Get The Todays Date- Yesterdays Date And Tomorrows Date
I get the todays date- yesterdays date and tomorrows date, like so:
$yesterday = date ("Y-m-d", mktime (0,0,0,date("m"),(date("d")-1),date("Y")));
$tomorrow = date ("Y-m-d", mktime (0,0,0,date("m"),(date("d")+1),date("Y")));
$actualdate = date("Y-m-d");
Which returns the date in the format "200-11-13" But I need to add 13 hours to all three - how owuld I do this?
View Complete Forum Thread with Replies
Related Forum Messages:
Tomorrows Date
I've got a link on my site which I click to bring up todays jobs. Its made up like this. PHP Code: $todaysDATE = date("d/m/Y"); The $todaysDATE is then put in my URL which I click to give me the jobs that are for today. This all works ok. What I'm trying to do is make another string. PHP Code: $tomorrowsDATE = ???? How would I do this?
View Replies !
How To Get Todays Date
I have an application where I need to get todays date - preferably in Julian format. I have seen a function CAL_JULIAN but I can't figure out how to get it to work. I am aware that there are many java scripts out there to get dates but I get I am looking for something in PHP.
View Replies !
Todays Date NOW() Function
I simply want to add todays date when inserting into MYSQL. $query = "insert INTO home_page (title, content, date) "; $query = $query . " VALUES ('$title',$content, NOW()) "; I keep getting the error: Call to undefined function showerror().
View Replies !
Drop Down Menu With Todays Date
What is the best way to add a drop down menu to generate the below html <br> <select name="date"> <selected><option value="20-11-2007">20-11-2007</option></selected> <option value="21-11-2007">21-11-2007</option> <option value="22-11-2007">22-11-2007</option> <option value="23-11-2007">23-11-2007</option> <option value="24-11-2007">24-11-2007</option> <option value="25-11-2007">25-11-2007</option> <option value="26-11-2007">26-11-2007</option> <option value="27-11-2007">27-11-2007</option> <option value="28-11-2007">28-11-2007</option> <option value="29-11-2007">29-11-2007</option> <option value="30-11-2007">30-11-2007</option> </select> DD-MM-YYYY<br>
View Replies !
Take Todays Date, Compare It With The Dates Held In The Db
I have a db which has a field called 'date' and is set to date type. I want to be able to take todays date, compare it with the dates held in the db and print out the record with the next date in it. Say today's date is 20/09/06, the record with the next date, say 23/09/06, should be printed out. How can I do this easily. I am very new to this, and can't seem to get it right.
View Replies !
Select Query To Get Only Todays Date Records
I want to use the following query to show only users who registered today with todays date.format(m/d/y)field name is: a.date_registration select a.id, a.fname, a.sname, a.status, a.login, a.login_count, b.lang_1 as gender, a.email from pro_user a left join pro_reference_lang_spr b on b.table_key=཈' and b.id_reference=a.gender where a.date_registration = (Todays Date m/d/y) order by a.login limit 0, 10 0, 10
View Replies !
Check Date From Input Must Greater Or Equal Today Date?
I have 3 select box. Code: <select name="day"> <option value="1">1</option> <option value="2">2</option> ....... <option value="31">31</option> </select> <select name="month"> <option value="01"> Jan </option> <option value="02"> Feb </option> ..... </select> <select name="year"> <option value="2002">2002 </option> <option value="2003">2003</option> </select> When I select and click submit in form. I will have 3 variable : $day, $month and $year How can I check the day that I choose in form must equal or greater than today date? If it less than today date. I must print error message to user.
View Replies !
Date Is Not Being Pulled From MYSQL Database, Instead Current Date Is Displayed!
I am having trouble pulling a date from a database using PHP at the <a href="http://www.mytuneslive.com/ameshkin69/"> following page.</a> Here is the code. As you can see, it is just making the date the current time. The values in the database are UNIX timestamp, and the DATE() function is used to convert from UNIX to readable date. Can <td width="55%" align="left" valign="top"><?php $row_comment['timestamp'] = date("n d Y g:i A");.....
