg, 1, 2, 3, 4 and 5)

Is there an easy way to do this?

Convert MySQL Results To XML
I just got Dreamweaver CS3, and I love the built in SPRY framework. It allows you to create web applications that use a table listing, and details listing very quickly. Unfortunately the only data the SPRY framework can accept is XML. Is there a built in function to convert from a $row result from MySQL to XML? Code:

Mysql Results - Ordering Them.
i need an mysql query to rank the results, like SELECT field FROM table and to order them greatest to least by the value of a different field.

Mysql Results Pagination
I have a php code to split the results of a sql query over pages taht works great... But I need to add some feature, I need to add that if there are more than * pages it shows me "..." instead of the hole numbers of pages.. Code:

Sum All Of My MySQL Integer Results?
I have a bunch of rows, and for each row, the column "rating" has a number from 1-5. I need to add all of these together, so like if there were 3 rows with 5 for rating, it would return 15. If it's possible to do it with an SQL statement, I'll like it to average them.

Splitting MySQL Results
So I have a database, and I want to split the results into 2 columns. I don't want to alternate them, but have the first half in the left column, and the second half in the right column. How can I handle this so that it does it automatically no matter what number of entries (and so that if it's an odd number, the one overflow is on the left).

MySQL Multiple Tables / Results
I would like to perform multiple queries to a MySQL database and have all
the results in 1 result set.

Parsing PHP Code In MySQL Results Set?
I have a PHP script that pulls content from an MySQL database and returns a result set.

Is there a way I can put PHP code within a field in the database and have that code parsed as PHP code on returning a results set? If possible, I want just one field of the database parsed for PHP code. The results set is return as a straight result, not within a loop. Just inserting the <? PHP code thus ?> returns that as sources code not parsed.

MySql - Outputting Results In Groups
I want to output mysql data by groups (states). However each time php/mysql comes to a new state in the results I want it to print the state name before putting the results. Does php have some sort of memory function to recognize when the state has changed?

Split Mysql Results Into Two Columns
Trying to develop php catalog, but can't split the results into two columns, PHPcode:

Mysql Results Output Problem
I trying to set up some subdomains and I'm at the early stages of just testing the the thing . I have set up a small test DB, with the following fields, company, id, url.

I have also set up a test page to see if the output corresponds with the subdomain name. If the domain exists the result with echo "domain exists" if not it will output "does not exist". But the page just says "does not exist" all the time even though the domains are set up.here's the code:

Exploding Results Of Mysql Query
I have a table with times and dates listed like this:

0000-00-00 00:00:00
2003-09-20 20:26:22
etc
etc

What I want is to query the DB for the field (matchdate) and then get it to explode the ' ' to give jsut the date for me and then put it into a dropdown in a loop. this may sound easy but i too sleepy to work it out and searching aint good.

Mysql Results <-- Previous Row, And Next Row, Showing Next Ok
I query a database and return a result on the column "reference".
There might be 7 listings. Each row is displayed in a table, with
links through to a detail page. I am working on having a "previous"
record and a "next" record link on the detail page.

This code below works, for the "next" record, by searching the values
in the array $myarray for the variable $ref. It then returns the key
value and the key value, as a number, is deducted by one and plus'd by
one to give me the previous row and the next row.

Returning the value of the next row works a treat, but for some reason
the previous row, deduct 1, while it echoes a value to screen, doesn't
work.

This is the code:

(query database and then:)
//$ref is a variable carried into the page

$num_rows = mysql_num_rows($result2);

$i=0;
while ($i < $num_rows) {
$next=mysql_result($result2,$i,"reference");

++$i;

$myarray = array("$i"=>"$next");
foreach($myarray as $key=>$value) {
if ($value == "$ref"){

$b=($key);
$c=($key+1);
$a=($key-1);

}}

if ($a == "0") {
echo "No Preceding Record";

} else {
if ($key == "$a") echo "<a
href=../detail/index.php?name=$value>Previous Record</a>";
}

if ($key == "$b") echo "This is the current Record";

if ($num_rows < $c) {
echo "Records End";
} else {
if ($key == "$c") echo "<a href=../detail/index.php?name=$value>Next
Record</a>";
}
}

} else {

JOIN Table Results W/MySQL
I have a query with a simple JOIN.

For example:

SELECT * FROM Companies
INNER JOIN CompanyTypes ON Companies.CompanyID = CompanyTypes.CompanyID

The query returns all fields from both Companies AND CompanyTypes. I would
like all fields from Companies only.

Counting Results From A Mysql Database
I want to know how many results throw a query in order to know if they have reached a limit.I.E.

$sql = mysql_query ("select * from classifieds where user='$username'");
while ($row = mysql_fetch_array($sql)){}

I want to check lets say that only 10 classifieds per 'username' can be created. If ten or more classifieds are in the database for that 'username' then show error message.

Alternating Row Colors With MySQL Results
Is there any way i could make a image for the alternating row colors instead of a strait bold color, for instance:

$color1 = "#CCFFCC";
$color2 = "#BFD8BC";

Would there be anyway to link an image in there? I have tried it this way:

$color1 = "<img src='..style1.jpg'>";
$color2 = "<img src='..style2.jpg'>";

How Can I Arrange Results Alphabetically In MySQL
I am using this code to retrieve names from the databse

$q = "SELECT * FROM
names
ORDER BY date DESC
LIMIT 5;";

How can i arrange names alphabetically

MySQL Query Not Returning All Results
I have a user table in the DB, for example:

+---------+----------------+-------------------+
| uid | username | firstname |
|----------+----------------+------------------+
| 1 | cobby | Andrew |
| 2 | admini | test-account |
+---------+-----------------+------------------+

If, in phpMyAdmin, I query:
SELECT `username` FROM `users`;

It will return results correctly (cobby and admini, respectively).
But if I make a simple PHP script, such as:

<?php

mysql_connect('localhost', 'cobby', 'dbpass');
mysql_select_db('testdb');

$query = mysql_query('SELECT `username` FROM `users`');
print_r(mysql_fetch_assoc($query));

?>

It only returns:
Array ( [username] => admini )

Why does it only return the second result? I have a feeling I'm doing something really silly, but I looked over this test script and its got me stumped.