Populating Dynamically Generated TextFields

How do I populate the second listbox in this form based on the selection of the first listbox?

The first listbox is populated by this query:
$year_query = "SELECT distinct year FROM bench_data";
The second listbox should essentially be populated by this:
$industry_query = "SELECT distinct comp_desc FROM comp_desc, benc_data where $_POST['year']=bench_data.year and bench_data.comp_key=comp_desc.comp_key";

I know this is alot to ask, but please EXPLAIN the code.  I am new and need the explanation elucidated and not just supplied code that will accomplish the goal. Code:

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I'm trying to write a script that dynamically generates HTML tables depending on the results from an SQL query. So far, I have managed to set the HTML table headers to be the same as those in the MySQL table. [thanks to rod k -cheers !]

Now i'm trying to put the results in the table. Basically, I need a MySQL function to retrieve data and put it into the table until there is no data left....

(At the moment I am using "mysql_fetch_array()", but with this it is necessary to know the names of the columns to retrieve the information for each result set. Since my table is dynamic and should be able to build itself from different MySQL tables, the column names aren't fixed and so i can't use this to put the data in the tables...)

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I'm trying to get POST data that was dynamically generated and I'm not sure how to go about doing this.

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I have a search form which makes queries to a database. In the form the user can search for many words (word1 && word2 && word3). I want in the results to highlight the words that the user has searched for. I 've searched in the internet and i've found some codes but none of them works with all the possible results.

What I have found so far which is closer to what I want is the following:

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I have a script that generates an image based on users' inputs. How would I make it so that the script automatically uploads that image to a different folder on the server? I'm stumped on this one. Does anybody have any ideas?

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In brief, in the following 2 portions of code I build a form based on data retrieved from a database. The second bit of code receives the posted data for processing and updating the database. Problem is that the update occurs for the first row of data but none of
the rest. I'm using a hidden field, written in dynamically (
name="tfHiddenId<?php echo $j ?>" ) where $j is a counter var in a loop.

When I print out the POST_VARS everything is as I want to be, fields all
named according ly, as above. Just the update either 1) only does one
row and quits or 2) updates same row with the same data over and over ( I
suspect the latter ). Apparently my counter variable is not being incremented, but only on one var, "tfHiddenId".$i , on the receiving page. Here's the code for where the form is built from the DB: PHP Code:

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I've written a code that runs a 'SHOW DATABASES' query on my mysql server and lists the results(the names of the databases on my server) in a dynamically generated dropdown box, and it works just fine, using the following code:

echo "<select name='databaseselect'>";
$dblist = mysql_query('SHOW DATABASES');
while ($row = mysql_fetch_row($dblist)) {
echo "<option value='$row2[0]'>$row2[0]</option>";
}
echo "</select>";

The problem is that it lists ALL of the databases on my server - that's two of my own user-created databases, and the two default databases that come with the mysql server - 'information_schema' and 'mysql'.  What I want to do is to, after running the 'SHOW DATABASES' query, eliminate those two databases from appearing in the dropdown box, because I don't want anyone to see them, as they're useless to anybody else. Code:

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I have one big form on a page, within which is a list of text fields pulled from a mysql db. Each text field has an 'update' button, which submits the main form, and should UPDATE the textfield it relates to.

The problem is, all the buttons have value="Update" and I can't think of an efficient way of passing the unique id of each record to be submitted with it. Obviously, having a hidden field for each textfield won't work because the form will use the last one displayed.

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i have a thing where u enter how many files and it makes that many textboxes for u to enter stuff each named $files[0] , $files[1] , etc i want to put them in 1 thing so like combind em all and put em in like this

$download_query = "INSERT INTO abc VALUES('$files1')";
$download_result = mysql_query($download_query);

i want all the stuff out of all the different checkboxes to go into like files1 and i like make it take all the text and put it into a variable?

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i dont know if its a stupid question but im so new to php you can forgive  me
well the thing is i have 3 text fields

textfield1
textfield2
textfield3

I want to add textfield 1 with textfield 2 and display it in a hidden textfield3 with a space between the text.

