Populating Dropdown Menu From Db
Okay, I am trying to populate a drop down menu with items from a table in my db. I have a table called "teacher" which has the following info: I use the following code to grab the info from the teacher table. Code:
View Complete Forum Thread with Replies
See Related Forum Messages: Follow the Links Below to View Complete Thread
Populating "Month" Dropdown Menu
I can get the current month to display in a text box by inserting value="<? print strftime("%B"); ?>"> into the code for that particular text box on a form but how can I populate a drop down with names of all the months with the current one being 'default' as it would be in the text box example?
View Replies !
[PEAR:QuickForm] Dynamically Change A Dropdown Menu According To Another Menu?
I've been using QuickForm for a few months now and I am now given a new challenge: I've got a search form with a dozen of dropdown menus, the first dropdown menu being "Brand". If you select either Brand A, B, C, D... Z, the second dropdown menu "Model" must be dynamically changed to model AA, AB, AC, AD..., according to the models manufactured by the brand selected in the first box. I've seen that done on quite a few sites, but never found if QuickForm had a quick & clean way of doing that.
View Replies !
Populating Dropdown Box.
I have been looking around the internet for an example of what I need to do but cant find anything was wondering if someone here might be able to help. What I need to do is to connect to a mysql db select a table and then a field from that table and put all the contents of that field into a dropdown box.
View Replies !
Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:
View Replies !
Populating A Dropdown From A Database
I have put together a script that populates a dropdown menu from a database. My database contains a table called casinocredit, and it contains records that have been enterend over 2 different months (may and june). There is a field in the database that contains the date in this format: 2006-05-12 00:00:00 So The drop down is currently showing a month for each of those records. I was hoping that it would only display one. (the plan is when a user selects a month (say May) and hits submit, then I would display all of Mays records on a different page) See the image i have attached for a view of what is happening. Code:
View Replies !
Populating Dropdown With Mysql Entries
I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.
View Replies !
Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.
View Replies !
Populating Drop Down Menu
I use the following code snippet to build a drop down menu with the results of a query. How can I set the initial value of this input based on the result of another query? What I am trying to do is update records in the data base. The field WkEndDate is pulled along with the rest of the record and the drop down menu is built from a table of valid WkEndDate values. Code:
View Replies !
MySql Menu Populating
My goal is to use a Drop Down Menu that is populated by the database. The user is then able to select a name from the Menu that pulls all of the information for a particular person from the database. Finally, a table is populated with the information of the selected person.
View Replies !
Populating A List/menu From MySQL
is there a way to populate a list, or a menu form using php, and MySQL? Basically i have a list, and i am planing to import 2 variables, id, and name, bouth id and name are variables loaded from MySQL (yes there are multiple id's, and name's) Name would be the label displayed, and the value would be id. Thats what i need. After that i will make a submit button, witch will post the selected id to a different file. How can i achive this? Does anyone hae any samples maybe?
View Replies !
Populating City,state,country Drop Down Menu
In the registration form I have city, state, country fields. I was wondering if there was a database available on the net which has the list of states in each of the countries. That way when a user selects a country I could automatically populate the state drop down menu ...
View Replies !
Drop Down Menu Select And Populating Data Fields
I have a PHP/MySQL Content Management System set up for the job I work at. It's basically a shift program that lets users pick up shifts, post shifts, etc. The data fields are tied to the shift ID which is selected from a dynamically populated drop down box. However, I cannot get the data fields to be updated when I select a new value and I cannot get the form to accept the new selected Shift ID. I have tried using JavaScript but cannot quite get it to work. Code:
View Replies !
Dropdown Menu
i seem to be having some problems on finding how this ajax drop down menu i seen at Anime-Eden.com. it has a nice effect on how it appears. Now i am familar on how PLAIN drop down menu works, but not how this works.
View Replies !
Use A Dropdown Menu
I have a list of contacts which are sorted by name. I was hoping to create a dropdown menu in which someone can sort the list of contacts by office, city, state, and contact type. Is this possible? (I am sure it is, but I am not sure what the concept is called so I may research how to do it).
View Replies !
Advanced Dropdown Menu
I want to populate a dropdown menu with countries that are in one column of my table. I know how to do that, but I can't find how to eliminate multiple items. Some countries appear several times in different rows, but I only want each available country to be shown once in my dropdown list.
View Replies !
Mysql / Dropdown Menu
what i am trying to do is to make a system with a few input pages and edit and read pages.. so right now i got the input/edit/read pages working. (yay) But now I want to have on 1 input page a dropdown menu that reads its information from the database. and that if i go to the page i can select a value out of the db and submit that inside my form and that it reminds the value if i view or edit the page. So what i got now is a little system that is able to add/remove/edit a value inside a field called "drop01" Well now i got a other input page called "input01.php" inside this script i want to have the dropdown menu that reads its values from the "drop01" field. PHP Code:
View Replies !
