Convert SQL Table Data To XML Format

Oct 31, 2006

Hello,

I need to convert a SQL table or SQL table data to XML format. I tried using the Import Export Wizard in SQL 2005 (used SQLXMLOLEDB and SQLXMLOLEDB 4.0 as the source). However, it didn't work. Any way you know how I can convert and obtain data in XML format?

Thanks all in advance,
Saurav

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Mon 4 7 Ma A Pr 5
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Aloha !

I am posting this information simply as an FYI. This is in reference to the MS-SQL command "CONVERT"

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format_code : well.. that's the tricky part. See below.

What I did was ran a script that originally went from 1 to 20,000. It crashed at 15. Apparently the format codes are not totally sequential. So I put in an on error resume next.

What I found is that :
1) the codes are not uninterrupted sequential numbers.
2) the code output repeats every 255
3) negative numbers can be used, but its pointless.
4) useful valid codes are in the ranges of : 0-14, 20-25, 100-114, 120, 121, 126, 130 and 131
5) 0-25 typically represent "short dates" with the year being only 2 digits, but there are exceptions
6) 100 and above always returned a 4 digit year. the exception was 130 and 131, I don't know what it was trying to do.

Here is the script i ran

<%
on error resume next

for iintCounter = 0 to 256
SQL = "SELECT CONVERT(CHAR(128), getdate(), " & iintCounter & " ) as TheDate"
Set rsTheDateFormat = TheDatabase.Execute(SQL)

response.write SQL & " = " & rsTheDateFormat("TheDate") & "<br>"

set rsTheDateFormat = nothing
next
%>



and here is the output
SELECT CONVERT(CHAR(128), getdate(), 0 ) as TheDate = Aug 28 2007 6:46AM
SELECT CONVERT(CHAR(128), getdate(), 1 ) as TheDate = 08/28/07
SELECT CONVERT(CHAR(128), getdate(), 2 ) as TheDate = 07.08.28
SELECT CONVERT(CHAR(128), getdate(), 3 ) as TheDate = 28/08/07
SELECT CONVERT(CHAR(128), getdate(), 4 ) as TheDate = 28.08.07
SELECT CONVERT(CHAR(128), getdate(), 5 ) as TheDate = 28-08-07
SELECT CONVERT(CHAR(128), getdate(), 6 ) as TheDate = 28 Aug 07
SELECT CONVERT(CHAR(128), getdate(), 7 ) as TheDate = Aug 28, 07
SELECT CONVERT(CHAR(128), getdate(), 8 ) as TheDate = 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 9 ) as TheDate = Aug 28 2007 6:46:45:507AM
SELECT CONVERT(CHAR(128), getdate(), 10 ) as TheDate = 08-28-07
SELECT CONVERT(CHAR(128), getdate(), 11 ) as TheDate = 07/08/28
SELECT CONVERT(CHAR(128), getdate(), 12 ) as TheDate = 070828
SELECT CONVERT(CHAR(128), getdate(), 13 ) as TheDate = 28 Aug 2007 06:46:45:507
SELECT CONVERT(CHAR(128), getdate(), 14 ) as TheDate = 06:46:45:507
SELECT CONVERT(CHAR(128), getdate(), 20 ) as TheDate = 2007-08-28 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 21 ) as TheDate = 2007-08-28 06:46:45.540
SELECT CONVERT(CHAR(128), getdate(), 22 ) as TheDate = 08/28/07 6:46:45 AM
SELECT CONVERT(CHAR(128), getdate(), 23 ) as TheDate = 2007-08-28
SELECT CONVERT(CHAR(128), getdate(), 24 ) as TheDate = 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 25 ) as TheDate = 2007-08-28 06:46:45.540
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SELECT CONVERT(CHAR(128), getdate(), 101 ) as TheDate = 08/28/2007
SELECT CONVERT(CHAR(128), getdate(), 102 ) as TheDate = 2007.08.28
SELECT CONVERT(CHAR(128), getdate(), 103 ) as TheDate = 28/08/2007
SELECT CONVERT(CHAR(128), getdate(), 104 ) as TheDate = 28.08.2007
SELECT CONVERT(CHAR(128), getdate(), 105 ) as TheDate = 28-08-2007
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SELECT CONVERT(CHAR(128), getdate(), 107 ) as TheDate = Aug 28, 2007
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SELECT CONVERT(CHAR(128), getdate(), 110 ) as TheDate = 08-28-2007
SELECT CONVERT(CHAR(128), getdate(), 111 ) as TheDate = 2007/08/28
SELECT CONVERT(CHAR(128), getdate(), 112 ) as TheDate = 20070828
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SELECT CONVERT(CHAR(128), getdate(), 114 ) as TheDate = 06:46:45:930
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