PHP :: Place File Contents Into Table On Page

Grab Content From HTML Table And Place Into MySQL Table?
I am in the process of helping a co-worker upgrade some of his old static html pages into dynamic MySQL driven pages. He currently has a lot of pages with huge tables displaying data. Does anyone know if there is a script or class that can convert a table to a .sql file for upload?

Place The Results In Another Table
I am trying to take the results from a query and place the results in another table.
I want to take all the results from $row join them together. is this possible to do?
And can the results be stored with the information from the print statement? ( from each row) Code:

How To Place Formatted Text On The Php Page
I'm entering data through textarea, and I want to display the same data on the
form with all formatting settings. means, if I pressed enter while entering text in the textarea to make a separate line, the separate line has to come when displaying on the form also.

Adding Next And Prev Page To Code That Is Already In Place
I have code that I already had in place but my end user would like to have next page for the MYSQL display. I have read the doc that is posted on this site. Code:

Writing To A Specific Place In A File
I have a text file. I would like to write a line of data as the first
line and then another as the last line. What is the easiest way to do
this using php 4?

Place A Cookie File For Keywords
Webmaster are starting to place a cookie file for keywords with alt tags and link to their page. So everytime you see the words INTERNET it would be underlined and the link would be the webmaster site! Question is how do I stop this from happening?

Check Contents Of Mysql Table
ok, so now that I've figured out how to allow users to upload files (with help!) I'm trying to run a script that will check the name of the uploaded file and determine if that file name already exists in a specific mysql table. Here's what I've got so far:

$filename = $_FILES['uploadfile']['name'];

$query = "SELECT * FROM $table";
$result = mysql_query($query, $conn);

while ($checkfile = mysql_fetch_assoc($results)){
$existfile = $checkfile['filename'];
}//end while

if ($existfile == $filename){
print "A file with that name already exists.";
}
else {
some script that adds the file info to $table
}

Now, this combination of while and if statements will only catch a match with an already existing filename if the already existing filename was the last one to be updated. I've tried adding the if and else statements into the while statement but then the file info gets added to the table multiple times. Does anyone have any ideas? Am I even making any sense?

PhpMyAdmin Not Reading Table Contents
I'm running phpMyAdmin 2.5.3 / MySQL 4.0.14 / PHP 4.3.3 / Apache
1.3.20

phpMyAdmin is installed and appears ok at first, I can login, select
databases, view which tables are in each db, see the exact structure
of each table, but when I do anything that requires reading of the
table contents - browse / select / etc - nothing. If I try browsing a
table, the page gets rendered as far as the "Insert" tab along the
top, then nothing more. If I look at the source of the page it's
stopped after drawing the spacer td after the Insert tab.

I've checked the priviliges - seem fine. No PHP or MySQL errors occur
in any of the server logs. No errors are reported on the web page.

Inserting The Contents Of One Page Into Another
I want to put one php created page inside of another. page1.php PHP Code:
<?

Page Contents To Email
I have scripts that will email a link to the page but what I need is an email form that will allow someone to put an address in and when they click 'Send' on the form certain contents that have been passed to the page will be sent in the email.

Send Contents Of Page In Email
is there not an easy way to simply send the contents of a page in the
body of an email? i.e. i have a report.php that pulls from a mysql db.
i need to be able to send the displayed file right in the body of the
email. can anyone help with this?

Change The Web Page Contents On Click
I want to sort the data displayed on web page on click of button. I have a combo in which all user have to select the sort order in which he wants to see the data...(The combo box or drop down box contains values "Name, Department Salary and Grade")

The user select the order (say name) by clicking the combo box or drop down box. The moment the user releases the combo or drop down box, I want to refresh the page with new sort order.

Hide The Contents Of A Page Unless Redirected?
I have a website where I sell one downloadable product. Someone pays for it and then is redirected to the download page. Problem is they could just bookmark the url and go back and download it again all they want. Is there a way to prevent that from happening? Somehow set it up so the page only displays if they've been redirected from PayPal perhaps?

Download Protect Script Getting Contents Of Current Page
I'm half way through a custom built download protection script that does various things. However this is the bit that isn't working....

$name = 'file.txt'
$fulldownload = '/files/'.$name;

header('Content-Disposition: attachment; filename="'.$fulldownload.'"');
header('Cache-control: private');

Instead of linking straight to the file in questions it actually prints the current page (HTML) and puts it in the txt file to download.

