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How To Compare 2 Dates In Mysql As Mysql Treats Dates As String ?


I'm trying to compare two dates in MYSQL. But its not treating the dates as numbers, but as strings. I try using strtotime but that did not work.




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so i always use php for mydates stuff but i was reading on something and i saw that is better to user mysql to do dates comparison for my queries. but how do i do this kind of search


<?php

$month=date("m");

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Then I do my insert into my table.

Any ideas what I'm doing wrong?

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When I do the query to the Mysql database, it displays the date of the first movement of the calendar, and this is wrong, because it suppose to display the later date of the movement.

Here is the code, to explain myself more:

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I am trying to do select all of the records in a table where they data
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I am getting all of the records returned when I execute:

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What am I missing? Can anyone recommend a good site to look at that
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I need to convert a MySQL date "2007-03-08", into "March 8th, 2007".
Normally I would use MySQL to accomplish this task but I have to use
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Here's my code:

echo date("F jS, Y", $row['date']);

But this returns "December 31st, 1969". I'm not sure what's going on
here.

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use the MySQL function date_format to format it before its returned but I
use a simply query (e.g. SELECT * FROM TABLE WHERE colum = '$somevalue') and
a while loop to read all the variables in, so I don't think I can format it
before its returned.

$date1 = "2005-04-12 20:45:54";
$date_array = explode("-", $date1);
$year = $date_array[0];
$month = $date_array[1];
$day = $date_array[2];
$day = $day[0].$day[1];
$ts = mktime(0,0,0,$month, $day, $year);
$dateVal = date("j-M-y", $ts);
echo "<br>Date is: ".$dateVal;

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What's the best way to translate a date into "Monday June 25, 2001" format that has been pulled from MySQL (the date format of which is "2001-06-25")? PHP date/time functions all seem to be based on UNIX timestamp (seconds since 1/1/1970), but the MySQL timestamp is YYYYMMDDHHMMSS.

I've tried translating the MySQL date when I select and retrieve data by using the "SELECT DATE_FORMAT(columnName)" syntax but this simply creates a new column - different from "columnName". Ideally, I could pull a date from MySQL as a formatted date so that I could set a variable in one operation or discover a PHP function to handle this. The bothersome task of writing my own is translating the YYYY-MM-DD format into daynames and monthnames.

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I can extract from a MYSQL database and view in a form text field a date in the following format d/m/y. I am using the Date type in MYSQL which requires the format 0000-00-00 (Y-m-d).

My question is once I have extracted and filtered the date to "display" as d/m/y why when I send it back to the database doesn't it send the the date back in the format that MYSQL prefers. Here is my code:

<td align=left bgcolor="#6495ed"><input type="text" name='payment_due(<?php echo $customer_details->AbsolutePosition()?>)' value='<?php echo FormatDate($customer_details->Value("payment_due"),"d/m/y") ?>

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I took over a website, and can't figure out how php calls get their date from the MySQL database date field, that is a varchar type.

Specifically, an example I'm looking at has field=date, type=varchar(14) in the structue, and the data for the date field is 1094284800. When I do a php call to this field using the following script echo "<b>". date("D. M. j", $events[$i]['date'])

it returns Sat. Sep. 4, which is correct. How does 1094284800 become this date? If I change it to 1094384800 it becomes Sun. Sep. 5. How is this possible, by simply changing one digit, and how can I change to other dates simply other than trial and error?

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$sql = "INSERT INTO `dogs` (`owner_id`, `callname`, `breed`, `sex`, `birthdate`, `height`, `accessid`, `accesstype`) VALUES ($oid, '$nm', '$brd', '$sex', '$dt2snd', '$ht', $aid, '$atyp')";
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what to do or where to 'read up'?

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Is there a quick and easy way to order dates stored in a MySQL db in the following format:

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Like maybe a MySQL data type or built-in function?

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This was working fine until it changed to a new month and now it's not ordering them in the correct order. ie anything with this months date is now appearing at the bottom when it should be most recent at the top of the results.

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This has been puzzelling me for a couple of weeks now, and just can't figure
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Does anyone know how to return an array of dates from MySQL given the start
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date', ie:

Start Date = 15/06/2004
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Array returned: 15/06/2004,16/06/2004,17/06/2004

Hope this make sense?... I would love to hear if anyone has done this before
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I need to say something like this: take begin_date and end_date, if begin_date == end_date, echo $begin_date

else if begin_date(month) is not equal to end_date month, echo begin_date_month-begin_date_day - end_date_month-end_date_day, end_date_year (like this January 28-February 3, 2006)

else if begin_date_month is equal to end_date month, echo begin_date_month-begin_date_day - end_date_day, end_date_year (like this January 28-30, 2006)

Here's the code I currently use to get the events from the database. Code:

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Is there a way to convert a date in this format:

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the 8-7-2002 is a field in which users pick a date from a pop-up calendar in javascript. When I enter that date into the database, i want to convert it to the MySQL date format.....is there a way to convert it?

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Can anyone tell me if this has been done before in a similar application I could look at or else point me in the right direction?

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http://i16.photobucket.com/albums/b14/aburnzi/formdatetime.jpg

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