Dymanic Populating Checkboxes
i like to retrieve a value from DB,
accordingly i like to display the checkbox, either checked or not.
Now im able to retrieve the value from DB, i can show even show the
checkbox, but i cant make it checked????
the Code i used to display as follows,
#Require the database class
require_once('../dbinfoinc.php');
#Get an array containing the resulting
record
$query = "SELECT * FROM event";
$result = mysql_query($query);
$num=mysql_numrows($result);
mysql_close();
$i=0;
while ($i < $num) {
if(($i % 2) == 0) { $c =
'"TableDetail"' }
else { $c = '"TableDetail2"' }
$event_id=mysql_result($result,$i,"event_id");
$event_name=mysql_result($result,$i,"event_name");
$event_publish=mysql_result($result,$i,"publish");
// if(($event_publish) == 0) {
$event_publish = 'No' }
// else { $event_publish = 'YES'
}
$take_action = 'Delete'
echo "<tr>
<td Class='navText'
align='center' class=$c>$event_id</td>
<td class='navText'
class=$c>$event_name</td>
<td class='navText'
align='center' class=$c><input type='checkbox'
name='publish' if($event_publish==1){'CHECKED'}?></td>
<td class='navText'
align='center' class=$c><a
href='delete_event.php?event_id=$event_id'>$take_action</a></td></tr>";
$i++;
}
?>
View Complete Forum Thread with Replies
Related Forum Messages:
Dymanic Variables In PHP, Possible?
Having some issues with a variable. I have a query running that returns 10 results of data, in a while loop. During the while is open it does something like : $data = Result Data For each row, and then after prints.. PRINT $data; That works however I'm now trying to give dymanic variables, so I can count the rows. So id have a count in the row return: Code:
View Replies !
Dymanic Menus
I have products stored in a MySQL database with each product belonging to a category. That category may sit under one or more other categories. What I need to be able to do it produce the site navigation based on the different categories and their parent categories. So basically I need to be able to produce the following HTML dynamically based on the categories store in the database. <ul> <li>Category 1</li> <li>Category 2</li> <li>Sub Category 1</li> <li>Sub Category 2</li> <li>Sub Sub Category 1 <li>Category 3</li> </ul> How would you store the category information in the database and what would the PHP script look like to produce the navigation?
View Replies !
Creating A Dymanic Website Generator In Php/mysql
I am creating a dymanic website generator in php/mysql and I have a particular question. I have the following sql statement: $sql = "CREATE TABLE one ( Email CHAR(50) NOT NULL, First_Name CHAR(25) )"; and it works just fine. I need it to act dynamically and vary with different contents that are being submitted by a form. In short, I need the name of the table that is being created to be a variable and not a static name. Here is an example: $sql = "CREATE TABLE $wstitle ( Email CHAR(50) NOT NULL, First_Name CHAR(25) )"; Can this be done in any other way that the above example because it does not work.
View Replies !
Browser Using Cached Version Of Dymanic Page
I have a javascript voting system along that looks like this: function rate(score){ bug=new Image(); bug.src="/score.php?score="+score; return false; } Every time the script opens the score.php page, a MySQL table updates itself with the new score. The problem is, if a user has ever voted, their vote is not always counted if they vote the same score again. I'm pretty confident this is because the browser is using a cached version of the score.php page, and not requesting the page again. How can I ensure the browser will always access the link, even if it has already been cached? Right now the score.php is a blank page. I'm wondering about maybe adding some headers to the page, or something.
View Replies !
Checkboxes - Form Is Not Working AT ALL For The Checkboxes
I want the user to be able to check a box in front of each fair he/she would like to attend and then proceed to providing us with registration details. Once complete, I want a reply sent to the client to thank them and indicate that his/her form was submitted. I also want the information submitted to be e-mailed to a particular address. (The information is not being submitted to a database) My form is working just fine for the submission of client details but is not working AT ALL for the checkboxes. The following is the code of the pages (the html registration page first, the php second) Code:
View Replies !