Output Variable Contents In Htm File From Php File
I have a PHP file. No MYSQL database. I'd like to have it open an .htm file and output the results in the php file to the .htm template. So, for example say there is a bunch of variables called:

$make
$model
$year

I want to open a .htm file and output the contents of $make, $model & $year in the htm format using variables in the htm itself. ie. {make} {model} {year} and it would import the contents of each into the corresponding tag.

File Get Contents()
I need to verify, (working on the HTML section of a mailer), If in my php.ini: allow_url_fopen is On Will file_get_contents(file URL) called as follow:

$mailer->Body = str_replace('{MEMBER_NAME}', $member_name, file_get_content($htmlBody) );

Allows the file to become my email body? where $htmlBody comes from the DB...

Getting The Contents Of A File.
Is it possible to get the contents of a file; display the contents in a textbox; and edit the contents of that file. Then click a button and change the contents to the new updated file.

The reason I want to know this is because I have programmers on my site and I don't want them to have access to the FTP or cPanel. They will jus enter the name of the file, click submit, be able to edt and replace that file. All without FTP or cPanel.

File Put Contents
looking to write to a file with out overwriting the previous data? is there a way to turn overwrite off with the file put contents?? im trying to keep a log of form data.

File Get Contents
i am trying the example of get_file_contents but i get the following error.

what i want to do is get all the web page of google but the code wont work any ideas please cheers.

Warning: file_get_contents() expects at most 2 parameters, 5 given in

<?php
$content=file_get_contents("http://www.google.com",FALSE,NULL,0,20);
echo $content;
?>

Deleting Contents In File With PHP
Hi, I need to get to a specific part of the file and delete a line so i can overwrite it with a new value. Example ...

$Money = array(
0 => 10000,
1 => 932394,
2 => 3254#<Money>
);

I need to change first choice "0 => 10000" and replace it with "0 => 7500" so it seems like they spent 2500 moneys I dunno if its possible but if it is please help, and thanks in advance FYI, the file is called testfile.inc and i dunno what that .inc means :P I just got it from a script i downloaded Further more, i want to do this change/replace through a form or a click using PHP.

File Get Contents Issue.
In folder WWW i have text file named news.txt. I'm calling file_get_contents("news.txt"); form index.php in the same folder. I got error:

Warning: file_get_contents(news.txt): failed to open stream: No such file or directory in /home/www/index.php on line 14.

File Get Contents - Timeout
I Have googled and founds lots of references and examples of stream_set_timeout for fsockopen, but none showing how you apply a timeout to file_get_contents which I need to use in this case.

Can anyone give me a sample of how to set a timeout on file_get_contents, as I understand that it can be applied to all PHP streams?

This does not timeout after 2 seconds:

$url ="http://www.mydomain.com";
stream_set_timeout($contents, 2);
$contents = file_get_contents($url, false);
Print $contents;

File Get Contents() Error
I made a PHP5 script that uses the file_get_contents() funtion and when I run the script, I get this error:

Warning: file_get_contents() [function.file-get-contents]: URL file-access is disabled in the server configuration

I called my host up and they said that it is a coding error, not a security or server error,

Here is the code:

<?php
$address = "http://www.example.com";
echo htmlspecialchars(file_get_contents($address));
?>

Put Contents Of XML File Into An Array
I need some way to generate an array that holds the same structure and data of a xml file.

File Get Contents .limitation?
See this simple file_get_contents code

<?php
$link= 'http://www.example.com'
$content=file_get_contents($link);
echo $content;
?>

I tried the code with these links:

1. http://www.example.com (...worked OK. Also tried google.com, yahoo.com,... all OK.)

2. http://www.example.com/buy/chess (...$content captured an error page instead of the result)

3. http://www.example.com/chessmotifs (...$content returned nil, ... totally nothing. This is the one I need the code to work btw.)

Could this be because the site (in this case cafepress) uses some sort of scripts to generate their sub-pages? If yes, is there an alternatif method to "file_get_contents" that allows a page to generate fully before capturing?

