Setup A Page When You Open A Drop Down Menu Of Options
How do I setup a page when you open a drop down menu of options, select an option and then an image on the page changes to the selection you landed on. Code:
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Changed Page From .htm To And My Drop Down Menu Stoped Working
I have been building a rottweiler site for a friend. I just installed "The Search Engine Project" so I need to change one of my pages from .htm to .php so I can integrate the search results window into my layout. But, whenever I change the page from .htm to .php my menu, a project 7 css drop down menu, stoppes working. Why is this? Code:
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Drop Down Menu - Every A Value Of It Is Selected To Reload The Page And Submit That Value.
i have a drop down menu and i want every a value of it is selected to reload the page and submit that value. i'm using something like this: HTML Code: <select name="menu"> <option selected value="1">GENERAL</option> <?php while ($cat = mysql_fetch_array($q)) { $cid = $cat[0]; $cname = $cat[1]; echo "<option value='$cid'>$cname</option> "; } echo "</select>"; i tried using <select name="c" size="1" onChange="MM_jumpMenu('parent',this,0)"> but i got confused so i'm looking for an alternative way..
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How To Generate Month Options In A Menu?
I'm trying to generate options in a menu that read <option value="2006-03-01 00:00:00.0">March, 2006</option> <option value="2006-04-01 00:00:00.0">April, 2006</option> .... <option value="2006-12-01 00:00:00.0">Decmeber, 2007</option> where the beginning is defined by the month/year of today's date and the end is defined by a constant "FINAL_YEAR". How would I generate the above menu using PHP 4?
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Frames To Display Menu Options
I am just starting web development after a long break (6 years). Last time I was developing frames were often used to display menu options on the side of the page. I was wondering as frames seem to be no longer used how would a menu bar on the left hand side of the website and possibly a bar along the top would be achieved in a php site?
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Restricting Access To Menu Options
I'm building a very simple content management site that tracks "tasks." The options available are: 1.Add Task 2.Edit Task 3.View Task 4.Print Task I need to restrict some users to only View and Print and I'm trying to find a way to tell the page not to load the menu options (the text) for those not having access to the Add and Edit functions. Code:
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Drop Down Options
I've got a drop down box which when I select the relevant item correcly updates the database but when I return to edit the form again the drop down is showing the wrong option even though the correct option is in the DB ....
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How To Add URL To Options In Drop Down List
I am have a drop down list, whose options are read in dynamically from a table in a MySQL database. one of the items being read in is an URL. I am unable to display this URL in the drop down list. The following is the code snippet I am using: Code:
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Drop Down That Holds Date Options
I have a drop down list that holds the following options: "today", "this week", "this month", "this year". Is it possible to get records from a mysql database based on what the user chooses from the above drop down using only one query? I know that using something like that: SELECT * FROM table WHERE (month(DATEFIELD) = month(now()) and dayofmonth(DATEFIELD) = (dayofmonth(now())) and year(DATEFIELD)=year(now())); I can retrieve today's records. So, one solution would be to create multiple queries and based on user input, execute the associated query. But given the fact that my form has various search criteria, i will end up with to many queries.
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Pick From A Drop Down List That Automatically Gives Options In A Second Dropdown Box
does anyone know how to create a form that allows the user to firstly pick from a drop down list that automatically gives options in a second dropdown box. eg. 'category1' is selected from dropdown box 1, this then populates dropdown box 2 with the options 'category1.a' or 'category1.b' or if 'category2' is selected from dropdown box 1 then dropdown box 2 gives the options of 'category2.a' or 'category1.b' i f any one knows how I should code this please help, if not point me in the direction of a tutorial that can.
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Drop Down Menu(add Cat)
I have DB to add category and forum to edit the terms that in the cat so I add this code in the edit forum to change the cat of the term by choose the cat from drop down menu PHP Code:
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Drop Down Menu?
Im looking for a script for a site im making that will make a drop down menu which I can customise the color of. Simple, like a border and background color, but is friendly with all types of IE explorer.
