Tracking Forums, Newsgroups, Maling Lists
Home Scripts Tutorials Tracker Forums
  Advanced Search
  HOME    TRACKER    PHP


SuperbHosting.net have generously sponsored dedicated servers to ensure a reliable and scalable dedicated hosting solution for BigResource.com.





Use Query Result Field As Query Key For New Query..


$query  = "SELECT ProjID, UserID, ProjDesc, file, OrigProj, OrigUser, ProjDate FROM projects";
$result = mysql_query($query);

I would like to take the field 'UserID', and utilise it for a Query statement to my users table in my database, to read and fill in information to my table, which looks like this:
PHP Code:




View Complete Forum Thread with Replies

Related Forum Messages:
Field Name Of Result Query
I want to get name of the fields of a result query i.e. i have a query

$result=mysql_query("select * from reports order by report_id desc");

One thing is clear here i don't know how many fields present here above query is a example bcoz actul is a too much long query that's why i am using a simple query. i can get value easily like this

while($row=mysql_fetch_array($reslult))
{
$abc=$row[0];
}

View Replies !
Turn Select Query Result Into Hyperlink To Other Query
I have a query which gives results of selecting coursenames from a table called trainingtopics but this does so in a continuous bulk of text without any breaks between each record. my question how do I create line breaks between each record and also how can I force each query result to become a hyperlink which when clicked runs another query that gives details of that course.

<?php
$user = "root";
$host = "localhost";
$password = "";
$connection = mysql_connect($host, $root, $password) or die ("Couldn't connect to server.");
$database = "courses";
$db = mysql_select_db($database) or die ("Couldn't select database.");

$sql = "SELECT coursename FROM trainingtopics";
echo $sql."=sql<br>";

$result = mysql_query($sql) or die(mysql_error());
echo $result."=result<br>";

while($row=mysql_fetch_array($result))
{ // NOTE this one ABOVE the echo
echo "result found!";
echo $row[0];
}
?>

View Replies !
Speeding Up Query/code (query Within Result Set)
I'm looking for ideas on how to speed up this script. Basically it finds all the zip codes in a zipcode table, then looks for all the records in another table with those zip codes.

Right now it finds all the zips then within that WHILE, it looks for a record in another table with that zip: PHP Code:

View Replies !
Using Query Result To Do Another Query In Loop
I have 2 tables, one called users2 and one called books. Books has a field called UserId, which is the ID of the user that added the book to the database.

My problem, is that i need to take this ID from the book table, and use it to get some information from the user table. Here is my code to get the ID from the book table: Code:

View Replies !
REGEX: Can't Seem To Replace LIMIT Clause In Query Using Preg_replace ($pattern, $replacement, $query)
Want to replace the limit clause in a query, but can't get it right.
What's wrong with this:

$pattern = "(.*)limit (.*)";
$replacement = '$1'
$replacement .= "LIMIT $limit";
$replacement .= '$2'
$query = preg_replace ($pattern, $replacement, $query);

View Replies !
Nest One Mysql Query Within Another (for Cross Referencing Another Table In The Middle Of That First Query)?
How do i nest one mysql query within another (for cross referencing another table in the middle of that first query)? for example:

i am referencing a table with news posted by members and in the middle of that reference i want to reference an up to date version of their email address as listed in their profile (in case they change it after posting a news message).

View Replies !
Execute An Update Query Based On The Results Of A Select Query
I'm trying to execute an update query based on the results of a select query... This doesn't work - any ideas? This is the code I'm trying to get to run (it updates all products which are set to arrive by a certain date if that date has arrived or passed - and there are products that should and should not be updated in the db this is being tested with...): Code:

View Replies !
Result From A Sql Query
Is there anyway I can exclude just one result from the database based upon the value of a field, for example i want to exclude the field with an ID of 1 but get all the other fields in the database. is this possible and can anyone tell me how? PS: I had thought about doing something like