View Replies !
Date() Question - Minus One Day Of The Return Date Choose By User
I have a date function, that gets today's date. Then my user can choose a date for the return date. I need to minus one day of the return date for a date_flag , but having trouble. PHP Code: <? $date_book = date("Y-m-d H:i:s"); $date_return = $_POST['date_return']; //Returns a date like this 2007-05-25                          // needs to be date_return - 1 day like 2007-05-24 $date_flag  = mktime(date("Y", $date_return), date("m", $date_return), date("d", $date_return)-1); ?>
View Replies !
Store Date In A Date Field In My MYSQL Data Table
I have a form with a feild that when clicked on pops up a calendar which I can select a date I wnat to insert into the field. The date inserted displays "03 Apr, 2007". I want to store that date in a date field in my MYSQL data table, a field named "f_date" set to date type. When I save the record the data field "f_date" displays "0000-00-00" which I take it the date input is not getting inserted to the table. My insert field code is PHP Code: <input name="f_date"Â Â type="text" class="bodytext" id="f_date" onclick='scwShow(this,this);' value="" size="15" />
View Replies !
Read Today's Date Print Tomorrow's Date
I've got a small script that writes a random number and the date to a text file. Then the script opens this text file and if date = date from this text file something must happen. If something happened this script must open this text file again and replace it with a new random number and tomorrow's date. <?php $date = date("d-m-Y"); mt_srand((double)microtime()*10000000000); $num=mt_rand(0, 20); if ($num == $num && $date == "$tomorrowdate") { echo"$num -- $date";} else echo " ";?> So if the script gets activated on the 05-05-2003 it must write tomorrow's date into the text file (06-05-2003). How will I get tomorrow's date today?
View Replies !
Date Validation - Date In String Format
i have got an date in string format ddmmyyyy (eg: 15052007).i have to validate this date. i have alrady validate this date for a number. now all i have to do is check the day (dd) against month (mm). example, 29 feb is invalid date, if not a leap year.i have tried to wrote some bit of code but still struggling with it.
View Replies !
Save Date To Table Field Date Type
I have a calendar picker on a form that fills a text box with XX/XX/XXXX date format. If I run a insert statement the date field in the database shows 0000-00-00. If i change the field type to varchar the correct format displays. What is the correct way to save a date to a mysql database? Furthermore to query on the date how about a select * from db_name where servicedate >= $startdate and servicedate >= $enddate I supose this will not work Any pointers?
View Replies !
Date Dropdown From Mysql Date Entries
For the PHP gurus out there, here is what I want to do: create a dropdown list of available dates from a mysql database date entries. But the dropdown/s should have 3 separate fields in month, day and year which in effect shows only those months, days and years that have corresponding entries from the database. Planning to use this in the archive section of an online news publication so people can select issues to view via dropdown list that have corresponding entries only.
View Replies !
Start Date - End Date = Number Of Days
I have a starting date for var 1 and today’s date for var 2. I need to calculate how many days are between those two dates. 02/24/03(today) - 01/14/2002(start date) = number of days. In theory this is easy but there are many instances were I could get an inaccurate answer. For example one consideration is that some months have 30 days others have 31. exc. My question is, is there an easier way to solve this problem other than using endless if statments to error handle all possible instances? Does PHP4 have any built in functions that could calculate this formula correctly?
View Replies !
UNIX Mktime To MySQL Date Or Date
A form that sends a starting date and an ending date. I have figured out how to tell the difference between the two and even rip the difference into an array because I need to compare the individual dates against a mySQL database to pull results from a particular date in a series. This is no problem. My problem is that teh mySQL database uses DATE as a field definition and this can not be changed. I managed to pull the date differences using some cleaver mktime stuff but no I do not know how to get this 1072242000 into this 2003-12-24... Is there a function that reverses the mktime result into a usable date format? I would take anything at this point and I can explode and then array it to get what I want - but there has to be something. Code:
View Replies !
