Duplicates In A Dropdown Menu Populated From My Database
I've been searching to figure out how not to have duplicates in a dropdown menu populated from my database. This is what I have, but how do I change it to get rid of duplicates.
<?php
$result = mysql_query("SELECT City FROM residential order by City");
echo "<select MULTIPLE NAME="City_code">";
while($row = mysql_fetch_array($result)){
echo "<option name="City" value="$row[City]">$row[City]</option>";
}
?>
</select>
View Complete Forum Thread with Replies
Related Forum Messages:
Dropdown List - Trying To Get Default Populated From Db.
Nooby question but when I try and get this to work (it should identify which rows in the database have GK, MID, DEF, FWD against them and then put SELECTED into the option value to give a default of what the entry is currently) it just adds SELECTED to all the results as if $row["Position"] is returning true against all four conditions? What am I doing wrong? CODE:..
View Replies !
Dynamically Populated List Menu
I have a DB with a field called county in a table called info. I want to populate the list menu below with the counties in the field county. Would there be a way to get around the fact that there will be many entries with the same county and we want only 1 instance in the list menu? Code:
View Replies !
[PEAR:QuickForm] Dynamically Change A Dropdown Menu According To Another Menu?
I've been using QuickForm for a few months now and I am now given a new challenge: I've got a search form with a dozen of dropdown menus, the first dropdown menu being "Brand". If you select either Brand A, B, C, D... Z, the second dropdown menu "Model" must be dynamically changed to model AA, AB, AC, AD..., according to the models manufactured by the brand selected in the first box. I've seen that done on quite a few sites, but never found if QuickForm had a quick & clean way of doing that.
View Replies !
Dropdown Menu
i seem to be having some problems on finding how this ajax drop down menu i seen at Anime-Eden.com. it has a nice effect on how it appears. Now i am familar on how PLAIN drop down menu works, but not how this works.
View Replies !
Use A Dropdown Menu
I have a list of contacts which are sorted by name. I was hoping to create a dropdown menu in which someone can sort the list of contacts by office, city, state, and contact type. Is this possible? (I am sure it is, but I am not sure what the concept is called so I may research how to do it).
View Replies !
Drop Down Populated By Database
I currently have a php file that pulls a query from the field "category" from my database. this file is called category.php. I am trying to populate a drop down box in another page (called add_subpage.php) from the results of the category page. the code below is on the add_subpage.php file: (It was my best guess and does not work) <select name="category"> <option value="CAT"<?php include 'category.php' ?>></option</select> Can anyone tell me how to make this drop down populate from the category php file?
View Replies !
Advanced Dropdown Menu
I want to populate a dropdown menu with countries that are in one column of my table. I know how to do that, but I can't find how to eliminate multiple items. Some countries appear several times in different rows, but I only want each available country to be shown once in my dropdown list.
View Replies !
Mysql / Dropdown Menu
what i am trying to do is to make a system with a few input pages and edit and read pages.. so right now i got the input/edit/read pages working. (yay) But now I want to have on 1 input page a dropdown menu that reads its information from the database. and that if i go to the page i can select a value out of the db and submit that inside my form and that it reminds the value if i view or edit the page. So what i got now is a little system that is able to add/remove/edit a value inside a field called "drop01" Well now i got a other input page called "input01.php" inside this script i want to have the dropdown menu that reads its values from the "drop01" field. PHP Code:
View Replies !
Autoselecting A Value In A Dropdown Menu
I'm revamping my sites administration panel and I put in a dropdown menu to select the section to administrate (it was a LOT better than the list of links I had before, I'll probably update it some more though) and I want to know how I can autoselect whatever page I'm on in the dropdown menu, for example, here's the menu: Code:
View Replies !
Dynamic Dropdown Menu
with help from the PHP Gurus here, I have a dynamic menu script: PHP Code: <?php $time = time() + 28800; $time_plus2 = strtotime('+ 6 days'); echo '<select name="select">' while ($time <= $time_plus2) { Â Â Â Â echo '<option value=>' . date('l, F d', $time) . '</option>' Â Â Â Â $time = strtotime(date('Y-m-d', $time) . ' + 1 day'); } echo '</select>' ?> how do I now get the days of the week to link to different pages?
