Hi Guys, Can anyone please let me know How to find the first day of the week, if I know the weekno and the year. For ex: If I know the week no is 22 and Year is 2003 then I should find a way to output the date. which is the first day (monday) of that week for the above query the date will be eg:26/06/2003
I really appreciate your Help
Thanks:confused: Find the Date if I know the week and year
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK GO create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK ( @Datedatetime ) returnsvarchar(10) as /* Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. */ begin
declare @YearWeekDayOfWeekvarchar(10)
Select --Format to form YYYY-W01-D @YearWeekDayOfWeek = convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+ right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) + '-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1) from ( select YearStart = -- Case finds start of year case whenNextYrStart <= @date thenNextYrStart whenCurrYrStart <= @date thenCurrYrStart elsePriorYrStart end from ( select -- First day of first week of prior year PriorYrStart = dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690), -- First day of first week of current year CurrYrStart = dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690), -- First day of first week of next year NextYrStart = dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690) from ( select --Find Jan 4 for the year of the input date Jan4= dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0)) ) aaa ) aa ) a
return @YearWeekDayOfWeek
end go
-- Execute function on first day, first day+60, -- and first day+364 for years from 1990 to 2030.
select DT= convert(varchar(10),DT,121), YR_START_DT = dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT), YR_START_DT_60 = dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60), YR_START_DT_365 = dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364) from ( select DT = getdate()union all select DT = convert(datetime,'1990/01/01') union all select DT = convert(datetime,'1990/12/31') union all select DT = convert(datetime,'1991/12/30') union all select DT = convert(datetime,'1993/01/04') union all select DT = convert(datetime,'1994/01/03') union all select DT = convert(datetime,'1995/01/02') union all select DT = convert(datetime,'1996/01/01') union all select DT = convert(datetime,'1996/12/30') union all select DT = convert(datetime,'1997/12/29') union all select DT = convert(datetime,'1999/01/04') union all select DT = convert(datetime,'2000/01/03') union all select DT = convert(datetime,'2001/01/01') union all select DT = convert(datetime,'2001/12/31') union all select DT = convert(datetime,'2002/12/30') union all select DT = convert(datetime,'2003/12/29') union all select DT = convert(datetime,'2005/01/03') union all select DT = convert(datetime,'2006/01/02') union all select DT = convert(datetime,'2007/01/01') union all select DT = convert(datetime,'2007/12/31') union all select DT = convert(datetime,'2008/12/29') union all select DT = convert(datetime,'2010/01/04') union all select DT = convert(datetime,'2011/01/03') union all select DT = convert(datetime,'2012/01/02') union all select DT = convert(datetime,'2012/12/31') union all select DT = convert(datetime,'2013/12/30') union all select DT = convert(datetime,'2014/12/29') union all select DT = convert(datetime,'2016/01/04') union all select DT = convert(datetime,'2017/01/02') union all select DT = convert(datetime,'2018/01/01') union all select DT = convert(datetime,'2018/12/31') union all select DT = convert(datetime,'2019/12/30') union all select DT = convert(datetime,'2021/01/04') union all select DT = convert(datetime,'2022/01/03') union all select DT = convert(datetime,'2023/01/02') union all select DT = convert(datetime,'2024/01/01') union all select DT = convert(datetime,'2024/12/30') union all select DT = convert(datetime,'2025/12/29') union all select DT = convert(datetime,'2027/01/04') union all select DT = convert(datetime,'2028/01/03') union all select DT = convert(datetime,'2029/01/01') union all select DT = convert(datetime,'2029/12/31') union all select DT = convert(datetime,'2030/12/30') ) a
Hi every one, I have a database table and currently users may retrieve records for a specified date range by providing the start and end dates and then records between those dates provided are retrieved. For example if users wanted to view all records entered in april, they would have to select 04/01/2007 as the start date and then 04/30/2007 as the end date. The records for april would then be displayed in a gridview. How can configure my sql query such that instead the user selectes a month from a dropdownlist of 12 months. I would love a user to just select the desired month from a list instead of selecting start and end dates. Eg if they are intrested in a report for june, then they should just select june from the list instead of specifying the start and stop dates. HOW can i achieve this.