Counting Days From $date To Current Date
how to count the time between two variable dates? Such as someone inputting 6/8/1991 in a form and it comparing that to todays date... then getting the number of seconds elapsed... I know I have to use the mktime() function to get the seconds.. but not quite sure how.
View Replies !
Date Comparison - Checks If A Date Is In Between Two Other Dates
I'm having trouble writing a program that checks if a date is in between two other dates or not. $today = date("d-m-y"); $a = "09-09-06"; //September 9th, 2006 $c = "09-09-09"; //September 9th, 2009 if($a <= $today && $today<$c){ echo "Wee";} else{ echo "Wrong";} When I try outputting this, it outputs always outputs "Wrong" for some reason, although $today is clearly inbetween $a and $c (Sept.09'06 and Sept.09'09). Am I doing something wrong?
View Replies !
Compare Date Of Today And The Date In The Database
i have a db that stores a date in a table with a specific column. db=test table=test_date_compare column name=date_inserted ok i hv a php form that allows user to input date and it enters in the above column (date) as in format eg: 21/03/2007 now i wat i would like to do is i would like to compare date of today and the date in the database if it is lesser then todays date it deletes that row of data. deleting the row of data i know how but the problem comes wen coparing the date i dunno how to ...
View Replies !
Convert Date To A MySQL Acceptable Date
I've got a date that looks like this: 06/08/2007 AM I'm trying to convert it to a MySQL acceptable date so it can be inserted into the data and read as normal MySQL dates would read so I can use my date searching functions. I use a lot of -30 days searches and stuff like that. As I insert the records into the database (which come in from a .csv file) the "SCHEDULED_DATE" looks like that above but that, as we all know, won't work with things like 'SCHEDULED_DATE > $onemonth' ($onemonth being a date that is a month ago). So while the records are imported I have been trying to take that date and convert it into a usable MySQL date. Although my attempts have completely failed. Here is one of the newest things I have used, which didn't work and I really don't know why. Code:
View Replies !
Convert Input Date To Mysql Date
Wanted to see if there was a cleaner way to do this. My form takes a user-input date in the format MM/DD/YYYY. I need to convert that to YYYY-MM-DD to query against my database. The code below works, but basically I take input dates convert them to a UNIX timestamp with strtotime() and then convert them back to the format I need using strftime() PHP Code: $format = '%Y-%m-%d' $startDate =Â Â strtotime($startDate); $startDate = strftime($format, $startDate); $endDate =Â Â strtotime($endDate); $endDate = strftime($format, $endDate);
View Replies !
Convert The Date Separator Before Inserting The Date Into The DB
I need to convert the date separator before inserting the date into the DB. Right now, I have 01/01/2006 and I want 01-01-2006. The dates are coming from a CSV and so are an array element. I've tried strrpos and a few other functions trying to just replace the slashes with hypens and that's not working (I think maybe because it's an array and those functions don't work on arrays?) Could someone post example code for something like this? I have an array called $items[3] that holds the date with the separator mentioned above. I'm sure there are several ways to do it in both php and with mysql functions but I've been stuck on it for a while and REALLY need to get through this for a project I'm working on right now.
View Replies !
Converting Database Date To Normal Date
I am looking for a way to convert a date that is stored in a MySQL database like this after useing the date() function in PHP: 2006-08-16 21:03:54 and convert it into a date this: 16 August 2006 @ 11:03:54pm Does anyone have some insight as to how I would go about doing that?
View Replies !
Unix Date Stamp Convert To UK Date
How do I go about converting the Unix date stamp to UK date/month/year. I know how to get the date from the database, I just need to know how I can convert this date using a php script to convert this to UK date format and display on my php page.
View Replies !
How To Convert Uk Date To Mysql Date Format
how to convert uk date to mysql date format? I have 3 textboxes having the values of dates. the format are the following: textbox1-29/08/2007 textbox2-14/08/2007 textbox3-20/08/2007 upon entering it into the database the following dates should be converted already to the mysql date format like 2007-08-29
View Replies !
