Forms :: Open A Specific PDF File Per Record With A Command Button
Apr 18, 2013
I need to open a specific pdf file per record by using a command button. The pdf files will all reside in a specific folder in a partition on my hard drive. Each pdf file will have a unique four digit file name e.g 1234.pdf.The file name will match a unique number allocated to each record. This number is generated by adding 1000 to the record ID.Record 10 will therefore have an associated pdf file name of 1010.pdf.I have created a text box field , named 'TestReportID', to capture the unique four digit number per record that I assume is needed to be referred to when setting up the code to find and display the correct related pdf file.
I have set up a command button on the records form and as simple test using the hyperlink address to the folder where the pdf files reside, I can open a pdf file by clicking on the command button but it does not matter what record is open when I click the command button, it will always open the same pdf file.If I don't identify a specific file name in the hyperlink address, when I click on the button it will display a file open dialog which lists all the relevant pdf files and I can then select and open the required file.I would like to cut out that step and get the correct file to open when I click the button.
I have a form called "frmProducts" which is linking to table "tblproducts".
Easy Enough...
The form shows all the Products information (fields). I have a "More Info" command button (cmdMoreInfo) next to every record in the form.
When the command button is clicked I would like it to open up another form "frmMoreInfo". But On frmMoreInfo I would only like it to show that specific product.
I have tried the following code on the on click event on the command button but it was always asking me for the value of Form![frmMoreInfo]![txtInternalCode]
Code:Private Sub Command12_Click()On Error GoTo Err_Command12_ClickDim stDocName As StringDim stLinkCriteria As StringstDocName = "frmMoreInfo" stLinkCriteria = "Form![frmMoreInfo]![txtInternalCode]=" & Me![txtInternalCode]DoCmd.OpenForm stDocName, , , stLinkCriteriaExit_Command12_Click:Exit SubErr_Command12_Click:MsgBox Err.DescriptionResume Exit_Command12_Click End Sub
I would like to create a form that allows me to search for a folder on my desk top, then once located i can transfer that file to a specific location on another drive, Similar to the Browse / upload function you see on many applications.I am using Access 2003. Is this possible??
I have a form that opens from a different form based on the primary key within the original form. Unfortunately it seems to be opening a new record every time I open the form--not only from the original form but also straight from the sidebar.
The command button that opens the second form from the first uses the following VBA:
This exact coding worded perfectly in a similar set of forms that I had created; the only difference is a change in the form name & primary key field.
Add onto this, I think that the code DOES work, but then it immediately opens another new record. When I open the second form from the command button, then change to Design View, the form's Filter property is set to [Event_ID]=X (where X is the proper key from the first form) and Filter On Load is set to Yes. The X in the Filter changes accordingly when it changes in the first form. Also, every time I open the form a new record is added to the underlying table.
I've tried setting "Allow Additions" in the second form to No, but then when I open the form nothing appears. Literally; the entire form is blank, no labels, textboxes, combos, buttons or anything. When going to Design View it's still all there.
I've also checked the On_Load, On_Current & Form_Current events and found nothing. I even deleted them and the problem still occurred.
I have a subform in which I want to put in a Command Button to open another form.
I used the wizard as per normal, but when you come to matching specific data fields, there is nothing in my left hand column of the sub form. I have checked the record source property and it is bound to the correct table.
I have read that this is an issue with Access 2007? Is this the case or am I missing something obvious here?
I have set up a database that houses file locations. The form that I have made shows a job # and the files that correlate with it. I would like to set up a command button that will read the file name and open it in Excell. If any one know how to do this I would greatly appreciate the help.
I am trying to open a workbook with a command button on a form however the path to the file is giving me a fit. The path for the file location contains spaces and I am going blind trying to figure out how to rectify the path. Heres the line. I am sure someone here will see this problem quick! Thanks.
Private Sub Command0_Click() On Error GoTo Err_Command0_Click
I have a continuous form in which I put a command button for each record called "detail". I would like to click on the "detail" button and make it open another form containing all (and only) the info on this record.