$query1 = mysql_query("SELECT * FROM table ORDER BY id ASC");

while ($row = mysql_fetch_array($query1,MYSQL_ASSOC))
{
$id = $row['id'];
if ($id == 1)
{
//DO NOT DISPLAY ITEM
}
else
{
//DISPLAY ALL OTHER ITEMS
}
}

View Replies !
Result For Query
I dont know why this query is not returning a value, when I should be getting the value of &#3915;'. PHP Code:

mysql_select_db($dbname, $conn) or die (mysql_error());
    $query = "SELECT MIN(q_id) FROM questions2 WHERE quiz_id='".$quiz_id."'";
    echo $query.'<br />'
        $result = mysql_query($query) or die(mysql_error());
            $row = mysql_fetch_array($result) or die(mysql_error());
                $first = $row['q_id'];
                echo 'first='.$first.'<br />'

View Replies !
Accessing Query Data From Query Against Multiple Tables
I have a query that gets info from two tables in my database. How do I access the data from the query?

I know how to use the mysql_fetch_assoc() when the query in question only pulls information from a single table. How do I do the same thing for multiple tables and then insert the necessary data into my page? Code:

View Replies !
Query Result = Resource ID #10
I have an array $countertop.... i run through each one like this.
PHP Code:

View Replies !
Query Result In A Mail!
How do I insert a query result in a mail()? PHP Code:

View Replies !
Linked Result From A Query
I'm trying to create a query that will return a linked record from a
database that will take me back to an update page with that record so I

can change things in the record.

I'm having trouble finding simple code to do this.

View Replies !
Echo A $result Of Query?
Trying to have an echo display a result from a query. Not such a hard concept. Yet I am having trouble. What good is the data without analysis. Here is what I am using to try and grab result. Have been told it looks correct, must be missing something small.
When this runs, alternate echo displays in browser. So you know: 'testdata' is the table 'score' & 'id' are columns or fields.

Almost think it is missing a table structure to display in. Looking for player name column and score column (for the sake of example). Code:

View Replies !
Paging Of Query Result
This script used to be working in splitting query result into pages. But now, PREV 1 2 3 4 NEXT links is not working anymore. Any idea how to fix this ? or what is wrong with this script ? Code:

View Replies !
How To Select One Row From Query Result
once the button is clicked to find an appointment the following query is executed: Code:

View Replies !
Populate Result Query
I query database and it produces rows of results. I want to populate it so that the first 10 rows go to the 1st page, the next 10 rows to the 2nd page and so on. The last page will be at most 10 rows and it can be less than that. How do I do it? Or do anybody know if there is any sample code that I can refer to?

View Replies !
Filtering In Query Result With WHERE
I am trying to filter out records in a query using WHERE expressions. See example below.

if ($league="All") {$leaguebool="1"} else {$leaguebool="League='$league'"};
$query = "SELECT League,HR FROM ranfranbattingsim WHERE ('$leaguebool') ORDER BY $sorder DESC LIMIT $limit";

My desire is to select all records if $league='All' and select only records where LEAGUE=$league if $league is anything other than 'All'. LEAGUE is one of the fields of the database. I hope that I explained that well enough. I am open to any solutions, and have considered that perhaps I should be using something other than the WHERE statement to filter the records.

View Replies !
One Row Result Database Query
Most of the pages I write are multi-row queries. I have about 30 pages that will only yield one row of about 15 columns. What is the best way to design this page?

Right now, I am using $row = mysql_fetch_object($results) - this is causing a minor issue with positive/negative signs with numbers.

View Replies !
Query Not Returning First Result
I have a query that is returning the correct number of rows. However, when I try to print the rows out, it will not print the first row, but all after that. I can't figure out why it isn't printing out the first row, even though the query is returning the results. Here is my code below to print the results in a table: Any suggestions?

while($row2 = mysql_fetch_array($result1))
{
$affinity_name = $row2['affinity_name'];
$affinity_detail = $row2['affinity_detail'];
$affinity_no = $row2['affinity_name'];
$track_id = $row2['id'];
get_name($affinity_name);

