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Using A Equations In Textbox


hello,
i want to write an equation with all the mathematical symbols in a textbox /Richtextbox. is there any dll which suppoerts it or any other way to do it.
in simple i want to do like how we r writing an equation in word 2000. i tried by adding that exe in my application but i failed to make it work at runtime.
can anyone helps me plz
Thnkx




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Code:
Private Sub cmdCalculate_Click()
Dim loopint As Double
Dim pos As Double
Dim pos2 As Double
Dim pos3 As Double

For loopint = 1 To 5
equ(i) = ""
Next loopint

Dim num1 As Double
Dim num2 As Double
Dim num3 As Double
Dim final As Double

equ(1) = txt1.Text ' }
equ(2) = txt2.Text ' }
equ(3) = txt3.Text ' } puts the equations into the array
equ(4) = txt4.Text ' }
equ(5) = txt5.Text ' }

For loopint = 1 To 5
'reset everything
num1 = 0
num2 = 0
num3 = 0
final = 0

'get #1
pos = InStr(equ(loopint), "X")
If pos = 0 Then pos = InStr(equ(loopint), "x")

If Left(equ(loopint), 1) = "X" Or Left(equ(loopint), 1) = "x" Then
num = 0
ElseIf Left(equ(loopint), 1) <> "X" Or Left(equ(loopint), 1) <> "x" Then
num1 = Left(equ(loopint), (pos - 1))
End If

'get #2
pos = InStr(equ(loopint), "+")
If pos = 0 Then
pos = InStr(equ(loopint), "-")
pos2 = InStr(equ(loopint), "=")
num2 = Mid(equ(loopint), (pos + 1), (pos2 - (pos + 1)))
num2 = num2 -1
ElseIf pos <> 0 Then
pos = InStr(equ(loopint), "+")
pos2 = InStr(equ(loopint), "=")
num2 = Mid(equ(loopint), (pos + 1), (pos2 - (pos + 1)))
End If

'get #3
num3 = Right(equ(loopint), (Len(equ(loopint)) - pos2))

If num1 <> 0 Then
final = ((num3 - num2) / num1)
ElseIf num1 = 0 Then
final = (num3 - num2)
End If
answer(loopint) = final

Next loopint
lblAnswer1.Caption = answer(1)
lblAnswer2.Caption = answer(2)
lblAnswer3.Caption = answer(3)
lblAnswer4.Caption = answer(4)
lblAnswer5.Caption = answer(5)
End Sub

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I have a Text box with the actual date it was received.

My code is as follows:

If [Ackn_of_Receipt_Due] > Date And IsNull(Me![Date Received]) Then
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Else:
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Howdy all,

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Code:
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The user needs the ability to create an equation that calculates the cost/lb of product based on Raw Materials Cost/Lbs of production. But raw materials cost is the sumation of all the data items that belong to the cost group. The units are related to the data item, so I know whether it is dollars, lbs, metric tons or whatever.

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Private Sub Command1_Click()
Dim t As Integer
Dim x As Long
Dim y As Long
Dim j As Integer

Do Until j = 100
For t = 1 To 1000
Let x = ((Sin(3 * t / 180)) * 1000) + 6000
Let y = ((Sin(4 * t / 180)) * 1000) + 4100
Command1.Move x, y
j = j + 1
Loop

Circle (x, y), 20, vbRed

Next t

Let Text1.Text = x
Let Text2.Text = y

End Sub

__

Private Sub Form_Load()
WindowState = 2
End Sub

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etc.

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For an example, see the screenshot of some sample output from my program. I would like to know what is the best method to solve a system of linear equations.

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For X = XMin to XMax
For Y = YMin to YMax
-Code-
next Y
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Invert Matrix, Solve Equations.
Various people have asked me about inverting matrices and solving simultaneous linear equations. Instead of answering several people via email, I am posting what I know here.

There is some untested code further on. I apologize if there are typo’s or syntax errors. When I do not get paid for my work, I am less obsessive compulsive about avoiding errors.

