PHP :: Populating An Auto_increament Attribute

Domxml_new_doc - Can I Add Encoding Attribute?
I've got a question about adding encoding attribute to my DOM XML Document?

I'm from Poland and we use extended latin alphabet - I'd like to use
iso-8859-2 Polish charset

e.g.:
<?xml version="1.0" encoding="iso-8859-2"?>

is there such posibility in DOM XML?

LDAP And TelephoneNumber Attribute
Anyone have a problem with PHP returning the telephoneNumber attribute empty while all the other attributes return just fine. Someone had the same exact problem on phpbuilder but it was never solved. Apparently it holds true for facsimileTelephoneNumber also. Any ideas?

A '<' Character Cannot Be Used In Attribute 'href', Except Through <[xml]
The following embedded snip it of PHP code won't validate using xhtml 1.0 strict. When validating I get the following error:

A '<' character cannot be used in attribute 'href', except through <[xml] Code:

href="/_Director/forms.php? <?PHP create_request_query('AskQuestions', 'AskQuestions'); ?>" Any idea what's wrong?

SimpleXML Parsing By Attribute Value
I have an existing XML data set and would like to parse it with PHP5 based on the value of an attribute (any attribute!). I don't want to convert all my data from an attribute-heavy structure to a more proper element-based structure if I don't have to because of the javascript I am using on the client side. Listed below is the XML structure and PHP code I have been testing.

My existing data structure looks like this:
<gallery>
<photos>
<photo
path = "sunflower01.jpg"
width = "500"
height = "375"
thumbpath = "sunflower01.jpg"
thumbwidth = "125"
thumbheight = "94">
</photo>
</photos>
</gallery>

The script is here:

<?php
$xml = simplexml_load_file("pictures.xml");
$image = $xml->xpath("/gallery/photos/photo[@path='sunflower01.jpg']");
echo $image[0]->photo@thumbpath;
?>

Counting Items In An Array Having X Attribute
I want to randomly select 5 cards from a standard playing card deck and count how many of each suit are returned:

[connect]
$sql = "SELECT * FROM cards ORDER BY RAND()LIMIT 5";
$result = mysql_query($sql);
while($cards = mysql_fetch_array($result)) {

$value = $cards["card_value"];
$suit = $cards["card_suit"];
$image = $cards["card_image"];
--------

Using count() within the loop returns a count of 1 since each card can only be of one suit. I tried using something like this:

$spades = 0;
if($suit='spades') {
$spades = $spades+1;
}

and I tried a foreach statement to count within the loop which always returns a count of 1.

Would someone be so kind as to point me in the right direction?

Sort A Group Of Nodes By Attribute? How?
I have the following XML file:

<?xml version="1.0" encoding="iso-8859-1"?>
<items>
<item line="2">all that glitters is gold,</item>
<item line="1">Theres a lady thats sure,</item>
<item line="3">and she's buying a stairway to heaven</item>
</items>

To output this code Im using the following PHP:

$xmldoc = domxml_open_file('stairway.xml',
DOMXML_LOAD_DONT_KEEP_BLANKS);
$node = $xmldoc->document_element();
if ($xmldoc->has_child_nodes()) {
$node = $node->first_child();
$endwhile = false;
while ($endwhile != true) {
echo $node->get_content() . "<br />";
if ($node->next_sibling()) {
$node = $node->next_sibling();
}else{
$endwhile = true;
}
}
}

This does what it supposed to do except I want to ensure that it
outputs nodes ordered by 'line' attribute. The obvious answer would be
to put them in order in the XML file and the above example is very
simple so that you get the point, the real life example however will be
much larger and encase anyone put something in the wrong order it would
muck up my presentation. How could I adapt my code above to allow my
nodes to be sorted? I dont mind the nodes being out of order in the
physical file (stairway.xml) but when they are output using my script,
I want them to be ordered.

Accept Form Attribute Not Working
I cannot get my accept attribute working properly inside either my form, or my input tag. W3schools says that accept is supposed to go inside the input tag, but msdn says it goes in the form tag. I need it for an upload form I'm making, I want to only allow application/octet-stream type files, so I put this as my opening form tag:

<form enctype="multipart/form-data" accept="application/octet-stream" action="{$_SERVER['PHP_SELF']}" method="POST">

But I can still upload music, text files, and movies. What gives?

