Strtotime - Setting From Present
I am having trouble setting the strtotime function to echo 'Y-m-d' on any day from 1 - 24 months past.
I have attempted the following from links that call to different ranges of dates; 6 months, 9 months, 12 months, etc. -- from present time:
My SQL is set up as follows:
WHERE Date between 'pastDATE' and CURDATE()
pastDATE = $HTTP_GET_VARS["getDATE"]
<a href="oldies.php?getDATE=<? echo strtotime ("-6 months ago"); ?>"> 6 MONTHS OLD </a>
How can I echo the strtotime as "Y-m-d"?
View Complete Forum Thread with Replies
Related Forum Messages:
Present File For Download
I was using my contract company's website to download a pdf. Basically they provide a form, with radio buttons. after i select a radio, the file download prompt window pops up for me to download the file.
View Replies !
SOAP: Procedure 'foo' Not Present
I'm trying to find out what is causing this error: <faultstring>Procedure 'foo' not present</faultstring> I've got a class 'bar' with a public function 'foo'. I create a SOAPServer with a wsdl, call setClass with a single parameter, the string 'bar', then call the SOAPServer's handle() function. However, the result from a client is always the above message (wrapped in a SOAPFault). If I try to access a function that is not present in the wsdl or class bar, say foo2, I receive the message "Unrecognized method 'foo2'. List of available method(s): foo." If I loop through the output of the SOAPServer's getFunctions() function, it does indeed say that function foo is available. So, the question is, what is causing the "Procedure 'foo' is not present" message?
View Replies !
How To Display Only Entires Where Certain Field Is Present
I am trying to display some data from my database. I only want to display the entires that have a certain field populated. EG. If I have a list of names and addresses, only some of which have phone numbers. I want to call only the entries which have phone numbers and display them. What do I do with the where statement?
View Replies !
Upload And Present As HTML Page?
I'd like to have a form where users can upload a photo, add a short bio, put in some contact info, and have all of this information stored in a database (natch). Then I'd like for this form to take this user's data and put it into an html presentation template. Ideally, members would sign in and be able to modify their own profiles as well as view other profiles. Basically I need the sort of functionality you see on dating sites or job search sites.
View Replies !
MySQL, Check If The Result/row Is Present/not Empty
I am using the following code to check if the result is present if not display error message. $num_rows = mysql_num_rows($result); if ($num_rows == 0){ header(error.php ) /// redirect to error message } however this does not seem to work. BUT! when i do this $num_rows = mysql_num_rows($result); if ($num_rows > 0){ header(error.php ) /// redirect to error message } then it works but for the wrong reason. i need it to redirect to the error message if their is no result e.g. no rows displayed.
View Replies !
How Do I Present A Form For Users To Be Able To Upload One Or More Pictures
I would like for users to be able to upload files to my site. However, considering the size of image files nowadays from digital cameras, these files would all have to be resized so that they aren't too big (maybe 200kb or so). So my question is how do I present a form for users to be able to upload one (or more) pictures to the website, and then resize all of these pictures. I don't know even how to give permission for files to be added to the server by people other than myself... Thanks for any answers, or at least for pointing me in the right direction.
View Replies !
Check A Session To See If It Contains A Word & If Present Echo A Statement
I would like to know how to check a session - to see if it contains 2 letters at the begining of a certain word. - and if it does echo "statement"; i.e $_SESSION['cart'] I have items with ID's that start with 2 letters and then 3 numbers i.e FF345, FF561, OF456 (Nice and simple) Now how would I check a session to see if it contains an item with the ID "OF" at the start? And if any item that starts with "OF" is present then simply echo "Something Here"; ?
View Replies !
Php Configure File Not Present In Current LAMP Configuration - CURL Implementation
I run a few websites, and feel fairly confident about my PHP skills, but not so much with my Linux skills. We are running PHP 4.3.6, and I need to configure it to utilize cURL. I got cURL installed and configured on the server, but now I need to reconfigure PHP with the command: ./configure --with-mysql --with-apache=../apache_1.3.31 --with-curl=/usr/local/lib The only problem is that my confgure file is not present in the PHP directory. I'm not sure where to go with this. I'm trying to get the site set up to be able to connect to Authorize.net, and I can't get past this cURL problem. Does anyone have any idea what I need to do to get PHP configured to recognize the cURL functionality?
View Replies !