$affinity_details .=<<<EOD
<tr>
<td><a href="/m_t5.php?affinity_id=$affinity_no&q=$name">$name</a></td>
<td>$affinity_detail</td>
<td><a href="/delete_track.php?track_id=$track_id">Delete</a></td>
</tr>
EOD;
}

View Replies !
Not Able To Grab 1st Result Of Query
I am having an issue, when I run my query (shown below) directly in MS SQL it returns the first row (home.php / 323 hits), along with the rest. Code:

View Replies !
If Query Result Returns Nothing
i have a marquee which scrolls across news items, all this is database driven, however if no news items are returns from the query, my page errors, can someone help me write an else statement or something so that the page doesn't error. my code is below:-

<?php

require('database3.php');

if(!isset($news_item))
$news_item=''

$query = "select * from monksc.news where DATE_SUB(CURDATE(),INTERVAL 14 DAY) <= startDate order by id";

$result = mysql_query ($query) or die (mysql_error());

if (mysql_num_rows($result)>0)
..............

View Replies !
Displaying Result Of A Sum Query:
$sql = "SELECT sum(value) FROM `offers' WHERE sid='$sid'";
$result = mysql_query($sql);

As you can see, I'm trying to select a column in my database which is named "value" I want to return the sum of the records which match the current user's subscriber id ($sid) I think the query is structured correctly.

However, I'm having trouble placing the result of the query into a variable that php can echo to the page. In the database, the numbers are formatted as decimal. I just want to get the sum of the fields into a numeric php variable that I can add/subtract/divide etc and echo to the page. How do I go about doing this?

View Replies !
Mysql Query Result
I have successfully selected 4 rows using a mysql SELECT query. However, I would like to random pick a row from this result so that every page refresh will yield something different.

View Replies !
Weird Query Result
I am trying to do a simple query, but instead of a numeric value, I get "Resource id #34".

$newdodgemod1 = "select default_dodgemod from phpbb_classes where class='$newclass'";
$newdodgemod2 = $db->sql_query($newdodgemod1);

Any idea what is wrong with the code? All field exist and the variables are set correctly. I don't understand why I am getting this error.

View Replies !
Query Result To Array
i have a table with two field ID and CAPACITY. i want the ID to point to the capacity on an array

$top = "SELECT * from topics";
$db = new mysqli('localhost','root',?');
$db -> select_db('testing');

$res_top = $db->query($top);
$topics = array();
while ($row = $res_top->fetch_row())
{
$topics[$row['id']] = $row['capacity'];
}

View Replies !
Query Result Values
i have two tables a customer and package table. a customer can have many packages. how i can i set a status in the customer table to 'complete' if all the packages in the package table that relate to that customer are set to 'paid'? i can do a simple select statement but how will i know if all the status rows returned from packages are set to 'paid'.

View Replies !
Searching A Query Result
I have a simple query that selects everything from a database and limits the results to one row ordered by desc. The code does work. The next step is to search the query result to see is if a certain feild has a result. <?php

Include("config.php");
$con;
if (!$con)
  {
  die('Could not connect: ' . mysql_error());  }
$result = mysql_query("SELECT * FROM photos ORDER BY photo_id DESC LIMIT 1");
while($row = mysql_fetch_array($result))
{
echo $row['photo_id'];
}
?>

View Replies !
Query Doesn't Show First Result
I've created this query but it never shows the first result. I can have any number of results and order them however I like but whatever the first result in the list is it doesn't appear. Code:

View Replies !
Query Result Display
PHP Code:

<html>
<head><title>Display Table</title></head>
<body>
<?php
$database="temp"; /* DB name */
$host="localhost";
$user="root"; /* Set DB Username */
$pass=""; /* Set DB password*/
mysql_pconnect($host,$user,$pass); /* DB connect....*/

View Replies !
Limit Query Result According To A Criteria
I have the following code which doesn't work:

"SELECT COUNT(*) AS total FROM $table_name
WHERE certain criteria HAVING total<=100";
The query above doesn't work and i get zero results.

