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How I Can Make A List That Acts Like A Html Jump Menu?


how I can make a list that acts like a html jump menu (for a regular list I have to use a "Go" button in order to achieve the desired behaviour and jump menus I cannot use because they work only with links to other pages).

For example,I want such a list filled with questions from my db and when I select one I want to see its possible answers; the page stays the same, only its data differs based on the selection. Or you can have a look at such a jump menu on this website, the one with options for geting to various sections of the forum.




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Related Forum Messages:
Script That Is A Bit Like A Jump Menu But Without The Pull Down List.
I am looking for a script that is a bit like a jump menu but without the pull down list. I want users to be able to enter a post code (4 digits) and then be redirected to a web page based on that post code as each web page is different per code.

the jump menu provided in dreamweaver is almost there but as there are thousands of codes it is impractical to have them drop down.

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HTML 'list/menu' And PHP/mysql
tell me the correct syntax to use for assigning the selected option from a pick-list before inserting to a mysql database? I am trying to give the visitor the option of some 20-30 categories from a pick-list and then I want to store the selected category in a field (called 'cat') in my mysql table.

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Using Jump Menu
I am using a jump menu to select multiple drop down boxes in a form which are related to the choice you make in the first drop down box.  The problem is that the page reloads and everything before this tag is cleared.  I want to be able to repost the data.  I know that I need to use sessions in my code but I dont know exactly how to use them for this case. Code:

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Jump Menu
<select name="menu1" onChange="MM_jumpMenu('parent',this,0)">
<option value="www.site1.com">google</option>
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<option value="www.site3.com">mynet</option>
<option value="www.site4.com">asa</option>
</select>

above code ; i want to get the selected value and post as named $url into a php code.
How can i call the selected value?

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Jump Menu Selected Value
I have a set of 2 menus where the values of the 2nd are dependent on the value selected in the first. Yes, I will (eventually) convert this to a javascript process, but for now I am content reloading the page.

I have created a jumpmenu that reloads the page with the state passed in the url (ie. community.php?state=NY). This determines the values displayed in a second (dependent) menu which then lists the counties available for that state. Code:

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Dynamic Jump Menu
I'm looking to create a dynamic jump menu/list menu that will enable me to navigate to a particular record by selecting a value from the list, however the list is dynamically generated from the recordset. Code:

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Header - Jump Menu Does Nothing In IE
I have a php header and php footer that are being called into my content pages. In the php header, I have a jump to menu system. The jump to menu works great in Firefox, however, the jump menu does nothing in IE. Have any of you experienced problems with jump to menues in php headers and whatnot?

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Jump Menu Call Page
Is it possible to use a jump menu to call a page within a page? To be clearer. I can place an " include ('whatever.php'); " within my page which is fine. But i would like this include to be a variable set by the options within a jump menu. So when I select from the menu the include will swap from its default to the newly selected one. Am I making sense?

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How To Create A Jump-menu Using Dreamweaver?
I have 50 names and links I need to show up alphabetically in a jump-menu. I'm pretty green with php and databases. Is there a quick and easy way to accomplish this? I know how to create a jump-menu using Dreamweaver, but how would I set it to read the text file.

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Chain Menu But The Menu Should Be Multiple Select Menu/list
I am looking for codes to be able to do the same thing with multiple select menu/list.

PHP codes or javascripts codes are both fine.

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How Can Strip The Text Bullet And Then Make That Copy An Unordered List In The HTML?
I have some text coming into a web page from a MySql DB that contains bullets in the copy. The copy cannot be changed as it is also used in a Quark Xpress document we have connected to the DB. So, my question is how can strip the text bullet and then make that copy an Unordered list in the HTML?

This is what I have but and does the indents like a list but no bullets (I guess they are being stripped by the str_replace as well?

echo str_replace(Chr(13), "<p>", ("<ul>".str_replace('•', '', $bulletcontent1)."</ul>"));

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Jump To Html Page
I am a php newbe and I am trying to figure out how to simply display an existing html page from my php script. Here is the code I use but I get the normal "output started" errors.

$sql = "INSERT INTO author SET
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lastname='$name2',
workphone='$workphone',
email='$email',
loginid='$loginid',
password='$password'";
if (@mysql_query($sql)) {
header("Location: formSubmit.htm"); <--------HERE

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List Contents Of A Folder, Make List Of Links
Does anyone know how I can write a script that:

- reads in all the files in a particular directory
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<ul>
<li><a href="filelocation1">filename 1</li>
<li><a href="filelocation2">filename 1</li>
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etc.?