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Get Value In A Drop Down Menu
I try to build a drop down menu in a record update page the page get the id record to update the page example update.php?id=2 In the drop down menu, are there anyway I can get the value of the record that already insert? Everytime when i update the record, i have to set this level again. Code:
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Drop Down Menu And Php
the problem is i am trying to have the code work so that whoever wishes to add to the options given in the drop down menu can by choose add new option. the page seems fine and doesn't give me any errors but it doesn't seem to be adding the new option in the drop down menu list.
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Using Drop Down Menu
I have big problem. i have post this problem in alot of forums, but nobody help me. i have hear from my friend phpbuilder is the best php forum. so i to i register here. approve/delete comments using Drop Menu, look at the below example : Click here to view the example I want to approve some comments and to delete some comments.
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Php Drop Down Menu Variable
I have been playing with one script for more than two weeks. It is a simple poll script. Once the user has selected from a drop down menu...it is mailed to me. The problem is that I only get the first word of their choice! That defeats the purpose of having the poll!
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Echo Drop Down Menu
What I do is when the form is posted (php_self) it does its check and if there are errors, ie. user has not filled in required data, it takes them back to the form but the text fields are already filled in with what they have already typed. But the drop down menus default back to the PLEASE CHOOSE option, how can I get my drop down menu to be what they have just selected. The reason I need this is there are 6 drop down menus for different things on the page and a user would get fed up having to reselect each one when they have not filled in a field. Code:
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Populating A Drop Down Menu
How would I go about populating a Drop Down menu from data in MySQL? If you can show me wither a URL to learn this, or if you feel like telling me here, that would be great.
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Query Using Drop Down Menu
can i query a table based on a drop down list? i have a list of agents that i just want a simple drop down list to show the records they entered.... right now i just have the entire table showing all records in a html table format...but i want a drop down list so that if they only want to see the ones they entered, they can just select their name and poof...only theirs are shown...
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Drop Down Menu Refreshing
Sites that have mulitple drop down menus where 1 menu decides what the next menu will contacin, after you select the otion you need in menu 1 the next menu refreshs with its new contents and so on and so on..Is this done with Java?
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Updating SQL From Drop Down Menu
i am trying to change a php asset program to include another drop down menu , I have created the drop down and it shows the correct entries from Audit in sql , the process is that the user completes the php form for a new asset then clicks save to enter it to the database , the details below adds another drop down menu once they have selected the correct value i do not know how to capture this and write it back to the sql database . Code:
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Dynamic Drop Down Menu
I'm having difficulties displaying the MakeModelID for a row selected from a drop down menu I've populated from a table combining three attributes (Make, Model and Specification - for example Ford Transit LWB 350 HR). What I require is to capture in a variable, such as $MakeModelID, the ID for that record selected. Code:
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Drop Down Menu Values
I have a form below that shows a dropdown menu. The values are email addresses populated by my SQL database, with their associated names placed between the option tags. (Don't ask why I'm using a SQL database - not my decision) My dilemma: I need to insert the $ManagerName into another database, while at the same time emailing them. I DO NOT want to insert the email address into the database. Currently it won't work because only the value is entered into the database, and not what is showing in the selection list. Code:
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Drop Down List Menu.
How do I make one item required on my "drop down" list menu? E.g., let's say that I want one state to be selected, how do I make this possible with PHP? My PHP skill is amature, but I do understand most.
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Drop Down Menu Without Using A Database?
A lot of people are turning off javascript on their browsers so the script doesn't always work. I would like to know Is their a php script that can do the same thing without using a database? Can I get the links to open in a new window when they are selected?
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How To Make A Nav Menu Drop Down In Php
i am interested in learning to make a drop down menu bar - the ones you hover the mouse over and a drop down list of choices (with an almost transparent bg) comes down. then when click it takes you to another page that has another sidebar which highlights the page you are in. so on the side bar you can click and both the img on side bar and the menu bar will change so to indicate what section of the site you are in.
