Converting Degrees To Radians
For those of you who have ever tried to use the Sin(),Cos() or Tan() functions. does anyone know why it takes the angle in Radians only, this has been quite anoying for me at times because the conversion of Degrees to Radians uses Pi.
Even if I use Pi to a ridiculous accuracy it still comes out slightly off. For example Sin(180 degrees) = 0 and 180 degrees in Radians is 2*Pi so in VB if I write Sin(2*Pi) i should get 0 but I don't doesn't matter if I split Pi up into 2 "Double" variables (30 decimal places, I think) it still comes out off. Wouldn't it have been easier to have made the functions to accept Degrees?
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Converting Radians To Degrees, How Can I Do It?
I need to be able to change the answer which is in radians to degrees.
lblSinValue.Caption = "The Sine Value of " & txtAngle & " is " & Math.Sin(txtAngle)
That is my current code for it. I need to make it in degrees but I cant figure it out. I have searched other threads to no avail. All help is greatly appreciated.
Sin && Cos In VB, Degrees/Radians
I have a program for which I need to calculate the Sin and Cos of certain angles.
The angles are represented in degrees.
However, when I put Sin(60) it gives me -0.3048....., which appears to be in radians instead of degrees.
I want it to be in degrees. ie: Sin(60) should be equal to Sqr(3)/2
(I actually want to do more complicated degrees, so I can't use exact values)
Is there any way to make VB calculate Sin using degrees instead of Radians?
Or alternatively, someone told me that to get it into degrees you would do Sin(180 * degree/ pi). However, how do I represent pi visual basic?
Any help would be much appreciated.
Radians To Degrees....
I'm making a triangle calculator and I thereby use sin, cos and tan.
The results is in radians,but I want them in Deg, so i multiply with 180 and divide with pi, but now the results equals 0 and angle a is 90 deg!!?!?!?
Could you please help me....
Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Pi = 3.1415926535897931 End Sub Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) End Sub Private Sub cmdBeregn_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdBeregn.Click VinkelA = txtVinkelA.Text VinkelB = txtVinkelB.Text SideA = txtSidea.Text SideB = txtSideb.Text SideC = txtSidec.Text 'Kontroller at der er de tilstrækkelige vinkler/sider If (txtVinkelA.Text = 0 And txtVinkelB.Text = 0) And _ (txtSidea.Text = 0 And txtSideb.Text = 0 Or txtSideb.Text = 0 And _ txtSidec.Text = 0 Or txtSidea.Text = 0 And txtSidec.Text = 0) Then MsgBox("Der er ikke de tilstrækkelige sider/vinkler til at fortsætte!", MsgBoxStyle.Exclamation, _ "Fejl!") End If 'Start beregninger. 'Tjek at Vinkel A findes. Hvis ikke findes den ud fra Vinkel B og Vinkel C. If VinkelA = 0 Then VinkelA = 180 - (90 + VinkelB) End If 'Vinkel B kendes ikke, så Vinkel A vil blive fundet ud fra siderne. If Not SideA = 0 And SideC = 0 Then VinkelA = Math.Asin(SideA / SideC) Else If Not SideA And SideB = 0 Then VinkelA = Math.Atan(SideA / SideB) Else If Not SideB And SideC = 0 Then VinkelA = Math.Acos(SideB / SideC) End If End If End If 'Find side a, hvis denne ikke allerede findes: If SideA = 0 Then If Not SideB = 0 Then SideA = SideB * Math.Tan(VinkelA) Else SideA = SideC * Math.Sin(VinkelA) If Not SideB And SideC = 0 Then SideA = Math.Sqrt(SideC ^ 2 - SideB ^ 2) End If End If End If 'Find side b. hvis denne ikke allerede findes: If SideB = 0 Then If Not SideA = 0 Then SideB = SideA / Math.Tan(VinkelA) Else SideB = SideC * Math.Cos(VinkelA) If Not SideA And SideC = 0 Then SideB = Math.Sqrt(SideC ^ 2 - SideA ^ 2) End If End If End If 'Find side c, hvis denne ikke allerde findes: If SideC = 0 Then If Not SideA = 0 Then SideC = SideA * Math.Sin(VinkelA) Else SideC = Math.Sqrt(SideA ^ 2 + SideB ^ 2) End If End If SideA = SideA * 180 / Pi SideB = SideB * 180 / Pi SideC = SideC * 180 / Pi SideB = SideB * 180 / Pi VinkelA = VinkelA * 180 / Pi VinkelB = VinkelB * 180 / Pi lblDone.Visible = True lblSidea.Visible = True lblSideb.Visible = True lblSidec.Visible = True lblVinkelA.Visible = True lblVinkelB.Visible = True lblSidea.Text = "Side a: " & SideA lblSideb.Text = "Side b: " & SideB lblSidec.Text = "Side c: " & SideC lblVinkelA.Text = "Vinkel A: " & VinkelA lblVinkelB.Text = "Vinkel B: " & VinkelB End Sub Private Sub cmdNulstil_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles cmdNulstil.Click 'Nulstil alle felter txtSidea.Text = 0 txtSideb.Text = 0 txtSidec.Text = 0 txtVinkelA.Text = 0 txtVinkelB.Text = 0 End SubEnd Class
