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Re-populating A Form If Errors


I am learning php. I have created a simple Web page with a form.
After receing the POST request, I do some error checking. In case of
errors, I would like to re-post the page, but with the current values
for each field.

I have organized my files like this:
1) Webpage with the form (all in html, form action points to a php
file)
2) php file that receives the request.




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?>

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I am trying to create a webpage that will allow me to view my 'email' website whilst I'm at work. The firewall blocks the page and I was hoping that there was some surreptitious way to get around this problem. My thoughts for a solution to this would be to create a variable with the website's name in pieces. Then send it to a function that opens it in a frame or something.

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line A1 line B1 line C1
line A2 line B2 line C2
line A3 line B3 line C3

line D1 line E1 line F1
line D2 line E2 line F2
line D3 line E3 line F3
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I am looking to generate a dropdown box from MYSQL data:

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i like to retrieve a value from DB,
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Now im able to retrieve the value from DB, i can show even show the
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the Code i used to display as follows,

#Require the database class
require_once('../dbinfoinc.php');

#Get an array containing the resulting
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$result = mysql_query($query);

$num=mysql_numrows($result);
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$i=0;
while ($i < $num) {
if(($i % 2) == 0) { $c =
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$event_id=mysql_result($result,$i,"event_id");

$event_name=mysql_result($result,$i,"event_name");

$event_publish=mysql_result($result,$i,"publish");
// if(($event_publish) == 0) {
$event_publish = 'No' }
// else { $event_publish = 'YES'
}
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echo "<tr>
<td Class='navText'
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<td class='navText'
class=$c>$event_name</td>
<td class='navText'
align='center' class=$c><input type='checkbox'
name='publish' if($event_publish==1){'CHECKED'}?></td>
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Green
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I'm creating a data entry system using php/mysql that includes the standard add/update/delete forms in PHP with a MySQL backend.

On the update pages I'm trying to fill the select boxes (that come from other tables) with the values in those other tables, yet defaulting the selection in each of those select boxes to the value currently stored in the main table which is being updated.

For example, the main table is called 'dates' and a related table is called 'department'. So one of the select boxes should have all the various departments listed in the select box but the currently selected value should be whatever is in the department field in the 'dates' table for the record the user is trying to update. Code:

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Populating Drop Down From MySQL
I am trying to populate a drop down menu of MySQL data using PHP and I have hit a snag. I think its probably something simple that a freah pair of eyes could pick out right away that I am just not seeing...

For some reason only the "firstname" part of the data is populating in the drop down and I can't figure out why. When I try to make changes to the echo lines to correct this, nothing shows up including the "firstname" data. Code:

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Populating Drop Down Menu
I use the following code snippet to build a drop down menu with the
results of a query. How can I set the initial value of this input based
on the result of another query?

What I am trying to do is update records in the data base. The field
WkEndDate is pulled along with the rest of the record and the drop down
menu is built from a table of valid WkEndDate values. Code:

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Populating <options> Tag With SQL Data?
I have a problem that I cannot seem to figure out. If any of you have
an answer or suggestion, I would appreciate it.

My HTML/PHP code needs to pull options from a database to populate the
<optionstag for a drop down menu and I cannot get it to work.

Basically, there is a form on the website with a drop down box. I need
the options in this box to be pulled from a preexisting table in a
database. That's all. Sounds very simple but I'm totally lost on how
to accomplish it.

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