Populating A Select Box
What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box. I can do this on my own, but I was curious if I have to use a database in order for this to be possible.
View Replies !
Populating Drop Down
How do I do this drop down box ? Making an edit page. I have 2 tables groups id || categoryname program id || cateogry_id I need to populate the groups in it at same time show the selected choice from program. Not showing id but needs to show categoryname with of course the values being the id of groups.
View Replies !
Populating Dropdown Box.
I have been looking around the internet for an example of what I need to do but cant find anything was wondering if someone here might be able to help. What I need to do is to connect to a mysql db select a table and then a field from that table and put all the contents of that field into a dropdown box.
View Replies !
Populating A Webpage
I am trying to create a webpage that will allow me to view my 'email' website whilst I'm at work. The firewall blocks the page and I was hoping that there was some surreptitious way to get around this problem. My thoughts for a solution to this would be to create a variable with the website's name in pieces. Then send it to a function that opens it in a frame or something.
View Replies !
Populating Tables
I'm trying to populate an HTML table using the data in MySQL. "how to do format it to where I can make shipping labels?" There will be three lines of text for each label but I will have three columns of labels X 10 rows. Code: line A1 line B1 line C1 line A2 line B2 line C2 line A3 line B3 line C3 line D1 line E1 line F1 line D2 line E2 line F2 line D3 line E3 line F3 ....
View Replies !
Populating Two Combo Boxes
I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).
View Replies !
Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:
View Replies !
Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.
View Replies !
Re-populating A Form If Errors
I am learning php. I have created a simple Web page with a form. After receing the POST request, I do some error checking. In case of errors, I would like to re-post the page, but with the current values for each field. I have organized my files like this: 1) Webpage with the form (all in html, form action points to a php file) 2) php file that receives the request.
View Replies !
Populating Form Text Box.
I have a PHP form for entering data on-line into a mySQL table.. Because of the intended search facility, I require one field in the form to be completed with exact and precise item names and spelling. In testing, I had achieved this with look-up tables. Ideally I would like the selected item from one of five drop-down lists to autopopulate the form text field when selected. Alternatively at least the option of copy and paste. Copy and paste - for some reason will not work. Autofill worked fine on a test form with no database connection and in standard HTML and javascript, however, once the PHP is added to the page neither method works. Could anyone please point me in the direction of how to get the autofill to work?
View Replies !
Populating A Select Box From A Database
I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it. The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like: Green Red Blue Green Black How can I make it so that Green only shows up once?
View Replies !
Populating Drop Down And Table
I have a database with the following fields. Name | Company | Date values in each column could be repeated, or not. as in there could be several same names with the same company with different dates, or different names with same company. How do I populate a table with this info and have drop down boxes, so that I can narrow down the search? For example: Name | Company | Date 12 | 1 | 1929 13 | 1 | 1929 14 | 1 | 1929 12 | 2 | 1929 12 | 4 | 1929 13 | 1 | 1941 12 | 6 | 1929 So if in the drop down I select '12' under name, only those entries with 12 are shown, and then I can further sort it by selecting only '1' under Company. Hope I'm clear, I manage to complicate things when I post them.
View Replies !
Populating An Auto_increament Attribute
I have just designed a BD. there are companies with auto increament which are integer. When I try to populate it after i tool value from another form and try to insert it into a table i recieve an error! I don't ask the companyID value from user as it is auto increament. Don't tell me to put NULL for that entry as it didn't work as well! Code:
View Replies !