So basically it creates a list of links with the contents in that directory,
so you can download them from there.

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PHP Acts Different On Ftp
I have tried the following code on localhost and it works perfectly but when I upload it to our ftp account (server) I got blank pages!! So is the problem with my code or is it the server? here is the code:

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How To Make A Nav Menu Drop Down In Php
i am interested in learning to make a drop down menu bar - the ones you hover the mouse over and a drop down list of choices (with an almost transparent bg) comes down. then when click it takes you to another page that has another sidebar which highlights the page you are in.

so on the side bar you can click and both the img on side bar and the menu bar will change so to indicate what section of the site you are in.

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Make A Dropdown-menu Filter?
I have a dropdown menu which is supposed to filter a table to show results for professionals, students or all. But I don't really know what I'm doing.  This is what I have so far. Code:

Initially, I was able to filter for students or professionals, but since trying to have an all option (students and professionals) it has gone to pot, and I keep getting errors.  I know that my quotation marks are not right, but I can't think of a solution. I would be more than happy to see any ideas, even if they are completely different to mine!

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If Is Possible To Make A Dynamic Menu In PHP5.
I want ask if is possible to make a dynamic menu in PHP5. like in JavaScript.

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List/menu
im using this to create a list/menu that takes the values from my database. Code:

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Array Driven Menu - Make Sticky
I have an array that holds the values of US States. I have populated a drop down menu using the array (which works fine), and want to make the menu hold the selected value when the page is processed. Code:

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How Can I Make A Drop Down Menu That Are Dynamiclly Generated
How can i make a drop down menu that are dynamiclly generated base on
the value selected in another drop down menu?

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Echoing Value To List Menu
Hi, I was wondering can I echo out value from db to list menu and how?

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List Menu Choices?
Why does Multiple Choice List only report 1 value? i got a normal form: Code:

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Can You Read A Value Into A List Menu?
a system i am developing has both a user and an admin side. The user can add a record and then the status of this is initially set to a fixed value.

What I am wondering is, if i stick with a list of say 4 possible status', how can i get whatever status the admin changes the record to to be "sticky" on the menu the next time he looks at the call, as opposed to the menu showing the default value set in dreamweaver?

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Drop Down List Menu.
How do I make one item required on my "drop down" list menu? E.g., let's say that I want one state to be selected, how do I make this possible with PHP? My PHP skill is amature, but I do understand most.

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Cannot Get List To Stay In Menu
I am using 2 drop down menus which pull their options from a database. Once the user selects a language and then a product a list of available pdf's are displayed.

However the form resets it self. How can I set this up so the products for the language selected stays. I was thinking about using a session but im not sure how to go about that when dealing with pulling data from MySQL Code:

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Mysql List Menu
how can I modify this code to list queries in alphabetical order and eliminate duplicate names.

<?php
mysql_connect("localhost", "xxx_xx", "xxxx") or die(mysql_error());
mysql_select_db("xxxx_xx") or die(mysql_error());
$query="SELECT Bloom_Name FROM ihs";
$result = mysql_query($query);

echo '<select name="ihs">'
while($nt=mysql_fetch_array($result)){ //Array or records stored in $nt
echo '<option value="' . $nt['id'] . '">' . $nt['Bloom_Name'] . '</option>'
/* Option values are added by looping through the array */
}
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?>

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A Form Menu List
I have a date of birth script on my website and at the moment im faced with typing in about 100 dates ranging from 1900 to 2006 is their any way i could use php to create the range of dates in a form menu list?

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Make Menu Items Visible Different User Groups
I have created a humble CMS sort of thing where I have users logging in and out. And there is of course me, the admin. I am working on a menu system where I first create menus and then add menu items into them. Code:

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Select List/Menu Using PHP And MYSQL
Here is my code:

<select name="country" class="sidelinks">
<?php
do
{
?>
<option value="<?php echo $row_AllCountries['country_ID']." ";?>"<?php if ($row_AllCountries['country_ID'] = $acountry) { echo "selected"; }?> >
<?php echo $row_AllCountries['countryname'];?></option>
<?php
}
while ($row_AllCountries = mysql_fetch_assoc($AllCountries));
?>
</select>

A few words to describe:
-$row_AllCountries['country_ID'](get from MySQL) is a unique country ID number
-$row_AllCountries['countryname'](get from MySQL) is the name of the country
-$acountry is the country ID number that i want to be selected when the form loads

I have all the values and country names named OK...the only problem is that when the form loads it selects the last country.

