Query Result Display
PHP Code:
<html>
<head><title>Display Table</title></head>
<body>
<?php
$database="temp"; /* DB name */
$host="localhost";
$user="root"; /* Set DB Username */
$pass=""; /* Set DB password*/
mysql_pconnect($host,$user,$pass); /* DB connect....*/
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Turn Select Query Result Into Hyperlink To Other Query
I have a query which gives results of selecting coursenames from a table called trainingtopics but this does so in a continuous bulk of text without any breaks between each record. my question how do I create line breaks between each record and also how can I force each query result to become a hyperlink which when clicked runs another query that gives details of that course. <?php $user = "root"; $host = "localhost"; $password = ""; $connection = mysql_connect($host, $root, $password) or die ("Couldn't connect to server."); $database = "courses"; $db = mysql_select_db($database) or die ("Couldn't select database."); $sql = "SELECT coursename FROM trainingtopics"; echo $sql."=sql<br>"; $result = mysql_query($sql) or die(mysql_error()); echo $result."=result<br>"; while($row=mysql_fetch_array($result)) { // NOTE this one ABOVE the echo echo "result found!"; echo $row[0]; } ?>
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Speeding Up Query/code (query Within Result Set)
I'm looking for ideas on how to speed up this script. Basically it finds all the zip codes in a zipcode table, then looks for all the records in another table with those zip codes. Right now it finds all the zips then within that WHILE, it looks for a record in another table with that zip: PHP Code:
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Use Query Result Field As Query Key For New Query..
$query  = "SELECT ProjID, UserID, ProjDesc, file, OrigProj, OrigUser, ProjDate FROM projects"; $result = mysql_query($query); I would like to take the field 'UserID', and utilise it for a Query statement to my users table in my database, to read and fill in information to my table, which looks like this: PHP Code:
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Display The Result
I have a sql statement : mysql_query = "select count(*) from clips where cat = $show[id]"; How do I display the result to this? Normally I put "while($show = mysql_fetch_assoc($result)) { echo $show[id] }" But thats to create a loop of certain results. How do I show the results from a "count" function?
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If Clause To Display One Result
I have a variable and I want to run an if clause to display one result if the variable is an odd number or display a different results if it is even. if ( $schedule_rs->Fields("team1") == 1 )Â { Â Â echo "odd"; } else { Â Â echo "even"; }
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Using Query Result To Do Another Query In Loop
I have 2 tables, one called users2 and one called books. Books has a field called UserId, which is the ID of the user that added the book to the database. My problem, is that i need to take this ID from the book table, and use it to get some information from the user table. Here is my code to get the ID from the book table: Code:
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Display Of Mysql Table Result...
I have a mysql table of articles with fields: - recordID - department - articleTitle - articleText Using PHP, I'm attempting to get the results of the table to display as follows: Department 1 - articleTitle 1 - articleTitle 2 - etc.... Department 2 - articleTitle 1 - articleTitle 2 - etc.. I figure I should use a while loop but can't figure out how to exit/reset the loop when a new 'department' is encountered in the $result.
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Display Array Result Horizontally
I have two issues but i'll diplay them in two threads for clearity sake. one now and the other in a different thread. thanks for your support. I want to display the output of the script below horizontally, say in five colums without diplaying an element twice. Code:
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Display A Preferred Group As First Result
My database has my stuff and competitors items for sale. I have written a PHP search script that allows users to dynamically select what criteria they want to base their search. Results will always be formatted in an ASC order based upon price. What I want to do is Group these results by vendor and then have my Group always display first? I am using the latest MySQL, PHP4x, and Apache. I've tried a CASE statement but the results were spiradic: I obviously did it wrong and I wasn't sure it would ever work. Currently, I'm thinking about the following: SELECT * FROM idxdownloansfm, fa WHERE $sqlZ AND EXISTS (SELECT * FROM fa LEFT JOIN idxdownloadsfm ON fa.LO_NAME=idxdownloadsfm.LO_NAME WHERE fa.LO_NAME = 'FIRST ADVANTAGE ERA' ORDER BY LO_NAME;
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Page Numbering - Display A Set Amount Of Records From My Result.