Auto Populating A Drop Down Box
Basically I'm setting up a website which needs an populated drop down box made up from all fields in a specific column of a table in a mysql db.... Here's the code I've made up using various tutorials.... <?php $user = ""; $host = "" $password = "" $dbName = "" /* make connection to database */ mysql_connect($host, $user, $password) OR DIE( "Unable to connect to database"); mysql_select_db($dbName); //did you forget this line? $sql = "SELECT model FROM usedVehicles"; $query = mysql_query($sql) or die(mysql_error() . "<br>$sql"); //use the or die(...) part ONLY IN DEVELOPMENT ?> <form action="action" method="post"> <select name="option"> <?php while ($row = mysql_fetch_array($result)) { echo "<option value="" . $row['model'] . "">" . $row['model'] . "</option> "; } ?> </select> <input type="submit"> </form> I've left out the connection details for obvious reasons... When I upload and try to test this, jus a blank drop down appears... there are definately fields in the column as I have tried the query on phpMyAdmin.
View Replies !
Populating Fresh Data
Im building a live web chat using php, mysql, javascript, ajax I am fine with sending and retreiving data in real time using ajax as the transfer protocol However, my problem, which is becoming a nightmare, is how to I display it !! Lets say the below is the chat screen, <div id="messages"> Jamie - Hello Peter = Hi Jamie = Nice Day Peter = I know </div> Lets say Jamie's next message is "What are you doing today". I can send that off to the database no problem and I can get peters live chat to pull that message in, however, how do I get it to display underneath Peter = I know As a practice I was using document.getelementbyid('messages').innerHTML = document.getelementbyid('messages').innerHTML + "<BR>What are you doing today" That works, but, lets just say the chat gets to 1000 lines, for each new message those 1000 lines have to be pulled out via javascript, a new line written to it and then printed back in the div Im not sure but I'd take a good guess at this not being optimal and will cause CPU load on the users machine What is the best way to do this! Chat messages are deleted after 1 minute, but that doesnt matter because by then they have already been sent the the users chat. Just incase you are thinking of completely repopulating there chat with every message they have sent since the chat started..
View Replies !
Populating A Dropdown From A Database
I have put together a script that populates a dropdown menu from a database. My database contains a table called casinocredit, and it contains records that have been enterend over 2 different months (may and june). There is a field in the database that contains the date in this format: 2006-05-12 00:00:00 So The drop down is currently showing a month for each of those records. I was hoping that it would only display one. (the plan is when a user selects a month (say May) and hits submit, then I would display all of Mays records on a different page) See the image i have attached for a view of what is happening. Code:
View Replies !
Populating A Drop Down List With Php
I am trying to get a drop down list to populate vbia php. What I have a is a script that allows a airline/user to enter airfare and price for tickets. It dumps them into a database and then allows the user to view/delete/add. I want the user to be able to edit the airfare. I have a drop down list that is set as a variable $ticket_from, $ticket_to. The list contains around 400 cities. When the user clicks 'edit' I have the price population but no the drop down list. How do you go about something like that? I have this right now: Code:
View Replies !
Populating Drop Down Lists
Could anyone help me on populating database driven drop down menus. I am trying to populate a second drop down list based on the selection of the first drop down list. I have the first drop down list running. Not sure about getting the second now.
View Replies !
Populating Combo Box Dynamically
when I click on a Country name in the first combo box the name should be checked on the database and the name of the respective states. should be populated in the next combo box dynamically. please give us the basic code and the way to go ahead to develop the code. We are new to PHP ,we have read the basics but how to develop now?
View Replies !
Populating Form Fields
I have a online order form that does not require a user to be logged in to use, but if the user is logged in I am attempting to get certain fields to populate with information stored in the database for the user. If the user is not logged in I need the information to be sent to the database.
View Replies !
Re-populating Text Fields
When a user submits a form on my page and there are errors, the page returns the errors and re-populates the correct fields - So the user doesnt have to complete them again. I using the below code to do that... <input style="width:200px; "Â name="userfile" type="file"Â id="menu_textbox" value="<?print $file_path; ?>" /> However, for the file upload field above it doesnt seem to work and the user must select the file they wish to upload from there computer again. Should the code for this be a little different or is there something I am missing?
View Replies !
Populating Drop Down From A Query
I'm trying to populate a drop-down box from the results of a query. I end up with the first option coming through and then blanks in the rest. Something like this... <option value=Acevedo>Acevedo</option> <option value=></option> <option value=></option> <option value=></option> <option value=></option> .......