Autoselecting A Value In A Dropdown Menu
I'm revamping my sites administration panel and I put in a dropdown menu to select the section to administrate (it was a LOT better than the list of links I had before, I'll probably update it some more though) and I want to know how I can autoselect whatever page I'm on in the dropdown menu, for example, here's the menu: Code:
View Replies !
Dynamic Dropdown Menu
with help from the PHP Gurus here, I have a dynamic menu script: PHP Code: <?php $time = time() + 28800; $time_plus2 = strtotime('+ 6 days'); echo '<select name="select">' while ($time <= $time_plus2) { Â Â Â Â echo '<option value=>' . date('l, F d', $time) . '</option>' Â Â Â Â $time = strtotime(date('Y-m-d', $time) . ' + 1 day'); } echo '</select>' ?> how do I now get the days of the week to link to different pages?
View Replies !
Dropdown Menu Updates
I have seen this on lot of sites, where say you goto a car site, and you click the make of the car from a drop down menu, and than after u click it, it will load up the appropriate models for that make.
View Replies !
2 Questions. Dropdown Menu And # Of Rows.
1. I have a table named pics and a column named name, just to let you know for use. I want to take the data from each row in the name column and insert it into a dropdown menu. I know how I could do it, but I would have to go: Code: <SELECT NAME="name" SIZE="1"> <OPTION SELECTED><?php $name[10 ?> <OPTION><?php $name[1] ?> <OPTION><?php $name[2] ?> <OPTION><?php $name[3] ?> <OPTION><?php $name[4] ?> <OPTION><?php $name[5] ?> <OPTION><?php $name[6] ?> </SELECT> but then I could make too many or too less. I want it to automatically adjust to the number of rows. 2.What is the code needed to find out how many rows are in a table?
View Replies !
Unwanted URLs In URL Dropdown Menu
I'm working on a PHP script and it has a user login, and the variables (username, password, id number) are passed via the URL bar. Is it possible to somehow not allow the visited page show up in the dropdown list of URLs in the browser? The problem is that people can view the list and easily see people's usernames and passwords. Example: http://www.somesite.com?username=john&password=12345 What I only want is: http://www.somesite.com/ I know that Hotmail.com doesn't show all of the pages that have been visited, all it shows in the list is hotmail.com, so I think it is possible to do this, but I don't know how.
View Replies !
Make A Dropdown-menu Filter?
I have a dropdown menu which is supposed to filter a table to show results for professionals, students or all. But I don't really know what I'm doing. This is what I have so far. Code: Initially, I was able to filter for students or professionals, but since trying to have an all option (students and professionals) it has gone to pot, and I keep getting errors. I know that my quotation marks are not right, but I can't think of a solution. I would be more than happy to see any ideas, even if they are completely different to mine!
View Replies !
Dropdown Menu <selected Name="...
I have a dropdown menu like this one: <select name="country" tabindex="6" id="select_country"> <option value="">- Country List -</option> <?php $query = "SELECT * FROM country ORDER BY country ASC"; $result = mysql_query($query) or die('Error, query failed'); while ($row = mysql_fetch_array ($result)) { $country = $row['country']; ?> <option value="<?php echo $country ?>"><?php echo $country ?></option> After I have selected one country and I hit the submit button it go back to the default value in the box, what I want is to show the selected value in box until I selected another value. If the default value is Australia when I start this page, I then select USA and hit the submit button it reset to the default value "Australia", but I want it to show USA as long I not select anything else. I have tried to use session in selected="<?php echo $_SESSION['country']; ?>" but it didnt work.
View Replies !
Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:
View Replies !
Selecting Item In Dropdown Menu
Im having problems trying to select a specific option in the drop down menu which has been populated with a list pulled from the 'category' table in the db. The option that needs to be selected is pulled from an id in a 'item' table, relating to the aformentioned category table.
View Replies !
Dynamic Dropdown Menu Glitch
I wrote this code to dynamically generate an array from files on my server and put it into a drop down menu, but the code cannot be inserted on any page anywhere without it cancelling the loading of the rest of the page. Any ideas? Here is the code: PHP Code: <? $the_array = Array(); $handle = opendir('walrus/strips/.'); while (false !== ($file = readdir($handle))) { Â Â Â if ($file != "." && $file != "..") { $file = substr($file, 0, -4); $the_array[] = $file; Â Â Â } } closedir($handle); asort ($the_array); reset ($the_array);.....