Textfield1(Sam) + Textfield2(Yam) = Textfield3 (Sam Yam)

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Is there a way to disable PHP, HTML, and the sort in textboxes and input fields? There are things called SQL Injections which are usually used in an url or input field to steal data from the database.

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We have a drop down list on a PHP page, with several product names, and
when people click one item, we will refresh the same page with the
product name as parameter, and in turn we want to include a HTML file
into the content area of the same page.

I know it is recommended to put everything into database, but we want
the web site to be very "portable", so the drop-downlist and the
content should both in text files.

Let's say the drop-down list will be poplulated from the product.txt
file, and there will be a file for each corresponding item in the
drop-down list. From the user point of view, if he wants to add a new
product, he will just need to open the product.txt file, and add a new
line with the product name, "Laptop", then add a new text file named
"laptop" in the same folder which contains the HTML fragment to be
included in the content area.

What is the easiest way to do this?

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What I want to do for members of my website is to allow them to click a button that will add their name to a list that populates a select box.  I can do this on my own, but I was curious if I have to use a database in order for this to be possible. 

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I am looking to generate a dropdown box from MYSQL data:

db name = h2, table = Working, Column = Home.

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I have one combo box (Category) which is populated by a MySQL table using php. I am trying to use the onchange javascript to submit the value selected so that I can populate the other combo box (sub-category) based on what was previously choosen. So can anybody give me a clue on how to submit the first boxes value so that the second can see what was selected (javascript function).

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I am wanting to know how to populate the <SELECT> dropdown menu with all existing values from the DB and also have the value associated with that id selected. This is an updating area of my admin. Any ideas? Here's the code so far. At the moment it only retrieves the value assigned to that id. PHP Code:

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How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.

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i like to retrieve a value from DB,
accordingly i like to display the checkbox, either checked or not.

Now im able to retrieve the value from DB, i can show even show the
checkbox, but i cant make it checked????

the Code i used to display as follows,

#Require the database class
require_once('../dbinfoinc.php');

#Get an array containing the resulting
record
$query = "SELECT * FROM event";
$result = mysql_query($query);

$num=mysql_numrows($result);
mysql_close();

$i=0;
while ($i < $num) {
if(($i % 2) == 0) { $c =
'"TableDetail"' }
else { $c = '"TableDetail2"' }

$event_id=mysql_result($result,$i,"event_id");

$event_name=mysql_result($result,$i,"event_name");

$event_publish=mysql_result($result,$i,"publish");
// if(($event_publish) == 0) {
$event_publish = 'No' }
// else { $event_publish = 'YES'
}
$take_action = 'Delete'
echo "<tr>
<td Class='navText'
align='center' class=$c>$event_id</td>
<td class='navText'
class=$c>$event_name</td>
<td class='navText'
align='center' class=$c><input type='checkbox'
name='publish' if($event_publish==1){'CHECKED'}?></td>
<td class='navText'
align='center' class=$c><a
href='delete_event.php?event_id=$event_id'>$take_action</a></td></tr>";

$i++;
}
?>

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I am learning php. I have created a simple Web page with a form.
After receing the POST request, I do some error checking. In case of
errors, I would like to re-post the page, but with the current values
for each field.

I have organized my files like this:
1) Webpage with the form (all in html, form action points to a php
file)
2) php file that receives the request.

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I have a PHP form for entering data on-line into a mySQL
table..
Because of the intended search facility, I require one field in the form
to be completed with exact and precise item names and spelling.
In testing, I had achieved this with look-up tables.
Ideally I would like the selected item from one of five drop-down lists
to autopopulate the form text field when selected.
Alternatively at least the option of copy and paste.
Copy and paste - for some reason will not work.
Autofill worked fine on a test form with no database connection
and in standard HTML and javascript, however, once the PHP
is added to the page neither method works.
Could anyone please point me in the direction of how to get the
autofill to work?

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I have a subscription database that allows you to edit a subscribers data. For example, you enter a search term like "Bob" and it returns a list of everyone named Bob. You click the one you want and it goes to a subscriber detail page, where all of his data is populated to a form. You can directly edit this form and click save to overwrite it.

