Assign Dynamic Dropdown To Variable?
Is it possible to assign a dynamic dropdown script to a $variable? Code:
View Complete Forum Thread with Replies
Related Forum Messages:
Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add". But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:
View Replies !
Assign Value To Variable
Is there any way I can use a function to create a variable and assign a value to it? I have a Perl script that returns some LDAP information: sn=Shore givenname=Mike logintime=20041008153445Z logindisabled=FALSE Instead of parsing this text and assigning the values, I was wondering if a function exists where I can pass a variable name and a value, and the variable would be created. ie. somefunc("sn", "Shore") Would create the variable $sn and assign the value "Shore" to it.
View Replies !
Assign To Variable
I am trying to take data from the database and assign it to a variable but i'm not sure how this is the code ive been trying $sql = "SELECT Name FROM Names WHERE Name = 'Peter'"; while($row = @mysql_fetch_array($sql)) { $var == $row['Name']; }
View Replies !
Dynamic Dropdown?
I am posting a code for dynamic dropdown by Leon Atkinson, it works fine but i have a doubt: I tried to add another functionality to it where i got stuck! Once the city also gets selected from the second drop down i wanted that on clicking the submit button it should go to some html page wrt to the city choice. Code:
View Replies !
Dynamic Dropdown Box
im looking to have two drop down boxs one with makes of car and the second drop down box to automatically populate with all the model of that particular make of car. there are about 50 makes and upto 50 models per make. I just would like to know the best way to do this - javascript or use a database? it would be a lot of code todo it in javascript wouldnt it?
View Replies !
Dynamic Dropdown
This may be rudimentary but I'm just trying to get my head around this without having to write a billion lines of extraneous code. I have a dropdown selection list, populated from a mySQL database, containing times in a HH:MM:SS format. The times are 30 minutes interval spanning an entire day, as in 01:00:00, 01:30:00, 02:00:00 all the way to 24:00. I have it entering fine into the database, but when I want to edit this time, I'd like to have the value in the database be marked as the CHECKED value on the dropdown so I don't have to manually re-enter the time for every edit.
View Replies !
Dynamic Dropdown Lists
I am recoding a greeting card website. I am using dropdowns as filters for items in a DB, so when the user picks "animals" from the "theme" dropdown, the returned cards all feature animals, and when the user picks "birthday" from the "message" option, the returned cards all feature birthday cards. However, there are some combinations that don't return any results, for example "get well" "floral" cards. Code:
View Replies !
Dynamic Dropdown Menu
with help from the PHP Gurus here, I have a dynamic menu script: PHP Code: <?php $time = time() + 28800; $time_plus2 = strtotime('+ 6 days'); echo '<select name="select">' while ($time <= $time_plus2) { Â Â Â Â echo '<option value=>' . date('l, F d', $time) . '</option>' Â Â Â Â $time = strtotime(date('Y-m-d', $time) . ' + 1 day'); } echo '</select>' ?> how do I now get the days of the week to link to different pages?
View Replies !
Dynamic Content Using Dropdown
I have the following dropdown menu which is populated by content or categories (with catID being the category ID) from the database. What I want to do though is when an item in the drop down list is selected, I want to show dynamic content under it. BTW, I must not emphasize on "dynamic" too much because it may seem like a DHTML thing going on here. For example, if a user selects a certain item/category in the list, I want content such as coupons in the DB which have the same catID as the category selected showing up. The coupons are discreetly placed in the DB table "coupons" with the category ID being catID and...for eg: catID --- couponname --- couponinfo --- expiredate If you are going to include any kind of javascript, please write them as well. Here is the code I am starting off with: =========================== <form name="myform"> <select name="selectID" size=10 > <? $resultcat = mysql_query("SELECT * FROM Category"); while ($myrow2 = mysql_fetch_array($resultcat)) {?><?printf("<option value=%s>%s</option>", $myrow2["catID"],$myrow2["name"]); } ?></select></form>
View Replies !
Three Dynamic Dropdown Boxes
Can any one help me in dynamic drop down creating? I have three dropdowns One for Country one for state and one for location. My plan is to select the country from dropdown according to this i have load the values in state drop down from MySql table. Depending on the state i have to select the location too.
View Replies !
Is It Possible To Assign A Whole Function Or Block To A Variable ???