I am having a problem with trying to display a set amount of records from my result. I have modified the Page Numbering tutorial from this site and adapted it to use MSSQL. I have verified that the correct values for my variables are being passed to the query. The calculation for the records that should be displayed per page is correct. The total number of records returned from my query is correct. And the calculated number of total pages to be displayed is correct. So, initially it displays the first 10 results as it should, and has the pages numbers at the bottom. The problem is, when I click on a different page number the same 10 results are ALWAYS displayed. Even though my $page variable IS being updated. Code:
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Result From A Sql Query
Is there anyway I can exclude just one result from the database based upon the value of a field, for example i want to exclude the field with an ID of 1 but get all the other fields in the database. is this possible and can anyone tell me how? PS: I had thought about doing something like $query1 = mysql_query("SELECT * FROM table ORDER BY id ASC"); while ($row = mysql_fetch_array($query1,MYSQL_ASSOC)) { $id = $row['id']; if ($id == 1) { //DO NOT DISPLAY ITEM } else { //DISPLAY ALL OTHER ITEMS } }
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Result For Query
I dont know why this query is not returning a value, when I should be getting the value of ཋ'. PHP Code: mysql_select_db($dbname, $conn) or die (mysql_error()); $query = "SELECT MIN(q_id) FROM questions2 WHERE quiz_id='".$quiz_id."'"; echo $query.'<br />' $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_array($result) or die(mysql_error()); $first = $row['q_id']; echo 'first='.$first.'<br />'
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Linked Result From A Query
I'm trying to create a query that will return a linked record from a database that will take me back to an update page with that record so I can change things in the record. I'm having trouble finding simple code to do this.
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Echo A $result Of Query?
Trying to have an echo display a result from a query. Not such a hard concept. Yet I am having trouble. What good is the data without analysis. Here is what I am using to try and grab result. Have been told it looks correct, must be missing something small. When this runs, alternate echo displays in browser. So you know: 'testdata' is the table 'score' & 'id' are columns or fields. Almost think it is missing a table structure to display in. Looking for player name column and score column (for the sake of example). Code:
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Paging Of Query Result
This script used to be working in splitting query result into pages. But now, PREV 1 2 3 4 NEXT links is not working anymore. Any idea how to fix this ? or what is wrong with this script ? Code:
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Populate Result Query
I query database and it produces rows of results. I want to populate it so that the first 10 rows go to the 1st page, the next 10 rows to the 2nd page and so on. The last page will be at most 10 rows and it can be less than that. How do I do it? Or do anybody know if there is any sample code that I can refer to?
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Filtering In Query Result With WHERE
I am trying to filter out records in a query using WHERE expressions. See example below. if ($league="All") {$leaguebool="1"} else {$leaguebool="League='$league'"}; $query = "SELECT League,HR FROM ranfranbattingsim WHERE ('$leaguebool') ORDER BY $sorder DESC LIMIT $limit"; My desire is to select all records if $league='All' and select only records where LEAGUE=$league if $league is anything other than 'All'. LEAGUE is one of the fields of the database. I hope that I explained that well enough. I am open to any solutions, and have considered that perhaps I should be using something other than the WHERE statement to filter the records.
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One Row Result Database Query
Most of the pages I write are multi-row queries. I have about 30 pages that will only yield one row of about 15 columns. What is the best way to design this page? Right now, I am using $row = mysql_fetch_object($results) - this is causing a minor issue with positive/negative signs with numbers.
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Query Not Returning First Result
I have a query that is returning the correct number of rows. However, when I try to print the rows out, it will not print the first row, but all after that. I can't figure out why it isn't printing out the first row, even though the query is returning the results. Here is my code below to print the results in a table: Any suggestions? while($row2 = mysql_fetch_array($result1)) { $affinity_name = $row2['affinity_name']; $affinity_detail = $row2['affinity_detail']; $affinity_no = $row2['affinity_name']; $track_id = $row2['id']; get_name($affinity_name); $affinity_details .=<<<EOD <tr> <td><a href="/m_t5.php?affinity_id=$affinity_no&q=$name">$name</a></td> <td>$affinity_detail</td> <td><a href="/delete_track.php?track_id=$track_id">Delete</a></td> </tr> EOD; }
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If Query Result Returns Nothing
i have a marquee which scrolls across news items, all this is database driven, however if no news items are returns from the query, my page errors, can someone help me write an else statement or something so that the page doesn't error. my code is below:- <?php require('database3.php'); if(!isset($news_item)) $news_item='' $query = "select * from monksc.news where DATE_SUB(CURDATE(),INTERVAL 14 DAY) <= startDate order by id"; $result = mysql_query ($query) or die (mysql_error()); if (mysql_num_rows($result)>0) ..............
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Displaying Result Of A Sum Query:
$sql = "SELECT sum(value) FROM `offers' WHERE sid='$sid'"; $result = mysql_query($sql); As you can see, I'm trying to select a column in my database which is named "value" I want to return the sum of the records which match the current user's subscriber id ($sid) I think the query is structured correctly. However, I'm having trouble placing the result of the query into a variable that php can echo to the page. In the database, the numbers are formatted as decimal. I just want to get the sum of the fields into a numeric php variable that I can add/subtract/divide etc and echo to the page. How do I go about doing this?
