Update Mysql Database Without Replacing?
what I want to do is ADD TO the existing data in a row. From what I know, I have to fetch the data first, then take it and add the extra piece, and add it back in. That way, I end up with two queries...is there any way to do it with just one query?
View Complete Forum Thread with Replies
Related Forum Messages:
Update To The Mysql Database Is Not Working?
Any ideas why this update to the mysql database is not working? PHP Code: $email=$_POST['email']; $temp=$_POST['temp']; $pass=$_POST['pass']; $sql="update config set Passwd='".$pass."', Template='".$temp."', Email='".$email."'"; $result=mysql_query($sql, $conn); if(!$result){ echo "there is a problem"; echo "<script>setTimeout("window.location='index.php?action=config'",1400); </script>"; }else{ ........................
View Replies !
Php - Update Mysql Database - Syntax Error
When i try and update the database table i get this error. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'desc='My name is ***** and I'm a 17-yr. old junior. I play electric ba' at line 1 what i am doing is having the user fill in a large text area and saving it to a database. So i think the problem could possibly be that they are using ' and " in textarea to mess it up? Code:
View Replies !
Update Query - How Do You Update A Value In The Database In A Certain Row?
I am trying to make a little thing that allows you to edit something that you have previously submitted to be in the database. How do you update a value in the database in a certain row? Right now when I run my script, it submits the updated info into into every row in the database. How do I just make it so it inserts it into row x? (x being some random number that I will have passed to it).
View Replies !
Replacing Records In Mysql
I have a web form for updating projects that feeds a bunch of mysql tables. The problem is that some of the fields on the form may generate more than one entry. So for example, I may have a project that is working into 5 countries. Code:
View Replies !
Replacing Array With Mysql Result
I wanted to repalce the following line of code $data = array(40,21,17,14,23); with for($i=0;$i<$numrows;$i++) { //print(mysql_result($result,$i,2));print("<br>"); array_push($data,mysql_result($result,$i,2));} where mysql_result($result,$i,2) is the value and when i print it displays the values. But $data array is the Y axis value for drawing a chart. Here I wanted to replace the hard coded value with values from mysql but the second code does not function. Does anybody have idea how can I replace the $data array or what may be the problem with my coding The first one works but the second one does not work but in both cases it does not display any error.
View Replies !
Replacing Text In A Mysql Table
How can I replace a string in a column by another string in a mysql table? For example, I've got a table called program with 2 columns called program_id and program_name. Some fields in the column program_name contain the string 'some text F/ some text' and I want to replace this with 'some text Ft some text'. Can I do this via command line?
View Replies !
Update A Database Based On Another Database
I need to update a database based on another database. I can already run the php code to make the update file, but I have to remove an 'or' option at the end. This is what i have: PHP Code: <?php require("db_info.php"); $db=@mysql_connect("$host", "$dbuser", "$dbpass"); @mysql_select_db("$dbname"); echo("update phpbb_users set user_active="0" where"); $result=@mysql_query("SELECT * FROM members WHERE disable=1 ORDER BY rank DESC, myname"); while($row=@mysql_fetch_array($result)) echo(" username="$row[myname]" or "); ?> I realize that i'd have to open the other database up, but I'm not sure if I have to close the first db's connection before i open the second database up.
View Replies !
Update A Database Row.
I'm trying to update a database row. I don't know if there is something wrong with my PHP or the mysql query. mysql_query("UPDATE `playerranks` SET player_points=player_points + $Amount WHERE player_name=$Player_Name"); all my variables are set to the desired value.
View Replies !
Database Won't Update
I have written an application locallly that updates a database but when I moved the database files to the remote hosting server along with the php files, the database will no longer update or sometimes only update part of the fileds.
View Replies !
Update Database
I have a table with following structure. This table is to keep records of which titles the member has on his list. tablea: ID title checked. I pull records from the table and display them. He can check or uncheck the results and submit the form for update. <form method="post" action="<?php $_SERVER['PHP_SELF']; ?>"> <?php $result = mysql_query("SELECT ID,title,checked FROM tablea") or die(mysql_error()); while ($row = mysql_fetch_array($result)) { extract($row); echo "$title"; echo " "; echo "<input type="checkbox" name="checkbox[]""; if ($checked==1) { echo " checked";
View Replies !