Begin Date And End Date, But No Weekends!
I am making a system to plan my work days. If i begin on a project on 01-10-2007, and the project is 100 hour and i work 10 hours a day, it will cost 10 days for me too work. The answer is simple, project is done @ 10-10-2007, but i dont work in the weekend. So it must be 12-10-2007, i got the following script;, but it aint working right. Because when the begin date and end date is more then 2 weeks, and more than 2 weekends, it doenst count the weekends good. Can someone help me, or is there somebody with a better solution? I am working two days on it, but i cant get it right <?php $begin_date = strtotime( date( '2007-10-01' ) ); $hours = 100; $workdays = 10; $total_days = $hours / $workdays; $total_days *= (60 * 60 * 24); $weekend = $total_days / 7 * 2; $enddate = $begin_date + $total_days + $weekend; if( date('D', $enddate ) == 'Sat' ) { echo 'End date <b>' . date('d-m-Y', $enddate + (2*86400)) . '</b> 2 days<br /><br />'; } elseif( date('D', $enddate ) == 'Sun' ) { echo 'End date <b>' . date('d-m-Y', $enddate + (1*86400)) . '</b> 1 day<br /><br />'; } else { echo 'End date <b>' . date('d-m-Y', $enddate) . '</b><br /><br />'; } ?>
View Replies !
Date Conversions ( Date, Mktime )
I have a date in three pieces dd mm yyyy. I'm just wondering the best way to convert this for inserting into a DATETIME field and then back again when displaying it. I have tried date, strtotime mktime but it keeps inserting a blank date. i.e. 00:00:00 00:00... I've been looking through the php manual but I can't seem to get this working. Also would I be better off using the UNIX_TIMESTAMP function?
View Replies !
Display The Date As A Real Date Xx/xx/xx
Basically im putting a join date into the database but i don't want it displayed as a date, i want it as pure numbers so that i can use it to work out things such as how long they've been a member, comments per day (by dividing the posts by how many days they've been a member) ect ect So whats the best way of putting that into the database? I have a vBulletin forum and looked in the database at what they had for the join date and i saw stuff like 112823... is that seconds or something? I also need to display the date as a real date xx/xx/xx so that must be possible aswell.
View Replies !
Re-arranging The Date Without Time() Or Date?
I have dates logged in a MySQL table of when people are logged in in my site, the date gets entered into the table like so: 2007-01-17 19:18:58, i am using MX Kollection for Dreamweaver to create the site so I cant really change the fields to integar and use the time() function as it comes built with the extension Code:
View Replies !
Order By Date When Date Not A Timestamp
I have a database of items with 2 fields, LogDate and LogTime. I would like to be able to display these items ordered newest to oldest. LogDate is a VarChar(11) and the format of the data is always DD-MMM-YYYY (30-AUG-2006) LogTime is a VarChar(7) and the format is always HH:MMAP (02:47pm) How can I order my SQL to sort by those 2 fields as if they were real dates?
View Replies !
Search Between Start Date And End Date
Here is the sql query string. WHERE (`work_orders`.`date_closed` > $ > $start_date) AND (`work_orders`.`date_closed` < $end_date) ORDER BY (`work_orders`.`date_closed`)"; The dates are in the 2005-05-16 format already. A typical start_date might be: 2005-05-11 with end_date of 2005-05-16. I get no results returned even though there are records that meet that criteria.
View Replies !
Change The Date To The Current Date
Using the code below I want to change the date to the current date if the post variable is equal to Prospect, but the date is changed to the current date no matter what is in the post variable. Is there something wrong with the code that I don't see? if ($_POST['status'] = 'Prospect') { $query = ("UPDATE cust Set status = '$status', regdate = curdate() WHERE id = '$id'"); $result = mysql_query($query) or die ("Could not Update"); } else { $query = ("UPDATE cust Set status = '$status' WHERE id = '$id'"); $result = mysql_query($query) or die ("Could not Update"); }
View Replies !
|
TRACKER