In general the query take lots of time mainly because the criteria is not specific enougth and I get many many hits. I want to stop the query after getting the first 100 hits according to a certain criteria. When I use LIMIT 0,100 and not HAVING i get result from the first 100 records in the table but my table contain few million records.

View Replies !
Query Result Navigator Function
I've just updated this, and I thought I'd also say that not only can this provide a page navigation for MySQL or other database results, but can be used to navigate other lists.. such as a file list. PHP Code:

View Replies !
Easiest Way To Print The Result Of A Query
I am using the following code:

$host ="";
$username="";
$password="";
$database="123";
mysql_connect($host,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT SUM(rcountry) FROM 123 WHERE sessid = '$PHPSESSID'";
$result=mysql_query($query);
$num=mysql_num_rows($result);
mysql_close();

Whats the easiest way to print the results of the query? I just need the value returned by this section: $query="SELECT SUM(rcountry) FROM 123 WHERE sessid = '$PHPSESSID'";
I will be using the value in a mathmatical problem later on, but for now I just want to print it out and I am unsure as to which variable to echo.

View Replies !
Variable Interpolation From Sql Query Result
I have data in a MySQL table like:
the variable is: $var

and an assignment in a file like:
$var = "some text";

but when I print the output of a query for the data it prints:
the variable is: $var

rather than:
the variable is: some text

View Replies !
Multiple Result Sets With One Query
I need to query the DB and find records that coorespond to a given month and then display the data.

$sql="select * from $tbl where month='january'";
....... through december

My question is this -> is it better to create 12 different queries or create one query and use an array (or somethiing else) to create basically 12 result sets? To me - 12 queries seems like it would be taxing on the db.

View Replies !
Same Mysql Query Doesn't Always Return A Result
We have no access to a mysql NG on my provider's server, so we ask here:

We have a long query (long in text) with a UNION between 2 select.

We have been informed that some times the query doesn't return any result.
We have tried on our server and we always get a result. BUT, trying on the
hosting server, many times the query doesn't return any result and doesn't
get any error.

Any idea ? does Union have any problem ? how to check if the query failed ?
My hoster said that sometimes the table can be locked (if the server is
overloaded) and then mysql doesn't return any result, but this seems to me
an aberration.

the query takes about 0.0050 sec to execute when it doesn't return any
result, and 0.030 when I get results

View Replies !
Moving A Query Result Into An Array
I have read all the array stuff done searches for examples, but am still not clear if there is a way to do a query from a MySQL table and move those vaules into an arry.

I am sure it can be done, but I thought I would find a function that would do it. Am I just overlooking something?

$resultID = mysql_query("SELECT DISTINCT slot FROM items");
while(list ($slot) = mysql_fetch_row($resultID)){echo"$slot";}

So anyone have a good way to move the result into some array?

View Replies !
Obtain Parameter From Result Query
In PERL: $trx_status = lc(param('eTrnStatus')); How to do equivalent in php?

View Replies !
Sending Query Result To Excel
How can I send query result to EXCEL in PHP pages? is there such a function in PHP ? any code example !

View Replies !
Strange Result From Table Query
I have a simple query that I am restricting to the first 4 character, however instead of the first 4 characters I am getting only the characters from the end of the field.

The information in the field resembles: 4285-002

My result should be: 4285

What I am getting is: -002

The following is the code to pull the dat from field 'Dest':
    $dest=odbc_result($rs1, 'Destination');
        $deststrcount=1;
        $deststr = $dest;
        $deststr = str_split($deststr,4);
        foreach($deststr as $destv){
          if ($deststrcount<="1"){
            $desttext=$destv;
            $destnew = "DEST[1,$deststrcount] $desttext";
 
            $strcount=$strcount+1;
            }

View Replies !
Query Giving Array As Result
I just started PHP and getting the following error when trying to read and echo something from my DB. I get Array as an result of a working SQL query (I tested it in PHPMyAdmin SQL Query) and it should be something else. Array doesnt return in the database i selected, but still it's here.