Update Certain Records In Database
I would like to update certain records in database so they are all written in lowercase....i have tried with it but doesn't work: <?php $db = mysql_connect("$host", "$user"); mysql_select_db("albums",$db); $result = mysql_query("SELECT * FROM albums",$db); while ($myrow = mysql_fetch_row($result)) { $al_artist = strtolower($myrow[1]); $al_name = strtolower($myrow[2]); $site = strtolower($myrow[4]); $sql = "UPDATE albums SET al_artist='$al_artist', al_name='$al_name' site='$site' WHERE id='$myrow[0]'"; $query = mysql_query($sql); } mysql_close($db) ?>
View Replies !
Update Access Database
Can anyone spare a good example of how to update a specific field in a row within a table in an access database? I am good with fetching the data and representing in a table, but what if I want to update a specific field?
View Replies !
Offline Update To Database
We have a web page where they can enter sales call information. They want to be able to enter this information at any time, while in the car, at home etc. What would be the best way to have information entered offline, then when they get connected to our intranet it would sync or upload all their data ? I thought about creating some type of web page, that would write the information out to a file. Then they would have a "sync" button or something on the intranet web page that would read this file in.
View Replies !
Database Record Update
i have about 10,000 records that contains this link in a record "http://site/directory" now i want to replace it all with "http://site2/directory".. i cannot do a update set command because the position of the link is not always the same ex.. text text text text <link> text text text.
View Replies !
Display Then Update Sql Database
I have an html drop down list that I have populated from a sql database, a selection is made and the information on the selection retrieved from the database and output in text forms on another page. I want to be able to edit or add data and then update the database. Code for the second page is below. I have echo'd the post variable and it does make it through. From what I understand the post variable is being removed when I submit the second form and so it all fails. How can i sustain the variable from the first page? Code:
View Replies !
Update Database Using A Form
i would like to up date i have the following fields; Prod_ID Prod_Desc Date_sent_in_house Used_by_date Supplier Cases_sent Cases_sold Price_p from a form i would like to enter new data into the database table., but unsure on how do do this can you help?
View Replies !
Session - Only Update The First Name In My Database
where i can only update the first name in my database details no matter whose logged in.here is the code. First part of the code [php] case 'detail': echo '<p> Please enter your details below.</p> <form action="'.$_SERVER['PHP_SELF'].'" method="post"> <p>Price<br> <input name="price" type="text" class="textBox"></p> <p>Area:<br> <input name="area" type="text" class="textBox"></p> <p>Description<br> <input name="description" type="text" class="textBox"></p> <p><input type="submit" value="Edit Details" name="editdetail"></p> </form> ..............
View Replies !
Update Database Program
i need to design a small program that runs on computers and every few seconds sends a packet to a server, which tells the server information, such as the computer's IP or the time of the day etc. I also need to design a program on the server's side that knows how to accept this information and communicate that information with a PHP file or inserts the information into a mysql database. E.g. let's say someone isn't at home and wants to check the amount of hd space they have on their computer at home. Since their own computer continually updates the server with information, the person can just log onto the server to check this. I would relaly appreciate it if someone could tell me how to do this, and which programming language should i use to create the server and client programs? Would it be c++?
View Replies !
Doesn't Update The Database ?
in my members section members can update there contact information. PHP Code: if (isset($_POST['submit'])) { $query = 'UPDATE wsd_members SET ' $query .= "first_name = '" . prepareData($_POST['fname']) . "'" . ',' $query .= "last_name = '" . prepareData($_POST['lname']) . "'" . ',' $query .= "address = '" . prepareData($_POST['address']) . "'" . ',' $query .= "city = '" . prepareData($_POST['city']) . "'" . ',' $query .= "zip = '" . prepareData($_POST['zip']) . "'" . ',' $query .= "WHERE username = '" . addslashes($_SESSION['username']) . "'"; $confirm = 'Contact Information Updated.' unset($_POST); } else { $error = mysql_error(); } when I submit, it doesn't actually update the database ? now why is that?
View Replies !
Update Database From A Form
I'm still learning PHP while im making a user-account system on a site. So all this is helping me learn. What i need to know is, when a person submits a registration form, how do you make it submit to your database and create a membership for them?
View Replies !
Code To Update Database
I am trying to update my SQL database using the script: <? include("header.php"); $a = $_GET['action']; if($a == 'giveaway') { $sql = mysql_query("UPDATE pets SET user='pound' WHERE `id`='$id'"); if($sql) { print "How sad!"; } } include("footer.php"); ?> It writes the "How Sad" with no errors but it is not updating the database. I am calling the script by: ?action=giveaway&id=156 All of the database info is held in the header.php and I know that works because I am successfully accessing the database using another .php script.