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Mysql Query Result
I have successfully selected 4 rows using a mysql SELECT query. However, I would like to random pick a row from this result so that every page refresh will yield something different.
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Weird Query Result
I am trying to do a simple query, but instead of a numeric value, I get "Resource id #34". $newdodgemod1 = "select default_dodgemod from phpbb_classes where class='$newclass'"; $newdodgemod2 = $db->sql_query($newdodgemod1); Any idea what is wrong with the code? All field exist and the variables are set correctly. I don't understand why I am getting this error.
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Query Result To Array
i have a table with two field ID and CAPACITY. i want the ID to point to the capacity on an array $top = "SELECT * from topics"; $db = new mysqli('localhost','root',?'); $db -> select_db('testing'); $res_top = $db->query($top); $topics = array(); while ($row = $res_top->fetch_row()) { $topics[$row['id']] = $row['capacity']; }
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Query Result Values
i have two tables a customer and package table. a customer can have many packages. how i can i set a status in the customer table to 'complete' if all the packages in the package table that relate to that customer are set to 'paid'? i can do a simple select statement but how will i know if all the status rows returned from packages are set to 'paid'.
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Searching A Query Result
I have a simple query that selects everything from a database and limits the results to one row ordered by desc. The code does work. The next step is to search the query result to see is if a certain feild has a result. <?php Include("config.php"); $con; if (!$con) { die('Could not connect: ' . mysql_error()); } $result = mysql_query("SELECT * FROM photos ORDER BY photo_id DESC LIMIT 1"); while($row = mysql_fetch_array($result)) { echo $row['photo_id']; } ?>
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Query Doesn't Show First Result
I've created this query but it never shows the first result. I can have any number of results and order them however I like but whatever the first result in the list is it doesn't appear. Code:
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Field Name Of Result Query
I want to get name of the fields of a result query i.e. i have a query $result=mysql_query("select * from reports order by report_id desc"); One thing is clear here i don't know how many fields present here above query is a example bcoz actul is a too much long query that's why i am using a simple query. i can get value easily like this while($row=mysql_fetch_array($reslult)) { $abc=$row[0]; }
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Limit Query Result According To A Criteria
I have the following code which doesn't work: "SELECT COUNT(*) AS total FROM $table_name WHERE certain criteria HAVING total<=100"; The query above doesn't work and i get zero results. In general the query take lots of time mainly because the criteria is not specific enougth and I get many many hits. I want to stop the query after getting the first 100 hits according to a certain criteria. When I use LIMIT 0,100 and not HAVING i get result from the first 100 records in the table but my table contain few million records.
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Query Result Navigator Function
I've just updated this, and I thought I'd also say that not only can this provide a page navigation for MySQL or other database results, but can be used to navigate other lists.. such as a file list. PHP Code:
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Easiest Way To Print The Result Of A Query
I am using the following code: $host =""; $username=""; $password=""; $database="123"; mysql_connect($host,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT SUM(rcountry) FROM 123 WHERE sessid = '$PHPSESSID'"; $result=mysql_query($query); $num=mysql_num_rows($result); mysql_close(); Whats the easiest way to print the results of the query? I just need the value returned by this section: $query="SELECT SUM(rcountry) FROM 123 WHERE sessid = '$PHPSESSID'"; I will be using the value in a mathmatical problem later on, but for now I just want to print it out and I am unsure as to which variable to echo.
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Multiple Result Sets With One Query
I need to query the DB and find records that coorespond to a given month and then display the data. $sql="select * from $tbl where month='january'"; ....... through december My question is this -> is it better to create 12 different queries or create one query and use an array (or somethiing else) to create basically 12 result sets? To me - 12 queries seems like it would be taxing on the db.
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Same Mysql Query Doesn't Always Return A Result
We have no access to a mysql NG on my provider's server, so we ask here: We have a long query (long in text) with a UNION between 2 select. We have been informed that some times the query doesn't return any result. We have tried on our server and we always get a result. BUT, trying on the hosting server, many times the query doesn't return any result and doesn't get any error. Any idea ? does Union have any problem ? how to check if the query failed ? My hoster said that sometimes the table can be locked (if the server is overloaded) and then mysql doesn't return any result, but this seems to me an aberration. the query takes about 0.0050 sec to execute when it doesn't return any result, and 0.030 when I get results
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Moving A Query Result Into An Array
I have read all the array stuff done searches for examples, but am still not clear if there is a way to do a query from a MySQL table and move those vaules into an arry. I am sure it can be done, but I thought I would find a function that would do it. Am I just overlooking something? $resultID = mysql_query("SELECT DISTINCT slot FROM items"); while(list ($slot) = mysql_fetch_row($resultID)){echo"$slot";} So anyone have a good way to move the result into some array?
