Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result Resource Code Error
im trying to access the 'update' time from my database by using the below code.
$result = mysql_query("SHOW TABLE STATUS FROM logtable;");
while($array = mysql_fetch_array($result)) {
print_r($array[Update_time]); // Will print information about each table stored in database
The only problem is I get this error. What am I doing wrong??
'Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in...'
View Complete Forum Thread with Replies
Related Forum Messages:
Warning Mysql_fetch_array(); Supplied Argument Is Not A Valid MySQL Result Resource?
i am getting the following error with this bit of code? Warning mysql_fetch_array(); supplied argument is not a valid MySQL result resource? Code: <?php /* Connect to database */ $extra = 'blah' $size= Ƈ' $paper= 'matte' $db= mysql_connect("localhost", "", ""); mysql_select_db("", $db); $sql="select type_id FROM type WHERE extra=".$extra." AND size=".$size. " AND paper=".$paper ; $type_id=mysql_query($sql); ............
View Replies !
Mysql_fetch_array :: Supplied Argument Is Not A Valid MySQL Result Resource
I've got a problem with mysql_fetch_array function. I have two function: function db_query($dbh,$qw) { db_test($dbh); $result = mysql_query($qw); return $result; } function db_insert($dbh,$table,$what,$info) { db_test_table($dbh,$table); $id=0; $qw="insert into $table $what values $info"; $result = db_query($dbh, $qw); return $result; } Then I have the following piece of code: $result = db_insert($dbh, $table1, $what1, $info1); $row = mysql_fetch_array($result); The db_insert call workes fine, 'cause a new record is inserted into the table. The problem is that when I call mysql_fetch_array I got the following error: "Supplied argument is not a valid MySQL result resource".
View Replies !
Mysql_fetch_array(): Supplied Argument Is Not A Valid Mysql Result Resource
i recieve this error from this part of the code: mysql_fetch_array(): supplied argument is not a valid mysql result resource it's returning a long text from the database which is about 200 characters long. <?php if ($_SESSION['is_town'] = 1){ $query = "SELECT usemap FROM town WHERE town_id = " . $_SESSION['townID'][0]; $db_result = mysql_query($query); $db_usemap = mysql_fetch_array($db_result); echo $db_usemap;} ?>
View Replies !
Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
Here is my script: <?php $dbh=mysql_connect("localhost", "my_username", "my_password") or die ('No can do!'); mysql_select_db ("my_databasename"); $query = "SELECT * FROM contacts"; while($i = mysql_fetch_array($query)){ echo $i[first]; echo $i[last]; echo $i[email]; } ?> Get this error message: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home2/my_username/my_domain/my_databasename/test.php on line 6.
View Replies !
Warning: Supplied Argument Is Not A Valid MySQL Result Resource
<? Warning: Supplied argument is not a valid MySQL result resource if (mysql_num_rows($result) >0 ) !Didnt have this problem before session_start(); if ($username && $password) { // if the user has just tried to log in $db_conn = mysql_connect("localhost", "*****", "*******"); mysql_select_db("micro_db.adf", $db_conn); $query = "select * from users " ."where name='$username' " ." and pass=password('$password')"; $result = mysql_query($query, $db_conn); if (mysql_num_rows($result) >0 ) { // if they are in the database register the username $valid_user = $username; session_register("valid_user"); } } ?>
View Replies !
Warning: Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource In *** On Line 9
I keep getting an error result saying: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in *** on line 9 Warning: Cannot modify header information - headers already sent by (output started at ***:9) in **** on line 12 I'm pretty new to PHP so I'm thinking its a problem with syntax. Any help is appreciated. Code is below. <?PHP $ni = trim($_POST['ni']); require 'db_connect.php' $sql = "SELECT * FROM $db_table WHERE ni = '$ni'"; $query = "mysql_query($sql) or die (mysql_error())"; if (mysql_num_rows($query) < 1) { require 'db_close.php' header("location: DESIRED LOCATION"); } else{ require 'db_close.php' header("Location: EXIT "); } ?>
View Replies !
Warning: Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource In /mounted-storage/
my code: $username = mysql_real_escape_string($username); $result= mysql_query("SELECT * from `admin_login WHERE username=".$username); if (mysql_num_rows($result) != 0) { echo ("That Username is already being used. Please try a different username."); } I know that there is a row that has the same username as $username, but i keep getting an error like: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /mounted-storage/home23a/sub001/sc21473-GRUR/www/inphp/members/register.php on line 56 Line 56 being: if (mysql_num_rows($result) != 0)
View Replies !