Present An Array Of Data, And The Corresponding Primary Key And Let The Code Work Out Whether To INSERT Or UPDATE It.
There's lots of DB abstraction layers out there, but a quick look around them hasn't turned up anything which seems to met my requirements. Before I go off and write one I thought I'd ask here if anyone knows of such a beast... I want some code where I present an array of data, and the corresponding primary key and let the code work out whether to INSERT or UPDATE it, I also want to be able to present the data from a QBF or QBE then be able to step through the result set. However I don't want to have to configure the DBMS structure - after all most of it is already in the DBMS (OK so not the relationships in a MySQL db). It'd be really cool if I could throw SQL directly at it *too*.
View Replies !
Using Strtotime()
Lets say I have a variable $time = 'Apr 30 2007 7:00AM'. Is there a function that I can use or a way of using the strtotime function to see if that variable $time is between the hours of 7am and 7pm?
View Replies !
Strtotime
I am trying to compare 2 dates, so that if a post is older that 90 days the user is not allowed to edit it. i am storing the post date in mysql in datetime field (2007-04-21 10:53:07). My question is how to user strtotime function to compare the NOW() date&time with the stored one, so if greater that 90 days return true.
View Replies !
A Bug With Strtotime
Something seems to be wrong with the strtotime function in PHP5. I've created a staff resourcing database, which is used to assign staff to projects on a weekly basis. The database stores assignments against a week ending date, which is derived using: PHP Code: $week = date('Y-m-d',strtotime('Sunday')) This works fine, $week is set to the current week ending date (Sunday) using this. However, I also create $nextweek and $lastweek using: PHP Code: $nextweek = date('Y-m-d',strtotime('next sunday',strtotime($week))); $lastweek = date('Y-m-d',strtotime('last sunday',strtotime($week))); This has also been working fine, until we got to week ending Sunday 30th October. For some reason, when $week = 2005-10-30, $nextweek becomes 2005-10-05, which is a Saturday. I've tried replacing the 'next Sunday' with '+7 days', but this returns the same date. Is this a bug? Am I missing something?
View Replies !
Strtotime &
I've got a question and was hoping someone could offer some assistance. I've got this simple line in a test file. PHP Code: echo date("Y-m-d", strtotime("next Monday")); Here's my results using different versions of PHP:PHP 4.4.7: 2007-11-04PHP 5.1.2: 2007-11-05PHP 5.2.3: 2007-11-05 Todays date is November 03, 2007 (2007-11-03).
View Replies !
Strtotime()
<?php $current = date ("F", strtotime("now")); $next = date("F", strtotime("next month")); //or try "+1 month" echo $current.'...'.$next; ?>
View Replies !
Problem With Strtotime
I am stucked with strtotime to convert date earlier than 1970 into time. Is there any other way to convert older dates between 1900-1970 into time?
View Replies !
StrToTime () Issue
I'm using strtotime to get the timestamp for midnight. I have a statistics script for my pagecounter that displays hits since midnight. I also display the number of hours and minutes passed since midnight. $start = strtotime ('today 00:00'); $timepassed = date ('H:i', time () - $start); The weird part is at 11.30 AM it says 12 hrs and 30 minutes have passed. I tried adding GMT+1 like so: $start = strtotime ('today 00:00 GMT+1'); because I suspect the fact I'm in Holland is the reason for the miscalculation. But this format is refused by strtotime. (-1) Does anyone know a) whether this is indeed the problem, and b) how to fix it. Preferrably not alone for me here, but in suc a way anyone around the globe would have a correctly working script if they'd use mine. The php page for strtotime pointed me to a link at gnu.org where the syntax for it apparantly is listed, but I get a no such page error.
View Replies !
Strtotime And Cron
I've got a db of events which have dates attached to them which have been created using strtotime(). They don't have any time.. just the date. I've got a script which gets today's date using strtotime("today"). I use this as a comparison to find events which happen today. This works fine when I call the script from a URL, however when I called the php file from a cron job... the strtotime("today") creates values which are different each time. Are there any thoughts on what could be causing this? Firstly, I was wondering if the cron job was somehow using a different timezone to me (I'm On GMT). How do I explicitly tell php to use GMT.. .but then again.. this should matter too much, because I jsut want to date not the time! It also wouldn't account for the changing values of strtotime("today"). Just out of interest, does php4 and php5 handle strtotime("today") differently? I'm just wondering if cron is using the correct version of php?
View Replies !
Strtotime Question?
