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Mysql_fetch_array Error - Warning: 4 Is Not A MySQL Result Index


I have written a function to bulid a table of url links stored in MySQL. In my database I have two tables: tblLinkTypes and tblLinks. My Output should look like this:

Link Type1
Link Title2 URL2

Link Type2
Link Title1 URL1

However I get this error when the code gets to the bottom (see //errors here).
Warning: 4 is not a MySQL result index in /home/httpd/inc/dbWhiteWater.inc on line 275
Code:-




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How To Solve The Error: Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
I keep getting this:

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in ....... 

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im trying to access the 'update' time from my database by using the below code.

$result = mysql_query("SHOW TABLE STATUS FROM logtable;");
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The only problem is I get this error. What am I doing wrong??

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Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
Here is my script:

<?php

$dbh=mysql_connect("localhost", "my_username", "my_password") or die ('No can do!');
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Get this error message:
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Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result Resource
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home/xswapco/public_html/techsupport/account.php on line 41

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Warning Mysql_fetch_array(); Supplied Argument Is Not A Valid MySQL Result Resource?
i am getting the following error with this bit of code? Warning mysql_fetch_array(); supplied argument is not a valid MySQL result resource? Code:

<?php
/* Connect to database */

$extra = 'blah'
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Service Provider Problem: Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result
Strange one this, I have checked the forum and tried everything I can that is related and it still won't work.

I keep getting the following error on all my code:

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i got this message:

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for these lines of code:

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I'm trying to outtput records from a mysql table and I get an error here

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in

PHP Code:

<?php
$i = 0;
while ($result = mysql_fetch_array($query)) {
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Warning: Mysql_fetch_array(): Supplied Argument Is Not A Valid MySQL Result Resource In /home/szauerne/public_html/sites/yourcapecoral/wizard/listings.php On Line 364.
PHP Code:

$number = mysql_query("SELECT * $housesTable WHERE house_id='".$select."'");
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returns

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Error Message - 0 Is Not A MySQL Result Index
Could anyone explain what this might mean?

Warning: 0 is not a MySQL result index

I have a simple form set up where a user types in a keyword and then a page is displayed based on the keyword. See below:

HTML page:
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submitform.php3 page:
<?php
mysql_connect ("localhost", "username", "password");
mysql_select_db (dbname);
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The concept is really simple. A user types in an keyword and that page is displayed. There is a database set up with a table that has two columns. One is "keyword" and the other is "url" For example row 1 the keyword is abc, and the url is http://www.abc.com.

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While ($row = Mysql_fetch_array($result)) Error Suppression
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Mysql_fetch_array Result Type Error
I'm trying to run mysql_fetch_array with a variable in place of the
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About PHP::: Error/Problem PHP Warning: Mysql_fetch_array():
About PHP::: Error/Problem PHP Warning: mysql_fetch_array():
==================================================

In the past i use my code/script work fine with
Mandrake 9.1 - 10.1 ( + apache ,mysql )

Now i move to redhat EL4 with the same code/script

I got error can't login to my code.
and found error on /var/log/httpd/error_log like this

PHP Warning: mysql_num_rows(): supplied argument is not a valid MySQL
result resource in /var/www/html/website_in_server/showdata.php

or

PHP Warning: mysql_fetch_array(): supplied argument is not a valid
MySQL result resource in /var/www/html/website_in_server/showdata.php

I think problem source from php.ini or httpd.conf .

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I've got a problem with mysql_fetch_array function. I have two function:

function db_query($dbh,$qw)
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db_test($dbh);

$result = mysql_query($qw);

return $result;
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function db_insert($dbh,$table,$what,$info)
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db_test_table($dbh,$table);
$id=0;

$qw="insert into $table $what values $info";

$result = db_query($dbh, $qw);
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Then I have the following piece of code:

$result = db_insert($dbh, $table1, $what1, $info1);
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The db_insert call workes fine, 'cause a new record is inserted into the table. The problem is that when I call mysql_fetch_array I got the following error:

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Mysql_fetch_array(): Supplied Argument Is Not A Valid Mysql Result Resource
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mysql_fetch_array(): supplied argument is not a valid mysql result resource

it's returning a long text from the database which is about 200 characters long.

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Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
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even though if I echo the query to the browser and cut and paste it into the
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Do I have to store the first result in an array before doing the second set?

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$PIDresult = ("SELECT * from hours WHERE PID = '$thisPID'") or
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I'm running PHP/MySQL/Apache on my home system on Windows for testing purposes. As a run a specific query, I get this error:

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I'm getting this error:

Warning: MySQL: Unable to save result set in /www/hosts/wwwroot/mainPage.php on line 11

Here is what line 11 looks like:

$articles = mysql_query("select entryID from articles where siteID like 'senior'");

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<?
Warning: Supplied argument is not a valid MySQL result resource
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Warning: mysql_fetch_row(): supplied argument is not a valid MySQL
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I am building an aunction site but have an error on this line. The error is:

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I am trying to merge results from two tables, but this is something I haven't done so far, so manybe my mistake will look stupid to Pro's. I get the "Warning: mysql_fetch_array(): supplied agrument is not a valid MySQL resource".

Here is my code:

$result = mysql_query("SELECT * FROM az_mustseethis LEFT JOIN az_articles ON az_mustseethis.art_id = az_articles.art_id WHERE az_articles.category = 'Must See This' ORDER BY art_id DESC LIMIT $from, $max_results",$connect);

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Warning: Mysql_num_rows(): Supplied Argument Is Not A Valid MySQL Result Resource In *** On Line 9
I keep getting an error result saying:

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in *** on line 9

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my code:

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<?php
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so i try this:
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i get error warning cant connect to localhost.


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I get the following error:
Warning: Undefined index: 23232 in D:phpStatsdisplay_stats.php on line 6

however if I use the while loop to get the data from the form it works fine. Anyone know why this is happening?

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Mysql_fetch_array() Error - Php Code Error
I have the following error on my php code: PHP Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result.This is part of the PHP where the problem is and the message i get on the HTML page is something wrong in artistinfo table: Code:

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