<?
$host="localhost";
$user="xxxxxxxxx";
$password="xxxxxxxxxxx";
$dbname="mohaaleague";
$connection = mysql_connect($host, $user, $password) or die ("Kan niet verbinden");
$clan = "Belgian Fun Clan";
$db = mysql_select_db ($dbname,$connection) or die("Je Stinkt");
//SELECT clan FROM clan WHERE clan='Belgian Fun Clan'
$query = "SELECT clan FROM clan" or die("Query Mislukt");
$result = mysql_query($query) or die("Query Mislukt1");
$row = mysql_fetch_array($result, MYSQL_ASSOC) or die("Query Mislukt2");
extract($row);

echo($row. "<br>");
if ( $clan == $row )
{
echo "het werkt";
}
else
{
echo "het werkt niet";
}
$disconnect = "mysql_close";
?>

View Replies !
MySQL Query Result Rows
Still learning the ropes of PHP/MySQL here so pardon if this is something from a 101 class. I am wanting to know if/how I can query a MySQL database, pull two rows of information and assign them individual variable names. I know this isn't too clear. Let me try to explain what I want to do. Let's say I have something similar to this:
Code:

$query = mysql_fetch_assoc(mysql_query("SELECT entry_id, user_id, date FROM my_entries WHERE user_id = '$user_info[user_id]' ORDER BY date DESC LIMIT 2"));


What I would like to be able to do is assign separate variables for the info on the two rows returned by the query. I want to have the following variables:

$first_date = $query[date]; <= from the first row
$second_date = $query[date]; <= from the second row

I can then use the two variables to compare to each other, etc. Can this be done with a single query? Or are two queries required (if so how)?

View Replies !
Processing MySQL Query Result
after executing the query, say it returns 1000 results. if i just want to do some sampling and like to have a look on 4 of them, how can i refer to these 4 random records out of 1000? i'm working on processing the result of $res_array which has 1000 records.

query = select * from test;

result = mysql_query(query);

records1000 = db_result_to_array($result);

//how to select/remove records1000 to get say, records4?


function db_result_to_array($result) {
$res_array = array();
for ($count=0; $row = $result->fetch_assoc(); $count++) {
$res_array[$count] = $row;
}
return $res_array;
}

View Replies !
Manipulating Result On A SELECT Query
I have the following table:

+-------------------------+
| id | tid | type | value |
+-------------------------+
| 1 | 23 | 1 | 8 |
| 2 | 21 | 1 | 6 |
| 3 | 21 | 2 | 4 |
| 4 | 21 | 2 | 9 |
| 5 | 22 | 2 | 9 |
| 6 | 22 | 1 | 10 |
| 7 | 23 | 1 | 5 |
| 8 | 22 | 1 | 4 |
| 9 | 21 | 2 | 7 |
| 10 | 22 | 2 | 7 |
+-------------------------+

and I want to get the result like this: Code:

View Replies !
Query Problem - $result = Mysql_query
PHP Code:

<?php

$lic_id = $_POST['licid'];

$result = mysql_query ("SELECT DATE_FORMAT(license.exp_date, '%M %d, %Y') AS exp_date1, usersw.user_id, usersw.lic_id,                 users.user_id, users.user_name, license.lic_id, license.sw_id, license.lic_num, license.po_num, sw.sw_id, sw.sw_name, license.auth_num, DATE_FORMAT(license.purch_date, '%M %d, %Y') AS purch_date1, license.notes, license.quantity
            FROM users, usersw, license, sw
            WHERE $lic_id = license.lic_id and license.lic_id = usersw.lic_id and users.user_id = usersw.user_id and license.sw_id = sw.sw_id and users.user_id = usersw.user_id
            ORDER BY license.lic_num, users.user_name") or die(mysql_error());

while($row = mysql_fetch_array($result))
        {

View Replies !
PHP Update Query Mysql: Query Succussful?
I can't seem to successfully test an update query. Below is a piece of code that updates a statistics table. If row today doesn;t exist, a new day must be created. But this doesn't work...

thank you for your reply.

