I have array contain numberi create new char array and i want to check if a number is >= 90 in array then input A at the same index in char arraythen second part i want to check if char array contain "A" then a = a + 1.
The result is like this:
A: 5
B: 29
C: 38
D: 24
E: 12
F: 17
public class Test {
public static char[] grades(int[] getMarks) {
char[] grade = new char[getMarks.length];
for (int i = 0; i < getMarks.length; i++) {
if (getMarks[i] >= 90) {
I can't figure out how to have all of the random characters generated to go into the String. Below I can only get the last character to covert over to a String.
System.out.println("Original random character string:"); String printingString = "a"; for (int i = 0; i < 50; i++)//loop to obtain 50 random characters { char randomChar = (char) ((Math.random() * 255) +32); System.out.print(randomChar); printingString = Character.toString(randomChar); } return printingString; }
Goal this time is to take a charArray, copy it into another charArray while reversing the things in it.
E.g. charArray["!ollaH"] into charArrayNew["Hallo!"]
My first idea was to revert the stuff in the Array with a ! cause i saw earlier that u can work with that too revert booleans. Sadly i didnt happen to make it work.
Next thing i thought of was a for loop to go trough the charArray and copy every section into charArrayNew just at the opposite end.
Java Code:
import java.util.Arrays; public class aufgabe43 { public static void main(String[] asgr){ char[] charArray
[Code] .....
Eclipse doesn't show any errors, and as u told me last time i did include import java.util.Arrays; to output the array in the end.
When i try to compile the code eclipse returns with an error
Java Code:
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 68 at aufgabe43.main(aufgabe43.java:8) mh_sh_highlight_all('java');
Which I frankly don't understand since the array . Length is exactly the same.
So I am working on a project for my Java course and for whatever reason, I am absolutely struggling with this assignment. I've made some progress but I can't seem to completely wrap my head around the algorithm I'm being told to use. I feel that everything is correct up to a particular point.I believe I am having issues moving a char array into a char matrix.
package edu.cofc.csci221.ui; import java.lang.*; public class Decoder { private int[][] M;
[code]...
Would I just need to loop through lsb one at a time and assign them to sequential spots within D? Basically call my get binary value and such in the outer loop and then use the inner to loop through both arrays and reassign values?
I'm trying to take the information from one 2d char array and put it into another char array but instead of traversing the array left to right I want the new array to be top to bottom.
Example fg would be fh hi gi
I'm having trouble getting the information from one to the other.
[code]public static char[][] translateIt(char[][] english){ int rows = english.length; int columns = english[0].length; char[][] chinese = new char[columns][rows]; for(int j=0; j < columns; j++){ for (int i = 0; i < rows; i++){ //chinese[i][j] = english; this is commented out because it didn't work. }//Ending bracket of columns for loop }//Ending bracket of rows for loop
return chinese; }//Ending bracket of translateIt[code]
I have a string array but each cell in the 1d string array stores each character the text file is :
"START START START The quick brown fox jumps over the lazy dog 1234567890-= !"$%^&*()_+ QWERTYUIOP{}ASDFGHJKL:@~|ZXCVBNM<><? /.,mnbvcxzasdfghjkkl;'#][poiuytrewq789654123.0 +-*/``""$% hello this is a test file using all the characters availible on the keyboard for input END END END END"
so in the string it is:[0] = S, [1]=A, [2]=R ...ect along the text basically i need to convert each character in each cell of the 1d string array to its hesidecimal value..i have created my own method which will take in a char and return a string containing the charcters hex value.
public static String toHex(char c) { char char2ascii = c; int i = 0; int num = (int) char2ascii; String hex ="";
[code]...
what i want to do is run each cell through the toHex method so i eventually have a string array containing the hex value of each character in my text.
example..i want:
String[] hexarray = S, T, A, R, T
a run it through my method to convert to hex then it will become
String[] hexarray = 53, 54, 41, 52, 54
Im not allowed to use inbuilt libarys and classes to do the hex conversion thats why i have my own method for it .