At first I refused to use an "id" to link both forms, but finally I added the "id" in the table... however still does not work.
continuous form: "04 - GASTOS_BUSQUEDA" id field on continuous form: "Gastid"
pop-up (details) form: "GASTOS_EDITAR" id on pop-up (details) form: "editar_id"
This is what I have tried on the "click" properties of the "details" button field (called "btn_editgs"):
4) Private Sub btn_editgs_Click() On Error GoTo btn_editgs_Click_Err Dim strWhere As String strWhere = "[editar_id] = " & Me.Gastid DoCmd.OpenForm "GASTOS_EDITAR", , , strWhere btn_editgs_Click_Exit: Exit Sub btn_editgs_Click_Err: MsgBox Error$ Resume btn_editgs_Click_Exit End Sub
It just read in Access Help that if you have open db using record locking checked that you must open the database using the File=> Open command from the MenuBar. Does anyone know anything about this or can anyone comfirm this a s true?
I would like to open a PDF document using a button control on a form to a file path listed in a field on the form (Me.Link). I am trying to use the followHyperlink code but I keep getting the runtime 490 error.
This is the code im using:
Dim strFilePath As String strFilePath = Me.Link Application.FollowHyperlink (strFilePath)
If I put a filepath to one of the pdf documents in the place of (strFilePath) it opens that pdf document fine but not when I declare a filepath based on the one listed on the form.
I am creating a database. I have all my forms, queries, tables, reports just as I need them. However, I would like to have a command button on my switchboard that will pull from a query to feed to a Word document (that's actually a letter on my company letterhead). I know a Macro has to be involved with this, but again, I have little to no knowledge of Macros. Also, I would like to be prompted to enter a client ID number when I click on this command button (because I only want to print a letter for a new client, not all of them).
I am trying to add a command button to my main menu to open the contact names as a datasheet, I have changed the properties on the contact names form to datasheet as well as changing the properties on the button to the below:
Private Sub Command48_Click() DoCmd.OpenForm "Contact Names", acFormDS End Sub
at first after I saved it, the button did nothing. Now after a bit of playing around (probably not a good idea) I have a new message that states:"The expression On Click you entered as the event property setting produced the following error: Ambiguous name detected: Contacts_Click.To add some additional information, in the vba sheet above the code i wrote above it says:
Option Compare Database Private Sub Contacts_Click() DoCmd.OpenForm "Contact Names", acFormDS End Sub
Private Sub Contacts_Click() DoCmd.OpenForm "Contact Names", acFormDS End Sub
I have a main form [Job Quote Form 10-2205] and I am trying to add a command button to open up [Job Process Form-MKD] and have the [Job Process Form-MKD] open up and only show the records that match a certain field, in this case what I call "JobTrackNo" in the [Job Process Form-MKD]. (see attached .jpg)
This problem started to happen only recently, namely you will see that the left column under [Job Quote Form 10-2205] is blank, where normally there had been a number of fields to choose from. The fields are all still available, they are just not opening when I try to match two fields.
I have a access 2003 database, and i am wondering if i can't setup a search function in a form that will open a file in windows explorer?
What i would like to do is have a test box that i enter in a number for example: 1234 then have a button named "Search" hit that button and it opens a corresponding file in windows explorer named 1234, or just opens that folder directly..
1. I have created a button in a switchboard with embedded macro:-
Close Window OpenForm (Form name: frmCustomerFind)
2. I have created a form "frmCustomerFind), in which I can select a customer name in a combo box named "CustomerName".
a. The row source: SELECT [tblCustomer].[CustomerID],[tblCustomer].
[CustomerName] FROM tblCustomer ORDER BY [CustomerName];
b. After Update Macro:
Open Form (Form name: frmCustomer) SearchForRecord (Object Type: Form Object Name: frmCustomer Record: First Where Condition = "[CustomerID]=" & Me.CustomerID
At the end, the form "frmCustomer" does open but not go to the record I want. It goes to the first record instead. (The frmCustomer has the "CustomerID" and "CustomerName" fields).