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Adding Items To A List Or Menu
Not sure if it is a php question but since i am working in php here it is.

Ho can i add items to (the item label=visual text and the value=index
number) a list object on a website.

I am having a list with 4 items and i would like to add the text from a
textfield (textfield1.value) to the list object so it will hold 5 items.

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PHP / Javascript Menu List Population
I would like a web page to have 2 menu lists

The contents of the second menu list depending on the selection made in
the first.

The contents of the second would be populated from a database.

I am fairly new to programming using PHP, Javascript and MySQL but I am
sure what I am asking has been done before. Could someone please give
me some pointers or direct me to a tutorial.

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Trying To Create Dropdown Menu From List
I am trying to create a dynamic dropdown select menu from a directory containing other directories and files. This is to select a certain page from the list so I can edit it. I only want the files in the menu. Here's what I have so far but it doesn't populate the dropdown. Code:

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Calendar Type List/menu
how do i do 3 list type menu one with the 12 months next with the days in that month and  the year. so want i want is when people select a month the next list show the days as soon the pick the month.

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Ordering A Drop-down Menu List
I am building a form that has a list/menu populating from the database. I'm using Dreamweaver to help code (which I know adds a mess), but I can usually edit it to do what I want. this is what it has:

<option value="<?php echo $row_rsPhysician['specialtyID']?>"<?php if (!(strcmp($row_rsPhysician['specialtyID'], $row_rsPhysician['specialtyID']))) {echo "SELECTED";} ?>><?php echo $row_rsPhysician['specialtyName']?></option>
<?php
} while ($row_rsPhysician = mysql_fetch_assoc($rsPhysician));
$rows = mysql_num_rows($rsPhysician);
if($rows > 0) {
mysql_data_seek($rsPhysician, 0);
$row_rsPhysician = mysql_fetch_assoc($rsPhysician);
}
?>

although if you have any generic code, I can play with it to get it to alphabetize my list. (the list is specialtyName and specialtyID is going into the database.

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Populating A List/menu From MySQL
is there a way to populate a list, or a menu form using php, and MySQL? Basically i have a list, and i am planing to import 2 variables, id, and name, bouth id and name are variables loaded from MySQL (yes there are multiple id's, and name's) Name would be the label displayed, and the value would be id. Thats what i need. After that i will make a submit button, witch will post the selected id to a different file. How can i achive this? Does anyone hae any samples maybe?

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Array List Menu Problems
I am trying to store values from a List Menu into an sql database table as an ARRAY. However, when I select the multiple values from the form, it only stores the selected values as 'Array' in the SQL table. Here is the Select Statement:

<select name="NOTES[]" size="9" multiple="multiple" id="NOTES">
<?php
do {
?>
<option value="<?php echo $row_literarydevices['LDEVICE']?>"<?php if (!(strcmp($row_literarydevices['LDEVICE'], $row_Recordset1['NOTES']))) {echo "selected="selected"";} ?>><?php echo $row_literarydevices['LDEVICE']?></option>
<?php
} while ($row_literarydevices = mysql_fetch_assoc($literarydevices));
$rows = mysql_num_rows($literarydevices);
if($rows > 0) {
mysql_data_seek($literarydevices, 0);
$row_literarydevices = mysql_fetch_assoc($literarydevices);
}
?>
</select>

Can anyone offer a reason to why the values are not being stored?

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Default Menu/List Option
I'm trying to create a form with three menus, each with the same values, and I have no problems there. Each menu has it's initial value set at "None" and then the rest of the values are pulled from my MySQL db. Everything works great if the user selects three values that came from the database or selects something from the first menu but not the other two and then submits. The problem is when the user doesn't select anything from the first menu.

The next page reads the form value as "" instead of "None" but only for the first menu. The other three menus work fine. I know this isn't really php related, but this is usually such a helpful forum that I thought I'd post here before I start to search for some helpful html forum. Answers would be greatly appreciated, but so would corrections for my terminology (which I think I am confused about) or a good link to a place where I should be asking this question.

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Dynamically Populated List Menu
I have a DB with a field called county in a table called info. I want to populate the list menu below with the counties in the field county.

Would there be a way to get around the fact that there will be many entries with the same county and we want only 1 instance in the list menu? Code:

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Search With A Menu List Criteria
Now I try this, past all data bye get , and use the temp var with the query , but I don't have a good results... Code:

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Change List View To Dropdown Menu
Im working on a script that has to be change so a user can choose from a dropdown menu instead of a list that now is displayed.
Here is the part that is insert on the index page.