This function returns the ISO 8601 week of the year for the date passed. The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day of each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_WEEK_OF_YEAR go create function dbo.F_ISO_WEEK_OF_YEAR ( @Datedatetime ) returnsint as /* Function F_ISO_WEEK_OF_YEAR returns the ISO 8601 week of the year for the date passed. */ begin
declare @WeekOfYearint
select -- Compute week of year as (days since start of year/7)+1 -- Division by 7 gives whole weeks since start of year. -- Adding 1 starts week number at 1, instead of zero. @WeekOfYear = (datediff(dd, -- Case finds start of year case whenNextYrStart <= @date thenNextYrStart whenCurrYrStart <= @date thenCurrYrStart elsePriorYrStart end,@date)/7)+1 from ( select -- First day of first week of prior year PriorYrStart = dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690), -- First day of first week of current year CurrYrStart = dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690), -- First day of first week of next year NextYrStart = dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690) from ( select --Find Jan 4 for the year of the input date Jan4= dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0)) ) aa ) a
return @WeekOfYear
end go
-- Execute function on first day of first week of year from 1990 to 2030 select DT, ISO_WEEK_OF_YEAR = dbo.F_ISO_WEEK_OF_YEAR(a.DT) from ( select DT = getdate()union all select DT = convert(datetime,'1990/01/01') union all select DT = convert(datetime,'1990/12/31') union all select DT = convert(datetime,'1991/12/30') union all select DT = convert(datetime,'1993/01/04') union all select DT = convert(datetime,'1994/01/03') union all select DT = convert(datetime,'1995/01/02') union all select DT = convert(datetime,'1996/01/01') union all select DT = convert(datetime,'1996/12/30') union all select DT = convert(datetime,'1997/12/29') union all select DT = convert(datetime,'1999/01/04') union all select DT = convert(datetime,'2000/01/03') union all select DT = convert(datetime,'2001/01/01') union all select DT = convert(datetime,'2001/12/31') union all select DT = convert(datetime,'2002/12/30') union all select DT = convert(datetime,'2003/12/29') union all select DT = convert(datetime,'2005/01/03') union all select DT = convert(datetime,'2006/01/02') union all select DT = convert(datetime,'2007/01/01') union all select DT = convert(datetime,'2007/12/31') union all select DT = convert(datetime,'2008/12/29') union all select DT = convert(datetime,'2010/01/04') union all select DT = convert(datetime,'2011/01/03') union all select DT = convert(datetime,'2012/01/02') union all select DT = convert(datetime,'2012/12/31') union all select DT = convert(datetime,'2013/12/30') union all select DT = convert(datetime,'2014/12/29') union all select DT = convert(datetime,'2016/01/04') union all select DT = convert(datetime,'2017/01/02') union all select DT = convert(datetime,'2018/01/01') union all select DT = convert(datetime,'2018/12/31') union all select DT = convert(datetime,'2019/12/30') union all select DT = convert(datetime,'2021/01/04') union all select DT = convert(datetime,'2022/01/03') union all select DT = convert(datetime,'2023/01/02') union all select DT = convert(datetime,'2024/01/01') union all select DT = convert(datetime,'2024/12/30') union all select DT = convert(datetime,'2025/12/29') union all select DT = convert(datetime,'2027/01/04') union all select DT = convert(datetime,'2028/01/03') union all select DT = convert(datetime,'2029/01/01') union all select DT = convert(datetime,'2029/12/31') union all select DT = convert(datetime,'2030/12/30') ) a
I am trying to group counts by week,month,quarter, year for a particular activity type and I'm having issues.Here's my code so far:
SELECT distinct EmailAddressID, emailaddress, SUM(CASE WHEN [ActivityDate] >= DATEADD(WEEK, DATEDIFF(WEEK, 0, @DT), 0) THEN SUM(CASE WHEN EmailActivityType = 'OPEN' THEN 1 ELSE 0 END) END AS WeekTotalOpens FROM EmailActivity WHERE DATEPART(YEAR, [ActivityDate]) = DATEPART(YEAR, @DT) GROUP BY EmailAddressID,emailaddress Desired Output: EmailAddressId EmailAddress WeekTotalOpens MonthTotalOpens etc. then WeekTotalClicks and so on....
SQL doesn't seem to like the sub-aggregate. What is the best way to approach?
Hi, I have a Serial No which has a length as 14.For eg IL010730123456. IL01 is The Default Code. 07 is the current year and 30 is the week of the year. 123456 is Serial. How shoud I find The Year and week with the help of this serial no ie The First day of the 30th week of 2007.Is it Possible?
Plz Help me with an appropriate solution. Thanks.....
I have to insert YEAR WEEKNUMBER STARTDATE ENDDATE values to a datatable (sayweekrange), if I pass 2011 as year.
Week range starts at 2011-03-28 to 2011-04-03 (because in my database 2010 last week range ends with 2011-03-27) like this I have to generate for 52 weeks.
I want to write a stored procedure, that takes only year as parameter. with this year I have to generate week ranges and insert into my table as shown above.