Is it possible to assign a whole function or block to a variable ??? eg. <BLOCKQUOTE><font size="1" face="Verdana,Arial,Helvetica">code:</font><HR><pre> <? if (db_num_rows($qid_p) == 0) { ?> <li>No <? } ?> <? while ($prod = db_fetch_object($qid_p)) { ?> <p><b><a href="product_details.php?id=<?=$prod->id?>"><? pv($prod->name) ?></a></b> <br><? pv($prod->description) ?> <br>$<? pv($prod->price) ?> <br>[<a href="cart_add.php?id=<?=$prod->id?>">+ Add to Cart</a>] <? } ?> How to assign this code to a unique variable ???
View Replies !
Assign Function Output To Variable??
I've found some references to this topic at : http://forums.devshed.com/showthrea...ion+to+variable but it does not seem to be working for me. here's a snippet... <? PHP function listPeople ($getArray) { foreach ( $getArray as $val ) { echo "$val, "; } } $foo = listPeople($splitDirector); ?> The function works, and as you can see i'm simply trying to assign the output of the function to $foo. But instead, the output is written to the page where I assign it... like a print or echo statement, and the variable $foo is empty.
View Replies !
Ways To Assign A Value To A Session Variable.
I am wandering which way to assign a value to a session variable exist. Which of the following examples will work. Example #1: session_start(); session_register("ex"); $ex = 2.0; Example #2: In first.php: session_start(); session_register("ex"); In second.php: $ex = 2.0; Example #3: In first.php: session_start();...
View Replies !
Assign Variable From Database Field
Is there a way to assign a variable from a database field? I'm thinking along the lines of $make = $row_rsList['make']; $model = $row_rsList['model']; then they'll switch out based on my SQL WHERE statement. This valid syntax?
View Replies !
Assign Userid To A Session Variable
When a user logs into my system, i assign their userid to a session variable [php] $_SESSION['userid'] = $myrow[0]; [php] and then a user logs out, i do the following [php] $_SESSION['userid'] = '' session_write_close(); [php] so, when a user clicks on a link to a page they should only see when logged in, i do the following test [php] if (isset($_SESSION['userid'])) { header('Location: members.php3'); } [php] but the logout does not seem to work for some reason? userid still seems to be set after running the logout script, any ideas? am i doing something silly?
View Replies !
Dynamic Dropdown Menu Glitch
I wrote this code to dynamically generate an array from files on my server and put it into a drop down menu, but the code cannot be inserted on any page anywhere without it cancelling the loading of the rest of the page. Any ideas? Here is the code: PHP Code: <? $the_array = Array(); $handle = opendir('walrus/strips/.'); while (false !== ($file = readdir($handle))) { Â Â Â if ($file != "." && $file != "..") { $file = substr($file, 0, -4); $the_array[] = $file; Â Â Â } } closedir($handle); asort ($the_array); reset ($the_array);.....
View Replies !
Network Bar, Dynamic, Dropdown Menu
Basically I have a "network bar" that I place on the top of all my sites, which has a dropdown menu box to interlink all my other sites. Basically I would like to really modify this idea out more. Code:
View Replies !
Assign A New Value To A Variable Passed From An Html Form
I'm trying to assign a new value to a variable passed from an html form to a php3 script. I'm using an if statement to evaluate variable 3 to see if it is equal to a specific string, if it is I'm reassigning variable 2 to be variable2+variable 3. if ($question3!="select days") { $question2=$question2+$question3; } This is the statement. It keeps giving me a parse error and I can't seem to find the right documentation to show me how to combine two string variables.
View Replies !
Multi-Dimensional Arrays - Assign Variable
It's a simple question, but I'm just not getting it. I have two files: <?php $precinct = array ( array ( number=>2324, centerlat=>-122.31705665588379, centerlong=>47.710367959402525, etc... <?php include ("precinctdata.php"); $filename = $_GET['id']; $number = $precinct[filename-1][number]; etc... I want to assign the value of "2324" to the variable $number. I've done this with arrays that start with number=>1, 2, 3, etc., but not successfully with specific values. What am I missing?
View Replies !
Assign MySQL Function Result To PHP Variable
I know to use: mysql_fetch_row($result) to convert a row from a SQL query result set into an array for use with PHP. but in the case of SQL queries that return one value, such as calls to MySQL functions, is there another PHP mysql api function I should use. For example, right now I use a "workaround" technique from PHPBuilder: $result=mysql_query("SELECT COUNT(*) FROM tablename"); list($numrows)=mysql_fetch_row($result); Rather than using this "workaround" code is there a way to simply assign the result of the MySQL function query to a variable. $result=mysql_query("SELECT COUNT(*) FROM tablename"); $numrows=mysteryfunction($result);
View Replies !