View Replies !
Simple Database Update Problem
I'm getting the error "Could not complete update of database". It looks like my updating is going wrong. Can someone please check for me and see whats going wrong because i cant seem to find it. PHP Code:
View Replies !
Looping Through Checkboxes To Update A Database
I'm developing an application that is highly database dependent. I've to use checkboxes in a number of places so as to ease the use of the system. However, I'm experiencing problems when it comes to looping through the checkboxes so as to update the related info to the database. I'm retrieving info from a a database, then the user has to select a number of unpredetermined records. When he does this, a flag for the selected record is set. But I experience problems when it comes to looping through the checkboxes to set the flags for the selected records.....
View Replies !
Scheduling - Update The Numbers In Database
I am trying to make a script that will update the numbers in my database depending on how long the script was in use. For example if the number 50 is in the database and the script is run. If it is run for 10 minutes i want the number to change to 100. If it was only run for 5 mins it should only be increased by 25. Can this be done? If so how would I go about doing this?
View Replies !
Update Database Info Using Forms
i have a page uses select and cases. i already have setup and working, auth/login to the page, create a new row in the table. i am now trying to have the user alter the information that the just put into the table. this is the code where i have setup to modify the info, $id is passed over. this puts the correct information into the form field. when i hit submit, the information, $name, $content, $id are not passed over. echo-ing results blank. PHP Code:
View Replies !
Counting Field And Update Database
I was trying hard to alter an existing script ut I didn't succeed to... I have 2 databases: - Categories (catid, shortname, description) - Transactions (date, amount, balance, user) in the categories I have 9 categories. the script displays the categories as checkboxes to choose from. I want to add the following functionality: If I select for example 3 categories, I would like to know how can I count the selected checkboxes and based on the count update the transactions database: in another way: if count=3 => add amount x 3 to the transactions database so if a user select 4 categories I update the transaction database with $5 x 4 categories and then we will get a balance of $20 for the choosen categories.
View Replies !
Tick Box, Select And Update Database.
I am trying to change the value in table with a tick box. If the tick box is selected it changes the value in the field to 'y' and if it is not selected it changes the field to 'n'. First of all I need to bring back the current state of the field and then I need to be able to update it from 'y' to 'n' as many times as I want. Code:
View Replies !
Update All Records In A Database 364 Days
I have a calendar with events for this year in a SQL database that I would like to use for next year too (the events will remain the same). The days of the week are important; what is on Monday, November 6, 2006 should be on Monday, November 5, 2007. I will copy the existing table to another table for the next year, so what I would want to do is update the dates to be 364 days from each date. Does anyone know a command that I can update all records by 364 days? The table is practice07 The field is PracticeDate (that holds the date that I want to update)
View Replies !
Database Update/edit And Delete
i have spent the last few days trying to create a simple script to add/edit and delete entries in a mysql database with php. i have 1 database with 40 tables, each table has 3 fields (id, header and body) i created an input page with input fields for header and body. the table to store the information in is selected from a drop down menu. all this works fine. for some reason i cannot get the edit and delete page top work at all. would someone mind taking a look at the code and let me know what i am doing wrong? Code:
View Replies !
Update The Status Of The User In The Database
i have a user registration script and it creats the user name and sends the user the activation link now problem there but for some reasson my script does not want to update the status of the user in the database at the moment by activated colunm default value is no and well it does not want to update to yes Code:
View Replies !
Problem With Database Update Script?
i had a script written for me that managed orders and stuff like that, part of the script was a section to change prices. so i went there an hour or so ago and tried to change the prices, and when i pressed "go" everything reset to 9.99. So then i started to get a little nervious and when i checked the database it reflected 9.99. So in a last hope i tried to edit the 9.99 price through phpmyadmin and even when i tried to save it in there it reflected the 9.99 price! What is causing this to happen!? Code:
View Replies !
Update String Value In Filed Of Database?
I am needed to remove a certain "class" number from a field of classes separated by commas from MySQL. I know how to update fields but not when in a string like that. Any help on how to approach this one? Explanation below. Field "Classes" has this value: [110,120,130,140] -> remove "120" Now field "Classes" has this value: [110,130,140]
View Replies !
