Right-click Menu And Sending Left Click To Item
Can anyone tell me how I can use insert a right-click menu into my program so that when the user has selected a file (in a file list) and right-clicks, a menu appears at the location of the mouse pointer. I aleady know how to use the PopupMenu function to show a menu as I suppose that will need to be used, I just don't know how to capture a right-click mouse event and also use the position of the mouse pointer to show the menu.
Thanks in advance!
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http://support.microsoft.com/default.aspx?scid=kb;en-us;137033
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Added green "resolved" checkmark - Hack
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Click On Menu Item [vb6]
Hi,
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Let me know if part of code or example is needed.
Thanks you for your help.
best regards.
yk.
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In the MDIform I have
Code:
Private Sub mnuIndividualSpinsTypeIn_Click()
frmNewSpins.Show
End Sub
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Code:
Private Sub imgNew_Click(Index As Integer)
Select Case Index
Case 0:
frmMain.mnuIndividualSpinsTypeIn_Click
End Select
End Sub
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Hello,
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Hi,
I have a list box which holds several list items (logs). I want to right click on the individual list items and select them (which only works with left click) and then show a popup menu.
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Thanks in advance
--------------------------------------------------
Should I apologize if what I say burns your
ears and stains your eyes?!
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Hello folks,
Here is my problem and I would appreciate your input.
When I want to left click on a lable, I want the colors of the label to change in one order.
When I want to right click on this label again, I want the color to change in opposite order.
It does the job but has one bug. For example, when I left click it works as expected but when I right click, it behave as it is left clicked (once) and then it changes to the opposite order. Please check the attachment. Thanks
Code:
Option Explicit
Dim intIncrementor As Integer
Private Sub Label3_MouseUp(Button As Integer, Shift As Integer, X As Single, Y As Single)
'Private Sub Label3_MouseDown(Button As Integer, Shift As Integer, X As Single, Y As Single)
' Select Case Button
' Case vbRightButton
' MsgBox "right button down"
' Case vbLeftButton
' MsgBox "left button down"
' End Select
'End Sub
Label6.Caption = intIncrementor
Select Case Button
Case vbRightButton
'intIncrementor = intIncrementor - 1
If intIncrementor = 0 Then
Label3.BackColor = &H0& 'black
intIncrementor = intIncrementor - 1
Label3.Caption = "black"
intIncrementor = 9 'reset to end
ElseIf intIncrementor = 1 Then
Label3.BackColor = &H404040 'brown
intIncrementor = intIncrementor - 1
Label3.Caption = "brown"
ElseIf intIncrementor = 2 Then
Label3.BackColor = &HFF& 'red
intIncrementor = intIncrementor - 1
Label3.Caption = "red"
ElseIf intIncrementor = 3 Then
Label3.BackColor = &H80FF& 'orange
intIncrementor = intIncrementor - 1
Label3.Caption = "orange"
ElseIf intIncrementor = 4 Then
Label3.BackColor = &HFFFF& 'yellow
intIncrementor = intIncrementor - 1
Label3.Caption = "yellow"
ElseIf intIncrementor = 5 Then
Label3.BackColor = &HC000& 'green
intIncrementor = intIncrementor - 1
Label3.Caption = "green"
ElseIf intIncrementor = 6 Then
Label3.BackColor = &HFF0000 'blue
intIncrementor = intIncrementor - 1
Label3.Caption = "blue"
ElseIf intIncrementor = 7 Then
Label3.BackColor = &HC000C0 'violet
intIncrementor = intIncrementor - 1
Label3.Caption = "violet"
ElseIf intIncrementor = 8 Then
Label3.BackColor = &HC0C0C0 'gray
intIncrementor = intIncrementor - 1
Label3.Caption = "gray"
ElseIf intIncrementor = 9 Then
Label3.BackColor = &HFFFFFF 'white
intIncrementor = intIncrementor - 1
Label3.Caption = "white"
End If
Case vbLeftButton
If intIncrementor = 0 Then
Label3.BackColor = &H0& 'black
intIncrementor = intIncrementor + 1