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Creating Simple Unordered List Menu From XML?
Does anyone have any examples or links to examples of generating a
simple unordered list menu with multiple levels from an XML file? We
are redesigning the navigation on our website and I was hoping to make
this as flexible as possible.


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Long Strings In List/menu Boxes
Is there a way to get a list/menu box to resize as the page is resized and
for any long string that is an item in the list to be spread over two or
more lines in the same way as text in a table does.

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Flat File List Style Menu
I'm trying to build a Menu Building out of flatfiling with a section to add new areas to it.  The idea behind it is to have a header for each section (as the top order list item) then each one below is a link of that category.

I already figured I'm buillding it with limits (20 items Max per heading) and that to do it I will simply have each Heading/links in it be a new row in the document.  example row Tips tips.php Tips on Php, file tips File Tips tips/files.php, etc etc

With the first item of each row being the Heading and each other being the ones under it My question is What delimiters should I use to seperate in the row (I need to separate each item by 1 delimiter and then in each row separate the href, alt, name)

Secondly for rewrtiign it should I simply write it so each time it rewrites the whole file or should  I try and do string replacing and do modify sorta deal.

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Form Validation :: List / Menu In Dreamweaver
Does anyone know anyway to put in additional php coding to validate list/menu in forms? I am currently using Dreamweaver, so I am using their Validation check in their Tags/Behaviour sections. I read in alot of places that this default function does not allow a validation check for list/menu. But I am wondering if anyone know of anyway to put in some additional coding so that it will allow it to validate the list/menu as well?

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Pull Down Menu Generating A List Off Another File
Is there a way I can make a pull down menu generating a list off another file of all the destination case coming from the file locations.php?

locations.php

switch ($destination){
case "Las Vegas":
echo "Bring an extra $500";
break;
case "Amsterdam":
echo "Bring an open mind";
break;
case "Egypt":
echo "Bring 15 bottles of SPF 50 Sunscreen";
break;
case "Tokyo":
echo "Bring lots of money";...........

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Stuck On Dropdown Menu List, Could Use Some Guidence
I have a form with some drop down list/menus. I do a check for ommissions and if found display a message to re-try. What I need is a way to show which options where chosen when the user submitted the form the first time.

If someone could show me how to do the first one, I'm sure it's the same process for the second one. Here's the code:

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Print Array In List/menu Form Object
how i print a full column array into a list/menu form object, so that the text links to their respective page.....it is basically for a list of interviews so you click on the band name and then goto the interview page.

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Make A List Of All Zones
I want to create a script where the surfer can chose their respective timezones, and then I´ll use the putenv function to display the correct time and date. I know there are timezone information on my freeBSD server at /usr/share/zoneinfo/, but I dont know how to convert that information into useful dropdown menus or lists.

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Is It Possible To Make This? (Online Signup List)
I'm trying to create an online signup list for jobs in a "restaurant" type thing.  I've got the part where I can get users to login, signup for certain jobs and when the list is full, they can't sign up anymore.  The problem I'm now having is, I now have to create the MySQL table and the php signup page for every day of the year. Is there an easier way to create this? 

What I was thinking was if it was possible to make one signup list and have a constant variable that changes ... actually I have no clue how to get around this.  Could anyone point me in the right direction?  or should I just create all the pages manually, it's possible and I'd have to do it because the project is kinda due soon -_-.

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How To Be Able To Make A Page Where You Click On A Game From A List
I am making a php arcade script and I need to know how to be able to make a page where you click on a game from a list (generated from a mysql database) then it takes you to a page that displays more data from a table (the game name, category, the code to display the game (thats in a row) and reviews, ect).

Understand all that. Basicly what I have is displaying a list of games from a database, displaying the code to make the game come up, but I need to be able to put the code that displays the game (and other things) on another page (the game page). So how to I do it?

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<?php
if ($handle = opendir('.')) {
while (false !== ($entry = readdir($handle))) {
if ($entry != "." && $entry != "..") {
echo "$entry
";
}
}
closedir($handle);
}
?>

to list the contents of a directory on my server. I need to change it to only show directories, make the lists into links, and I need it to list the directories vertically.

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Editing HTML Menu
I have a html menu as below.

<ul>
<li><a href="#">home</a></li>
<li><a href="#">about</a></li>
<li><a href="#">news</a></li>
</ul>

Should I use xml?

I would imaging setting up a form with the menu displayed. The user could then select to add/delete/update the menu and PHP would process this.

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