View Replies !
Network Bar, Dynamic, Dropdown Menu
Basically I have a "network bar" that I place on the top of all my sites, which has a dropdown menu box to interlink all my other sites. Basically I would like to really modify this idea out more. Code:
View Replies !
Tree View Dropdown Menu
I have such a categories MySQL table: ID | name | parent and have such a function that displays the categories in a SELECT element as a drop-down menu: function DD_ProjectCategories($parent=0) { include("db.php"); $query = "SELECT ID,name FROM categories"; $result = mysql_query($query) or die(mysql_error()); echo '<select name="parentcategory">' echo '<option value="">Choose a parent category</option>' echo '<option value="0">Root Category</option>' while ($row = mysql_fetch_array($result)) { echo "<option value="$row[0]""; if ($parent == $row[0]) {echo " selected"; } echo ">$row[1]</option>"; } echo "</select>"; unset($query,$result,$row); }.....
View Replies !
How To Pass The Value Of Selected Dropdown Menu To Another File?
there is a php-myql script that list the mysql databases in the drop-down menu, use wil select one and the submit button should pass the value or variable $db_name to the test.php, this script list the databases in the drop-down menu but when i select one and then click on submit cannot pass the db_name to the test.php:
View Replies !
Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time. If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:
View Replies !
Duplicates In A Dropdown Menu Populated From My Database
I've been searching to figure out how not to have duplicates in a dropdown menu populated from my database. This is what I have, but how do I change it to get rid of duplicates. <?php $result = mysql_query("SELECT City FROM residential order by City"); echo "<select MULTIPLE NAME="City_code">"; while($row = mysql_fetch_array($result)){ echo "<option name="City" value="$row[City]">$row[City]</option>"; } ?> </select>
View Replies !
Pagination And Dropdown Menu Used In Searching Mysql
I am working on building a database made for searching. I have a text search and a dropdown box used for searching different table collumns (lets people search for certan criteria). I have that working correctly. I also only want to show 25 results per page. I have that working correctly. My problem is that when I combine the two it breaks the code. The pagination works fine without the dropdown and vice versa. I think it is due to the variable that is being used to choose the collumn in the sql query. Code:
View Replies !
Choose From A Dropdown Menu Of Encryption/decryption Cyphers
I've written a php page which allows users to type in a text string and a key, then choose from a dropdown menu of encryption/decryption cyphers, and a method (encrypt, decrypt). The whole thing works, except the mcrypt command doesn't work. here is my mcrypt command: if ($method == 0) { //Encrypt $output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_ENCRYPT); } else { //Decrypt $output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_DECRYPT); } Here's a list of what the variables may be: $algorithm = MCRYPT_3DES $key = "plain text" $input = "more plain text"
View Replies !
Chain Menu But The Menu Should Be Multiple Select Menu/list
I am looking for codes to be able to do the same thing with multiple select menu/list. PHP codes or javascripts codes are both fine. 1) javascript + php approach: Prefer to be javascripts codes to display the chain menu. I can use the php to get the all three levels menu data from the database, and assign these values to the javascript. 2) php codes only: Or use the pure php codes (the problem is if just using php codes then I have to submit the form to the server every time, when top level menu select changes to create new menu.).
View Replies !
Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add". But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:
View Replies !
Collapsing Menu - Code A Menu For A Webpage
I am trying to code a menu for a webpage, the menu is broken up to groups i.e: Home Group1 Â*menuitem1 Â*menuitem2 Â*menuitem3 Group2 Â*Â*menuitem1 Â*Â*menuitem2 Â*menuitem3 And so on. What I want to achieve is that the groups are shown in a collapsed state depending on the page which is currently being displayed i.e so it starts out like this Code:
View Replies !
Child Menu Name Changes When Parent Menu Changes
THIS IS FOR A SEARCH RECORDS IN A DATABASE TO MATCH SELECTED CRITERIA OF A DYNAMIC OPTIONS LIST I have a set-up whereby the <select name=" "> of the List determines which field of the datbase is searched. I've create a dynamic drop down menu whereby the Parent menu changes the values of the child menu - that works fine. Code:
View Replies !
Populating A Select Box
What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box. I can do this on my own, but I was curious if I have to use a database in order for this to be possible.
View Replies !
Populating Drop Down
How do I do this drop down box ? Making an edit page. I have 2 tables groups id || categoryname program id || cateogry_id I need to populate the groups in it at same time show the selected choice from program. Not showing id but needs to show categoryname with of course the values being the id of groups.
View Replies !
|
TRACKER
