I am working in the field of validating data. I need to validate names and test scores and i keeping getting errors in my code. I keep tracing back all the errors and now I am stuck at a logic error. It is giving me a the validate sentence over and over even when i type stuff in. I have searched up how to do the .equals to a string but it doesn't give me a accurate enough to my problem.
import java.util.Scanner;
public class P5A
{
public static void main (String args[]) {
System.out.println( "Always Show" );
Scanner reader = new Scanner(System.in);
Design and write a Java program that will generate a set of test scores between 0-100, inconclusive. The exact umber of scores is determined either randomly or by the user input. There should be a minimum of 5 test scores. The program calculates the average of all test score in this data set. Then it asks the user how many scores are to be dropped and drops that number of low scores. The average is recalculated.
Output of this program:
The original test scores printed in rows of 10 scores The average before low scores are dropped The number of low scores to be dropped The list of low scores dropped The new average
Write a program in JAVA in response to the following prompt:
Design a GUI program to find the weighted average of four test scores. The four test scores and their respective weights are given in the following format:
testscore1 weight1 ...
For example, the sample data is as follows:
75 0.20 95 0.35 85 0.15 65 0.30
The user is supposed to enter the data and press a Calculate button. The program must display the weighted average.
Here is what I have written:
import javax.swing.*; import java.awt.*; import java.awt.event.*; public class weightedaverage2 extends JFrame { private JLabel Score1L,Score2L,Score3L,Score4L;
a project I am working on. Its a program that creates a singly linked list that stores names and high scores and prints them. For some reason it is printing an entry extra times. Also my remove function is not working properly
GameEntry class: package project; public class GameEntry implements Comparable<GameEntry> { private String name; private int score; public GameEntry(String n, int s) { name = n;
Write a program that asks the user to enter five test scores. The program should display a letter grade for each score and the average test score. Write the following methods in the program:
calculateAverage This method should accept five test scores as arguments and return the average of the scores. determineGrade This method should accept a test score as an argument and return a letter grade for the score, based on the following grading scale
Score Letter Grade 90-100 A 80-89 B 70-79 C 60-69 D Below 60 F
System.out.println("Enter the first score"); test1 = keyboard.nextDouble(); System.out.println("Enter the second score"); test2 = keyboard.nextDouble();
I was almost finished with my program when I noticed I had a big logical error. At the very beginning of my else if statements I would jump down to my else statement.
Java Code:
import java.util.Scanner; public class InternetServiceProviderNew { public static void main(String[] args) { double packageA, packageB, packageC, extraA, extraB, userHours, aHours, bHours, cHours, userCharges; packageA = 9.95; packageB = 13.95; packageC = 19.95; aHours = 10; bHours = 20; String userPackage, A, B, C ;
Total IS those numbers. But question[10] will not cooperate with me and it's getting a bit aggravating as I can't find a logical reason for it to be doing that.how to perhaps lock the value of total and sTotal after 10 button clicks from any?
I have written this program but I am seeing error when I compile this program ( javac TestArithmetic.java).
1)TestArithmetic.java:26 cannot find symbol
2)symbol: class Arithmetic
3)location: class TestArithmetic
4) Arithmetic ar = new Arithmetic(x1,x2,x3);
1)TestArithmetic.java:26 cannot find symbol
2)symbol: class Arithmetic
3)location: class TestArithmetic
4) Arithmetic ar = new Arithmetic(x1,x2,x3);
2 errors.
Code :
import java.util.*; class TestArithmetic { public static void main (String[] args){ float number; Scanner console= new Scanner (System.in); System.out.println("Enter first number");
I am working on a program that simulates a bug moving along a horizontal line, My code works correctly when I test it in it's own class but when I tried testing my constructor and methods in a test class I received an error saying, "package stinkBug does not exist" on lines with my methods. However, stinkbug is not a package.
Java Code:
/* * To change this license header, choose License Headers in Project Properties. * To change this template file, choose Tools | Templates * and open the template in the editor. */
I've created a truth table for logical operators. Now I'm supposed to alter the code so the table prints 1's and 0's instead of true or false. Here's a bit of the original code - just the header and the first line of the table.
System.out.println("p q AND OR XOR NOT"); System.out.println(); boolean p, q; p = true; q = true; System.out.print( p + " " + q + " " ); System.out.print( ( p & q) + " " + ( p | q) + " "); System.out.println(( p ^ q ) + " " + ( !p) );
All of my ideas involve using an if-then statement, but that would be all kinds of inefficient and unwieldy, I think.
The title says already where my difficulties are. I forgot to say, the "S" printing part works, but why the others doesn't. To make it more clear:
java Monoton 1 3 3 4 & java Monoton 1 3 4 1
=> nothing (my output)
I forgot to notice, with 1 3 3 4 as parameters it jumps out at if (b < c), which is expected. but it jumps out of the whole if instead just run the else part. that's the essence of my problem.
The Exercise:
=> The program should print the following letters;
S, if every number is true bigger than the before,
M, if every number is bigger or equal than the before,
N in the other cases
Examples (from the exercise)
=> java Monoton 0 1 2 4
S
=> java Monoton 1 3 3 4
M
=> java Monoton 1 3 4 1
N
The Exercise should done without the use of logical operators or other combined requirements.
Java Code:
public class Main { public static void main(String[] args) { int a = Integer.parseInt(args[0]); int b = Integer.parseInt(args[1]); int c = Integer.parseInt(args[2]); int d = Integer.parseInt(args[3]);
Assuming that x, y, and z are integer variables, which of the following three logical expressions are equivalent to each other, that is, have equal values for all possible values of x, y, and z?