I have a string that looks like (a series of them) 1 Sep 2007 21:06:11 2 Sep 2007 13:45:31 2 Sep 2007 13:45:31 3 Sep 2007 01:40:42 and I want to go strto time on it any ideas its return -1 right now so I know somethings wrong.
View Replies !
Date Strtotime
i am trying to right a date into the mysql database but when i get the date from the html form and do strtotime on it it goes to an invalid date (by this i mean it is not the date i entered in the html form so for example 22-06-2007 changes to 28-11-2027).
View Replies !
Remove 0 From Strtotime?
Like every other blog in the world, I have mine displaying the date and time of each entry. Right now this is what I'm using: echo date('h:ia', strtotime($r[date])); My latest entry's time is displayed as 07:56pm. How do I remove the 0 when the hour is a single digit?
View Replies !
Strtotime(date('m/d/Y'))
does the following code give the correct time:?strtotime(date('m/d/Y')) or do I need to use : strtotime(date('d/m/Y'))? I tried to find out which way the month and day work, but can't seem to find anything that will tell me.
View Replies !
Strtotime() Pre-1970
if I code $birth = strtotime(Ƈ April 1950'); then $birth = -1, I guess that this is because time "began" on 1st Jan, 1970. (although I seem to remember a few good times before that). So, what's the easiest way to find out how many days old I am (exactly, please, not just taking 1 April 1970 and adding 20 *365, which does not account for leap years?
View Replies !
Strtotime Failure
I don't know how I should input date + time into a strtotime function (i'm a total noob) so I tested this: <? $d=01; $M=01; $y=1970; $h=01; $m=01; $s=01; echo "$d $M $y $h:$m:$s"; echo strtotime("$d $M $y $h:$m:$s"); ?> I get as echo strtotime '-1', wich means the strtotime has a failure. Can anybody explain me why? Or can anybody tell me how I can make a strtotime function that puts a timestamp in the database depending on the date and time inserted in a textbox? (one textbox or one textbox to insert the day, another to insert the year,...) I should be able to change a format like (for example) this : 01-02-1990 00:00:00 (midnight) into a timestamp. so dd-mm-yyyy hh:mm:ss (or something else just to make it work)I'm clueless.
View Replies !
Strtotime With Days
On this - "next Thursday" is that next thursday or the next thursday ie: on wed will it show tomorrows time or the next week? PHP Code: <?php echo strtotime("now"); $timestamp = strtotime("now"); echo "Â Â "; $str = date('l dS of F Y h:i:s A', $timestamp); echo $str; ?> <p> <?php echo strtotime("next Thursday"), ""; $timestamp = strtotime("next Thursday"); echo "Â Â "; $str = date('l dS of F Y h:i:s A', $timestamp); echo $str;
View Replies !
Strtotime Problem
How do I find the number of seconds from a certain date to the current? I have logged in my database a completion date within the past year and I want to figure out how many seconds it has been since the completion date until now. I know the strtotime command is fairly versatile and I have tried the following without the right conclusion: PHP Code: strtotime("since ".$completion_date); //and strtotime("from ".$completion_date); What do I need to do to fix this?
View Replies !
Strtotime Busted
$thing = "2005-10-01"; $storedDate = date("z",strtotime($thing)); echo $storedDate; it just alwats returns today's date, ive tried it on a php5 server and it worked fine however on the server I need this one it is PHP4.2.
View Replies !
Strtotime() - Compare Two Dates
i dont get the format for it, say i have a date 06-06-2003, will it read that as month/day/year or day/month/year? what about mysql dates. 2003-06-06 how does it read those? i just want to compare two dates.
View Replies !
Strange Strtotime() Behavior
I'm trying to use the strtotime() function to manage sessions. But I get the following <?php print(time() . " - " . strtotime("+1 hour")); ?> outputs: 1097380666 - 1097308800 Strange strtotime("+1 hour") produced a time stamp less than the current time. It also never changes. In other words strtotime("+1 hour") always results in the time stamp 1097308800. I have also tried strtotime("+1 hour", time()) with the same result Is this correct, have I misunderstood the strtotime() function? I'm running Gentoo with kernal 2.6.8.1, php 5.0.1, apache2
View Replies !
Displaying A Date With Strtotime
I have successfully used strtotime to format the date on a webpage that is pulled form a MySQL database in the form yyyy-mm-dd. However, in another part of the webpage, I have to insert another date that may contain a NULL entry in the database. If I use strtotime to format this then it enters the current date, whereas I want it left blank.