After I Load An XML File, Can I Sort It By Node Attribute
After loading an xml file, is it possible to sort it by attribute?

For example, I have the following xml file:

<xml...
<diary>
<entry date="2005-01-01">I went to the park</entry>
<entry date="2005-01-03">Sold the car today</entry>
<entry date="2005-01-02">Went for a stroll</entry>
</diary>

When I go to load this using PHP, I would use some this similar to
this:

$xmldoc = domxml_open_file('diary.xml', DOMXML_LOAD_DONT_KEEP_BLANKS);

$node = $xmldoc->document_element();

Before I go storming through the xml tree outputing along the way, can
I sort it by (in this case) date?

Php-4.4.0 And Test.wsf = Error: The Value For The Attribute Is Not Valid: Language
We need to use version php-4.4.0-Win32 because one of the portal software
doesn't support version php-5.0.5-Win32. We cannot get the PHP setup part
working. Here is the error message:

Windows Script Host

Script: C:kits est.wsf
Line: 3
Char: 11
Error: The value for the attribute is not valid: language
Code: 80040049
Source: Windows Script Host

Here is the code from the install.txt

To test if ActiveScript is working, create a new file, named test.wsf (the
extension is very important) and type:

<job id="test">

<script language="PHPScript">
$WScript->Echo("Hello World!");
</script>

</job>

Save and double-click on the file. If you receive a little window saying
"Hello World!" you're done.

Everything works fine using php-5.0.5-Win32.

Simplexml And Attributes With A Namespace In Front. How Do You Getthe Attribute?
Here's a bit of xml code that works.

<?php

$string =
"<?xml version="1.0" standalone="yes"?>
<world>
<people xmlns:ss="http://crap">
<person id="5">John Doe</person>
<person id="2">Susie Q. Public</person>
</people>
</world>";

$xml = simplexml_load_string($string);
print "<pre>";
print_r($xml);
print "</pre>";

foreach($xml->people->person as $p)
foreach($p->attributes() as $a =$b)
{
print "$a =$b<br />";
}

// prints out
// id =5
// id =2
?>

Now what if I change the first person to this
<person ss:id="5">John Doe</person>

Anyone know how to get the id?

This is a question that is pertinent to an excel .xml file as
you'll get lines like this
<Cell ss:Index="3">stuff</Cell>

btw: there is a guide on ibm that tells you how to do this with php
and dom. I'm just wondering if there's a way to do it with simplexml.

Populating A Select Box
What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box. I can do this on my own, but I was curious if I have to use a database in order for this to be possible.

PHP + MYSQL, Populating Drop Down Box
I am looking to generate a dropdown box from MYSQL data:

db name = h2, table = Working, Column = Home.

Populating Two Combo Boxes
I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).

Populating Dropdown List
I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:

Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.

Dymanic Populating Checkboxes
i like to retrieve a value from DB,
accordingly i like to display the checkbox, either checked or not.

Now im able to retrieve the value from DB, i can show even show the
checkbox, but i cant make it checked????

the Code i used to display as follows,

#Require the database class
require_once('../dbinfoinc.php');

#Get an array containing the resulting
record
$query = "SELECT * FROM event";
$result = mysql_query($query);

$num=mysql_numrows($result);
mysql_close();

$i=0;
while ($i < $num) {
if(($i % 2) == 0) { $c =
'"TableDetail"' }
else { $c = '"TableDetail2"' }

$event_id=mysql_result($result,$i,"event_id");

$event_name=mysql_result($result,$i,"event_name");

$event_publish=mysql_result($result,$i,"publish");
// if(($event_publish) == 0) {
$event_publish = 'No' }
// else { $event_publish = 'YES'
}
$take_action = 'Delete'
echo "<tr>
<td Class='navText'
align='center' class=$c>$event_id</td>
<td class='navText'
class=$c>$event_name</td>
<td class='navText'
align='center' class=$c><input type='checkbox'
name='publish' if($event_publish==1){'CHECKED'}?></td>
<td class='navText'
align='center' class=$c><a
href='delete_event.php?event_id=$event_id'>$take_action</a></td></tr>";

$i++;
}
?>

Re-populating A Form If Errors
I am learning php. I have created a simple Web page with a form.
After receing the POST request, I do some error checking. In case of
errors, I would like to re-post the page, but with the current values
for each field.