The only issue is the select boxes (drop downs) - say I have four options in the drop down box, red, blue, green and black. On my details page for bob I end up with five, I have those four PLUS whatever was saved for his color, so it shows up twice. If Bob is green, my select box looks like:

Green
Red
Blue
Green
Black

How can I make it so that Green only shows up once?

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I have a database with the following fields.
Name | Company | Date

values in each column could be repeated, or not. as in there could be several same names with the same company with different dates, or different names with same company.

How do I populate a table with this info and have drop down boxes, so that I can narrow down the search? For example:
Name | Company | Date
12     | 1           | 1929
13     | 1           | 1929
14     | 1           | 1929
12     | 2           | 1929
12     | 4           | 1929
13     | 1           | 1941
12     | 6           | 1929

So if in the drop down I select '12' under name, only those entries with 12 are shown, and then I can further sort it by selecting only '1' under Company.
Hope I'm clear, I manage to complicate things when I post them.

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I have just designed a BD. there are companies with auto increament which are integer. When I try to populate it after i tool value from another form and try to insert it into a table i recieve an error! I don't ask the companyID value from user as it is auto increament. Don't tell me to put NULL for that entry as it didn't work as well! Code:

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I am trying to dynamically generate bgcolors with to help populate some information for a site. Here is the code:

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Basically I'm setting up a website which needs an populated drop down box made up from all fields in a specific column of a table in a mysql db....

Here's the code I've made up using various tutorials....

<?php 
$user = "";  
$host = "" 
$password = "" 
$dbName =  "" 

/* make connection to database */  
mysql_connect($host, $user, $password) OR DIE( "Unable to connect 
to database"); 
mysql_select_db($dbName); //did you forget this line? 

$sql = "SELECT model FROM usedVehicles"; 
$query = mysql_query($sql) or die(mysql_error() . "<br>$sql"); //use the or die(...) part ONLY IN DEVELOPMENT 
?>

<form action="action" method="post"> 
<select name="option"> 

<?php  
while ($row = mysql_fetch_array($result)) {  
    echo "<option value="" . $row['model'] . "">" . $row['model'] . "</option>
";  
}  
?> 
</select> 
<input type="submit"> 
</form>

I've left out the connection details for obvious reasons... When I upload and try to test this, jus a blank drop down appears... there are definately fields in the column as I have tried the query on phpMyAdmin.

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Im building a live web chat using php, mysql, javascript, ajax I am fine with sending and retreiving data in real time using ajax as the transfer protocol However, my problem, which is becoming a nightmare, is how to I display it !! Lets say the below is the chat screen,

<div id="messages">
Jamie - Hello
Peter = Hi
Jamie = Nice Day
Peter = I know
</div>

Lets say Jamie's next message is "What are you doing today". I can send that off to the database no problem and I can get peters live chat to pull that message in, however, how do I get it to display underneath Peter = I know

As a practice I was using

document.getelementbyid('messages').innerHTML = document.getelementbyid('messages').innerHTML + "<BR>What are you doing today"

That works, but, lets just say the chat gets to 1000 lines, for each new message those 1000 lines have to be pulled out via javascript, a new line written to it and then printed back in the div

Im not sure but I'd take a good guess at this not being optimal and will cause CPU load on the users machine

What is the best way to do this! Chat messages are deleted after 1 minute, but that doesnt matter because by then they have already been sent the the users chat. Just incase you are thinking of completely repopulating there chat with every message they have sent since the chat started..

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Can anybody tell me how to read through a directory, get the file names and populate a select box(pulldown menu) with these names? I know how to loop through a directory using something like this:

while ($files = readdir($handle)) {

$ext=substr($file,-4);

if ($files != "." && $files != ".." && $ext == ".php") {

do some wild and crazy stuff here;

}

}

It's the populating the select box (pulldown menu) while doing this that I need the help on.

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$sql = "SHOW COLUMNS FROM table LIKE 'subject' ";
$qry = mysql_query($sql) or die("Query not valid: " . mysql_error());
$res = mysql_fetch_object($qry);
// This returns a row with a field 'Type' containing 'enum(...)'