Need to open a form to a specific record.Ive done the command button wizard that opens the form to a specific record but but that brings up the form with the filtered button showing.I've tried to put the formula into the filtered section but that doesn't work.I just want to be able to open the form to the specif record and then be able to navigate to other records if required (without aving to press the filtered button)
Currently, I have a form with tabbed pages in it. The second tab, I have a subform inserted into it. I have a completely separate form that looks through records. I want to be able to click on a record from the separate form and open the Main tabbed form, to the second tabbed page, to a specific record. Currently I have:
Private Sub Form_DblClick(Cancel As Integer) Dim stDocName As String Dim stLinkCriteria As String stDocName = "frm_Main_Data_Entry" DoCmd.OpenForm stDocName, , , stLinkCriteria Forms![frm_Main_Data_Entry]![pgAgreement].SetFocus End Sub
Which opens up to the tabbed page just fine. but I can not figure out how to get to a specific record.
Also, the subform in the tabbed page, doesn't have the same controls as the Main tabbed Form itself, so when I add something like:
No I know this one has been done, and I have a form with a button that this works on. Here is my problem. I have a list of parts in a continuous form, I added a button to open that specific record in a detail view and it works just fine. I used an open form macro and put in the criteria
="[Description]=" & "'" & [Description] & "'"
I have tried to use this similar procedure for another form, it however has two subforms in it and I get a data type mismatch in criteria exception error. I suspect that it has something to do with the subforms but am not sure.
I have a form named CORRES_TYP with 3 text boxes and a list box. I also have a separate table with 3 field from where the information I put in the form was saved.
In my form whenever I put information on the textbox at hit add record button, these information are saved in my table and will reflect on the listbox on my form below the textboxes. Also if I select a record in the Listbox the record I selected will apprear on the corresponding textbox in the same form.
My problem is that I have been trying to create a command button that will save and change the existing record everytime I select an item in the list box and modify the information through the textbox. Here are some infromation about my table and form:
Table name = CORRES_TYP Field 1 = CODE (Primary key, No Duplicates) Field 2 = DESCRIPTION Field 3 = FOLDER
Form name = CORRES_TYP Textbox 1 = CODE Textbox 2 = DESCRIPTION Textbox 3 = FOLDER Listbox name = LIST14
I have created Command buttons on forms with VBA code. Records GoTo previous and GoTo Next Record so both of working is good. But Next Record command is force to a new record. If suppose when we clicking on last record. It is go to new record without any message. So No need to force a new record with Next Record Command. Only just move to next record if there is no records show a message. Below mentioned both VBA codes so there is any changes on GoTo Next Record Code?
VBA Code: Go To Previous Record : DoCmd.GoToRecord , , acPrevious Go To Next Record : DoCmd.GoToRecord , , acNext
I am designing a database to manage hospital patient data. I will have to enter info at various points, e.g. when a patient is referred, admitted, discharged...
So for example, I have a main form with the patient's name and two subforms, one with the referral details (e.g. date, name of referrer...), and one with the admission details (e.g. date, diagnosis). They are linked through Parent-child links to the main form by PatientID. So, when I enter a new PatientID in the main form, the ID in the subforms is automatically added/synchronized.
However, I would like it not to be...since not all patients that are referred are then admitted. Therefore I would like to have a command button in the main Form that allows me to control when a new patient record is added to the admission subform. In other words, I would like an "Add a new Record in the admissions subform" button, which then creates a new record, with matching PatientID in the admissions subform (and in the related table). Is this possible???
I have tried using the command button wizard but it either requires a record to be already present in the subform, or it takes me to the first record of the form, and not the matching PatientID one.
I have been trying for weeks to get my login form to open up to a specific record on the mainform. I have built a form out of my Employee tbl (mainform). The table stores (ID,Name, password, EmpNumber ect.) I built a subform in that allows the user to type in the number of overtime worked on a paticular day. I have disabled the navigation on the main form so users can't advance to the next user but have enable the natigation on the subform so a particular user can advance to the next week of available overtime to input data.The goal is to get user login form to display a particular record on the main form and open a different form in the user is a supervisor.
Option Compare Database Private intLogonAttempts As Integer Private Sub cmdExit_Click() DoCmd.Quit End Sub Private Sub cmdLogin_Click()
[code]...
'If User Enters incorrect password 3 times database will shutdown
intLogonAttempts = intLogonAttempts + 1 If intLogonAttempts > 3 Then MsgBox "You do not have access to this database. Please contact your system administrator.", vbCritical, "Restricted Access!" Application.Quit End If End Sub