Assign Variable To A Block Of Html Code
Is it possible to assign variable to a block of html code? Something like this : $myblokvar = "<table width="487" border="0" cellspacing="0" cellpadding="0"> <tr> <td><table width="487" border="0" cellspacing="0" cellpadding="0"> <tr> <td><img src="images/bartitle_login.gif " alt="Login" width="475"...
View Replies !
Dynamic Fill Form Fields Depending On Dropdown Box
This question has probably already been asked, but let me ask again I have a mysql database to which I connect with my php scripts. The database contains articles. Name, Unit_Price and Reference Now my client needs to order 5 items, click a button and a table with 5 lines and 3 columns appears (until now easy) In the first column is a drop down box with a <select > and <options> in which I store all possible names. I would like than whenever the client changes one of the boxes (in my case there are 5) the Unite_Price column and Reference column in the line he just choose get automatically updated
View Replies !
Creating Dynamic Page Based On Dropdown Selection?
I'm using Dreamweaver, but I believe this is a general PHP/MySQL question. I have a table, with 4 fields: id, year, car_make, car_model. The data looks like this: 1 1992 Honda Civic 2 1994 Ford Probe GT 3 1999 Audi S4 4 2002 Porsche 959 On my web page, I have a drop down list that's propogated automatically with the "car_model" field entries which are pulled from that table. So when I click the down arrow, I see Civic, Probe GT, S4 and 959. Code:
View Replies !
Data Entry Form With Dynamic Dropdown Boxes
I am working on a Form for user to register & enter their info such as name, email, address, tel etc. and I put in a couple of dropdown boxes namely country and city where user can select. I made them dynamic, i.e. the city dropdown is based on the selected value from country and the data retrieved from MySQL database. The problem I have is the Javascript script involved a reload of the form and once I select a value from Country, the city dropdown populated with data OK but the data entered beforehand (Name, email, etc.) disappeared.
View Replies !
Assign Variable Name As Variable
I want to be able to create a foreach loop that will go through all the intended POST variables and then assign it as a standard variable. For example, I want to have $username = $_POST['username'] without even knowing username exists in the context of the foreach loop. Code:
View Replies !
Dynamic Variable Name
I have a MySQL query that returns a result array yielding $enrow[0], $enrow[1], etc. and a result array yielding $sprow[0], $sprow[1], etc. I want to call one of the results based on a user inputted variable (ie $lan="en" or $lan="sp") giving echo ' hello' . $enrow[0] . 'how are you?' I tried echo 'hello' . ${$lan."row[0]"} . 'how are you' doesn't work.
View Replies !
Dynamic Variable
foreach($_POST['hid_price'.$id] as $price) { $total = ($price*$qty); } Note the $id tacked on to "hid_price".the result being hid_price1, 2, etc. How would I go about tacking $id on to the $total variable so I get a corresponding variable named $total1, $total2, etc.
View Replies !
Dynamic Variable Selection...
Is it possible to create a bunch of variables in a loop with different #'s at the end of their name... like: while ($counter <= 10) { $myvar$counter; } to create 10 variables.... mayvar1, mayvar2, mayvar3, etc..... is there a way to do that?
View Replies !
Dynamic Variable Name Generation
I would like to write a for loop to perform the following assignment: if ($eliminalink1=="on"){$lnk1=Ɔ'} if ($eliminalink2=="on"){$lnk2=Ɔ'} if ($eliminalink3=="on"){$lnk3=Ɔ'} if ($eliminalink4=="on"){$lnk4=Ɔ'} if ($eliminalink5=="on"){$lnk5=Ɔ'} For example for ($i=1; $i<=$max_int_lnk; $i++) { if ($eliminalink.$i=="on"){$lnk.$i=Ɔ'} } But It doesn't work. Does anyone knows why?
View Replies !
Getting Php To Recognize My Dynamic Variable
I'm able to get the $itemg to be a recognized variable to check for, but when i try to change the $ceitem1_array items into a dynamic variable and make it like this $itemg2 = "citem" . $itemnum2 . "_array[0]"; that doesn't work becuase it never seems to evaluate true. This is the loop snippet of code that i wrote that works correctly. while ( $itemnum < 20 ) { if ( $$itemg == $citem1_array[0] ) { echo "$citem1_array[1] - $citem1_array[2]"; echo " "; } $itemnum = $itemnum + 1; $itemg = "item" . $itemnum; }
View Replies !
Dynamic Variable Names.
I want to make it so the name of a variable is changed by '$z' I'm not sure how to do this. Right not I'm trying: [$row + $z] = 1 But it doesn't work.