I have three web form controls, a ddl that contains the day, another ddl that contains the month and a textbox that contains the current year. To send the date chosen by the user to the database, I join the three web form control values so that the resultant string is ‘day/month/year’ thus:
And the resultant string is: dd/mm/yyyy, for example 30/08/2004. But the problem is if the user does not select any day or any day and month, then the resultant string is for example; 00/08/2004 or 00/00/2004, but the problem is the database does not accept this format as datetime. How can I do it?
I want the user has the possibility to chose as well only the month and year, and as well only the year. Is it possible to send to the database the datetime format with only the month and year, or only the year?
I need to build a report that compares a count on a certain day of the week by month by year by stacks. That is,for first Monday in October 2012 against first Monday in October 2013 for stack DM1 against first Monday in October 2014 stack DM1, same for second Monday, first Tuesday, second Tuesday, ect. Attached is a sample dataset and what I want to achieve.
SQL express 2012. I am trying to case in the where part and having a syntax errors - This is what i am trying to do:
select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare @yyyy int = 2014,-- THE YEAR @mm int = 1,-- THE MONTH @week1No int = 1,-- THE WEEK NUMBER IN THE YEAR @week2No int = 37-- THE last WEEK NUMBER IN last YEAR select count(tblDay.start)-- tblDay.start IS smallDatetime
I am trying to case in the where part and having a syntax errors - this is what i am trying to do:
Select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare @yyyy int = 2014,-- THE YEAR @mm int = 1,-- THE MONTH @week1No int = 1,-- THE WEEK NUMBER IN THE YEAR @week2No int = 37-- THE last WEEK NUMBER IN last YEAR select count(tblDay.start)-- tblDay.start IS smallDatetime
Does anyone have an example of an SQL query which returns rows for theyear-to-date, but where the "year" commences on August 1st?e.g. select * from mytable where datefield > last august 1stTIA for any helpIsabel
I have a table where hours are being loaded in a weekly basis. The YearWeek is populated when the data is loaded. The value format of the Year Week is 2015-39, 2015-41, etc. I need to calculate the total hours per Fiscal Year.For example, week '2015-39' will be return FY15 and week '2015-41' will return FY16, and so on. By extracting the year, I can do a group by and have total hours for each year.
Currently, I have it working by splitting the value into year and week and then looping through each year and week, so I can assign the totals to the corresponding FY.select sum(hours) as total, yearweek from tablename group by yearweek...Then I loop through using C#.I can return the FY using an actual date,how to do it for year-week format for any given year.
select CASE WHEN CAST(GETDATE() AS DATE) > SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000) THEN DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE()) END AS FY
Greetings All, I have a SQL question that maybe someone out there can help me with. Our fiscal year starts on 01/27. I want to write a query that I can pass a date to and it will return the week number (DATEPART("ww", someDate)) of the year using the Fiscal Year Start Date as the base. Datepart works great except it figures the first day of the year as 1/1. Does anyone know how I can make it work with a first day of the year equal to the fiscal year date 01/27. Any help would be appreciated. TIA, ~ck
Hello All, i have three textboxes in a page and i want fill those textboxes with the date, month,year respectively..... i have a datecreated column in discount table in a mm/dd/yy format ...how to extract the date, month, year from this format and put the value in textboxes..? Any help.. Thanks.. Anne
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
I'm wanting to see if there is a simpler way to accomplish the retrival of the first day of the week Date. What I currently have is:
CASE WHEN DATEPART(DW, GETDATE()) = 1 THEN DATEADD([D], - 7, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 2 THEN DATEADD([D], - 8, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 3 THEN DATEADD([D], - 9, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 4 THEN DATEADD([D], - 10, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 5 THEN DATEADD([D], - 11, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 6 THEN DATEADD([D], - 12, GETDATE()) WHEN DATEPART(DW, GETDATE()) = 7 THEN DATEADD([D], - 13, GETDATE()) END AS StartWeek1
I'm trying to figure if there might be an easier way to code this. Thanks.
I am trying to write a query that give me how many items were filed per year.
This is the error:
Conversion failed when converting the varchar value 'YEAR(1999)' to data type int.
Here is the query I am using:
SELECT COUNT (*), CASE WHEN ChargesFiledDate > 20141231 THEN 'YEAR (2015)' WHEN ChargesFiledDate > 20131231 THEN 'YEAR (2014)' WHEN ChargesFiledDate > 20121231 THEN 'YEAR (2013)' ELSE YEAR (0000)
[Code] ...
And got the same error. I know there is probably a better way to get this data (being that I need it from 2007 to present), but don't know how to write it.
Hey, Im pretty sure this is possible, but let me know if it isnt.I have a table of dates in the format "DD/MM/YYYY", is there a way of converting it to output the day of the week? for example 16/11/2007 would display Friday insted.Thanks in advance John