I am relatively new to java, and i am trying to create a window inside of a 2d char array, and eventually i will have to draw other shapes in this window. so for example
The problem is my window is not drawing correctly too the border, but a couple extra chars on the x columns. Here is code. The dimensions of the window will eventually be passed through scanner in main, if i ever work out how to even draw it.Also, in class we never learnt to use the Graphics class, so im pretty sure we are not supposed to use it.
public class Window { //default values private int xRow; private int yCol; private char ch; public char[][] windowz = new char[30][20]; //30,20 (yx)flat values cuz doesnt work
I'm trying to find a word in an array of char.....but I'm stuck. How to formulate the code to step through the array and pick out the word. This is what I have so far...
public static void searchAcross(String string, char[][] puzzle) { // Gets the number of rows in the matrix int rowLength = puzzle.length; //Gets the number of columns in the matrix. int colLength = puzzle[0].length;
What I'm trying to do is compare String input to a char array. Let me make it a little more plain, I'm working on a cipher assignment, and my line of thought is this: I will get String input from the user, COMPARE the characters in the string input to an alphabet array, which will then be compared to the cipher array so that the cipher's counterpart can be chosen over the alphabet's. Any way that I might compare the random input keyed in by the user to that alphabet array?
I had a Rest web service call and get InputStream.Now i want to Write Input Stream to PrintWriter of servlet.So that it can be downloaded.I am able to write String and file can be downloaded using following code, i want it to work for Input streamFollowing is code:
response.setContentType("application/x-download"); response.setHeader("Content-Disposition", "attachment; filename="" + name + ".pdf""); response.getWriter().write(is);
Write can take following: write(String) write(char[]) write(int) write(String, int len, int off) write(char[], int len, int off)
I think char[] will not harm PDF file which is going to download in it
I am trying to print a loop inside an array of a greater size than the loop itself. Like for example I have an array of size 7 but it has only 3 elements.
now what I want to do is print these three numbers in a loop so that my array[3]=2;array[4]=3;array[5]=4 ...... till the last one. Also the array could be any size and not just 7.
I have an array that I filled with 30 random characters, but now I am trying to sort them in ascending order and the descending order using lambda expressions.
public class RandomCharacters { public static void main(String args[]){ Random r =new Random(); char myarray[] = new char [30]; for (int i = 0 ; i < 30; i++)
I am writing a program which writes down all possible equation y=a+b+c values from min to max (in reality this equation would more difficult, but here is just short example).
The problem is that my sorting code can't get access to full array in loop.
Is there any way to pass array to sorting code, or somehow change sorting code?
package pkg06; public class Main { public static void main(String[] args) { double aS =-1; double aE = 3;
I need a phonebook that allows the user to input up to 100 numbers but stop when they want to. I have the code for the array and input and output. I thought I had the do...while loop correct for asking the user if they want to input another name but its not working, even when you input "N" it still keeps going. Here's my code.
import java.util.Scanner; import java.util.ArrayList; public class PhoneEntry2 { int x; char repeat; final int maxContacts = 100; String[] pNums = new String[100];
I have a 2 dimensional array assignment with a loop, i'm supposed find the average score of each student from a grade record and find the average score for each test. I've been trying to do the assignment all day with no progress. This is what i have so far
public class SiuTest { public static void main(String[] args) { String [] stu= new String [5]; int [] [] grade= new int [4][2]; String hold;
I have to take user input and then count how many times each number that the user input and print each one out. For some reason, I can't even get the for loop statement to print and it's pretty much the same as my other program except for the loop which is a little different.
//User inputs numbers between 1 and 100, program counts how many of each integer is and ends with a 0
import java.util.Scanner; public class occurrence { public static void main(String[] args) { //scanner/values Scanner input = new Scanner(System.in); int number = 0; int c = 0; //array count
What program needs to find is the most biggest number. It does the job, but another task of the program is to find the index of that number . The second loop should do just that, but for some reason, as the loop goes further, it passes through the if statement even though answer "a[i]" is not equal to "answer". The idea is that if a[i] and answer are equal, the "i" should represent the index number.
i want to check my array for a title, if the title is there i want to call a method, if the title is not there i want an error message. I am not sure how to get this. i think my code would work if it didn't always finish the method. for example if true the method stops and does run whats after the for loop. but that isn't happening.
void markItemOnLoan(String title, String name, String date){ int i=0; for (i = 0; i < numberOfItems; i++){ if (items[i].getTitle().equals(title)){ items[i].markOnLoan(name,date); } } System.out.println("ERROR: Can not find that item. "); }