Reading File Contents
I am parsing a file delimited by |. For some
reason the content is displayed to the browser properly - but the loop
is consistenlty outputting "one more row" of just the titles.
Perhaps I'm going about it completely wrong:

<?php

$filename = 'books.file'
$fp = fopen("$filename", "r");

while (!feof ($fp)) {
$contents[] = explode("|", fgets($fp, 4096));
}
fclose ($fp);
$loop=1;
foreach ($contents as $row) {
echo "$loop ------------------- ";
echo "Reviewer: $row[0] ";
echo "Date: $row[1] ";
echo "Title: $row[2] ";
echo "Author: $row[3] ";
echo "Rating: $row[4] ";
echo "Comments: $row[5] ";
$loop++;
}

echo "<a href="bookreview.html">Insert a new book review</a>";

?>

If File Contents Equals
I'm trying to create a script that will check the contents of the file and will display a certain message if it does equal the correct value. How would I go about checking a files contents? I tried

if (readfile("$file1") == "144.173.19.121") {
echo "your ip";
} else {
echo "doesn't work";}

File Contents To Variables
I have a file populated with information formated as on many lines:

date: person:id:info:info2

please note that : is the seperater. How can I get this data into variables:

$date:$person:$id:$info:$info2

I can open the file, display it's contents, even take the : out of it with this code I got from php.net: PHP Code:

Reading Zip File Contents
say i have a zip file - test.zip - with a file - somefile.txt - in it,
whose contents are as follows:

this is a test

when i try running the following script on the above zip file, i get
everything i should be getting, save for the contents of somefile.txt
(example output follows the script):

<?
$filename = 'test.zip'
if (($temp = zip_open($filename))) {
while ($entry = zip_read($temp))
if (preg_match('/.txt$/',zip_entry_name($entry))) {
print "file name = '".zip_entry_name($entry)."'
";
print "file size = '".zip_entry_filesize($entry)."'
";
print "contents = '".zip_entry_read($entry)."'
";
}
zip_close($temp);
}

?>

the output is as follows:

file name = 'somefile.txt'
file size = ཊ'
contents = ''

the output i would like and expect is as follows:

file name = 'somefile.txt'
file size = ཊ'
contents = 'this is a test'

Need To Read The File Contents
I have a small problem.i need to read the file contents from the url.here is the desc of the problemthe file(local file with compelte path) name should pass thru url(no file upload option)so i need to read that file and store that content in the databasehere is the examplehttp://example.com/read.php?file="D://text.txt"Once i enter this url in the browser, i need to read that text.txt file and store the content of text.txt into DB.

Open File And Get Contents
I need to open a file and then echo the contents into a text area. I tried file_get_contents(), but it doesn't work, it isn't recognised as a function..

Any other way of doing this?

Delete File Contents
Can someone post some code to show me how to delete a file from a folder please? I need to delete a file first, and then upload something in it's place. Maybe a bit of code to slide in what i have already would work? Code:

How To Append A Flv File Contents To Another Flv File.
Could u pls helpe me how to append a flv movie file to another flv movie file.

How Do I Open A Dir And Print The Contents Of Each File?
i can do it in perl with this

$dirtoopen = "./database/";
opendir(DIR, "$filetoopen") or die "cannot open";
@files = readdir(DIR);
closedir(DIR);

foreach $file(@files){
$filetoopen = "./database/$file";
open(FILE, "$filetoopen") or die "cannot open";
$contents = <FILE>;
close(FILE);
($addonname, $description, $submitter) = split(//, $contents);
print "$addonname | $description";
}

but how would i with php?

Overwrite File To Update Contents
I'm hoping someone can help me figure this little problem i am having with the following PHP script... i have registration form that a person can use to sign up for email, and when they submit there information, i have a script that is suppose to write to a text file the username and email address...
however, is there a way to delete the contents of the text file or overwrite it completely with all the usernames and email addresses in the database(which was already there to begin with) plus the new person's username and email address???? the idea here is to have the most current info from the database be written to the text file when someone signs up for email...
the following code snippet is the code that is suppose to place the new user's username and email address...

Displaying Contents Of A Text File?
I'm trying grab the content of a text file and print it a web page. I believe that I should be using something along the lines of "file" or "fopen", but I'm not having any luck. Any thoughts or tips?

Basic File Get Contents Errors
I'm a newbie and have been learning PHP on and off for a while now.
I am trying to rebuild my website after my host dissapeared along with all my sites data, and I am very nearly 100% complete to the point prior to data loss.