$today= date("Y-m-d");

$qq="update totals_r set hits_r=(hits_r+1), lang_$lang=(lang_$lang+1), cat_$cat=(cat_$cat+1), rating_$rating=(rating_$rating+1), bussite_$bussite=(bussite_$bussite+1) where date='$today'";

$result_6 = mysql_query ("$qq");

if (!$result_6){ /// IF !ROW_TODAY ==> CREATE NEW DAY

$qq_2="insert into totals_r (hits_r, lang_$lang, cat_$cat, rating_$rating, bussite_$bussite, date) values(&#391;',&#391;',&#391;',&#391;',&#391;','$today')";

$result_6_2 = mysql_query ("$qq_2");

if (!$result_6_2){
$err_msg_sql_6= mysql_error();
$err_loc_6="$PHP_SELF"." // Query6: update totals_r";
}
}

View Replies !
Update Query - Cant Execute Query Error.
I am having a problem with the update script. I making a group update and i keep on getting "cant execute query" error. I am wondering if its my SQL statement. PHP Code:

View Replies !
Query - Create The Mysql Query To Get All Fields
I've a table "article".
Any article is of a type in table "type1" or "type2"
Each type may be of a model in table "model1" or "model2".
Each model can be on a certain make, also in 2 tables, "make1" and "make2".

they are a few possibilities.
"article" can be of "type1" or "type2"
"type1" can be of "model1" only - "type2" can be of "model1" or "model2"
"model1" can be of "make1" only - "model2" can be of "make1" or "make2"

"article" has "type.id" field (char10). If it start with "my" then it's a
"type2", otherwise is a "type1"
"type1" has only "model1.id" field. "type2" has "model1" and "model2"
fields. If one is filled, the other isn't
"model1" has only "make1.id" field. "model2" has "make1.id" and "make2.id"
fields. If one is filled, the other isn't

so here are the possibilities:
article -> type1 -> model1 -> make1
article -> type2 -> model1 -> make1
article -> type2 -> model2 -> make1
article -> type2 -> model2 -> make2

Now, I must create the mysql query to get all fields given the "article.id".
Is it possible ?
How ?
will this work ? in pseudo-code

article left join type1 articleid = type1id
inner join model1 type1id = model1id //inner because if type1, the model is
1
inner join make1 model1id = make1id //inner because if model1, the make is 1
left join type2 articleid = type2id
left join model1 type2id = model1id
left join model2 type2id = model2id
left join make1 model2id = make1id
left join make2 model2id = make2id

View Replies !
How Can I Populate A Listbox With The Result Of Mysql Query?
I would like to populate a listbox with the result of a mySQL Query.

View Replies !
How To Get Mysql Query Result Into Temp. Txt File
I did a lite search in the archive but didn't find anything specific to my problem. Here is what I am trying to do:

I've got a table with about 25k entries of company addresses. I need to be able to pull specific data out of the table and put it in a temporary text file and then display the result in the browser for the user to save locally.

The query part and the format of the data is all simple enough but I am having trouble figuring out how to get the data from the query into a temporary text file and then displaying that file. here is what I whipped up but it obviously doesn't work: Code:
<?
$tmpfname = tempnam("/path/to/file/", "FOO");
$list = mysql_query("select * from FH_LIST where State='AK'");
while ($list_results = mysql_fetch_array($list)) {
$data = blah blah blah;
fwrite($tmpfname, ".$data
");
}

fopen($tmpfname, "r");
fpassthru($tmpfname);
?>

I get an error message saying:
Warning: Supplied argument is not a valid File-Handle resource (referring to $data).

View Replies !
If Result Of Mysql Query Is Only One Row/column, Why Use An Array?
If I'm doing a very specific select statement, which I know will only ever return one value, can I get that resulting bit of data without storing it in an array or object?
If not, is mysql_fetch_array() the fastest method for getting this one value?

View Replies !
MySQL Result Is Empty, But The Query Is Correct
I have written a script that grabs info from a database, and outputs it to a form. I figured I'd tidy things up a bit, and use a function to handle the queries, where I had previously hardcoded almost the same query several times. Code:

View Replies !

Copyright © 2005-08 www.BigResource.com, All rights reserved