I have organized my files like this:
1) Webpage with the form (all in html, form action points to a php
file)
2) php file that receives the request.

Populating Form Text Box.
I have a PHP form for entering data on-line into a mySQL
table..
Because of the intended search facility, I require one field in the form
to be completed with exact and precise item names and spelling.
In testing, I had achieved this with look-up tables.
Ideally I would like the selected item from one of five drop-down lists
to autopopulate the form text field when selected.
Alternatively at least the option of copy and paste.
Copy and paste - for some reason will not work.
Autofill worked fine on a test form with no database connection
and in standard HTML and javascript, however, once the PHP
is added to the page neither method works.
Could anyone please point me in the direction of how to get the
autofill to work?

Populating A Select Box From A Database
I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it.

The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like:

Green
Red
Blue
Green
Black

How can I make it so that Green only shows up once?

Populating Drop Down And Table
I have a database with the following fields.
Name | Company | Date

values in each column could be repeated, or not. as in there could be several same names with the same company with different dates, or different names with same company.

How do I populate a table with this info and have drop down boxes, so that I can narrow down the search? For example:
Name | Company | Date
12 | 1 | 1929
13 | 1 | 1929
14 | 1 | 1929
12 | 2 | 1929
12 | 4 | 1929
13 | 1 | 1941
12 | 6 | 1929

So if in the drop down I select '12' under name, only those entries with 12 are shown, and then I can further sort it by selecting only '1' under Company.
Hope I'm clear, I manage to complicate things when I post them.

Populating Table Information
I am trying to dynamically generate bgcolors with to help populate some information for a site. Here is the code:

Auto Populating A Drop Down Box
Basically I'm setting up a website which needs an populated drop down box made up from all fields in a specific column of a table in a mysql db....

Here's the code I've made up using various tutorials....

<?php
$user = "";
$host = ""
$password = ""
$dbName =  ""

/* make connection to database */
mysql_connect($host, $user, $password) OR DIE( "Unable to connect
to database");
mysql_select_db($dbName); //did you forget this line?

$sql = "SELECT model FROM usedVehicles";
$query = mysql_query($sql) or die(mysql_error() . "<br>$sql"); //use the or die(...) part ONLY IN DEVELOPMENT
?>

<form action="action" method="post">
<select name="option">

<?php
while ($row = mysql_fetch_array($result)) {
    echo "<option value="" . $row['model'] . "">" . $row['model'] . "</option>
";
}
?>
</select>
<input type="submit">
</form>

I've left out the connection details for obvious reasons... When I upload and try to test this, jus a blank drop down appears... there are definately fields in the column as I have tried the query on phpMyAdmin.

Populating Fresh Data
Im building a live web chat using php, mysql, javascript, ajax I am fine with sending and retreiving data in real time using ajax as the transfer protocol However, my problem, which is becoming a nightmare, is how to I display it !! Lets say the below is the chat screen,

<div id="messages">
Jamie - Hello
Peter = Hi
Jamie = Nice Day
Peter = I know
</div>

Lets say Jamie's next message is "What are you doing today". I can send that off to the database no problem and I can get peters live chat to pull that message in, however, how do I get it to display underneath Peter = I know

As a practice I was using

document.getelementbyid('messages').innerHTML = document.getelementbyid('messages').innerHTML + "<BR>What are you doing today"

That works, but, lets just say the chat gets to 1000 lines, for each new message those 1000 lines have to be pulled out via javascript, a new line written to it and then printed back in the div

Im not sure but I'd take a good guess at this not being optimal and will cause CPU load on the users machine

What is the best way to do this! Chat messages are deleted after 1 minute, but that doesnt matter because by then they have already been sent the the users chat. Just incase you are thinking of completely repopulating there chat with every message they have sent since the chat started..

Reading Directories, Populating Select Box
Can anybody tell me how to read through a directory, get the file names and populate a select box(pulldown menu) with these names? I know how to loop through a directory using something like this:

while ($files = readdir($handle)) {

$ext=substr($file,-4);

if ($files != "." && $files != ".." && $ext == ".php") {

do some wild and crazy stuff here;

}

}

It's the populating the select box (pulldown menu) while doing this that I need the help on.