I am sure that there are C programs available somewhere for solving linear equations and/or inverting matrices. I suspect that there are also programs written for various Basic dialects, but am not sure of this. While there are various methods applicable, a technique called Gauss Jordan elimination (or some similar name) is the most widely used. Perhaps a search of the web will turn up source code.

Many years ago I wrote Matrix software for various mainframes, using assembler and various compiler languages, but have never written such code for a PC. I can give you the general idea of the Gauss Jordan algorithm. I am pretty sure that this post is accurate, but cannot guarantee that my memory is 100% accurate. For a price, I would write and test a VB program.

I will use some VB code to describe the method, but warn the reader that this code is being made up as I create this post. It should not be viewed as tested code which is syntax perfect. For the benefit of those with little or no background, I will try to make it as simple as possible, which might bore or insult the intelligence of more knowledgeable readers.

First an overview of the method.The overall concept can best be understood by imagining an array with M rows and 2*M columns. The left half is a matrix to be inverted and the right half is an Identity matrix (All zeros except for main diagonal. Id est: A(X, X) = 1 for all X, with other elements equal to zero).If you systematically transform the left half into the Identity matrix and perform the same operations on the right half, the Identity matrix (right half) becomes the inverse of the original matrix. Some might find the following more confusing than the code to be shown later. Others might find the code harder to understand without the following description. For example: Start by dividing every element in the first row by the first element. This results in a value of one for the element in the upper left corner of the original matrix (left half of array) and the reciprocal of that element in the upper left corner of the original identity matrix (right half of array).Next: Multiply every element in the new first row by the first element in the second row, and subtract the products from the corresponding elements in the second row. Do the same for the third and all subsequent rows.The result of the above two operations is that the first column of the original Matrix looks like the first column of an Identity Matrix, and the first column of the original identity matrix no longer looks like an Identity matrix.Similar operations are performed to further transform the left half into an Identity matrix and the right half into the Inverse.

When coding the above, only an M by M array is used. Column by column, the Matrix is transformed into the inverse. Think about the above described operations which transformed the first column of the Matrix and the first column of the Identity matrix. It is known before doing calculations that the right half of the array is an Identity matrix. It is also known what the first column of the left half will look like after the first few operations: It will look like the first column of an Identity matrix. It is not necessary to actually store any columns which look like columns of an Identity matrix. Hence, only an M by M array is required for the program.

Another digression before showing some code. The Gauss Jordan elimination can also be used to solve simultaneous linear equations. A set of M such equations can be represented by an M by M matrix (coefficients of the unknowns) and a column of constant terms. Hence, an M by (M+1) array can represent a system of M linear equations in M unknowns. Similarly an M by (M+2) array can represent two such systems which have the same coefficients. If the operations which transform the matrix into the inverse are applied to the extra one (or more) columns originally containing constant terms, those extra columns will be transformed into solution vectors(s).

If it is only desired to obtain solution vectors, many of the inversion computations can be eliminated. After one set of operations, the first column of the matrix need not be processed. After two sets of operations, the first two columns need not be processed, and so forth.

One final digression before showing some code. The calculations require division, presenting the possibility of division by zero. The following code always uses a divisor from the main diagonal of the matrix, which is the simplest possible alternative. To avoid (if possible) division by zero and to improve precision, the correct algorithm analyzes the absolute value of potential divisors and chooses the largest possible divisor. This causes the resulting inverse and solution vectors to be scrambled, requiring some rearrangement of rows (and maybe columns) in the final array. The transform subroutine would not require any changes for off diagonal divisors, but the mainline which calls it would need modification. The mainline code shown is usable for most matrices.

A bit of jargon: The basic concept is a series of matrix transformations using pivot elements as divisors.