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Re-create A Drop-down Menu
I have 2 drop-down menus (1) States (2) Shows By State. how do I invoke a re-build of the Shows By State drop-down when the user requests a different state. I believe this has to be done with Javascript and I don't know Javascript. Could someone supply a small example of how this is done? I am using PHP and MySQL. Following is the PHP code for building the state drop-down menu: <tr><td bgcolor="#EFC891" width="496" align="left"><b>Select a Show in Your State: <select name="ShowState" > <?php $stateName=getStateName(); $stateCode=getStateCode(); for ($n=1;$n<=50;$n++) { $state=$stateName[$n]; $scode=$stateCode[$n]; echo "<option value='$scode'"; ..............
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Dynamic Drop Down Menu?
I have a customer table and I wish to be able to dynamically generate a drop down menu, to, for example, select the customer for which operations are to be performed. after I have made the initial select statements, I assume i will then need to use a while loop but this is where I am getting stuck....I am familiar with using while loops for creating tables dynamically but i'm not sure about drop downs. I just wish to show "company name" in the menu. While it be something along the lines of.... while ( $row = mysql_fetch_array ( $sql ) option = $customer_name etc..
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Keep Selection Of Drop Down From Menu
Im just working on a enquiry form submission script. When the form is submitted a php scripts checks for empty fields etc. If a empty field is found the for comes back and a error messages is displayed. When the forms re-appears the fields which werent filled out correctly before stay filled in, simply putting setting the fields 'value' with the $_post variables. Now this is ok but is there a way so if the users selects a choice from my drop menu the first time that this choice remains when the form re-appears if something else was found to be invalid ?? Hope I explained that ok?
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Nested Drop Down Menu
I am very familiar with php but I don't know javascript very well at all, and I suspect I may need to know some for this, so I'm looking for some pointers. I need to create a set of nested drop down menus that populate using data from a mysql database. So here's an example.....
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Drop Down Menu Redirection
Im having some troubles. When a user selects a topic from a drop down I want it so that when they click submit it brings them to a corresponding html page ....
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How Do You Create Sub Drop Down Menu?
I have been wanting to create this for my site but i am not sure how. I would appreciate if anyone could show me some example code of how it's done. What want to do is basically, say there are 2 drop down menus on my site, one for country and one for region. Say in the country menu you select UK, i would like all the regions in the UK to show up only, and if you select another country, only the regions in that particular country will show up. I am sure you understand what i mean. I would be very grateful if someone could show us how this is done.
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Assign Value From A Drop Down Menu
I am trying to assign a value to a PHP variable from a drop down menu. The default value is "no." However if "yes" is chosen, I want that to be assigned to $_POST['local_pickup'] Here is what I have so far: <select> <option class = "blue_standard">No</option> <option class = "blue_standard">Yes</option> <?php if ($_POST['local_pickup'] == 'yes') echo $_POST['local_pickup']; ?> </select> Can anyone suggest how to get the yes value assigned to the $_POST['local_pickup'] variable if "yes" is chosen.
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Add Values To A Drop Down Menu
I am trying to use this code to add values to a drop down menu. I can tell the variable is being passed to the correct document(PHP_SELF) however the value will not store into the mysql table. is my syntax incorrect? I've read and copied and pasted several samples of scrips attempting the same task but they are causing parse errors. Code:
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Selected Value In Drop Down Menu
I want the first option ("selected" option) in a drop down menu to be based on the URL a user clicks on. For example, if the user clicks on the link: layouts.php?submit=true&category=abstract The first and selected value in the drop down menu should be abstract Then the rest of the menu will pull from the database. The code I am using now (below) lists all my categories from my database, but it is not putting the selected value first. How can I get this to work?? Code:
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Drop Down Menu Of Pictures
I will be here for a long time to help others. You have to share your knowledge. Anyhoo, I would like to know if this is possible: Drop Down Menu of Pictures. Choose your host: (drop down menu of host faces). Keep in mind I'm totally new to PHP so if my question is really stupid, please don't hurt my feelings.
