PHP :: Populating Form From Database, Then Passing Results To Next Page

Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.

Populating A Form Wth Database Info
I've coded a piece of code which populates a form with data read from the database:

$connection=mysql_connec ("localhost", "f2821842", "f2821842");
$result=mysql_select_db("QUERIES");
$query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'");
while($row=mysql_fetch_array($query))
{$empname=$row['emp_name'];}

<form name="webregform" action="webadmin2.php" method="post">
<input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>">
</form>

When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?

Passing Form Results Problem
I have a form that validates itself when the user submits it. I have another page that formats the form results and sends an email. But I don't know how to pass the form results from one page to the other. Here's the form: PHP Code:

Populating Array With Mysql Results
I'm returning a result set of one field in a table, and want to populate an array with the results. I can't for the life of me figure out a simple way to do this without using mysql_fetch_array() to cycle through the results, append that to a var, then explode that into a var and pass that. PHP Code:

Search Form And Results Page
I have a table called "lista" into my mysql database.This table has 5 text columns : "TRANSLATEDTITLE" "ORIGINALTITLE" "ACTORS" "DIRECTOR" "YEAR" , and 1 image column called "COVER".

I want to create a page with a form to search entries into this table (ex. with Title, Actors, Director, Year), and anotger php page with the search results shown inside, everyone with a link that opens a pop window (ex. 400X320). Code:

Link To Form Results Page Dynamically
I have a dropdown box that pulls information from a database. What I want to achieve is that when a caller selects an option, the option determines that page that comes up.

I tried setting the form action to the name of the option, but this down not bring up anything; actually the resulting page is .php. I also tried moving the form action statement after ther selection, but that does not work either - the Submit button does not work. PHP Code:

Passing Objects Form One Page To Another
Is it possible to transfer objects derived from a class form one page to
another?

I made 2 testscripts:

person.php
-------------------------------------
<?php

class person {

private $_name;

public function setName($name) {

$this->_name = $name;

}

public function getName() {

return $this->_name;

}

}

$p = new person();

$p->setName("Jim");

$safep = urlencode(serialize($p));

header("Location:person2.php?data=".$safep);

exit;

?>

person2.php
---------------------------------
<?php

class person {

private $_name;

public function setName($name) {

$this->_name = $name;

}

public function getName() {

return $this->_name;

}

}

$x = unserialize(urldecode($_GET['data']));

echo $x->getName();

?>

But this does not work for me....

Passing Form Data Through A Page
I'm in the process of creating a new form that stores customer input into a MySQL database. What i'm attempting to do is allow them to fill out their data, and hit 'next' to go on to a file upload form.

Upon completing that form and submitting, all information (including their data from page 1) is posted at the same time (so it's all under the same ID). What would be the easiest way to do this? Right now my submit file (submitquote.php) contains the following data (all on one page). Code:

Populating A Select Box From A Database
I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it.

The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like:

Green
Red
Blue
Green
Black

How can I make it so that Green only shows up once?

Re-populating A Form If Errors
I am learning php. I have created a simple Web page with a form.
After receing the POST request, I do some error checking. In case of
errors, I would like to re-post the page, but with the current values
for each field.

I have organized my files like this:
1) Webpage with the form (all in html, form action points to a php
file)
2) php file that receives the request.

Populating Form Text Box.
I have a PHP form for entering data on-line into a mySQL
table..
Because of the intended search facility, I require one field in the form
to be completed with exact and precise item names and spelling.
In testing, I had achieved this with look-up tables.
Ideally I would like the selected item from one of five drop-down lists
to autopopulate the form text field when selected.
Alternatively at least the option of copy and paste.
Copy and paste - for some reason will not work.
Autofill worked fine on a test form with no database connection
and in standard HTML and javascript, however, once the PHP
is added to the page neither method works.
Could anyone please point me in the direction of how to get the
autofill to work?

Populating Form Item From SQL Enum Set Rev#2
$sql = "SHOW COLUMNS FROM table LIKE 'subject' ";
$qry = mysql_query($sql) or die("Query not valid: " . mysql_error());
$res = mysql_fetch_object($qry);
// This returns a row with a field 'Type' containing 'enum(...)'