Label3.Caption = "black"
Label5.Caption = intIncrementor
ElseIf intIncrementor = 1 Then
Label3.BackColor = &H404040 'brown
intIncrementor = intIncrementor + 1
Label3.Caption = "brown"
ElseIf intIncrementor = 2 Then
Label3.BackColor = &HFF& 'red
intIncrementor = intIncrementor + 1
Label3.Caption = "red"
ElseIf intIncrementor = 3 Then
Label3.BackColor = &H80FF& 'orange
intIncrementor = intIncrementor + 1
Label3.Caption = "orange"
ElseIf intIncrementor = 4 Then
Label3.BackColor = &HFFFF& 'yellow
intIncrementor = intIncrementor + 1
Label3.Caption = "yellow"
ElseIf intIncrementor = 5 Then
Label3.BackColor = &HC000& 'green
intIncrementor = intIncrementor + 1
Label3.Caption = "green"
ElseIf intIncrementor = 6 Then
Label3.BackColor = &HFF0000 'blue
intIncrementor = intIncrementor + 1
Label3.Caption = "blue"
ElseIf intIncrementor = 7 Then
Label3.BackColor = &HC000C0 'violet
intIncrementor = intIncrementor + 1
Label3.Caption = "violet"
ElseIf intIncrementor = 8 Then
Label3.BackColor = &HC0C0C0 'gray
intIncrementor = intIncrementor + 1
Label3.Caption = "gray"
ElseIf intIncrementor = 9 Then
Label3.BackColor = &HFFFFFF 'white
intIncrementor = intIncrementor + 1
Label3.Caption = "white"
intIncrementor = 0 'reset to start
End If
End Select
End Sub
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I have a strange problem. I have a picture box and when the menu drops down and I make a selection on it the picture box captures the event and fires the mouse click event. Normally this would be no problem but the mouse click depends on what is plotted and seeing as how nothing is plotted I get an error message. Nothing wrong with the error because nothing is printed.
Does anybody know how to get around this?
I hope I have explained it good enough!
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Hi,
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Thanks in advance
Ciao
Steve
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now this is a problem with clicks!
i have a msflexgrid and when i select a row it highlights that row and other rows alternatingly by the given function below
its working perfect
also i have a mouseup event for the same grid it also works but i want it like this
when i right click a row the row must get selected first then the popup menu should appear.but what actually happens is that if i have selected the first row and then right click over the 3rd row .the 3rd row does not get selected but the selection remains over the first row! .how do i solve this
VB Code:
Private Sub msfg4_Click()Dim j%, iCurRow%Static iLastRow As Integer With msfg4 If .Row = 0 Then Exit Sub iCurRow = .Row If .Row <> iLastRow Then .Row = iLastRow For j = 1 To .Cols - 1 .Col = j If iLastRow Mod 2 = 0 Then .CellBackColor = ODDROW_COLOR Else .CellBackColor = EVENROW_COLOR End If Next j Else Exit Sub End If .Row = iCurRow For j = 1 To .Cols - 1 .Col = j .CellBackColor = SELROW_COLOR Next j iLastRow = .Row End With End Sub
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How can I detect the left/right if the object haven't mousedown, mousemove, mouseup... event??
How can I make the mouse right click whereever it is on the screen through code?
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Hi guys,
I have a listview (lvwUserPunchedOut) that is populated with records in a database (persons first name in one column and last name in the second column), what I am looking to do is if I select a persons name by clicking on it in the listview on frmMain, and then bring up frmSearchCriteria, i would like to show that selected name in the combobox as default (cboEmployee.ListIndex = 0) on frmSearchCriteria (the combobox is sorted = True and is also populated with first name and last name of the person)
How would this be done? Hope I make sense. Thanks in advance.
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I am using VXFlexGrid and when you left click it selects a cell. Is it possible to repeat this behavior with the right click? Some how I would have to get the xy of the click, then do try and pass that to the flex grid to let it knwo what cell to select? I couldn't find the right functions, or maybe i'm barking up the wrong tree?
