Date Difference For Multiple Dates
Jun 18, 2014
I have a field called 'LOG_COMMENTS' in a table named T_PRODUCTION_WORK_LOG.
In the 'LOG_COMMENTS' whenever a request is placed on hold comments are added by the application, such as 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open' along with a 'LOG_DATESTAMP' field. A request can go on and off Hold multiple times, how do I determine the days a request is On Hold?
I know I can use the sql function DATEDIFF ( datepart , startdate , enddate ), but how do I account for the possiblity that the request was On Hold more than once? And how would I get LOG_DATESTAMP' times for 'LOG_COMMENTS' that contain 'Status changed from Open to On Hold' and 'Status changed from On Hold to Open''?
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Aug 27, 2012
I have already seen stored procedures that can calculate a difference in dates, excluding the weekends. Any extension of such a SQL query to exclude not only weekends, but other dates as well. We have a table of "holidays" (not necessarily standard holidays), and I am wondering if there is a way to exclude them from the calculation.
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Sep 25, 2015
I want a difference in daysÂ
Select datediff(dd,Target_Date,Achv_Date)Â
Now , checks areÂ
1] when target date greater than achv_Date the difference should be greater than 0Â
means for FileIDÂ 77608Â
Select datediff(dd,'2015-09-24 00:00:00.000','2015-09-24 10:42:32.823')
Â
i am getting -6 it should be 6 cant switch Target_Date and Achv_Date in datediff else i will get opposite result in first four records basically, i want a two column TAT and Status beside  achv_date based on the values of two dates difference see above ..and also want a result of (No. of Yes in status / No. of Files that has achv_date )i.e. result= (7/8) = 87%Â
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Oct 14, 2015
Here I have 2 Dates. CreatedDttm & ModifiedDttm.
I want  - DATEDIFF(Day,CreatedDttm,ModifiedDttm)  and I have to exclude the Weekend days from that query result.
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May 17, 2005
Hey people,
i was wondering if it was possible to get the difference bettween the current date/time and a date feild and store it in a feild in the same table. id like to do this to prevent constant php update querys.
cheers
mish
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Oct 23, 2007
I have 2 datatime columns....i want to get the difference in the dates...
EXample
Startdate Enddate Difference
10/10/2007 20/10/2007
11/10/2007 21/10/2007
12/10/2007 22/10/2007
13/10/2007 23/10/2007
14/10/2007 25/10/2007
I want the difference to be in the Difference column...
Kindly help me...thanks in advance...
pavan
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Mar 15, 2007
By using DateDiff we can do.Could you please send me the expression
Thanks
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Apr 10, 2008
advance thanks to all...can anybody helpme soon...........
i am using sql server 2005........i want to find out time difference between two dates in HH,MM,SS format
eg i want the time difference of these two dates
02/Nov/06 9:14:21 AM
19/Apr/07 11:52:31 AM
now i am using this calculation in my procedure is as follows...but i think this is wrong...if we will seperatly calculate like this wrong i am getting
set @totaltravelHr=datediff(HH,@datediff1,@datediff2)
set @totaltravelMI=datediff(MI,@datediff1,@datediff2)
set @totaltravelSE=datediff(SS,@datediff1,@datediff2)
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Oct 18, 2006
Hi, i'm trying to calculate the number of days between two dates, but within an UPDATE statement, so far I can't wrap my head around how I can update a field with the number of days.
I was thinking something like
Code:
Update #ClaimMaster
Set covered_days = (then insert select statement that subtracts the two dates)
Does that make any sense?
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Jun 23, 2007
i was working on a appication and just got stuck with this.