The following code is not a complete program, but indicates the basic computations and variables required.
Code:
Option Explicit
Public MatrixA() As Double 'Dynamic arrays to be dimensioned later.
Public WorkRow() As Double

Public MatrixSize As Integer 'Value supplied from external source
Public LastRow As Integer
Public LastColumn As Integer
Public X As Integer ‘Used in For loop

Public InvertMatrix As Boolean 'Assume these mutually exclusive
Public SolveEquations As Boolean 'Booleans initialized somehow.
Public DoBoth As Boolean
Public Junk As Integer
. . .
LastRow = MatrixSize - 1

If DoBoth Then
LastColumn = LastRow + 1 ‘Extra column for constant values
ElseIf InvertMatrix Then
LastColumn = LastRow ‘Square array
ElseIf SolveEquations Then
LastColumn = LastRow + 1 ‘Extra column for constant values
Else
Junk = MsgBox ("There is big trouble here")
Junk = 5 / 0
End If

ReDim MatrixA(0 To LastRow, 0 To LastColumn) As Double
ReDim WorkRow(0 To LastColumn) As Double
. . . .
‘Some code required here to obtain values and put them into array.
. . .
For X = 0 To LastRow ‘This loop call subroutine to do the work.
If InvertMatrix Then
Call Transform(X, X, 0)
ElseIf SolveEquations Then
Call Transform(X, X, X)
ElseIf DoBoth Then
Call Transform(X, X, 0)
Else
Junk = MsgBox("What happened?")
Junk = 5 / 0
Exit Sub
Next X
B]. . . .[/b]
‘Some code required here to display or pass results on for further processing.
. . .
Public Sub Transform(Row As Integer, Col As Integer, _
FirstColumn As Integer)
Dim J As Integer
Dim K As Integer
Dim PivotValue As Double
Dim RowMultiplier

PivotValue = MatrixA(Row, Col)

For J = FirstColumn To LastColumn
WorkRow(J) = MatrixA(Row, J) / PivotValue
Next J
'Following loop does some unnecessary work on Row
For J = 0 To LastRow
RowMultiplier = MatrixA(J, Col)

For K = 0 To LastColumn
MatrixA(J, K) = MatrixA(J, K) - RowMultiplier * WorkRow(K)
Next K

MatrixA(J, Col) = -RowMultiplier / PivotValue
Next J

For J = 0 To LastColumn
MatrixA(Row, J) = WorkRow(J)
Next J

MatrixA(Row, Col) = 1 / PivotValue

End Sub

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Hi guys,

does anybody know, how to solve the differential equations in VB 6 and how to make a graph input and calculate the unknown x for example from the graph straight in vb press clicking the button? cheers

Resize Multiple Images But Ignore Equations
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The problem is that I also have hundreds of equations made on mathtype (like equation editor). I don't want them to be affected.
The code i've tried to use goes like

For each iShape InliseShapes bla bla
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My problem is that I don't know the exact jargon for sthObject -meaning equation. Any ideas/suggestions?
Obviously the above code isn't the only one can be used. If u have sth elese in mind glad to hear.

Thnx in advance
apprentice

Help In Basic Air Data Equations/ Calculations In Excel
I have a couple of equations I need to figure out how to do in excel. But I dont know how to write them to use on the worksheet. I scaned the equations to jpeg but dont know how to post them to this form I dont know of any other way to have somebody take a look and see them to be able to help me.
If somebody will allow be to email the Jpeg tothem please let me know

How To Reveal Line Break For Perticuler Textbox In External Richtextbox/textbox?
Hi all could any one show me a method to identify the line break for perticuler richtextbox/textbox in external richtextbox/text. I am looking for things like this :<pbr>

I know all richtextbox/textboxes does not support that and some have thier own line break. could any one show me how to obtain that line break .thanks



class name info of rich edit :

RichEdit20A
#32770
AtlAxWin71
ATL:0053D798
WTL_SplitterWindow
WTL_SplitterWindow
WTL_SplitterWindow
My Window Class