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under the Form_Click sub, how would you say:
Code:
Private Sub Form1_Click
(click).Top = top 'variable
(click).Left = left 'variable
'where (click) is whatever the click is called
End Sub
On Right And Left Click Events
i also have a thread up about click and double click events but can someone plz tell me how to turn the following into read VB code
private sub label1_leftclick()
bit of code
end sub
private sub label1_rightclick()
a different bit of code
end sub
yeh somethin like that
thnx a lot im sure it could be done
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Hi,
I'm looking for some code to paste in the label1_click event to let this event only work when the left mouse button is pressed and not the middle or the right mouse button?
Thank you,
Gaz
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Hello,
This is probably a silly question but I was wondering how you could make Visual Basic 6.0 emulate a left click on a specific location?
So if you have a button on your form you make your code left click on command1!
Is that possibe and if so how would you go about it?
Thanks
Fraggy
PS: I hope my question was clear?
Playing A .wav On Left Click
Im using this code to play a .wav file everytime i left click
Code:
Option Explicit
Private Declare Function sndPlaySound Lib "winmm.dll" Alias "sndPlaySoundA" (ByVal lpszSoundName As String, ByVal uFlags As Long) As Long
Private Const SND_ASYNC = &H1
Private Sub Form_Mousedown(Button As Integer, Shift As Integer, X As Single, Y As Single)
sndPlaySound _
"The file Path", _
SND_ASYNC
Everytime i click on the form it will make the .wav play. But thats the thing it only plays when i click on the form. I want it to still play even if i click off the form. Thanks in advance.
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A ListView is populated with many items (all the items are URLs of web pages). I want that when any of the items is left-clicked with the mouse, then the user should be taken to that URL but if any of the items is right-clicked with the mouse, then a pop-up menu should come up. I tried it this way:
VB Code:
[color=blue]Private Sub ListView1_ItemClick(ByVal Item As MSComctlLib.ListItem) Item.SmallIcon = 2 wWeb.Navigate2 Item.TagEnd Sub Private Sub ListView1_MouseUp(Button As Integer, Shift As Integer, X As Single, Y As Single) If (Button = 2) Then PopupMenu mnuPopup ElseIf (Button = 1) Then Call ListView1_ItemClick(ListView1.SelectedItem) End IfEnd Sub[/color]
The problem with the above code is that when I right-click any item in the ListView, then the pop-up menu comes up but at the same time, the browser opens the URL that was clicked. How do I prevent the browser from navigating to the URL when any of the items in the ListView is right-clicked?
In fact, I didn't include the ElseIf condition in the ListView1_MouseUp event function but since right-clicking any item was taking the user to the appropriate URL, I added the ElseIf condition but that doesn't make any difference.
Thanks,
Arpan
How Would I Add A Left Click To This Button?
Code:
Private Sub Command1_Click()
Inet1.Execute "http://neopets.com/games/launch_game.phtml?age=0&chall=0&dc=&hiscore=600&sp=0&va=1&world=Space+Station&height=500&width=500&user_full_name=sasa_kill&r=1395972&game_id=156&nc_referer=neopets&questionSet=&quality=High"
End Sub
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Malb
Left And Right Mouse Click
I want to allow users to use the left mouse click while the right one will do something else... is there any way to check for which mouse button is clicked or _Click ?
~$uper-$tar
Disable The Left Click...
Here is the problem:
I have a ListView that list lots of URLs...
And I want to disable the left click in the "ItemClick"(ListView) method...
The user can only open when clicking with the right button
Apreciate,
Dany Gregory.
Left Mouse Click
how can I get VB to send a left mouse click to windows
so that windows thinks that the user did it over
the item the mouse is over
Mouse Left Click
Does anyone know what the code for a Left Mouse Click is? i want to loop certain keys in a continous cycle, i've completed the keyboard, i just need the code for the mouse. heres an example.
Private Sub Timer2_Timer()
SendKeys "z"
End Sub
Any help is appriciable
thanks.
Left Mouse Click Question
hello all.
i've come accross a small problem with mouseclicks and can't seem to find the awnser, and wondered if anyone knew how to do this.
basically all i want it to do is.
if label1.backcolour = vbred then
'click the left button on mouse
end if
any feedback would be greatly appreciated.
toothpick
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