I have a column on a table which is a date column and i need to get the days differenct and copy it in another column
e.g
date days between
27-02-2005 1
28-02-2005 0
28-02-2005 0
28-02-2005 1
01-03-2005 0
01-03-2005
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Nov 27, 2007
This is tricky so please read it through
For displaying data on the report I am using the following query
SELECT ReferenceNumber, ActivityID, ActivityTimeStamp, ActivityType, ActivityPerformedBy FROM ActivityDetails
ORDER BY ReferenceNumber, ActivityID
The result set is
Issue Reference #
Activity ID
Activity Date/Time
Activity Type
100819
4521404
11/4/07 2:06 PM
INIT
100819
4521405
11/4/07 2:07 PM
LOG
100819
4521406
11/4/07 2:07 PM
LOG
100819
4521473
11/4/07 2:28 PM
TR
100819
4521501
11/4/07 2:33 PM
WIP
100819
4521839
11/4/07 3:25 PM
RE
100819
4521844
11/4/07 3:27 PM
RE_Method
100819
4522575
11/4/07 8:53 PM
CL
100820
4521412
11/4/07 2:10 PM
INIT
100820
4521419
11/4/07 2:13 PM
ATTACHTDOC
100820
4525856
11/5/07 2:49 PM
ATTACHTDOC
100820
4525859
11/5/07 2:49 PM
LOG
100820
4525869
11/5/07 2:49 PM
CL
100821
4521423
11/4/07 2:14 PM
INIT
100821
4521425
11/4/07 2:14 PM
LOG
100821
4521429
11/4/07 2:14 PM
TR
100821
4521432
11/4/07 2:14 PM
ACK
100821
4522219
11/4/07 4:58 PM
RE
100821
4522221
11/4/07 4:58 PM
RE_Method
100821
4522447
11/4/07 6:51 PM
CL
On the report I have used the grouped by clause on 'Issue Reference #'. I want one more column which would calculate the difference between two consecutive Activity Date/Time of the same reference #.
e.g. Time difference between 4521404 and 4521405, 4521405 and 4521406, 4521406 and 4521473 etc. Please note that the difference between 4521412 and 4522575 will NOT be calculated since they are from different Reference Numbers.
Thanks,
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Sep 26, 2006
Hi all,
I have a table named Orders and this table has two relevant fields: CustomerId and OrderDate. I am trying to construct a query that will give me the difference, in days, between each customer's order so that the results would be something like: (using Northwind as the example)
...
ALFKI 25/08/1997 03/10/1997 39
ALFKI 03/10/1997 13/10/1997 10
ALFKI 13/10/1997 15/01/1998 94
ALFKI 15/01/1998 16/03/1998 60
ALFKI 16/03/1998 09/04/1998 24
...
At the moment, I have the following query that I think is on the right track:
€¦
SELECT dbo.Orders.CustomerID, dbo.Orders.OrderDate AS LowDate, Orders_1.OrderDate AS HighDate, DATEDIFF([day], dbo.Orders.OrderDate, Orders_1.OrderDate) AS Difference FROM dbo.Orders INNER JOIN dbo.Orders Orders_1 ON dbo.Orders.CustomerID = Orders_1.CustomerID AND dbo.Orders.OrderDate < Orders_1.OrderDate GROUP BY dbo.Orders.CustomerID, dbo.Orders.OrderDate, Orders_1.OrderDate, DATEDIFF([day], dbo.Orders.OrderDate, Orders_1.OrderDate) ORDER BY dbo.Orders.CustomerID, dbo.Orders.OrderDate, Orders_1.OrderDate
€¦
However, this gives me too much data:
€¦
ALFKI 25/08/1997 03/10/1997 39
ALFKI 25/08/1997 13/10/1997 49
ALFKI 25/08/1997 15/01/1998 143
ALFKI 25/08/1997 16/03/1998 203
ALFKI 25/08/1997 09/04/1998 227
ALFKI 03/10/1997 13/10/1997 10
ALFKI 03/10/1997 15/01/1998 104
ALFKI 03/10/1997 16/03/1998 164
ALFKI 03/10/1997 09/04/1998 188
ALFKI 13/10/1997 15/01/1998 94
ALFKI 13/10/1997 16/03/1998 154
ALFKI 13/10/1997 09/04/1998 178
ALFKI 15/01/1998 16/03/1998 60
ALFKI 15/01/1998 09/04/1998 84
€¦
So, do any of you have any ideas how I might achieve this? I know how to do it using a stored procedure, but I am trying to avoid that; I€™d like to do this in a single query.