View Replies !
Self Populating Drop Down Menus
i am trying to do is the following: I have a MySQL database that (very simplified) has a schema like this 'Students(Name, id, Course)' I would like to have a form on a web site that has 2 linked drop down menus, one 'Please select id' and one 'Please select course'. When a user of the site selects there Id from the first drop down menu, i want the second drop down menu to populate itself with the courses held in the database for the given users Id. I would like the first drop down menu to be populated from the database with a query similar to 'SELECT id FROM students'.
View Replies !
Populating Dropdown Menu From Db
Okay, I am trying to populate a drop down menu with items from a table in my db. I have a table called "teacher" which has the following info: I use the following code to grab the info from the teacher table. Code:
View Replies !
Populating Select Boxes
I'm creating a data entry system using php/mysql that includes the standard add/update/delete forms in PHP with a MySQL backend. On the update pages I'm trying to fill the select boxes (that come from other tables) with the values in those other tables, yet defaulting the selection in each of those select boxes to the value currently stored in the main table which is being updated. For example, the main table is called 'dates' and a related table is called 'department'. So one of the select boxes should have all the various departments listed in the select box but the currently selected value should be whatever is in the department field in the 'dates' table for the record the user is trying to update. Code:
View Replies !
Populating Drop Down From MySQL
I am trying to populate a drop down menu of MySQL data using PHP and I have hit a snag. I think its probably something simple that a freah pair of eyes could pick out right away that I am just not seeing... For some reason only the "firstname" part of the data is populating in the drop down and I can't figure out why. When I try to make changes to the echo lines to correct this, nothing shows up including the "firstname" data. Code:
View Replies !
Populating Drop Down Menu
I use the following code snippet to build a drop down menu with the results of a query. How can I set the initial value of this input based on the result of another query? What I am trying to do is update records in the data base. The field WkEndDate is pulled along with the rest of the record and the drop down menu is built from a table of valid WkEndDate values. Code:
View Replies !
Populating <options> Tag With SQL Data?
I have a problem that I cannot seem to figure out. If any of you have an answer or suggestion, I would appreciate it. My HTML/PHP code needs to pull options from a database to populate the <optionstag for a drop down menu and I cannot get it to work. Basically, there is a form on the website with a drop down box. I need the options in this box to be pulled from a preexisting table in a database. That's all. Sounds very simple but I'm totally lost on how to accomplish it.
View Replies !
Populating Multiple Rows
This is a very beginner's question. I have a mySQL database with 100 rows. I just created a new field (subjectID). All the rows in this new field will have the same data, the number "3". Would somebody please inform me on the command to insert this data in all the rows at the same time.
View Replies !
Populating Table Data
I am trying to dynamically generate bgcolors with to help populate some information for a site. Here is the code snipets; Code: function addColor($data){ $this->color1 = "#ff0000"; $this->color2 = "#00ff00"; $this->color3 = "#0000ff"; $this->color4 = "#ffff00"; $this->color5 = "#ff00ff"; $this->color6 = "#f3e3d3"; $this->color7 = "#11ee33"; $this->color8 = "#ab55e1"; $this->color9 = "#12c522"; $this->color10 = "#f033a9"; $this->color11 = "#44e2f1"; $this->color12 = "#3af422"; ...
View Replies !
Populating Drop Down Fields
I am trying to populate a drop down menu with a mysql database. I was hoping to have a selection of months in the dropdown menu, based on date fields in my database when a user then selects a month, they will be brought to a new page that will have only the records created in that month. But in my database, the date is stored in this format: 2006-05-12 00:00:00 if you need to see my code, here it is: <? //database connection $query = mysql_query("SELECT * FROM casinocredit"); // start to print out the form echo "<form action="cats.php" method="POST"><select name="clients"><option value="" "selected">Select A Client</option>"; // loop through the records while ($row = mysql_fetch_array($query)) { echo "<option value="{$row['ID']}">{$row['ddate']}</option>"; }.........