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Populating Drop Down Menu
I use the following code snippet to build a drop down menu with the results of a query. How can I set the initial value of this input based on the result of another query? What I am trying to do is update records in the data base. The field WkEndDate is pulled along with the rest of the record and the drop down menu is built from a table of valid WkEndDate values. Code:
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Drop-down Menu Item
I am looking for a way to submit my form without having the user click the submit button. I would like them to choose one option from a drop-down list, then I would dynamically populate the next drop-down list and so on, as in car buying websites. Choose Make --> then it populates the models ---> Choose Model. I gave this a try in Javascript but was unsucessful. I prefer to do it in php if possible because the user may have Javascript disabled, but if anyway knows of a sure way of doing this in javascript, I'm also open to that as well.
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Verify - Drop Menu
I have a form in HTML and a verification php file to check all required fields. Everything is perfect, except I don't know how to check drop menus (state, and topic). I'm using this code for the other fields: if (!ereg("^[A-Za-z]{1,}$",$firstname)){ echo ("<center>You entered an invalid <font color="#FF0000"><b>FirstName</b></font>.</center> "); echo ("<br /><br />"); $validated = false; }
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Dynamic Drop Down Menu
I'm trying to send emails to different users based on what is selected from a dynamic drop down list. Here is what I have that doesn't work: PHP Code: <?php $to = "me@myemail.com"; $subject = "current email test"; $message = "New RMA FORM FOR $rma"; $id = $_POST['status']; $query = "select id from mytablename where id='$id'"; $result = mysql_query($query); if (mysql_num_rows($result)==1){ Â Â Â Â mail($to, $subject, $message); } ?>
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Getting The Data From A Drop Down Menu
I have a sequence of drop down menus but I don't know how I can store the responses in other variables. Right now the output I'm getting looks like: location1 [status1] [change] location2 [status2] [change] location3 [status3] [change] . . . . where all the [status] are drop down menus and the [change] is a submit box. I'd like to use the change button to change the status of the location in the mysql database. How can I at least get my hands on the location that they modified and the new status of that location? Code:
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Multiple Search With More Than 2 Drop Down Menu
I have problem with multiple search with more than 2 drop down menu. After submit from search.htm, in the results.php page i dont get results or error and i dont know where the problem is. look my code and tell me if you see something or error in sourcecode PHP Code:
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Select Table From Drop Down Menu
I'm trying to select a table to submit form data to from a pull down menu. How do I submit the table along with the input data? I know I need to modify this line ($sql = " INSERT INTO $dnc "; )somehow to use the table selected in the pulldown menu. Code:
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Drop Down Menu Selection Activation
I have a form that is populated with a drop down list and a list box. I want to be able to automatically populate the list box, whenever a user selects a new item from the drop down list. Is there a way of doing this as soon as a new item is selected from the drop down box? (I'm trying to mimic a rich client interface in a web browser).
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Creating Dynamic Drop Down Menu
I have a mysql database called Auditions with a table called Sept7. The table has two columns Time and Name. I want to create a dynamic pull down menu and populate it with items pulled from the table based on a query. Code:
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Showing What Was Selected In Drop-down Menu
I'm trying to create a form where the user inputs data, i validate it with php, and if some of the input is missing or invalid then i print out errors with the form filled out with the information they entered/selected previously so they can change/add to it. The problem I'm having is setting my drop down menus to be selected when the form is returned instead of returning their original state. The menu I have is named A ($A). Here's an example of what I'm doing that isn't working: PHP Code:
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Default Select Drop Down Menu?
I have a drop down menu populated via a script that pulls all categories from the category table. However, when a user clicks to view a specify category (i.e. Toys), I want the drop down menu to display toys as the default value. Code:
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User Selection From Drop Down Menu
I have 2 drop down menus. 1 is to pick a Province and the other is to pick a trade (plumbng electrical etc) The user selects which province and then what trade then hits submit which should list all entries in the table. How would I formulate the select statment for MySQL to display the results in a webpage. The variable in my form are $province and $category
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