$res->Type = str_replace('enum('', '', $res->Type);
$res->Type = str_replace('')', '', $res->Type);
//now the string is something like this: one','two','three

$temp = explode('','',$res->Type);
//temp is an array with as much elements as the enum

while ($temp)
print array_pop($temp);

This way is much more easier using the elements since they are elements
of an array. Cleaver isn't it?

Populating Form Fields With Variables
The script itself works fine: mail gets sent. If there are any missing fields the form displays again with a list of the missing fields, but I can't get the form fields of the reloaded form to be populated with teh existing values. PHP Code:

PHP Not Populating Form Variables Passed Through POST Or GET
I"m running:

Windows Xp SP2
Apache2
PHP5
MySQL4

Everything seems fine and dandy, and I can do scripting on server side, but for some reason I cannot get data from a form to be put into a variable.

I have a simple form in an html page which submits, and in the php script that handles the input, none of the data in the form is going into the variables.

My php.ini file does have all the GPC's in place(ie variable_order, the way they get processed).

Populating SELECT Multiple Form Field And Inserting Into Db
I have an update form where I'm trying to populate a SELECT multiple field with a list of 48 categories, from tbl work_cat. And show, as SELECTED, the one or many choices that the user had previously selected from the 48 categories which are stored in tbl cat_relations as $relation_cat.

Then allow the user to update their selections and update the database. But I can't get my form to work. First problem, I can't get the SELECT field on the form to show the categories, and then I don't know where to go from there. Below are my form page and my processing page. Code:

Passing A Variable To Paginated Query Results
I have a form that passes a single variable via the GET function to a mysql databse query with the results paginated. The first page of the results work fine, but the link to the second page yields the page 2 results of the entire table. I'm guessing that the variable hasn't passed to page2 query? Here's my code:

Passing A Parameter From An HTML Page To A PHP Page
I want to pass a language value (EN/FR/DE etc.) from an Index HTML page to a PHP page with a language code in the call, so that the PHP page can select texts in that language. I would like to to it from an unordered list item if possible by extending the link ... <li><a href="scripts/pricelist.php???>Pricelist[/url]</li>

Populating Form In Parent Window With Value From Popup Window
I have a text box in the parent window.. now i want to populate this text box with a user_id that i will get from query within a popup window.. How do i get the value from the popup window to be passed to the main window form field in php. I know how it can be done in javascript but when i tried combining javascript and php i dont get the desired result.

Having Different Results On Same Page
I have a database that I would like to use to display the contents in different lists on the same page. In other words, I would like a list of the latest 15 entries in the database to appear in list...then I would like the next 15 to appear on the same page but in a different list structure, etc. I have this so far, but it only displays the latest 15...I am stuck on how to get another list generated from the same query: Code:

Getting Results From MySQL Database In PHP
I am trying to write a php page which connects to a MySQL
Database which is supposed to get the results from a table within a
database and display the results in a table.

Below is the code that I am using:

Database Search Results
i have a paid to read website,im hosting it off my own pc..as a member you can search offers and complete them, heres where i need some help..when a member clicks submit and the offer goes to an offerdone table i need the offer to hide from them so they cant do it again,also that same offer needs to hide in the search results as well...is there somthing like onclick hide and for the results something like if duplicate hide from search or if offer found in this table hide from results...

there are 2 tables one will all my offers the other with offer they have done,also this needs to apply for each member account.i am new to all this and have made it this far to have my site up and going but im looking for those extra catchs i could really use,so that a member cant repeat an offer they have already done,

Use Arrays To Page Through Results?
I've got a search facility that interrogates an SQL database then shows the results 30 at a time. Currently, when you go to the next page of results it has to run the query all over again, because there is no way of handing the resultset to the PHP file. So I wondered if there was another way of doing it.

I'm tempted to use mysql_fetch_array and create a multi-dimensional array full of result rows, then hand that around, but so far cannot find out how to hand a PHP array as a variable to a PHP page.

IS this possible, or am I barking up the wrong tree? Or is there a better way of doing this?