Radians Vs Degrees
Im trying to get the Log() of the number in VB. After messing with the formula for a while I realized I could not get the same answer on the simplist number as I would with the M.S. calculator. It was then I figured out that by default, the Deg. is checked in calculator scientific view, when I checked Radians and ran my numbers I got the same answer as VB was giving me. What that tells me is that VB uses the Radians to give the Log() of a number. What I want to do is get the Degrees answer in VB, (the same answer I get in calculator with Degrees.)
Can anyone help?
Here is the code if it helps
Dim gain1 As Single
Dim gain2 As Single
Dim gain3 As Single
gain1 = 1.0666 * 1.0666 * 12 * .2126
gain2 = Log(gain1) ' Log of gain1 should be .4627 but its not in VB
gain3 = 11.8 + (10 * gain2)
t_gain.Text = gain3 ' this number should be 16.42 in VB but VB shows something very different
Work In Degrees Instead Of Radians
Is there a way to set your vb program to work in degrees rather than radians?
Would make my program a lot easier to understand, when using cos and sin of angles!
Radians Vs Degrees (Resolved)
m trying to get the Log() of the number in VB. After messing with the formula for a while I realized I could not get the same answer on the simplist number as I would with the M.S. calculator. It was then I figured out that by default, the Deg. is checked in calculator scientific view, when I checked Radians and ran my numbers I got the same answer as VB was giving me. What that tells me is that VB uses the Radians to give the Log() of a number. What I want to do is get the Degrees answer in VB, (the same answer I get in calculator with Degrees.)
Can anyone help?
Here is the code if it helps
Dim gain1 As Single Dim gain2 As Single Dim gain3 As Single gain1 = 1.0666 * 1.0666 * 12 * .2126 gain2 = Log(gain1) ' Log of gain1 should be .4627 but its not in VB gain3 = 11.8 + (10 * gain2) t_gain.Text = gain3 ' this number should be 16.42 in VB but VB shows something very different
Degrees, Radians, And Trig Functions
I'm making a pi calculator that uses the formula:
Pi = Sine(180/n)*n; Where n is a lage number less than infinity. the code looks like this:
Private Sub cmdCalc_Click()
Dim Value As Double
Dim Number As Integer
Number = txtN.Text
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txtAnswer.Text = Sin(Value) * Number
lblLen.Caption = Len(txtAnswer.Text)
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How can I convert that degree-format into a +/- 90 degree format?
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Is this doable? I can't get the logic behind doing such a thing, really wish my math was better. :/
Edited by - ThisIsMyUserName on 3/17/2006 1:05:32 PM
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I am new to this type of programing, so the simpler the answer, the better.
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These are the results that i am getting
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which is correct
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this is wrong t should = 225
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First i tried:
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Public Function CreateFont(ByVal oFont As StdFont, Optional ByVal eFontStyle As FontStyle = FontStyleRegular, Optional ByVal eUnit As Unit = UnitPoint) As Long
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Private Sub Command1_Click()
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