Populating Form Item From SQL Enum Set Rev#2
$sql = "SHOW COLUMNS FROM table LIKE 'subject' ";
$qry = mysql_query($sql) or die("Query not valid: " . mysql_error());
$res = mysql_fetch_object($qry);
// This returns a row with a field 'Type' containing 'enum(...)'

$res->Type = str_replace('enum('', '', $res->Type);
$res->Type = str_replace('')', '', $res->Type);
//now the string is something like this: one','two','three

$temp = explode('','',$res->Type);
//temp is an array with as much elements as the enum

while ($temp)
print array_pop($temp);

This way is much more easier using the elements since they are elements
of an array. Cleaver isn't it?

Populating Array With Mysql Results
I'm returning a result set of one field in a table, and want to populate an array with the results. I can't for the life of me figure out a simple way to do this without using mysql_fetch_array() to cycle through the results, append that to a var, then explode that into a var and pass that. PHP Code:

Populating A Form Wth Database Info
I've coded a piece of code which populates a form with data read from the database:

$connection=mysql_connec ("localhost", "f2821842", "f2821842");
$result=mysql_select_db("QUERIES");
$query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'");
while($row=mysql_fetch_array($query))
{$empname=$row['emp_name'];}

<form name="webregform" action="webadmin2.php" method="post">
<input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>">
</form>

When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?

Populating Dynamically Generated TextFields
If one assigns something to the value iattribute off an input /text field, that value will be displayed when the form is loaded. My problem is, when building a form dynamically, the only way I can get the text to show is by doing the above, however, as this is an update form, when the form POSTS to processUpdate.php,
both the data entered by the user AND the data in the value attribute are inserted/updated.

So, how does one dynamically build a form where the data is displayed in the text fields but value atttribute is not set. PHP Code:

Populating A Drop Down List With The Year
i'm trying to loop the years from 1960 - 2010 with the function get_year() below:
PHP Code:

Populating Form Fields With Variables
The script itself works fine: mail gets sent. If there are any missing fields the form displays again with a list of the missing fields, but I can't get the form fields of the reloaded form to be populated with teh existing values. PHP Code:

Populating DHTML Menu From MySQL
I have a client that would like to have drop down menus added to a nav
bar that is generated from MySQL. Is it possible to have a dynamically
driven DHTML menu from MySQL?

Populating Arrays From MySQL Query
I have the following code: http://pastebin.com/746601

The field 'material' in 'is_material' contains multiple values for each
record in 'is_details'. Because of this I have used
'is_material_lookup' as a reference lookup table containing the
'style_code' and 'material_code' which refer to their full details in
the respective tables.

Currently I have got the script outputting all the details and one
material then in the next block of data, repeating the details with a
different material. What I would like to achieve is having 1 block of
data with a list of all materials in that, instead of the repeat, but
sadly I can't know exactly how to do it.

Populating Dropdown With Mysql Entries
I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.

Populating A Drop Box With Results From Database
I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.

Populating Table With Text File
My web hosting service uses phpMyAdmin and at the bottom of the screen
iis an area where I can upload a text file to populate a table.

I have a table named groups with two fields:
groups_idauto-increment primary
groups_name

So how do I create my text file to populate this table?

I'm going to use MS Notepad.

If it's set to auto-increment, do I need to include the number? If
so, does it start at 0 (zero)?

Would the file look like:

0,students
1,faculty
2, staff

or just

students
faculty
staff

PHP Not Populating Form Variables Passed Through POST Or GET
I"m running:

Windows Xp SP2
Apache2
PHP5
MySQL4

Everything seems fine and dandy, and I can do scripting on server side, but for some reason I cannot get data from a form to be put into a variable.

I have a simple form in an html page which submits, and in the php script that handles the input, none of the data in the form is going into the variables.

My php.ini file does have all the GPC's in place(ie variable_order, the way they get processed).

Auto Populating Multiple Drop Downs.
im trying to create two dropdowns, i need the first one to be the category and the second one to be the subcategory. The category drop down autopopulates with the correct info from the database. and uses the table "category", the value of each drop down is represented by the "cat" field in the table (cat is basically and integer id number) and "Category" is used as what the user actually sees in the drop down (category is the actual word of the category).

Once the category is selected i would like to have the sub category auto populate with everything that has the same values as the selected category (cat)

Here is a break down of how the tables work.