How Do I Make The Results Appear On The Same Page?
Presently i am calling a new file to accept my dropdownlist values. Is it possible to make it such that the results will just appear on the same page? Code:

PING Results On PHP Web Page!
Can someone show me sample code on how can I write a script that shows ping results on a web page.

Multi-page Results....
I'm working on an engine to search a MySQL database of a bunch of forum messages. The PHP code retrieves the results from the database, then stores them into an multi-dimensional array for processing.

Once stored, the code parses each result and assigns it a relevancy score, and once all of the results are scored, it then sorts all of the results according to relevance. The end product off all this is an array that holds all of the retrieved messages relevant to the search, holding such information as title, author, date, msgID, blah blah blah. now that i've kinda explained what's going on, i'll get into the problem i've bumped into.

Being that there's roughly 16,000 messages in the database (not to mention the 800,000 lines of message text) that could possibly be the results from a query, displaying it all on one page is most definately out of the question (it still takes a few seconds to load on my cable line with only a few hops to the T3'd server. I'd hate to see what a 33.6 or 56k user would be waiting for).

The real problem all comes down to: how am I going to pass the results from one page to the next? an array of a few thousand messages is a *little* large for an http post action, and storing the results in a table in the mysql database posses a few problems as well (namely, how long to keep the table around after the user has executed the search. temporary tables are out of the question, as they die as soon as the mysql connection is closed, but a persistent mysql connection would create exactly the opposite problem: ei, temp. tables never die).

10 Results Per Page But From Different Categories
I have a script that shows a list from a different category depending on what is in the URL. I've got it to limit the results to the 1st ten results and keep the chosen category in the link(?category=differentcategory) but when next page is clicked it repeats the same ten results. Code:

SQL Query - Results From Another PHP Page ?
Can I store this PHP code in another page, then refernece it on
multiple pages using Require or Include ???

//results from sql query
for ($i=0; $i<$number; $i++) {
$ID = mysql_result($result,$i,"ID");
$CompanyName = mysql_result($result,$i,"1");
$ContactName = mysql_result($result,$i,"2");
$Phone = mysql_result($result,$i,"3");
$HomePhone = mysql_result($result,$i,"4");
$MobilePhone = mysql_result($result,$i,"5");
$AltPhone = mysql_result($result,$i,"6");
$SecondContact = mysql_result($result,$i,"7");
$SecondPhone = mysql_result($result,$i,"8");
$ThirdContact = mysql_result($result,$i,"9");
$ThirdPhone = mysql_result($result,$i,"10");
$Notes = mysql_result($result,$i,"11")

Getting Other Webpage Results In To Php Page
I Have a page which will take authentication from a diffrent page from
a difrent website.

My program needs to call a page like this from php page lets say:
http://www.abc.com?handshake.jsp?us...htoken=94399843

my php page is at www.xyz.com
based on this url's response i need to print the result on my php page?

I tried this..

$url="http://120.126.79.21:6080/AutoPrintWeb/apvalidator.jsp?tempid=$tempid&authtoken=$authtoken&ipaddress=$rmtadd";
$fp = fopen($url, 'r');
$response1=stream_get_meta_data($fp);
print_r($response1);

The reukt is like this:

Array ( [wrapper_data] => Array ( [0] => HTTP/1.1 200 OK [1] => Server:
Apache-Coyote/1.1 [2] => Set-Cookie:
JSESSIONID=B55CA82D1790D6C0A9E20ED1CEDBB1B9; Path=/AutoPrintWeb [3] =>
Content-Type: text/html;charset=UTF-8 [4] => Content-Length: 382 [5] =>
Date: Fri, 10 Mar 2006 10:22:41 GMT [6] => Connection: close )
[wrapper_type] => http [stream_type] => tcp_socket [mode] => r+
[unread_bytes] => 382 [seekable] => [uri] =>
http://193.186.79.21:6080/AutoPrint...dress=127.0.0.1
[timed_out] => [blocked] => 1 [eof] => )

I need only sucesss or fail..

