I need to use print not println to declare stuff and I need to have string literals I think that's /n. Now when I compile it just shows row1, row2 ect. Why does it work like that?
public class art {
public static void main(String[] args) {
//local variables
String row1= "***********************";
String row2= "** *** *** **";
String row3= "** ***** ***** **";
public void addEvent(ActionEvent evt) { uname = Util.getUname(); boolean a = EventDAO.add(this); if ( a) { message = "Event has been added!";
[Code] ....
While executing this..i get the following error: ORA-01861: literal does not match format string. Could it be due to any mismatch in date format (chrome browser automatically takes date in the format mm-dd-yyyy )? If yes, how do I resolve it? (I'm using Oracle database)
I am working with java project which is kind of charting room..but the problem is when am writing the query for listing the message in the conversation the error prevail in my eclipse...string literal is not properly closed by double quote...this is my java file
The Java-program Matrix below first asks the user for the number of rows and columns in a matrix. After this the program asks for the values of the elements. Finally, program prints the elements of the matrix and their sum on screen. Your task is to create the missing methods. Check the example print to see how to modify the print. When printing the matrix, values on the same row are separated using tabulator.
Program to complete:
import java.util.Scanner; public class Matrix { public static void main(String[] args) { int rows, columns; Scanner reader = new Scanner(System.in); System.out.print("Type in the number of rows: ");
[code]...
Write the missing methods here / Methods are written in the text box below.
Example output
Type in the number of rows: 3 Type in the number of columns: 4 Type in the element 1 of the row 1: 1 Type in the element 2 of the row 1: 2 Type in the element 3 of the row 1: 3 Type in the element 4 of the row 1: 4 Type in the element 1 of the row 2: 5
[code]...
Matrix:
1 2 3 4 5 6 7 8 9 10 11 12
Sum of the elements of the matrix: 78
my code
import java.util.Scanner; public class apples { public static void main(String[] args) { int rows, columns; Scanner reader = new Scanner(System.in); System.out.print("Type in the number of rows: ");
I am writing a Java permutation program, it takes in N and k and gives k amount of combinations based on N length.
That portion works, but the portion I have that does not work is when k is greater then 1, the array is then then printing strings out of index.
The perm algorithm ends on index - 1 for moving characters but then I push all those characters into an Array List, I would think I could print them off however I want from there but that is not the case. I'll include the minimum amount of code possible.
//permString = 1234 or something, it doesn't matter //Use Case N = 4 k = 3, prints out 123,124,132,134 ect //Use Case N = 4 k = 2, error index out of range but only on the printing function; the perm function doesn't take k and //is based on length //the "" is just an empty string permNow("", permString); }
This is the code that I have so far, It will only print out the digit if it is entered first..How to I get it to print out all digits? and I am getting an error that the c is not initialized
import java.util.*; //Write a program that prompts the user for some text. Output only the digits in that text. Hint: Use a loop and the Character.isDigit method. public class Q1 {
Write an application that asks the user to enter his/her first name, last name, birthday, and where you born (all fields type String) and prints their information to the console. Use the techniques discuss in class. The data must be encapsulated. The program must be coded in Notpad++ and compiled in the Command Prompt.
Output should be like this:
Welcome!
What is your first name? Carlos
What is your last name? De La Torre
When is your birthday? 08/12/1979
Where did you born? Puerto Rico
First Name: Carlos
Last Name: De La Torre
Birthday : 08/12/1979
Born in : Puerto Rico
This is what I have so far :
package myinfo; import java.util.Scanner;
public class MyInfo { private String name; private String lastName; private String birthday; private String birthPlace;
Currently, my program converts Long values to String. And when I test it out, it do print out the correct output. However, when the converted String value is passed over to be written in a text file, it seems that BufferedWriter isn't printing out the outcome that it's supposed to be.
saltVs = Long.toString(saltV); System.out.print(saltVs); //will print out 79723172
Now the problem is here...It only prints out the last digit of the String value (instead of 79723172).
Here is my FileWriter/BufferedWriter part.
Why is that when I run my program using command prompt, it prints out the output that I wanted, but however when it comes to writing to the file, it doesn't come out right.
While doing trial and error got caught in the below scenario.
public class Crypt { public static void main (String args[]) { /*all I want is calculate a binary number (ex -: 22 , 34) using decimal base (10n). *So, I have to convert 2 p into 10n form so I have to find n in terms of p . We have x as the input. * The formula works as below. *2p =10n *p ln (2) =n ln (10) *n = p [ln(2) / ln(10)] *2 p = 10 p [ln(2) / ln(10)]
in Operator/Literals, it says "There is no literal representation for binary numbers in C, C++, or Java." seems "0b11001" could reprensent binary numbers?