$res->Type = str_replace('enum('', '', $res->Type);
$res->Type = str_replace('')', '', $res->Type);
//now the string is something like this: one','two','three

$temp = explode('','',$res->Type);
//temp is an array with as much elements as the enum

while ($temp)
print array_pop($temp);


This way is much more easier using the elements since they are elements
of an array. Cleaver isn't it?

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I'm returning a result set of one field in a table, and want to populate an array with the results. I can't for the life of me figure out a simple way to do this without using mysql_fetch_array() to cycle through the results, append that to a var, then explode that into a var and pass that. PHP Code:

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I've coded a piece of code which populates a form with data read from the database:

$connection=mysql_connec ("localhost", "f2821842", "f2821842");
$result=mysql_select_db("QUERIES");
$query=mysql_query("Select * from Emp_Details where emp_num = '$employnum'");
while($row=mysql_fetch_array($query))
{$empname=$row['emp_name'];}

<form name="webregform" action="webadmin2.php" method="post">
<input name="requiredname" type="text" size="30" value="<?php echo "$empname"; ?>">
</form>

When I echo the $requiredname, I get spaces and no data, and I know that $empname is not a space-it does read a value in a database. 1. How can I get $requiredname to print a value?

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i'm trying to loop the years from 1960 - 2010 with the function get_year() below:
PHP Code:

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The script itself works fine: mail gets sent. If there are any missing fields the form displays again with a list of the missing fields, but I can't get the form fields of the reloaded form to be populated with teh existing values. PHP Code:

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I have a client that would like to have drop down menus added to a nav
bar that is generated from MySQL. Is it possible to have a dynamically
driven DHTML menu from MySQL?

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I have the following code: http://pastebin.com/746601

The field 'material' in 'is_material' contains multiple values for each
record in 'is_details'. Because of this I have used
'is_material_lookup' as a reference lookup table containing the
'style_code' and 'material_code' which refer to their full details in
the respective tables.

Currently I have got the script outputting all the details and one
material then in the next block of data, repeating the details with a
different material. What I would like to achieve is having 1 block of
data with a list of all materials in that, instead of the repeat, but
sadly I can't know exactly how to do it.

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I would like to create a combobox in Flash which is populated with mysql data and programmed with php. For example: There are 3 entries in database .ie. apple, bannana, peach. Now these I want in combobox in Flash MX/flash5.

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I have a MySQL database with a table (category) with two fields, catId (int) and category (char(50)). What I want to do is to get all category names in this database and place all of them into a dropdown box on a web page so that the user can choose from the list of available categories.

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My web hosting service uses phpMyAdmin and at the bottom of the screen
iis an area where I can upload a text file to populate a table.

I have a table named groups with two fields:
groups_idauto-increment primary
groups_name

So how do I create my text file to populate this table?

I'm going to use MS Notepad.

If it's set to auto-increment, do I need to include the number? If
so, does it start at 0 (zero)?

Would the file look like:

0,students
1,faculty
2, staff

or just

students
faculty
staff

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I"m running:

Windows Xp SP2
Apache2
PHP5
MySQL4

Everything seems fine and dandy, and I can do scripting on server side, but for some reason I cannot get data from a form to be put into a variable.

I have a simple form in an html page which submits, and in the php script that handles the input, none of the data in the form is going into the variables.

My php.ini file does have all the GPC's in place(ie variable_order, the way they get processed).

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im trying to create two dropdowns, i need the first one to be the category and the second one to be the subcategory.  The category drop down autopopulates with the correct info from the database. and uses the table "category", the value of each drop down is represented by the "cat" field in the table (cat is basically and integer id number) and "Category" is used as what the user actually sees in the drop down (category is the actual word of the category).

Once the category is selected i would like to have the sub category auto populate with everything that has the same values as the selected category (cat)

Here is a break down of how the tables work.

Table 1 Name: "category"
Fields for Table 1:  "cat" (the id number), "category" ( the actual name of the category)

Table 2 Name: "subcategory"
Fields for Table 2: "cat" (corresponds with the cat id from table 1 to pull the correct data), "subc" (the basic id of the subcategory), "subcat" the actual name of the subcategory.

so the way i see it, have a normal drop down populated by a php query. then on change, populate subcategory drop down where cat = cat and display sub category.