Return Results On One Page
i have a search field on a .php page. i want to return the results on the same page i.e i dont want the action to point to test2.php but test.php which is were my search filed is sitting at the moment. how do i do this?

i got this on my first page:

<form method="post" action="test2.php">
Name: <input type="text" size="10" maxlength="40" name="name">

<input type="submit" value="Send">
</form>

and this on the second:

<?php
$name = $_POST['name'];
if ($name=="Friday")
echo "Have a nice weekend!";
elseif ($name=="Saturday")
echo "Tomorrow is Sunday!";
else
echo "Please enter Friday or Saturday";
?>

Limit Results To 20 Per Page.
I have a Database and script where it SELECT * FROM my database and lists the info on my website. I want to be able to limit the quary to only 20 per page. Here is an example of what i am talking about on this page http://sacvalleyhomes.com/Sacvalley/property_inquiry.php

Everything listed under Property Inquiry is genarated be my database. As it is now i have 5 diffrent tables for 5 diffrent pages. This is way to much work to keep updated.

What i want to do is put all 5 tables in to 1 table and have my php script only show the first 20 listing then generate the page numbers on the bottom or some way to view next 20 results and so on. Code:

Why Does My Page Always Show JUST First Set Of Results?
Whenever I execute a query I limit it to lets say 2 rows per page. The problem is my code will only say there is 1 page of results when there should be more! What am I doing wrong? Code:

Results Only X Number Per Page...
am doing a real state site and when searching it shows all the results from the database in one single webpage, can you help me with one easy way to show only 10 results per page?

I've seen some complicated sites with previous and next arrows, i only need to show 10 results then a link to show next 10 and that's it.

Limited Results Per Page
i have a download section for my site, with about 20 downloads, and i was wondering if their was a script so that it would only show 5, and clicking 'next' button would show the next 5 etc.

Having Trouble Alphabetizing Results From A My SQL Database
I'm a beginner and I'm having trouble figuring out the sort command (assuming that's what I'll need to alphabetize my results from a database.) Any helpful input is welcome.

Grouping Database Results In Pagination
I'm dealing with a situation where I can potentially have over 3000
results to display from a database. I'm successfully paginating the
results, 10 at a time, but don't want to display 300+ page links at the
bottom.

How can I group the pages to show, for example, the first 10 pages,
followed by a "next 10" link?

i.e., Page: 1 2 3 4 5 6 7 8 9 10 > >> Next 10

My current code:

Sorting Database Query Results
I want to know if it is possible to sort query results so that the records with a value in a certain field is displayed first and the records with the field empty thereafter.

Showing Image With Database Results
I am trying to retrieve data from a MySQL database and have got it working. Only thing is I would also like to display an image for each row. Each record has a file number and the images are all saved in an image folder and are named with the actual file number.

EG there is a record with file number 1111 and there is an image called 1111.gif in the images folder. I have included my code below. If someone can tell me how to include some html code to show the image in my php code. Code:

Problem Retrieving Results From Database
I'm trying to retrieve fields from my database with following mysql
statement:

$query = SELECT g_games.Title FROM g_collections, g_personal_reviews,
g_games WHERE (g_games.ID=g_personal_reviews.G_ID AND
g_collections.U_ID = '" . $data1['ID'] . "' AND g_personal_reviews.C_ID
= '" . $data2['ID'] . "' ) ";
$resultset = mysql_query($query);
$data = mysql_fetch_array($resultset);

3 Rows in my database comply with the above statement... though I only
get 1 to show up on my php page? How can I show all of them?

This is the php code I'm using to write the results:

while ($data= mysql_fetch_array($resultset))
{
echo $data[Title]." ";
}

My tables are as followed:
g_games
g_collections
g_personal_reviews > this table connects all others with G_ID ("game
ID"), C_ID ("Collection_ID"), U_ID ("User ID)...
users

Putting Database Results In A 5x1 Table
I have a db of tens of thousands of entries. It's not too hard to pull
all the entries and build a table that displays them one at a time, but
in my case, that will be a huge waste of space. What I want to do is
put one record in each of the columns. I thinks it's possible to do
because I have seen very elaborate thumbnail gallery scripts to do this.
I just want to be able to put two or three strings of text from each
record into each row, and a checkbox. Here's sample of what I mean:

<table width="76%" border="1" cellspacing="1" cellpadding="1">
<tr>
<td>$record1Line1<br>$record1$Line2<br>
<input type="checkbox" name="$record1checkbox" value="checkbox"></td>
<td>$record2Line1<br>$record2$Line2<br>
<input type="checkbox" name="$record2checkbox" value="checkbox"></td>
<td>$record3Line1<br>$record3$Line2<br>
<input type="checkbox" name="$record3checkbox" value="checkbox"></td>
<td>$record4Line1<br>$record4$Line2<br>
<input type="checkbox" name="$record3checkbox" value="checkbox"></td>
<td>$record5Line1<br>$record5$Line2<br>
<input type="checkbox" name="$record5checkbox" value="checkbox"></td>
</tr>
</table>

I want to pull about 200 records at a time from the db and display as
described above. How can I tell php to take five records from my result
set and display above, then loop through the result set until I'm done?

Filtering Results By DATE Value In Database
I have this code in my page for displaying some data from a database, sorted by date. i had posted a messed up version of this a while ago but I couldnt get it working even after a few suggestions. PHP Code:

Displaying Database And Getting Unwanted Results...
I want to display everyone in the database, but only if the 'level' field is larger than 0. Well, this works fine for most of the database... but if the last entry in the database is 0, then it prints it anyways.

Is there anyway around this? I tried adding an if statement before the last bit where I echo out the table rows, but it was killing the entire table, or still showing the same results. Code:

Function To Fetch Database Results
I have a function that is supposed to fetch all the results from my table "games". There are two database records in that table. My function is supposed to display all of the records, but it only displays one. I also use a function to display a certain template. Here is the coding for both functions and my index. Code:

Counting Results From A Mysql Database
I want to know how many results throw a query in order to know if they have reached a limit.I.E.

$sql = mysql_query ("select * from classifieds where user='$username'");
while ($row = mysql_fetch_array($sql)){}

I want to check lets say that only 10 classifieds per 'username' can be created. If ten or more classifieds are in the database for that 'username' then show error message.

Displaying Results From Database In A Particular Format
How do I display results from a database in a particular format. For example the following text in this format including the lines in stored in the database:

Quote“Hello,

Welcome to the news for 11/06/07.

Thanks”
When I echo the results using the usual, <? echo $row_news[‘news’]; ?> it doesn’t echo the information in the database in the format it is stored for example it will display like this. Quote“Hello, Welcome to the news for 11/06/07. Thanks” How do I get it to display in the format it in displayed in the database?

PHP / Microsoft SQL V7/2000 - Page Results
Anyone know a simple way to page results of a SQL Select using Microsoft SQL ? I don't believe they have anything as handy as MySQL LIMIT.

Displaying X Number Of Results Per Page
What I need to do is this. I query a MySQL database and, for example, 400 results are returned. I can get it to display the number of results, but I would like to set a value to display, say 20, results per page and generate numbered links with and offset to browse through and next/previous buttons -not unlike this page. Can anyone point me in the direction of a good article or if you have it, post some code here?

Newbie Question: Results By Page
How do I make results that I select from my database on different pages
based on length?

For instance, say I have over 50 records with more being added and I want it
to display 10 records per page. How do I get that info to display only 10 at
a time instead everything all in one page?

Fetching Results Across Page Loads
I would like to find a way to execute a query against an MS SQL server
and return a small number of rows each page load. However, I cannot
read all the results in during the first page load due to size
contraints.

Here are the details. A user submits a request. I construct a SQL query
and execute on the MS SQL server. The query results in a million rows.
The initial page load shows the first 100 rows. Each successive page
load shows the next 100 rows. Because our web server has limited disk
space, I do not want to return the entire result set now, but only 100
rows at a time. Also, for performance reasons, I do not want to rerun
the query each page load.

So, I need a "persistent result" set that can be fetched from across
page loads. I have tried to store the result set in a session variable
using serialize and unserialize, but to no avail. It seems that across
page loads the result set loses its way, even with a persistent
database connection.