Draw Textbox, Format Border And Type Text Into Textbox In A .doc File
I use this codes to open a .doc file and draw a textbox in it. What should I add to input text into the textbox (I used Selection.Text = "......." but the text are outside the textbox) and format it's borders?
[font=courier new][color=darkblue]
Private Sub Command1_Click()
Dim objWord As New Word.Application
Dim objDoc As Word.Document

objWord.DisplayAlerts = wdAlertsNone
Set objDoc = objWord.Documents.Add

objDoc.Shapes.AddTextbox msoTextOrientationHorizontal, 100, 100, 100, 300

objDoc.SaveAs "C:WINDOWSDesktoplabel.doc", wdFormatDocument
objWord.Quit

cmdEnd.SetFocus

TextBox – How To Invoke ‘Command_Click()’ Upon Carriage Return Press In TextBox
Hi All,

I have a TextBox which I use to enter a serial number and a Command Button to execute a query to a database that takes the value entered in the TextBox.

How do I simulate the ‘Command_Click’ event upon Carriage Return press in the TextBox after entering the serial number? (saves the user having to press the command button using mouse)

Thanks in advance, Ash

Text Dissapears Form Textbox When I Tab Or Click Into Another Textbox
The title says it all really.

I enter text into txtName and then I want to enter text into txtInitial so I either tab to it or click into it and when I do the entry in txtName just dissapears.!!!???!!

I am setting textbox proerties at runtime...

Code:
With txtAddMemName
.Text = ""
.TabIndex = 0
End With
Make sure the textbox is empty....Text = ""
Set the TabIndex....TabIndex = 0 ....and so on
I have all the textbox properties in Private Sub TextBoxProperties() so that the form load section is easier to read.

Is that not right?

Retreiving The Pixel Contents Of A TextBox When Textbox Is Not Visible?
Is that possible? I need to get the contents of a textbox using StretchBlt, but this only works when the TextBox is visibly on screen, other wise I just get the contents of the screen where the textbox would be shown. How can I do this?

Passing Array Value In Textbox. The Textbox Turns Up Empty.
I am passing the value of an array to a textbox, but it always turns up empty. When i pass the same value to an excel cell, i get the value. The function calculates the value of USCityA

I am giving parts of the code below:
Redim Pline(9)
Pline(9) = USCityA
test = "Hello"
USA = test & Pline(9)

In another sub, i call this funtion above to allocate the value of USC to the city as shown below:

CityA = USA

Activesheet.OLEobjects("txtbCityA").Object.Value = "CityA:" & CityA


The value i get in my textbox is only "Hello". When i pass USA to an excel cell, i get "Hello Fortworth" (or whatever the value of "USA" is calculated in the function)

Textbox Ctl Right Justify Sends Text Too Far Out The The Textbox [SOLVED]
I have a newly made textbox control by Thief_ that I've modified and it works fine if Alignment is set to 0 - Left, but if set to 1 - Right Justify I have to type in several numbers before they start to appear from the right. How can I fix this? What property do I have to change / include in the control to control where the string begins when set to right justify?


Thanks

_________________________________________________________________

Edited by - vbprog1144 on 5/30/2005 5:33:50 PM

Background Image In My Textbox Or Rich Textbox
I need to place a background image in a textbox or rich textbox as well. Is there no API or GDI(?) solution?

Background Image In My Textbox Or Rich Textbox
i would like to place a fixed background image in my textbox or rich textbox so it will act like a watermark. is that possible? please help.

i tried to use an rtf file template with image on it but everytime the rich textbox is updated the image is removed from view. i would like to remain on its position.

thank you very much. :P

Add Colored Text To Textbox Or Rich Textbox
Is there is script to make it add in a textbox the same text that is in the same text box plus some other colored text. eg

Before:

Code:
text

RichTextBox1.Text = RichTextBox1.Text + textFormated(&Hff,"lol")
After:

Code:
textlol

RichTextBox1.Text = RichTextBox1.Text + textFormated(&Hff0000," test")
After:

Code:
textlol test

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