Supplied Argument Is Not A Valid MySQL Result Resource
Before I get in trouble, I have searched extensively for this one, in the PHP Docs, online etc. I have a simple page: <?php $un="jim"; $pw="jim"; $db="localhost"; $link = mysql_connect($db,$un,$pw) or die("Could not connect: " . mysql_error()); $sql2 = "SELECT * FROM eib.book ORDER BY bookid"; $op = mysql_query($sql2) ; $num= mysql_numrows($op); ?> When I run the page I keep getting this error: Warning: mysql_numrows(): supplied argument is not a valid MySQL result resource in C:Program FilesApache GroupApache2htdocseibphpitemadd2.php on line 34
View Replies !
Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource
I've got the following error: Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wbdfdart/public_html/wbdfforum/verwijder.php on line 13 verwijder.php 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 <?php include "connect.php"; if (isset ($cat) AND isset ($topic) AND isset ($message)) { $query = "SELECT user FROM reply WHERE id='$message'"; $exec = mysql_query($query); $result = mysql_fetch_array($exec); $owner = $result["user"]; $moderator_check_query = "SELECT * FROM moderator WHERE category=$cat AND user=$myid"; $moderator_check_exec = mysql_query($moderator_check_query); $moderator_result = mysql_num_rows($moderator_check_exec); if ($moderator_result == 1 OR $owner == $myid) { $moderator = 1; } else { $moderator = 0; } if ($moderator == 1) { $replydelete_query="DELETE FROM reply WHERE id ='$id'"; mysql_query($replydelete_query) or die(mysql_error()); $topicmineen_query="UPDATE topic SET replies='replies -1' WHERE id='$topic'"; mysql_query($topicmineen_query) or die(mysql_error()); echo "<script>location.href='index.php?cat=".$cat."&topic=".$topic."&page=".$page."'</script>"; } else { echo "<script>location.href='index.php?cat=".$cat."&topic=".$topic."&page=".$page."'</script>"; }} ?>
View Replies !
Warning: Mysql_select_db(): Supplied Argument Is Not A Valid MySQL-Link Resource In E:htmldbconn.php On Line 4
I submitted the question about text files I decided to have a go with a database instead though Im having problems connecting to the Database. As a PHP novice Im not entirely sure where Im going wrong but I have been getting the following error: Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in E:htmldbconn.php on line 4 Can't select entries from table. SELECT * FROM Entry ORDER BY Entry.entryDate DESC LIMIT 5 No Database Selected Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in E:htmldbconn.php on line 11 The code I'm using looks like this: ....
View Replies !
Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid
When I run this script It says Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in blah blah. <? session_start(); include "db.php"; $username = $_SESSION['username']; $result = mysql_query("SELECT * FROM users WHERE to='$username'"); while ($row = mysql_fetch_array($result)) { ?> From: <? $row['from'] ?><br> Subject: <? $row['subject'] ?><br> Message: <? $row['message'] ?><br> <? } ?>
View Replies !
MySQL Error - Supplied Argument Is Not A Valid MySQL-Link Resource
I am getting the error Warning: mysql_select_db(): supplied argument is not a valid MySQL-Link resource in /home/server7/public_html/71/arranholloway/database4.php on line 7 I tested my code on local computer and there were no problems, the error message only appeared when I loaded it onto my web hosters server. I'm new to PHP so its probably something simple but any help would be appreciated.
View Replies !
Warning: Rewind() Supplied Argument Is Not A Valid Stream Resource In...
I am implementing Iterator in a class, I have pretty much copied the code from php.net on Object Iteration. Adding all the normal methods for the task...rewind, current, next, etc. I was attempting to add a seek method but am stymied by the above warnin, as well getting a seek on index 0 (zero) to work. public function __construct($contents) { if ( is_array($contents)) { if ( is_array($contents[1])) { $this->cktl = $contents[1]; } } } public function rewind() { $cktl = rewind($this->cktl); return $cktl; } public function current() { $cktl = current($this->cktl); return $cktl; } public function key() { $cktl = key($this->cktl); return $cktl; } public function next() { $cktl = next($this->cktl); return $cktl; } public function valid() { $cktl = $this->current() !== FALSE; return $cktl; } public function myseek($intPos) { $myPos = 0; $this->rewind(); while ( $myPos < $intPos && $this->valid() ) { $cktl = $this->next(); $myPos++; } if ( !$this->valid() ) { die("Invalid seek position"); } return $cktl; }
View Replies !