Update Multiple Database Entries
I want to make a quick to-do list script. I can handle entering the info, etc. What I have a question about is when I go and view the list of to-do items, once they are complete, I want to be able to mark them "Done" So I'd have a list of all the items and a checkbox for each item. If 3 of 10 are done, I'd select the checkbox for those three, click the submit button and I'd like it to update one field for each entry. So, I'd have todo_ID, todo_DONE and want to UPDATE todo_list SET todo_DONE = 1 WHERE todo_ID = '".mysql_real_escape_string($_POST['todo_ID'])."' My question is how can I do this for multiple entries all at once?
View Replies !
Linking To Update Database In Printf Statement
I have the following statement: printf("<tr><td class="ltgrey">%s<td class="ltgrey">%s, %s</td><td class="ltgrey">%s<td class="ltgrey">%s<td class="ltgrey">%s</tr>", $myrow["client"], $myrow["last"], $myrow["first"], $myrow["phone"], $myrow["email"], $myrow["url"]); and wish to have the client displayed as a link so that a user can clik on it to update the information in the db. How can i do this?
View Replies !
Using Checkboxes To Update Multiple Database Entries
I have a query that shows a list of options that a user can toggle on or off using a checkbox. query... form... while($row = mysql_fetch_array($result))... <input name="menu_show_attribute[]" type="checkbox" class="checkbox"'); if ($row['menu_show_attribute'] == 1) { echo (' value="'.$row[menu_id].'" checked /> } else { echo (' value="'.$row[menu_id].'" />'); } The list is generated from boolean values in a DB. This populates my form with checkboxes, some are checked and others are not. I'm using an if statement to sort it (checked). This works fine. The problem is when the user un-checks a checkbox, the value does not get passed and the DB does not update - set/change it to 0. The only values that get passed are the checkboxes that are checked. Below is the query / code after the submit button has been pressed. Are radio buttons the answer? Any help / suggestions would be very much appreciated. //process form for ($i = 0; $i < count($menu_show_attribute); $i++) { if (isset($menu_id) == 'checked') { $menu_show_attribute = 1; } elseif ($menu_show_attribute != 'checked') { $menu_show_attribute = 0; } $query = 'UPDATE menu SET menu_show_attribute = "'. $menu_show_attribute.'" WHERE menu_id = "'. $menu_show_attribute[$i].'"' echo("<br>"); echo $query; $result = mysql_query($query, $db) or die(mysql_error()); }
View Replies !
Update Database With Textbox Array W/ PEAR
I am having slight problems with trying to get my page to work properly. Right now i have a form which displays the information of the rows in the database through textboxes. I have two textbox arrays: name[] and price[]. first i connect to database... if form was submitted it goes through this code:
View Replies !
Simplify Insert-update-delete From Database
I'm looking for some functions or objects allowing to select-insert-update-delete from any table in a mysql database without the need to create a new query every time. Example: selectdatas(array('field1','field2','fieldn'),arra y('table1','tablen'),array('left join,idy','inner join, idx')) then the function build the query, execute it and then return an object with the query result. I must build a database driven site that is 90% of the time spent on building queries. If I may avoid build them manually it will help me a lot and let me gain some days of programming.
View Replies !
Setting A Cron Job Is The Most Suitable Way To Update My Database
The site I am working on needs to be updated everyday. I receive a nightly ftp feed containing 1 txt file. I found that setting a cron job is the most suitable way to update my database and I wrote a small script to achieve this. I realize the script is very rudimentary but I am an absolute beginner in web development. Please note that I am not asking you to write the code for me, just to point me in the right direction and help me see potential problems with the process i might be overlooking due to my limited experience. Code:
View Replies !
Update Database Based On Modified Fields
I have a php page that retrieves entries from a mysql database and puts the data back in their corresponding fields. I would also like to offer the option of updating the database within this page. What I'm thinking is that whenever the user modifies a field, the value is then updated in the database. What I'm concerned with is the time it will take to update the database if I use many select and update commands. Is there a smart way to detect which fields were modified and then only update the fields that have changed using some php coding and not javascript. Or only doing an UPDATE command will be the best way to do it.
View Replies !
Header Function Runs Before Update To Database Is Made
I have been having some problems with a part of my login script. This is the two lines of script I am having problems with: mysql_query("UPDATE " . $userName. " SET login = '$loginIN' WHERE pass = '$password' AND course = '$courseID'"); header( 'url=http://www.somewebsite.com/logged_IN.htm' ); The problem is that when this php script is executed the second line executes before the first and an update to the database is not made. I also tried the script without the second line and the first works then.
View Replies !
|