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1. The first is I have two drop down menus. The first is "year" and the second is "mfr". When a user selects a year from the drop down it then populates the second drop down, mfr, from the MySQL database. Theat is working fine. But the problem I am having is the "submit" button (which I have labeled as "browse"). When I click it. Nothing happens, no action tacks place. I have looked over the code and I can't figure it out. (See Code Box 1 Below).

2. Right now the "mfr" drop down is populated by the MySQL database and reads with a list like "Acr", "Alp", etc. These are abreviations. I need to set up an array to have them instead read the entire mfr name. Example: Instead of "Acr" it needs to be "Acura". Instead of "Alp" it needs to be "Alpine". I need these full names to appear in the drop down. I know I need to do something like this (See Code Box 2 Below) but I can't get my finger on it. Code:

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In the registration form I have city, state, country fields. I was
wondering if there was a database available on the net which has the
list of states in each of the countries. That way when a user selects
a country I could automatically populate the state drop down menu ...

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I have a multiple select input in a form that's being populated by a row
from my database as such:
<input type="checkbox" name="subm[]" value="$row[ID]">

That part is working fine as I can check the displayed page using View
Source and see that the value is the correct row number from the
database. It is then being submitted on a form by $_POST method to
another page where I want to evaluate the checkboxes and display the
contents of the entire row that corresponds to each value="$row[ID]"
that have been checked. But I can't seem to get it to work. I'm having a
problem passing the selected value. Can someone point me in the right
direction?

$query = ("SELECT * FROM `table`");
$result = mysql_query($query);

print "<p>Data for Selections:";
print "<table border=2><tr><th>You chose:";

foreach ($_POST['subm'] as $value) {
print "<tr><td>";
print "$row[ID];
";
print mysql_field_name($result, 1) . ": " . $row[name]."<br>";
print mysql_field_name($result, 2) . ": " . $row[address]."<br>";
print mysql_field_name($result, 3) . ": " . $row[city]."<br>";
print "</td></tr>";
print "</table>
";
}

if (!isset($_POST['subm'])){
print "<p>No matching entry ";
}

mysql_close();

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There is a nice tool using jquery/php to populate multiple select boxes out
there, it must be a very stupid question but I?m trying to apply this tool to get data from postgreSQL, but I always get an empty [] value. It means that the...

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I have an update form where I'm trying to populate a SELECT multiple field with a list of 48 categories, from tbl work_cat. And show, as SELECTED, the one or many choices that the user had previously selected from the 48 categories which are stored in tbl cat_relations as $relation_cat.

Then allow the user to update their selections and update the database. But I can't get my form to work. First problem, I can't get the SELECT field on the form to show the categories, and then I don't know where to go from there. Below are my form page and my processing page. Code:

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I am trying generate a new PHP file from an existing page using PHP. Currently I'm using the output buffer to capture content destined for the page, and then am capturing that output and writing to a file.

The problem I am having is that all PHP scripts within the new page content are executed and the results are written to the new file, when I would like the PHP code itself to be written to the new file, unprocessed.

So now I am trying to just store the new page as a string and bypass the use of the output buffer, but do not know how to store php code within a string without having it execute...

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I am able to create images with the use of the GDLIB.
but I am not able to use these images together with HTML. I always get the
message "headers are already sent.

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I am trying to pipe in some auto-generated PHP into php.exe, to no
avail:

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the font size declaration seems to be ignored. Is it possible to set format for
tables generated with php?

<?php

echo "<table border=1 font size=8>";
echo '<tr><th font size=8>Date</th>
<th>IP Address</th>
<th>Operating System</th>
<th>Browser</th>
<th>Referring Page</th>
<tr>'

?>

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I am a Java/JSP developer by trade but am currently developing a
MySQL/PHP solution.

In JSP when I run an INSERT statement on the db I am able to
automatically get back a list of any generated keys (without having to
do some sort of subsequent query to get the information).

Is there a PHP equivilent of this?

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