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Strange Result From Table Query
I have a simple query that I am restricting to the first 4 character, however instead of the first 4 characters I am getting only the characters from the end of the field. The information in the field resembles: 4285-002 My result should be: 4285 What I am getting is: -002 The following is the code to pull the dat from field 'Dest': $dest=odbc_result($rs1, 'Destination'); $deststrcount=1; $deststr = $dest; $deststr = str_split($deststr,4); foreach($deststr as $destv){ if ($deststrcount<="1"){ $desttext=$destv; $destnew = "DEST[1,$deststrcount] $desttext"; $strcount=$strcount+1; }
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Query Giving Array As Result
I just started PHP and getting the following error when trying to read and echo something from my DB. I get Array as an result of a working SQL query (I tested it in PHPMyAdmin SQL Query) and it should be something else. Array doesnt return in the database i selected, but still it's here. <? $host="localhost"; $user="xxxxxxxxx"; $password="xxxxxxxxxxx"; $dbname="mohaaleague"; $connection = mysql_connect($host, $user, $password) or die ("Kan niet verbinden"); $clan = "Belgian Fun Clan"; $db = mysql_select_db ($dbname,$connection) or die("Je Stinkt"); //SELECT clan FROM clan WHERE clan='Belgian Fun Clan' $query = "SELECT clan FROM clan" or die("Query Mislukt"); $result = mysql_query($query) or die("Query Mislukt1"); $row = mysql_fetch_array($result, MYSQL_ASSOC) or die("Query Mislukt2"); extract($row); echo($row. "<br>"); if ( $clan == $row ) { echo "het werkt"; } else { echo "het werkt niet"; } $disconnect = "mysql_close"; ?>
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MySQL Query Result Rows
Still learning the ropes of PHP/MySQL here so pardon if this is something from a 101 class. I am wanting to know if/how I can query a MySQL database, pull two rows of information and assign them individual variable names. I know this isn't too clear. Let me try to explain what I want to do. Let's say I have something similar to this: Code: $query = mysql_fetch_assoc(mysql_query("SELECT entry_id, user_id, date FROM my_entries WHERE user_id = '$user_info[user_id]' ORDER BY date DESC LIMIT 2")); What I would like to be able to do is assign separate variables for the info on the two rows returned by the query. I want to have the following variables: $first_date = $query[date]; <= from the first row $second_date = $query[date]; <= from the second row I can then use the two variables to compare to each other, etc. Can this be done with a single query? Or are two queries required (if so how)?
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Processing MySQL Query Result
after executing the query, say it returns 1000 results. if i just want to do some sampling and like to have a look on 4 of them, how can i refer to these 4 random records out of 1000? i'm working on processing the result of $res_array which has 1000 records. query = select * from test; result = mysql_query(query); records1000 = db_result_to_array($result); //how to select/remove records1000 to get say, records4? function db_result_to_array($result) { $res_array = array(); for ($count=0; $row = $result->fetch_assoc(); $count++) { $res_array[$count] = $row; } return $res_array; }
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Manipulating Result On A SELECT Query
I have the following table: +-------------------------+ | id | tid | type | value | +-------------------------+ | 1 | 23 | 1 | 8 | | 2 | 21 | 1 | 6 | | 3 | 21 | 2 | 4 | | 4 | 21 | 2 | 9 | | 5 | 22 | 2 | 9 | | 6 | 22 | 1 | 10 | | 7 | 23 | 1 | 5 | | 8 | 22 | 1 | 4 | | 9 | 21 | 2 | 7 | | 10 | 22 | 2 | 7 | +-------------------------+ and I want to get the result like this: Code:
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Query Problem - $result = Mysql_query
PHP Code: <?php $lic_id = $_POST['licid']; $result = mysql_query ("SELECT DATE_FORMAT(license.exp_date, '%M %d, %Y') AS exp_date1, usersw.user_id, usersw.lic_id,                 users.user_id, users.user_name, license.lic_id, license.sw_id, license.lic_num, license.po_num, sw.sw_id, sw.sw_name, license.auth_num, DATE_FORMAT(license.purch_date, '%M %d, %Y') AS purch_date1, license.notes, license.quantity             FROM users, usersw, license, sw             WHERE $lic_id = license.lic_id and license.lic_id = usersw.lic_id and users.user_id = usersw.user_id and license.sw_id = sw.sw_id and users.user_id = usersw.user_id             ORDER BY license.lic_num, users.user_name") or die(mysql_error()); while($row = mysql_fetch_array($result))         {
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