Thanks for any help you have to offer,
Regards,
Stephen.
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Feb 14, 2008
Its early in the morning and I am struggling with an easy one.
I have a calculated field in a report which displays the difference between 2 dates. The value that is returned is a number which I can then format to display difference like so 'Days.hh:mms'
I need the diffence between the dates to be expressed in hours, minutes and seconds only. eg '36:45:12'
It would also be usefull if I could build a parameter in to the query which would allow me to discount days selected by the user (Using multi select drop down in day format i.e 'Monday', 'Tuesday', etc)
Any Idea's?
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Dec 9, 2011
I have data in which i need to calculate employees working hours for a day...
name time in_out
manisha 2011-01-01 9:30:00.000am 1
manisha 2011-01-01 10:30:00.000 0
manisha 2011-01-01 10:45:00.000 1
manisha 2011-01-02 1:00:00.000am 0
How can i calculate time in that two dates as 1 is for entry an 0 is for exit..
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Feb 27, 2013
It has been a while since I have used SQL server and require to show a time difference between a start and end time, with only 1 date to determine these times
SQL
select
Arrival_date
locationdate as LocDate,
locationid as Loc_ID,
locations.loc_name as Location_Name
from current_locations
left outer join locations on
locations.loc_id = current_locations.location_id
where current_locations.Attend_ID = '1234567'
Results
Arrival Date LocDate Loc_IDloc_name
26/02/2013 19:2126/02/2013 19:271270Queue
26/02/2013 19:2126/02/2013 19:341278Dept 1
26/02/2013 19:2126/02/2013 21:10222Dept 2
26/02/2013 19:2127/02/2013 02:5631Left Department
What I want to acheive is the following where the Start location date is either the arrival date or the next location date and the endLocDate is the next finish date.
StartLocDateEndLocDateTime DifferenceDept
26/02/2013 19:2126/02/2013 19:2700/01/1900 00:06Queue
26/02/2013 19:2726/02/2013 19:3400/01/1900 00:07Dept 1
26/02/2013 19:3427/02/2013 02:5600/01/1900 07:22Dept 2
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Jun 2, 2015
Is it possible to get difference between two dates - first one and last one per every group in table (records are sorted by ID)?
ID Group Date
739 Group 1 2015-04-17 14:27
740 Group 1 2015-04-19 06:51
760 Group 1 2015-04-19 11:51
762 Group 1 2015-04-21 09:30
763 Group 1 2015-04-20 09:20
[Code] ....
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Feb 28, 2007
I have a need to display the difference between two dates, a start date and a end date in the format HH:mm where the hours could be greater than 60.
For example:
Start Date - 30/01/2007 09:00:01
End Date - 01/02/2007 20:40:04
When i use the following code (=Fields!dateend.Value - Fields!DateStart.Value) i get 2.11:40:03 which i can easily understand, but the customer wants it as above!
I would like to be able to get it to be 59:40:03.
Any help would be much appreciated.
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Jan 19, 2015
select datediff(wk, '2015-01-11', '2015-01-19') returns 1 (shouldn't it return 2?)
select datediff(wk, '2015-01-10', '2015-01-19') returns 2
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May 19, 2014
I have a table with a list of jobs along with their start and end datetime values.
I am looking for a function which will return the time taken to process a job using a start date and an end date. If the date range covers a Saturday or Sunday I want the time to ignore the weekends.
Example
Start Date=2014-05-15 12:00:00.000
End Date=2014-05-19 13:00:00.000
Total Time should be: 2 Days, 1 Hour and 0 Minutes
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Mar 17, 2015
How do I find the time difference when the dates are in one column? I need to find hours and minutes between each row.