However, one of the pieces of code written by another programmer is simply baffling me at the moment, and I think it may be due to the fact the code was badly written for a much older version of PHP compared to the version the site is on now with my new host etc

The code should be searching for images from one of my suppliers websites but it runs and does nothing at all...I have checked the suppliers URL's and they match the code so what is going on here....am I missing something really simple?

Printing The Contents Of Each File In A Directory
I've been trying to create a PHP page that reads each file in a directory (txt, for example), and then outputs the contents of the file. The purpose for this is for someone advertising products for a website, so that he can use a form to describe the product, and then saves each entry as a new txt file.

I then want the php to print the contents of the file. I've set it up so that it is html code, so formatting is not an issue.

I've figured out how to read the contents of a single file, using file_get_contents. I can also display each file NAME from the directory. However, when I add file_get_contents into the loop, the php script wont run.

Here's what I have so far:

<?php

 $handle = opendir('sales');

if($handle)
{
 while(false !== ($file = readdir($handle)))
 {
print "$file ";

$contents = file_get_contents($file);
print "$contents ";
 }
closedir($handle);
}?>

I've tried using seperate php entries and also had a play with readf and such, but can't seem to get anything to work. It seems like a common thing to want to do, and I've probably just made a small mistake somewhere?

Read A Text File Where Contents Are Going Over 2 Lines
I have this code to read the contents of a text file: PHP Code:

Read The Contents Of A Text File Into MySql Using PHP
New to this, have the basics, can build a form and such. My problem is I
need to be able to open a file on a pc/s on the network, read the data
character by character, check to see if a certain character is present, if
it is, update the database and continue reading the file until it comes
across the character again, updates the database and so on . . . .

File Get Contents Does Not Work When Reading Pages From 'mydomain.com'
Working on Linux, I created this script:
---
$url = "http://www.mydomain.com";
$html = @file_get_contents($url, "r") or die("Can't open URL");
echo $html;
-----

This script:
- works ok on my PC box (PHP 4.4.5) with 'http://www.google.com'
- works ok on my PC box (PHP 4.4.5) with 'http://www.mydomain.com'
- works ok on my server (PHP 4.4.2) with 'http://www.google.com'
- DOES NOT work on my server (PHP 4.4.2) with 'http://www.mydomain.com'

Does anybody have any tip to find out why I can't read 'http://www.mydomain.com' on my server? Must I modify something on my 'mydomain.com' server (I manage it)?

Printing New Table Header On Every Page
I query a database and print the info in a table.I need to print a new table header on each new page. Do I need to embed another loop somewhere so that like every 20 rows print a new table header, if so how, and where? Thank you so much for any help. Here is my code:

Refresh Page To Update Table (every Minute)
I fill my table from MySQL tables. Each 1 minute i need to update table contents according to the changes in database(made by another people)Can i do it in php? And how?

Displaying A URL Stored In A Table As An Image On The Page?
In a table in my database I have a column for storing the URL of an image of a product. What PHP code would I use to display the image? PHP Code:

Display Values Of The Form Inside The Table On The New Page
I am generating data from database and displaying it inside input text boxes (for users to make some changes). What I need to do is when user presses "submit" button display all of the results inside the table on the new opened page. How can I do it?

Building Dynamic Report Page On Table Data
I am posting this message to this forum because I need some advice and some help with building a page to produce a report from the database I am building. Firstly, however I will post the table structures for the involved tables..... Code:

Get A Table In My Database To Updae Everytime The Page Loads
I am trying to get a table in my database to updae everytime the page loads, it will count how many times a video has been watched. I need to update 'no_of_times_viewd.
How is this done?

Where Do I Place This?
i have a script which allows users to edit their information. I can make the form edit and update the data, but when the user returns to the form to update the information, it retunrs to the first value. I am not sure where to place this tag <?=$a13?> PHP code:

Where Does Php Place Cookies?
This is baffling me. I am starting a session and I know it is setting a
cookie on my computer - I called getallheaders() and see that it is
setting the cookie, and it is also accessible in $_COOKIE. I cleared
all cookies in my Cookies folder before starting the session, and
everytime I run the script it does not create a cookie in the folder.
For testing I even set the browser to accept all cookies to make sure.

session.use_cookies is on in php.ini, session.use_only_cookies is off,
and session.use_trans_sid is off. The session data file is definitely
being created, but I cannot find the corresponding cookie no matter what
I try.