View Replies !
Populating A List Dynamicly
Is there an easy way to populate a list dynamicly? It stinks javascript here, but I don't know how to do it with that either. I have one list A that contains enteries with ID's as values. List B should then fill with information from a database according to wich ID is choosen in list A. Since alot of otherthings is entered on the page to I would like to nopt have to deal with sending all the data and loading the same page again. Is there a way in PHP to link to the same page and have all the filled textfields stay as they were? Or do I have to use post? I have the thought of loading all the data from the database and having it in an array or something and having a javascript picking and writing the choosen ones to the list. But that would be alot of excess data so getting it "live" from the db would be better.
View Replies !
MySql Menu Populating
My goal is to use a Drop Down Menu that is populated by the database. The user is then able to select a name from the Menu that pulls all of the information for a particular person from the database. Finally, a table is populated with the information of the selected person.
View Replies !
Reading Directories, Populating Select Box
Can anybody tell me how to read through a directory, get the file names and populate a select box(pulldown menu) with these names? I know how to loop through a directory using something like this: while ($files = readdir($handle)) { $ext=substr($file,-4); if ($files != "." && $files != ".." && $ext == ".php") { do some wild and crazy stuff here; } } It's the populating the select box (pulldown menu) while doing this that I need the help on.
View Replies !
Populating Form Item From SQL Enum Set Rev#2
$sql = "SHOW COLUMNS FROM table LIKE 'subject' "; $qry = mysql_query($sql) or die("Query not valid: " . mysql_error()); $res = mysql_fetch_object($qry); // This returns a row with a field 'Type' containing 'enum(...)' $res->Type = str_replace('enum('', '', $res->Type); $res->Type = str_replace('')', '', $res->Type); //now the string is something like this: one','two','three $temp = explode('','',$res->Type); //temp is an array with as much elements as the enum while ($temp) print array_pop($temp); This way is much more easier using the elements since they are elements of an array. Cleaver isn't it?
View Replies !
Populating Array With Mysql Results
I'm returning a result set of one field in a table, and want to populate an array with the results. I can't for the life of me figure out a simple way to do this without using mysql_fetch_array() to cycle through the results, append that to a var, then explode that into a var and pass that. PHP Code:
View Replies !
Populating A Form Wth Database Info
I've coded a piece of code which populates a form with data read from the database: $connection=mysql_connec ("localhost", "f2821842", "f2821842"); $result=mysql_select_db("QUERIES"); $query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'"); while($row=mysql_fetch_array($query)) {$empname=$row['emp_name'];} <form name="webregform" action="webadmin2.php" method="post"> <input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>"> </form> When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?
View Replies !
Populating Dynamically Generated TextFields
If one assigns something to the value iattribute off an input /text field, that value will be displayed when the form is loaded. My problem is, when building a form dynamically, the only way I can get the text to show is by doing the above, however, as this is an update form, when the form POSTS to processUpdate.php, both the data entered by the user AND the data in the value attribute are inserted/updated. So, how does one dynamically build a form where the data is displayed in the text fields but value atttribute is not set. PHP Code:
View Replies !
Populating Form Fields With Variables
The script itself works fine: mail gets sent. If there are any missing fields the form displays again with a list of the missing fields, but I can't get the form fields of the reloaded form to be populated with teh existing values. PHP Code:
View Replies !
Populating Arrays From MySQL Query
I have the following code: http://pastebin.com/746601 The field 'material' in 'is_material' contains multiple values for each record in 'is_details'. Because of this I have used 'is_material_lookup' as a reference lookup table containing the 'style_code' and 'material_code' which refer to their full details in the respective tables. Currently I have got the script outputting all the details and one material then in the next block of data, repeating the details with a different material. What I would like to achieve is having 1 block of data with a list of all materials in that, instead of the repeat, but sadly I can't know exactly how to do it.
View Replies !
|
TRACKER