CREATE TABLE #Time ([TimeStamp] DATETIME, TimeDiff INT)
INSERT INTO #Time (TimeStamp)
VALUES ('2014-09-02 07:51:02.810'), ('2014-09-02 07:48:09.567'), ('2014-09-02 08:37:09.647')
, ('2014-09-02 16:16:42.593'), ('2014-09-02 08:06:13.387'),('2014-09-02 14:32:00.113')
DROP TABLE #Time
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Sep 4, 2015
I have a table with appdt as first appointment date and the another record for the same customer# has follow up appointment.
Each customer is uniquely identified by a customer#
I need to find out if the customer came back after 200 days or more when the first appointment date was between jan12014 and Aug 31 2014. I am only interested in first follow up appointment after 30 days or more.
How can i do that in a query?
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May 28, 2015
I need getting the HH:MM:SS format when we do datepart.
For example, am using a variable to capture the time taken to execute the package using Start and End time stamps captured.
I would like to get the HH:MM:SS format of the datediff.
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Sep 23, 2014
I'm using SQL Server 2012 and I need to run a query against my database that will output the difference between 2 dates (namely, DateOfArrival and DateOfDeparture) into the correct month column in the output.
Both DateOfArrival and DateOfDeparture are in the same table (let's say GuestStay). I will also need some other fields from this table and do some joins on some other tables but I will simplify things so as to solve my main problem here. Let's say the fields needed from the GuestStay table looks like below:
I need my query to output in the following format:
How to write this query?
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Jan 11, 2006
hello
how can i select all dates upto todays date and include the first next future date in a given data base
say todays date was the 01/06/2006 (MM,DD,YYYY)
below is a mock data base
id date (MM,DD,YYYY)
1 01/02/2006
2 01/04/2006
3 01/06/2006
4 01/09/2006
5 01/20/2006
i want to select all dates equal or less that 01/06/2006 and include the first next future date .. and in this case it would be 01/09/2006
so the results would return
1 01/02/2006
2 01/04/2006
3 01/06/2006
4 01/09/2006
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Sep 11, 2015
I require outputting the date difference between two date's if it is greater than 7(DateDiff(day, DateAdd(day, t.[Started], Nxt.started), (t.[started])) > 7).I get incorrect syntax on my operator.What is the correct code?
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Jan 7, 2014
I have an SQL code below which removes weekends and non working days when calculating days difference between two dates:
ce.enquiry_time represents when the enquiry was logged
(DATEDIFF(dd, ce.enquiry_time, getdate()) + 1)
-(DATEDIFF(wk, ce.enquiry_time, getdate()) * 2)
-(CASE WHEN DATENAME(dw, ce.enquiry_time) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, getdate()) = 'Saturday' THEN 1 ELSE 0 END)
-(SELECT COUNT(*) FROM nonworking_day WHERE nonworking_day.nonworking_date >= ce.enquiry_time AND nonworking_day.nonworking_date < dateadd(dd,datediff(dd,0,getdate()),1))
It works but I don't understand how it works it out. I am having issues understanding each coloured piece of code and how it works together.
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Aug 22, 2003
Hi I wanted to get difference between this two dates '12-31-2001','01-01-2002').
1 day 0 month 0 year.
Do we have any date function to get like this or we need write our own function stored proc?>
Any advice please?.
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Jul 30, 2007
select datediff(ss,In_time,Out_time)
select datediff(ss,'23:22:11','00:40:50')
But out time is as 12/6/2007 00:40:50
and in time is as 11/6/2007 23:22:11
when iam trying to get the date diff it gives the negitive value as
Column
------------
-81681
how can i get the actual difference
Malathi Rao
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Oct 1, 2007
Hi,
I have a problem with the following:
I have 2 dates in the following format mm/dd/yyyy hh:mm:ss AM.
I would like to measure the difference between 2 dates (Date1 and Date2).
When I use the following expression "DATEDIFF(d, Date1, Date2)" I get a value
without decimals. How can I have a value in days with decimals like e.g. 5.38? If you calculate this using Excel you get decimals behind the comma.
Please help!!!
Thanks!