View Replies !
Populating Dropdown Menu From Db
Okay, I am trying to populate a drop down menu with items from a table in my db. I have a table called "teacher" which has the following info: I use the following code to grab the info from the teacher table. Code:
View Replies !
Dropdown Menu Updates
I have seen this on lot of sites, where say you goto a car site, and you click the make of the car from a drop down menu, and than after u click it, it will load up the appropriate models for that make.
View Replies !
Pre Populated Php Form From Database Problem
so I want to populate a form from my database, edit it and then submit it back to a different table. I am using a while loop to display every row entry in the database as a form field. now when I try to add the submit button it adds one after each form field (row from the db) (I would also like to add a form field at the top that doesnt COME from the database but will be passed to it from the form) I figure that its just a problem with placement but I learn to program from google and Ive been googling all day and getting no where!
View Replies !
2 Questions. Dropdown Menu And # Of Rows.
1. I have a table named pics and a column named name, just to let you know for use. I want to take the data from each row in the name column and insert it into a dropdown menu. I know how I could do it, but I would have to go: Code: <SELECT NAME="name" SIZE="1"> <OPTION SELECTED><?php $name[10 ?> <OPTION><?php $name[1] ?> <OPTION><?php $name[2] ?> <OPTION><?php $name[3] ?> <OPTION><?php $name[4] ?> <OPTION><?php $name[5] ?> <OPTION><?php $name[6] ?> </SELECT> but then I could make too many or too less. I want it to automatically adjust to the number of rows. 2.What is the code needed to find out how many rows are in a table?
View Replies !
Unwanted URLs In URL Dropdown Menu
I'm working on a PHP script and it has a user login, and the variables (username, password, id number) are passed via the URL bar. Is it possible to somehow not allow the visited page show up in the dropdown list of URLs in the browser? The problem is that people can view the list and easily see people's usernames and passwords. Example: http://www.somesite.com?username=john&password=12345 What I only want is: http://www.somesite.com/ I know that Hotmail.com doesn't show all of the pages that have been visited, all it shows in the list is hotmail.com, so I think it is possible to do this, but I don't know how.
View Replies !
Make A Dropdown-menu Filter?
I have a dropdown menu which is supposed to filter a table to show results for professionals, students or all. But I don't really know what I'm doing. This is what I have so far. Code: Initially, I was able to filter for students or professionals, but since trying to have an all option (students and professionals) it has gone to pot, and I keep getting errors. I know that my quotation marks are not right, but I can't think of a solution. I would be more than happy to see any ideas, even if they are completely different to mine!
View Replies !
Dropdown Menu <selected Name="...
I have a dropdown menu like this one: <select name="country" tabindex="6" id="select_country"> <option value="">- Country List -</option> <?php $query = "SELECT * FROM country ORDER BY country ASC"; $result = mysql_query($query) or die('Error, query failed'); while ($row = mysql_fetch_array ($result)) { $country = $row['country']; ?> <option value="<?php echo $country ?>"><?php echo $country ?></option> After I have selected one country and I hit the submit button it go back to the default value in the box, what I want is to show the selected value in box until I selected another value. If the default value is Australia when I start this page, I then select USA and hit the submit button it reset to the default value "Australia", but I want it to show USA as long I not select anything else. I have tried to use session in selected="<?php echo $_SESSION['country']; ?>" but it didnt work.
View Replies !
Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:
View Replies !
Selecting Item In Dropdown Menu
Im having problems trying to select a specific option in the drop down menu which has been populated with a list pulled from the 'category' table in the db. The option that needs to be selected is pulled from an id in a 'item' table, relating to the aformentioned category table.
View Replies !
Dynamic Dropdown Menu Glitch
I wrote this code to dynamically generate an array from files on my server and put it into a drop down menu, but the code cannot be inserted on any page anywhere without it cancelling the loading of the rest of the page. Any ideas? Here is the code: PHP Code: <? $the_array = Array(); $handle = opendir('walrus/strips/.'); while (false !== ($file = readdir($handle))) { Â Â Â if ($file != "." && $file != "..") { $file = substr($file, 0, -4); $the_array[] = $file; Â Â Â } } closedir($handle); asort ($the_array); reset ($the_array);.....