Warning: Fread(): Supplied Argument Is Not A Valid Stream Resource
am trying to upload images in MySql using php. whenever I run the following code I get this message: Warning: fread(): supplied argument is not a valid stream resource in C:webs estCNST ProjectsGenaral Upload FormfigUpload.php on line 6 config.php is where I assign the database, the user, and the password. openDB.php is where the database is opened closeDB.php is where the database is closed <?php include'phpFigures/config.php'; include'phpFigures/openDB.php'; include'phpFigures/assignValues.php'; if (isset($figpath)){ $figImage=addslashes(fread(fopen($figpath,"r"),filesize($figpath))); $query = "INSERT INTO images(description, image) VALUES ('$figdescription', '$figImage')";
View Replies !
"Supplied Argument Is Not A Valid MySQL Result Resource"
this is one of the first scripts im writing completely by myself but its driving me crazy. the errors its returning are: Quote: Warning: Supplied argument is not a valid MySQL result resource in c:apachehtdocsquiz_chap12_view.php on line 16 There are currently in the table: PHP Code:
View Replies !
Counter - Warning: Fwrite(): Supplied Argument Is Not A Valid Stream Resource
I am trying to put one counter in my php with the next code: <?php $hitfile = "/admin/contador.txt"; if (!file_exists($hitfile)) { $file = fopen($hitfile,"r+"); $hits = fread($file,filesize($hitfile)); fclose ($file); } else { $hits = 0; } $file = fopen($hitfile,"w+"); fwrite ($file, ++$hits); fclose ($file); ?> but when i try to see the php page appears this error: Warning: fopen(/admin/contador.txt) [function.fopen]: failed to create stream: No such file or directory in /home/usuairo/pagina.php on line 9 Warning: filesize() [function.filesize]: Stat failed for /admin/contador.txt (errno=2 - No such file or directory) in /home/usuairo/pagina.php on line 10 Warning: fread(): supplied argument is not a valid stream resource in /home/usuairo/pagina.php.php on line 10 Warning: fclose(): supplied argument is not a valid stream resource in /home/usuairo/pagina.php.php on line 11 Warning: fopen(/admin/contador.txt) [function.fopen]: failed to create stream: No such file or directory in /home/usuairo/pagina.phpcontacto.php on line 19 Warning: fwrite(): supplied argument is not a valid stream resource in /home/usuairo/pagina.phpcontacto.php on line 20 Warning: fclose(): supplied argument is not a valid stream resource in /home/usuairo/pagina.phpcontacto.php on line 21
View Replies !
Fopen :: Warning: Fwrite(): Supplied Argument Is Not A Valid Stream Resource
I tried to store the file pointer returned by fopen as a session variable. I get a warning: fopen to open stream: HTTP wrapper does not support writeable connections. Thisis followed by a bunch of: warning: fwrite(): supplied argument is not a valid stream resource if (!isset($_SESSION['fh'])) { $fh = fopen("http://www.mydomain.com/somedir/debug", "w"); $_SESSION['fh'] = $fh; } ...... ...... fwrite($_SESSION['fh'], " some debugging text msg: ".$msg."msg_type: ".$msg_type);
View Replies !
LEFT JOIN - Get The "Warning: Mysql_fetch_array(): Supplied Agrument Is Not A Valid MySQL Resource".
I am trying to merge results from two tables, but this is something I haven't done so far, so manybe my mistake will look stupid to Pro's. I get the "Warning: mysql_fetch_array(): supplied agrument is not a valid MySQL resource". Here is my code: $result = mysql_query("SELECT * FROM az_mustseethis LEFT JOIN az_articles ON az_mustseethis.art_id = az_articles.art_id WHERE az_articles.category = 'Must See This' ORDER BY art_id DESC LIMIT $from, $max_results",$connect); Instead of adding the latest entry in the "az_mustseethis" table, I want to take it from the "az_articles" table, where it has already been added.
View Replies !
Paginating (mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL)
when I try to run my code it works..but sometimes it returns me these error : Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /var/www/html/dev/rob/SearchRND.php on line 44 Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /var/www/html/dev/rob/SearchRND.php on line 65 PREV 10 NEXT 10; ( total) it happens whenever I try to refresh the browser or even if I reached the end of the records..here's my code PHP Code:
View Replies !