View Replies !
Dynamic Variable Names
I've got something like this: if ( $host[$i][detail1stuff]!= "" ){ some_code_here; } if ( $host[$i][detail2stuff]!= "" ){ some_code_here; } etc... I want to do something like this: for ($count = 1; $count <= 100; $count++ ){ if ( $host[$i][details{$count}stuff]!= "" ){ some_code_here; } } However, the above doesn't work. Does anyone know how to do this?
View Replies !
Dynamic Variable Problem
I'm building a Flash-based app at the moment, and have run into a bit of a problem with the PHP scripting. It's probably a no-brainer, but I'm tired, and a fresh mind on the case might sort the problem quicker! I'm setting a variable dynamically, and then assigning it a value. The problem comes when I try to extract this value; how do I get hold of it? When I code echo $$varName, I get absolutely nothing back in Flash, but if I change this to $varName, I get the variable's name (i.e. categories2) Code:
View Replies !
Dynamic Page Variable
I was wondering if I can set a dynamic variable per page that declares the color the the current page in the menu to be a specific color seperate from the rest. If not maybe another way to do so, I was thinking CSS but thats messy. Code:
View Replies !
Dynamic Variable Incrementation
I'm trying to make this code dynamic so that I can decrease it by the number of items in the inventory, this is the static formula to that works, but I don't want to have to add this every time I have another item to check for. Help me to dynamically subtract one from the amount of items. Â if ( $$itemg == $citem1_array[0] ) { Â Â Â Â Â Â echo "$citem1_array[1] - $citem1_array[2]"; Â Â Â Â Â Â echo " "; } Â if ( $$itemg == $citem2_array[0] ) { Â Â Â Â Â Â echo "$citem2_array[1] - $citem2_array[2]"; Â Â Â Â Â Â echo " "; } Â if ( $$itemg == $citem3_array[0] ) { Â Â Â Â Â Â echo "$citem3_array[1] - $citem3_array[2]"; Â Â Â Â Â Â echo " "; }
View Replies !
PHP Dynamic $_POST Or $_COOKIE Variable
Ok guys the premise of this was to dynamically retrive either a $_COOKIE or $_POST variable depending on which exist. I thought it was simple and was simply using a variable called $element_type the idea is that $element_type is either "$_POST" or "$_COOKIE" So you would think the code $type."['FormName']" would work and retrieve either a cookie or post value .......but it doesn't. I've tried using an eval on it but I always get a parse error because of the square brackets (without eval the best I can get is literally the text $_POST['somevariable'] which is of course useless.
View Replies !
Dynamic Variable Names For Objects
I need to use dynamic variable names but for objects. As you know something like that works fine: $variable="content"; $part="able"; echo ${"vari".$part}; // gives out content but i need to use a database object after a mysql query something like that $sqlresult= mysql_query("SELECT * FROM t_table_xy"); while (($obj = @mysql_fetch_object($sqlresult)) { echo ${"obj->f_".$fieldname[1]}; } but this dont work, I suppose because of the -pointer. has someone an idea how to solve that ?
View Replies !
Variable Data In Dynamic Table.
What I'm trying to do is list the values of an array into different table rows while alternating the color of the table rows. Simple enough right? It makes the table fine. Creates the proper ammount of rows. It even alternates color (yay!). The only thing that it doesn't do is list the values in the array. PHP Code:
View Replies !
Dynamic Variable Names - Shopping Cart
I have a shopping cart page that allows a user to type in a new quantity and press a [Submit] button. The quantities entered are in form text boxes with the names "item302", "item7812", etc. reflecting which item that particular textbox is associated to. I store the entered variables using 'import_request_variables("p","p_")' so I end up with $item302, $item7812, etc. My script looks for these variables by looking through the shopping cart array which stores the item numbers themselves and then checks the value of $item<whatever>. If I have a number stored in $item is there any easy way to tell PHP to check the value of variable $p_item<item>? For example, if $item is ¹Ý' how can I tell PHP to evaluate $p_item302?
View Replies !
Cannot Re-assign $this ...
I'm one more guy having the cannot re-assign $this problem. someone left a php4 file here containing the lines |function linkbar() |{ |if(func_num_args() == 1) |{ |$this = func_get_arg(0); |return; } ... |} inside a php4 class definition. func_get_arg(0) in this case delivers an object - working fine in php4. I struggled a bit with the & referencing (while not really understanding it and the problem) but gave up. how must I modify the code to get it to work in php5?
View Replies !
|
TRACKER