View Replies !
Strtotime And A Very Mysterious Date
Namely the thirteenth of December 1901, 12:45:52, Pacific Time. All dates later than this passed in format "yyyy-mm-dd hh:mm:ss" to the strtotime function return the correct unix timestamp value (as can be verified by passing it back to date()). If a date earlier than 1901-12-13 12:45:52 is used, it returns an error. I tried this for a while to find the exact cut-off point, and this is it. Any reason - possibly a limitation of the integer value that is used? I didn't find this documented anywhere...
View Replies !
Strtotime - Use Abbreviations For Week
I'm pretty sure I used to be able to use abbreviations for week (w), days (d), etc in strtotime (e.g. strtotime("-3d") = 3 days ago), but now it doesn't work as expected unless I specifiy the whole word ("-3 days"). Has anyone else come across this ?
View Replies !
Comparing Dates With Strtotime()
I'm building a schedule script--well, modifying one I built last year--to add an event every second and third Sunday of the month. However, when I try to find that Sunday, and compare to my timestamp, I run into trouble: $myDays = getMyDays(); Code:
View Replies !
Use Strtotime To Convert A Date
I am trying to use strtotime to convert a date, gathered from a database, and add 21 days to the date. Example: Date from MySQL record is 2007-01-01 I need it to be echoed to the browser as 2007-01-22. Here is what I have now but it just outputs the database date without adding the 21 days. $requested = date('F jS, Y', strtotime($row['letter_requested'])); //Convert to letter requested date $sendBy = strtotime($requested, '+21 day'); echo $sendBy;
View Replies !
Strtotime - Data That's Output From My Db
I have data that's output from my db in the form Sunday 9th September 2007 21:29:22. I'm getting it by using <?php $timestamp= $row['timestamp']; echo date('l jS F Y H:i:s', strtotime($timestamp)); ?> I'd like to add 19 hours to it, but have no idea how to.
View Replies !
Difference Between Two Dates Using Strtotime
im having some problem regarding strtotime and date function.. i want to find the difference between two dates using strtotime.. and then use the difference in loop to determine the dates between the two given dates... but instead of year 2007.. the output year is 2001.. how come? here's my code:
View Replies !
Strtotime - Get The Dates Converted?
I inherited a website with an SQL database. I need to pull information from the database into Excel for future use but the date fields are in strtotime from what I can tell. (Example: 1149996306). Is there a formula I can plug into Excel that would allow me to convert these dates to actual dates I can use? Or is there a SQL script that I can insert in MySQL or Access to get the dates converted?
View Replies !
Strtotime And Date Functions
I'm trying to add 3 days to a stored starting date: echo $_SESSION['start_date']."<br>"; $new_timestamp = ($_SESSION['start_date'] + strtotime("+3 days")); $new_date = date('Y-m-d', $new_timestamp); echo $new_date; This ouputs: 2007-02-18 2007-02-25 (which is clearly + 7 days?) I would expect it to output: 2007-02-18 2007-02-21
View Replies !
More Date / Strtotime Confusion
I have an editable form, that (upon other things) retrieves a date from mysql. To prepopulate this text field, I use: $result = mysql_query("SELECT DATE_FORMAT(Expiration_Date, '%d-%b-%y') AS DateX FROM MyTable) or exit(mysql_error()); Which will return (for example): 01-Jan-06 I have a dropdown field that a user can use to select the number of days to add to this date. In addition, however, the user should also be allowed to opt to not use the dropdown, but type in the value instead, in the d-M-y format. Code:
View Replies !
Strtotime Accepting Invalid Values
I'm using strtotime to validate a date/time passed in from a form but am having some problems with it. It seems to allow invalid values, such as "2004-04-13 21:66:13". Does anyone know why this is? Is this a bug or a "feature"? I'm using PHP 4.3.2.
View Replies !
Strtotime & Relative Date String
I thought something like this would work to get the next February after a specified date. $nextFebruary = strtotime( "next February", $unixDate ); However, if $unixDate corresponds to a date after February, I get the February before $unixDate instead of the February of the following year. I can, of course, check to see if $nextFebruary < $unixDate and, if it is, make sure I jump forward one year. But, I am thinking there is an easier way to accomplish this...as I cannot think of the method myself, I thought someone else might know.
View Replies !
|