Table 1 Name: "category"
Fields for Table 1: "cat" (the id number), "category" ( the actual name of the category)

Table 2 Name: "subcategory"
Fields for Table 2: "cat" (corresponds with the cat id from table 1 to pull the correct data), "subc" (the basic id of the subcategory), "subcat" the actual name of the subcategory.

so the way i see it, have a normal drop down populated by a php query. then on change, populate subcategory drop down where cat = cat and display sub category.

Populating The Drop Down And Pressing The Submit Button
1. The first is I have two drop down menus. The first is "year" and the second is "mfr". When a user selects a year from the drop down it then populates the second drop down, mfr, from the MySQL database. Theat is working fine. But the problem I am having is the "submit" button (which I have labeled as "browse"). When I click it. Nothing happens, no action tacks place. I have looked over the code and I can't figure it out. (See Code Box 1 Below).

2. Right now the "mfr" drop down is populated by the MySQL database and reads with a list like "Acr", "Alp", etc. These are abreviations. I need to set up an array to have them instead read the entire mfr name. Example: Instead of "Acr" it needs to be "Acura". Instead of "Alp" it needs to be "Alpine". I need these full names to appear in the drop down. I know I need to do something like this (See Code Box 2 Below) but I can't get my finger on it. Code:

Populating City,state,country Drop Down Menu
In the registration form I have city, state, country fields. I was
wondering if there was a database available on the net which has the
list of states in each of the countries. That way when a user selects
a country I could automatically populate the state drop down menu ...

Populating Form From Database, Then Passing Results To Next Page
I have a multiple select input in a form that's being populated by a row
from my database as such:
<input type="checkbox" name="subm[]" value="$row[ID]">

That part is working fine as I can check the displayed page using View
Source and see that the value is the correct row number from the
database. It is then being submitted on a form by $_POST method to
another page where I want to evaluate the checkboxes and display the
contents of the entire row that corresponds to each value="$row[ID]"
that have been checked. But I can't seem to get it to work. I'm having a
problem passing the selected value. Can someone point me in the right
direction?

$query = ("SELECT * FROM `table`");
$result = mysql_query($query);

print "<p>Data for Selections:";
print "<table border=2><tr><th>You chose:";

foreach ($_POST['subm'] as $value) {
print "<tr><td>";
print "$row[ID];
";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print "</td></tr>";
print "</table>
";
}

if (!isset($_POST['subm'])){
print "<p>No matching entry ";
}

mysql_close();

Auto-populating Multiple Boxes... Php And Pg_fetch_array Problem?
There is a nice tool using jquery/php to populate multiple select boxes out
there, it must be a very stupid question but I?m trying to apply this tool to get data from postgreSQL, but I always get an empty [] value. It means that the...

Populating SELECT Multiple Form Field And Inserting Into Db
I have an update form where I'm trying to populate a SELECT multiple field with a list of 48 categories, from tbl work_cat. And show, as SELECTED, the one or many choices that the user had previously selected from the 48 categories which are stored in tbl cat_relations as $relation_cat.

Then allow the user to update their selections and update the database. But I can't get my form to work. First problem, I can't get the SELECT field on the form to show the categories, and then I don't know where to go from there. Below are my form page and my processing page. Code:

Dynamically Populating Listboxes Based On Previous Selection
How do I populate the second listbox in this form based on the selection of the first listbox?

The first listbox is populated by this query:
$year_query = "SELECT distinct year FROM bench_data";
The second listbox should essentially be populated by this:
$industry_query = "SELECT distinct comp_desc FROM comp_desc, benc_data where $_POST['year']=bench_data.year and bench_data.comp_key=comp_desc.comp_key";

I know this is alot to ask, but please EXPLAIN the code. I am new and need the explanation elucidated and not just supplied code that will accomplish the goal. Code:

Populating "Month" Dropdown Menu
I can get the current month to display in a text box by inserting
value="<? print strftime("%B"); ?>"> into the code for that
particular text box on a form but how can I populate a drop down with
names of all the months with the current one being 'default' as it
would be in the text box example?

Populating Form In Parent Window With Value From Popup Window
I have a text box in the parent window.. now i want to populate this text box with a user_id that i will get from query within a popup window.. How do i get the value from the popup window to be passed to the main window form field in php. I know how it can be done in javascript but when i tried combining javascript and php i dont get the desired result.