Mysql_query(): Supplied Argument Is Not A Valid MySQL-Link Resource
I use the following fragment of code to output datf from MySQL: ================================================== ==== $chan = mysql_connect ($db_host, $username, $password); mysql_select_db ($DB_name, $chan); $resultid = mysql_query ("select name_ru, description_ru, retail, dealer from lasershot WHERE le=Ƈ'", $chan); ........ ================================================== ==== This was working fine. Code:
View Replies !
Mysql_fetch_row(): Supplied Argument Is Not A Valid MySQL Result
Here is my script and when i get the data from a database it gives this error: Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in D:Fluke_Mambocomponentscom_confirmationorder_status.php on line 33 if you want to know where $my->username comes from it is defined from the user logged in at the moment becouse this file is included....
View Replies !
Supplied Argument Not Valid Resource?
I'm making an upload script to insert into my MySQL database, but it keeps on giving me an error message. "Warning: fread(): supplied argument is not a valid stream resource in /home/john1704/public_html/photos/upload.php on line 29" Here's the code I'm using:
View Replies !
Supplied Argument Is Not A Valid Stream Resource
I'm running PHP 4.x with an Apache web server on Macintosh OS 10.3.9. It's an internal school web server that sits on my desk, so I have complete control over it. I've hit a wall with a script I'm working on right now. This is not a web page. It's a php application that reads a directory and uses the data it gathers to write a web page that lets students view thumbnails of and vote on other students' graphic or Flash projects. Code:
View Replies !
Warning: Feof(): Supplied Argument Is Not A Valid Stream
i am using fopen to open a webpage, it works great when the page is not located on a secure server but as soon as i point it to look at that page i get the following error Warning: feof(): supplied argument is not a valid stream resource in C:AppServwwwSJMDBv2database_eagaDupChecker.php on line 11 Warning: fgets(): supplied argument is not a valid stream resource in C:AppServwwwSJMDBv2database_eagaDupChecker.php on line 14 this is the code for the page in question $fp = @fopen("https://somesecured.server", 'r'); while (!feof($fp)) { $buffer = fgets($fp, 4096); echo $buffer; } fclose($fp); i have tried it on several diffrent server and the only one i can get working are the normal http.
View Replies !
Ldap_get_values() Stating That The Supplied Resource Is Not A Valid Ldap Result
I'm checking a user identity on a secure LDAP server using the following code: $ldapconn = ldap_connect("ldaps://myserver.mycompany.ch", 636 ) or die( "Can't connect to LDAP" ) ; $ldapresult = ldap_search( $ldapconn,"o=mycompany,c=ch","cn=".$name); if( $ldapresult ) { $entries = ldap_get_entries( $ldapconn, $ldapresult ) ; if( $entries["count"] ) { $ldapbind = ldap_bind( $ldapconn, $entries[0]['dn'], $pwd ) ; if( $ldapbind ) { echo "Connected: user exists, password checked<br>" ; } } This works ok if I submit the right $name and $pwd Then I'd like to retrieve some data from the specified user, say the givenName and sn but can't figure out a way to retrieve those values using ldap_read or ldap_get_values For example: $results = ldap_read($ldapconn, "cn=myname,o=mycompany,c=ch", '(objectclass=person)', array( "givenname", "sn" ) ) ; $firstname = ldap_get_values($ldapconn, $results, "givenname" ) ; $lastname = ldap_get_values($ldapconn, $results, "sn" ) ; This fails on the ldap_get_values() stating that the supplied resource is not a valid ldap result entry resource. If I use something like: $firstname = ldap_get_values($ldapconn, $ldapresult, "givenname" ) ; $lastname = ldap_get_values($ldapconn, $ldapresult, "sn" ) ; It fails too...
View Replies !
Mysql_free_result Return Error Saying Not Valid Mysql Result Resource
im trying to do a query which takes rows of large amounts of text data and displays them one after another. the size of the fields is causing the page to be massive in size. so to try and reduce this im trying to use mysql_free_result to clear the contents from memory. however its returning an error saying not valid mysql data when im certain that it is. is this because im using a while loop like this...? ($row = mysql_fetch_result($result)) { mysql_free_result($result); }
View Replies !
|