(x == y && x != z) || (x != y && x == z) (x == y || x == z) && (x != y || x != z) (x == y) != (x == z)
None of the three
A. I and II only B. II and III only C. I and III only D. I, II, and III
I selected B, but got it wrong. I really think I need understanding boolean logic. The correct answer says something else but I don't get the logic. Here is the correct answer:
Answer Key : The following model answer has been provided to you by the grader. Carefully compare your answer with the one provided here.
Expression III is the key to the answer: all three expressions state the fact that exactly one out of two equalities, x == y or x == z, is true. Expression I states that either the first and not the second or the second and not the first is true. Expression II states that one of the two is true and one of the two is false. Expression III simply states that they have different values. All three boil down to the same thing. The answer is E.
In exercise 4, I get the same problem:
The expression !((x <= y) && (y > 5)) is equivalent to which of the following?
A. (x <= y) && (y > 5) B. (x <= y) || (y > 5) C. (x >= y) || (y < 5) D. (x > y) || (y <= 5) E. (x > y) && (y <= 5)
Exercise 4 ABCDE Incorrect Score: 0 / 1 Submitted: 2/10/2014 8:21pm Your answer is incorrect. Answer Key
The following model answer has been provided to you by the grader. Carefully compare your answer with the one provided here. The given expression is pretty long, so if you try to plug in specific numbers you may lose a lot of time. Use De Morgan's Laws instead:
!((x <= y) && (y > 5)) !(x <= y) || !(y > 5)
When ! is distributed, && changes into ||, and vice-versa
I am thinking of a project for my university the teachers liked it but I am not sure if its even possible.I am trying to make an andriod app. What I want to do is take a picture of a hand drawn logic circuit (having the AND, OR, NOT ... gates) recognize the gates, and make a circuit in the moblie and run it on all possible inputs.
For this I will have to make a simulator on mobile, that I dont think is the hard part. The problem is how could recognize the gates from a picture. Example of logical circuit is attached ( assume its hand drawn )..I found out that theres a edge detection plugin in java but still I dont think its enought to recognize the gates. Please share any algorithm or any technique or tools that I can use to make this thing.
I created a GUI with a jTextField as an input box and am wondering how to validate that this data is an integer from 0 - 9. Here is what I have. However the if statement shows an error that says int cannot be dereferenced.
private void doneButtonActionPerformed(java.awt.event.ActionEvent evt) { //Create and Initialize Variable int category = Integer.parseInt(categoryInput.getText()); if (category.matches(0-9)); //int cannot be dereferenced error here {
I want to validate username and password in JavaScript. I want to validate username and password with database values. If login failed i want to display alert message...ok. But problem is that i have index.jsp page. After clicking login button control goes to homepage.
jsp..okk.. in index.jsp I have taken dropdown to show designation. I select design then control goes to respective homepage... in homepage. I am checking username and password with database values. If login successful it goes to respective pages but if login failed it has to show me alert message. How can i do that ?
Why will this NOT validate correctly in my IF Statement? Basically, a user chooses an option from the drop down list. The value is passed to t.jsp (itself) and if the option "All" is chosen, then it does something. If any of the years are chosen, then it does something else.
I have a JSP which will let a user register for an account at my website. If the user submits wrong or illegal info into the JSP, then I want to return the same JSP with an appropriate error message next to/above each wrongly filled (form) fields.
If possible, highlight the wrongly filled form field - this feature is not necessary though.
I have given a sample below to show what I need. I understand that the sample must be using something like javascript, but I don't know all that client side scripting. I only want to use JSP to do it. As I said, I want to sort of return the JSP form to the user after marking all the mistakes and how to correct them.
I have a click button called log off , here once a user clicks it , task goes to logout servlet to end current user session . below is my code , I don't know why it works fine with mozilla firefox and google chrom but not working with internet explorer.
here it goes fine to my index, but if I logged in again, I should enter a new session , but unfortunately this not happened in explorer , works fine with mozilla , and chroom.
I have also done in my index.jsp the check like below:
just to erase whatever previous session . But why session exist on same page ! only in explorer , it makes me open new explorer for new user and that is what I don't want !
Code given below does real time validation for 2 JTextFields. While entering some values to txt1 and txt2 enables the save button and removing values from txt2 or txt1 reset the save button to disable. I use Netbeans as IDE.What I want to do is, enable Save button after checking multiple JTextFields for validity. If any of the text fields is empty, btnSave must be disabled.This program gives expected result up to some extent. But there is little issue. After form appears for the first time, When I type something on Textfield1, Save button enables without checking Textfield2. This happens only at the first time.
public class NewJFrame extends javax.swing.JFrame { private Boolean isValidFromTextField1 = true; private Boolean isValidFromTextField2 = true; public NewJFrame() { initComponents(); btnSave.setEnabled(false);
I am trying to implement an example (Book* : Java SE 7 ..By S G Ganesh) for validating an IP address but it fails to validate a valid IP addresses. I found another example on the internet(**) and it works super fine, no problem at all. I edited the code (the one I got from internet) into the exact format like book and it still works super but i don't understand why the books' example doesn't work though both look exactly the same now ,further more, how can i compare String x and y for equality?
public class TestClass { void validateIP(String ipStr) { String one = "((25[0-5]|2[0-4]d|[01]?dd?)(.)){3}(25[0-5]|2[0-4]d|[01]?dd?)"; //copied from internet and edited String two = "((25[0–5]|2[0–4]d|[01]?dd?)(.)){3}(25[0–5]|2[0–4]d|[01]?dd?)"; // copied from book String x = "((25[0-5]|2[0-4]d|[01]?dd?)(.))"; String y ="((25[0–5]|2[0–4]d|[01]?dd?)(.))";
