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Warning: MySQL: Unable To Save Result Set


I'm getting this error:

Warning: MySQL: Unable to save result set in /www/hosts/wwwroot/mainPage.php on line 11

Here is what line 11 looks like:

$articles = mysql_query("select entryID from articles where siteID like 'senior'");




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I know the second result means the specified query cannot be found, and I'm guessing for some reason MySQL cannot save the query. Here is my code. PHP Code:

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i want to grab the value of a sql entry. but the thing is, sometimes this value is <NULL>. i thought, no biggy, i'll just have an if statement:

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Code:-

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Warning: Supplied Argument Is Not A Valid MySQL Result Resource
<?
Warning: Supplied argument is not a valid MySQL result resource
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session_start();

if ($username && $password)
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$db_conn = mysql_connect("localhost", "*****", "*******");
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Warning: Mysql_fetch_row(): Supplied Argument Is Not A Valid MySQL Result
I removed the setcookie and ran the code and it shows this Warning.


Warning: mysql_fetch_row(): supplied argument is not a valid MySQL
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Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
Here is my script:

<?php

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Get this error message:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home2/my_username/my_domain/my_databasename/test.php on line 6.

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Warning: Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result
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Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result Resource
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i am getting the following error with this bit of code? Warning mysql_fetch_array(); supplied argument is not a valid MySQL result resource? Code:

<?php
/* Connect to database */

$extra = 'blah'
$size= &#391;'
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$db= mysql_connect("localhost", "", "");
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............

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How To Solve The Error: Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
I keep getting this:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ....... 

while($row = mysql_fetch_array($result, MYSQL_ASSOC))

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I keep getting an error result saying:

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in *** on line 9

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I'm pretty new to PHP so I'm thinking its a problem with syntax. Any help is appreciated. Code is below.

<?PHP

$ni = trim($_POST['ni']);

require 'db_connect.php'

$sql = "SELECT * FROM $db_table WHERE ni = '$ni'";
$query = "mysql_query($sql) or die (mysql_error())";
if (mysql_num_rows($query) < 1) {

require 'db_close.php'
header("location: DESIRED LOCATION");
}
else{
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header("Location: EXIT ");
}

?>

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im trying to access the 'update' time from my database by using the below code.

$result = mysql_query("SHOW TABLE STATUS FROM logtable;");
while($array = mysql_fetch_array($result)) {
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The only problem is I get this error. What am I doing wrong??

'Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in...'

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my code:

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}

I know that there is a row that has the same username as $username, but i keep getting an error like: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /mounted-storage/home23a/sub001/sc21473-GRUR/www/inphp/members/register.php on line 56 Line 56 being:

if (mysql_num_rows($result) != 0)

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Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource

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I'm trying to outtput records from a mysql table and I get an error here

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/scaspco/public_html/testing/reviews.php on line 41
in

PHP Code:

<?php
$i = 0;
while ($result = mysql_fetch_array($query)) {
    if($i++ % 2) {
        $bgcolor = "category";
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...............

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Warning: Mysql_fetch_row(): Supplied Argument Is Not A Valid MySQL Result Resource In /home/dyingtwi/public_html/functions/matchdb.php On Line 61
1: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in /home/dyingtwi/public_html/functions/matchdb.php on line 61

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PHP Code:

$number = mysql_query("SELECT * $housesTable WHERE house_id='".$select."'");
$row = mysql_fetch_array($number);

returns

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/szauerne/public_html/sites/yourcapecoral/wizard/listings.php on line 364.

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Warning: ftp_put(): Unable to access in /home/cjbcc/public_html/members/koerel/party/uploads.php on line 16

<html>
<head></head>
<body>
<?
$ftp = ftp_connect("koerel.cjb.cc");
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---------------
PHP Warning: Unknown(): Unable to load dynamic library 'E:Program FilesSWsoftPleskAdditionalPhpextensionsphp_curl.dll' - Access is denied. in Unknown on line 0
-------------------

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"Warning: Unable to fork [C:WINDOWSTEMPphp30.tmp /full/path/to/joesauto/images/anime_dvd_icongif.gif] in c:inetpubwwwrootadd_data.php on line 39"

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on line 172

or something similar, then listen up, here's the solution. PHP 4.3.x
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My php script :

$login = $_POST['pseudo'];
$passe = $_POST['passe'];
$ldapServer = "localhost";

$loginDN = "uid=".$login.", o=people, dc=toto, dc=org";
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}
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Warning: ldap_bind(): Unable to bind to server: Invalid credentials in
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Here's what I have -

My php.ini resides in my C:WINNT directory. In it, I have removed the
'' from the extension=php_mysql.dll.

Also in the php.ini file I set extension_dir = c:PHPExt

In c:PHPExt I have the following files:

libmysqli.dll
libmySQL.dll
php5apache2.dll (Do I need this since I am using IIS)?
php5ts.dll
php_mysql.dll

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I am trying to execute a DOS command with the exec() function. All I get is fork errors or access errors, regardless of what file I try to execute. Example:

<?php
exec("sync.bat");
`sync.bat`;?>

Warning: Unable to fork [sync.bat] in C:testexec.php on line 3
Warning: Unable to execute 'sync.bat' in C:testexec.php on line 4
PHP has encountered an Access Violation at 77F81B4D


Id doesn't seem to matter what kind of file I try to execute, .exe, .bat or .com. Any ideas? Has ANYONE executed an external program under php/Windows?

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Anyone seen this error before?

Warning: Unknown: 1 result set(s) not freed. Use mysql_free_result to free result sets which were requested using mysql_query() in Unknown on line 0

Not certain how / where it would find another result set. Been reading up on the mysql_free_result command; when/where would it be utilized? Here is my scenario. I have a dynamic form that stores, draws data, edits records and emails data. There are two main sections of the site: Submission and Revision.

I assume it's best to free results when a user logs out of their account; while logged, the user can proceed to make revisions. I'm afraid they will run into the same problem I'm experiencing now. Can the results be freed without causing the user to lose their work?

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Warning: Smarty Error: Unable To Read Resource: "index.tpl" In
I am using "Smarty 2.1 Version" in php. It is giving following error

Warning: Smarty error: unable to read resource: "index.tpl" in
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the directory which is containing templates i.e. templates and templates_c is
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Also tried with full absolute path in the Smarty.class.php. like
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Warning: move_uploaded_file() [function.move-uploaded-file]: Unable to move 'c:/wamp/tmpphp7F0C.tmp' to '' in C:wampwwwproject1upload.php on line 16

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Warning: ibase_pconnect(): Unable to complete network request to host "abc". Failed to establish a connection. Connection refused in ***.php on line 347

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And this is my code ....

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I'm having trouble with move_uploaded_file()- my script was working fine until a month or two ago when it suddenly stopped. Now I get the error:

Warning: move_uploaded_file() Unable to move *file* to *new file* in *script*

Thats it, no permissions error or "unable to open stream"- all the searching I've done everyone seeems to get another error- but I'm only getting the one. Permissions on the folder are 777, the paths are absolute and definitely correct, safe_mode and open_basedir are both off. I even called is_uploaded_file() on the line before it and it returned true. The only thing I can think of is that the hosts upgraded to php4.4 recently- could that be it? Are there any known problems (or changes that would break my script)?

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