I thought numeric literal were by default int or doubles, depending on if have a . and numbers after the But I wrote a quick test program as listed below. I understand the float float floatA = 5.5; failed to compile since 5.5 is a literal of type double and you are trying to assign this to a floag
What I am having problems with is byte byteA = 5; 5 is a literal of type int and this is being assigned to a byte and compiler should complain.The compiler does not allow two byte values to be added and assigned to a byte since the result of the addition is an int
class literalTesting{ public static void main(String[] arg){ byte byteA = 5; // allowed WHY I thought literal is an int and assigning int to byte byte byteB = 10; // allowed
byte b = 100; it works (implicit conversion of implicit int literal 100 to byte.
But if you have a methodvoid bla(byte b){}
And want to invoke it with a literal (which is an int by default):bla(8) then there is no implicit conversion.
Is the byte b = 100; just an exception in Java? And is it the rule that one has to explicitely cast (narrow) integer literals when passing to smaller-than-int types?
how the code is getting all the permutations of a string with recursion. The following code works correctly but I am having trouble grasping what it is doing.
public class Main { private static void permutation(String prefix, String str){ int n = str.length(); if (n == 0) System.out.println(prefix); else { for (int i = 0; i < n; i++) permutation(prefix + str.charAt(i), str.substring(0, i) + str.substring(i+1)); } } public static void main(String[] args) { permutation("", "ABCD"); } }
I see that each character is being appended to prefix through each iteration. So I know it adds "A" then "B" etc etc. I can follow it up until the "D" is appended to the prefix string. After that I don't understand how the D moves back to the str string and then the C moves back to str followed by the D moving back to the prefix string. I have stepped through the code many times in my debugger but still don't see how it moves back to str and knows to send D to prefix and not to send C. I feel I don't understand how recursion behaves therefore I can't follow.
I am trying to figure out how to convert a string of ASCII code into char.I know that you can use (char) to convert it, but the issue is you cannot really just it for Strings.
I am trying to code using error handling and I am a bit confused on how to go about doing it correctly. My code converts a string that has all numbers into an integer and the error handling should recognize that if it isn't a proper number and ask the user to try again or enter 'q' to quit.Do I place a throw new exception in the try block and put conditionals like if charAt(i) is some letter or a symbol then throw new exception?
Java Code:
import java.util.Scanner; public class practice { public static void main(String[] args) { Integer finalValue = null; boolean validValue = false; Scanner scan = new Scanner(System.in); int result = 0;
i.e. the generic alternative, I get this error message:
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -366 at java.lang.String.substring(Unknown Source) at main.HTMLGrabber.main(HTMLGrabber.java:45)
Is there a better and simple way to extract a substring?
import java.io.InputStreamReader; import java.util.Scanner; public class FinalCombinations { public static void main(String[] args){ //Read number of values System.out.println("Enter the no of values");
[Code] .....
I am getting output like this
Enter the no of values 4
Enter the values 1 2 3 4
Enter the number for combination 2 C(4,2)=6 1 1 2 1 1 3 1 1 4 2 2 3 2 2 4 3 3 4
where as I want output like this..wit one array 1 2 1 3 1 4 2 3 2 4 3 4
I was a bit confused of the code generated by the Axis2 Code Gen.
I have created a logIn(String username, String password) method in my service and used Axis2 Code Gen to generate the Stub.
I try to access the logIn method from my Client using the Stub like below:
TestServiceStub stub = new TestServiceStub("http://localhost:8080/axis2/services/TestService"); String test = stub.logIn("user","pass").
but instead of UserName and password as the parameters, the Stub created a Login object as the parameter for the logIn method. like the one below:
stub.logIn(Login login1);
I wanted to try the logIn method by providing a static userName and password but it seems impossible because the Stub changed the parameter for the logIn method.
The code here I have works fine if I just want to ask the user to enter four digits: //java application that asks user to input binary numbers(1 or 0) and convert them to decimal numbers import java.util.Scanner; //program uses class scanner public class binarynumber{
//main method that executes the java application public static void main(String args[]){ //declares variables
int digit; int base=2; int degree; double decimal; int binary_zero=0; int binary_one=1; //create scanner for object input
[code]....
The thing is, I want the java application to input more than four digits for the user and I want it to loop it manytimes f until the user ask it to stop.
I need to create a Java program that takes an input a color code in HSV and outputs the equivalent RGB code and Vice versa.
Example: If you test on the color RED in RGB: Input: (255,0,0) Output: (0,100%,100%) If you test on the color RED in HSV: Input0,100%,100%) Output: (255,0,0)