Strtotime() Pre-1970
if I code
$birth = strtotime(Ƈ April 1950');
then $birth = -1, I guess that this is because time "began" on 1st Jan, 1970. (although I seem to remember a few good times before that). So, what's the easiest way to find out how many days old I am (exactly, please, not just taking 1 April 1970 and adding 20 *365, which does not account for leap years?
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