View Replies !
Network Bar, Dynamic, Dropdown Menu
Basically I have a "network bar" that I place on the top of all my sites, which has a dropdown menu box to interlink all my other sites. Basically I would like to really modify this idea out more. Code:
View Replies !
Tree View Dropdown Menu
I have such a categories MySQL table: ID | name | parent and have such a function that displays the categories in a SELECT element as a drop-down menu: function DD_ProjectCategories($parent=0) { include("db.php"); $query = "SELECT ID,name FROM categories"; $result = mysql_query($query) or die(mysql_error()); echo '<select name="parentcategory">' echo '<option value="">Choose a parent category</option>' echo '<option value="0">Root Category</option>' while ($row = mysql_fetch_array($result)) { echo "<option value="$row[0]""; if ($parent == $row[0]) {echo " selected"; } echo ">$row[1]</option>"; } echo "</select>"; unset($query,$result,$row); }.....
View Replies !
How To Pass The Value Of Selected Dropdown Menu To Another File?
there is a php-myql script that list the mysql databases in the drop-down menu, use wil select one and the submit button should pass the value or variable $db_name to the test.php, this script list the databases in the drop-down menu but when i select one and then click on submit cannot pass the db_name to the test.php:
View Replies !
Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time. If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:
View Replies !
Pagination And Dropdown Menu Used In Searching Mysql
I am working on building a database made for searching. I have a text search and a dropdown box used for searching different table collumns (lets people search for certan criteria). I have that working correctly. I also only want to show 25 results per page. I have that working correctly. My problem is that when I combine the two it breaks the code. The pagination works fine without the dropdown and vice versa. I think it is due to the variable that is being used to choose the collumn in the sql query. Code:
View Replies !
Choose From A Dropdown Menu Of Encryption/decryption Cyphers
I've written a php page which allows users to type in a text string and a key, then choose from a dropdown menu of encryption/decryption cyphers, and a method (encrypt, decrypt). The whole thing works, except the mcrypt command doesn't work. here is my mcrypt command: if ($method == 0) { //Encrypt $output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_ENCRYPT); } else { //Decrypt $output = mcrypt_ecb ($algorithm, $key, $input, MCRYPT_DECRYPT); } Here's a list of what the variables may be: $algorithm = MCRYPT_3DES $key = "plain text" $input = "more plain text"
View Replies !
Query MySql Database - Duplicates
I've got a field in a MySql database that I'd like to query. This field contains names of people & there are some duplicates as well. The end result of my query should look like this:- HTML Code: NAMENUMBER OF RECORDS Jonh2 records Alice4 records Builder8 records Yahoo5 records
View Replies !
Checking For Duplicates In Database On Form Submit
I had the idea to use the following to check for duplicate value when a form is submitted to a database: elseif ($result == $_POST['serialnumber']) { $db_handle = pg_connect('dbname=test2 user=andy password=da4531'); $query = 'SELECT serialnumber FROM system'; $result = pg_query($query); pg_close($db_handle); echo "<h2><b>Duplicate serial number! Go back, change serial number and submit form again.<b></h2><br />"; } I can't figure out how to get $_POST['serialnumber'] to check against each record of $result. Any ideas? All values of 'serialnumber' need to be unique.
View Replies !
Populating "Month" Dropdown Menu
I can get the current month to display in a text box by inserting value="<? print strftime("%B"); ?>"> into the code for that particular text box on a form but how can I populate a drop down with names of all the months with the current one being 'default' as it would be in the text box example?
View Replies !
Populating A Dropdown From A Database
I have put together a script that populates a dropdown menu from a database. My database contains a table called casinocredit, and it contains records that have been enterend over 2 different months (may and june). There is a field in the database that contains the date in this format: 2006-05-12 00:00:00 So The drop down is currently showing a month for each of those records. I was hoping that it would only display one. (the plan is when a user selects a month (say May) and hits submit, then I would display all of Mays records on a different page) See the image i have attached for a view of what is happening. Code:
View Replies !
Autopopulate Dropdown List From Database
An events-registration page with a form containing a dropdown list for upcoming events, the events will be pulled from a table which is updated by...? what i've gathered so far is that this can be done with PHP. I am a little unclear on the concept of how this is done. How does the updated information get input into the table? 1) can this be done (updating database) through a web interface by the client, or is it something i would have to do locally and then upload. If done by the client, can he delete/edit existing information--assuming he is not familiar with code. 2) what other things aside from html(good), sql(so-so), and php(newb) will i have to know? i've seen a lot of good tutorials here and will have access to the necessary software. I just want to know if there is anything else i should know before i dive in head first without testing the PHP water, which i assume is frigid.
View Replies !
Add Data To A Database Using Dropdown Menus?
lets say i had a database with a table called admin hacks and another table called user hacks,and both tables had feilds called name and id now what i want to be able to do is create a submit form with a drop down menu saying the table names mentiond above, also the form will have a field called name. now lets say a user slected admin hacks from the drop down menu and enterd jack in the name, how would i get the data in that submitted form to be inserted into the correct database table, so jack should now be in the table called admin hacks also lets say someone selected user hacks and entered jon how would i do the same for that?
View Replies !
Insert Date To Database Using Dropdown Boxes
I be able to insert the date into my database if i have 3 dropdown boxes wherein it contain the month,day & year. i know the basic of inserting data into my database but with this 3 dropdown box i don't have any idea. after submitting, the data selected on these 3 boxes shall be in one field in my database with fieldname Date.
View Replies !
Chain Menu But The Menu Should Be Multiple Select Menu/list
I am looking for codes to be able to do the same thing with multiple select menu/list. PHP codes or javascripts codes are both fine. 1) javascript + php approach: Prefer to be javascripts codes to display the chain menu. I can use the php to get the all three levels menu data from the database, and assign these values to the javascript. 2) php codes only: Or use the pure php codes (the problem is if just using php codes then I have to submit the form to the server every time, when top level menu select changes to create new menu.).
View Replies !
Drop Down Menu Without Using A Database?
A lot of people are turning off javascript on their browsers so the script doesn't always work. I would like to know Is their a php script that can do the same thing without using a database? Can I get the links to open in a new window when they are selected?
View Replies !
Dynamic Dropdown And Hardcode Dropdown In Select Form
I have plenty of examples of dynamic dropdown choices but none of hardcoded dropdown choices. The ultimate goal is to have a job with various tasks and to track the status of those tasks for a given job. I've used one of the tutorials here to begin the process. Below is the code I have to add work on a given task. Perhaps I actually need to "Update" a job as opposed to "add". But the problem of the moment is I can't seem to hardcode one set of my options. This is the code I have: PHP Code:
View Replies !
MySQL Database In A Pulldown Menu
I have a script that I am trying run with PHP, that gets the contents of a database, and then arrange them in a pulldown menu. I then have that selected Name, for instance, and then I can choose between 2 Buttons. Edit and Delete. PHP Code:
View Replies !
Drop Down Menu Validation Against Database
I want to do a query which selects the config.maps table.field WHERE ladder_id = $ladder_id. I can do this fine, but the next bit is slightly harder. The maps are stored as an array, separated by commas. I can explode these commas to put the maps in to an array called $maps but how can I then check that a value inputted from the drop down menu matches one of these maps? I cannot do: if ($dropdown = $maps[1] || $dropdown = $maps[2] || $dropdown = $maps[3]) { // Continue }
View Replies !
Horizontal Drop Down Menu From Database?
I've been searching now for months and have just given up. I've also tried to create my own menu using pre-made drop down menu software then using dreamweaver to try and get the values from a database but have had no success. I've made a CMS which allows users to greate sub menu items, and then sub-sub menu items to those submenu items. And now the final thing to do is create the drop down menu on the front end of the site. Is there a particular site or software package that anyone could point me to that is very good and allows you to create the menu's based on data in a database? So it will allow me to select which table contains the main buttons, which table contains the sub menu items, and also the sub-sub menu items.
View Replies !
|
TRACKER