DHL
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Dec 18, 2007
Hi,
I and my friend are trying to solve problem :
I have a system where an employee makes a call. The call can be of type 1,2,3. I have to calculate:
a. the last time the employee called up for that particular call type.
b. Yesterday
c. Call Duration between the last call date and yesterday
Please see the expected output to get an idea.
I will be passing in EmpID and CallType to the procedure.
First a record gets inserted into CallDetail and then into the Call for each CallType.
SAMPLE SCRIPT:
DECLARE @Call TABLE(CallID INT, CallType INT, CallDetailID INT)
DECLARE @CallDetail TABLE(CallDetailID INT, EmpID INT, EntryDt DateTime)
INSERT @CallDetail
SELECT 12123, 1, '11/30/2007 10:41:34 AM' UNION ALL
SELECT 43555, 1, '12/1/2007 11:21:23 AM' UNION ALL
SELECT 65322, 1, '12/18/2007 04:12:34 AM'
-- 65322 is the current calldetail id
INSERT @Call
SELECT 111, 1, 12123 UNION ALL
SELECT 112, 2, 12123 UNION ALL
SELECT 113, 2, 12123 UNION ALL
SELECT 123, 1, 43555 UNION ALL
SELECT 134, 1, 43555 UNION ALL
SELECT 143, 1, 65322 UNION ALL
SELECT 145, 1, 65322 UNION ALL
SELECT 154, 2, 65322 UNION ALL
SELECT 185, 3, 65322
Select * from @Call
Select * from @CallDetail
EXPECTED OUTPUT-- For CallType 1 EmpID 1
LastCallDate Yesterday Duration
12/1/2007 12/17/2007 16 days
-- For CallType 2 EmpID 1
LastCallDate Yesterday Duration
11/30/2007 12/17/2007 17 days
-- For CallType 3 (There was no CallType 3 made earlier by Empid 1)
LastCallDate Yesterday Duration
- 12/17/2007 0 days
How to achieve it
thanks.
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Apr 15, 2015
Have a table that list item#, date the standard cost went into effect and the standard cost. How do I find the difference in StdCost on the last EffectiveDate and second to last EffectiveDate. 5.59 (01/05/2015) minus 5.81 (09/29/.014) = -.22.
Item#     EffectiveDate   StdCost
1152Â Â Â Â Â Â Â 01/01/2009Â Â Â Â Â 5.50
1152Â Â Â Â Â Â Â 09/29/2014Â Â Â Â Â 5.81
1152Â Â Â Â Â Â Â 04/04/2011Â Â Â Â Â 5.56
[code]....
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Apr 23, 2002
I have a table containing following Columns plus other columns:
Start Date 04-01-2002(mm-dd-yyyy) varchar(10)
Start Time column 09:30:30(hh:mm:ss) varchar(8)
End Date 04-05-2002(mm-dd-yyyy) varchar(10)
End Time column 09:45:30(hh:mm:ss) varchar(8)
1]We want to create a view for Report Users So that they could just select
the other columns and difference in start Date/time to End Date /Time.
2]The Difference in time should be based on Business Day. i.e.
Saturday & Sunday should be excluded. &
3]Each business day is defined as 8.00 am to 5 .00pm
( 1 Business day = 9 hrs)
4]The time is stored as 24 hour clock.
For e.g.
Start Date Start TimeEnd Date End Time Desired Output
04/01/2002 10:00:0004/01/2002 3:30:00 0 Days 5:30 Hrs
04/01/2002 16:00:0004/02/2002 10:45:00 0 Days 3:45 Hrs
04/01/2002 09:00:0004/03/2002 10:45:00 2 Days 1:45 Hrs
04/05/2002 16:30:0004/08/2002 9:45:00 0 Days 2:15 Hrs******
******In last case as 04/06/2002 & 04/07/2002 were Saturday & Sunday ,hence
excluded.So the difference of time is just 2:15 hrs
Can you please give me a suggestion/pseudo code/logic on how I might do this?
We cannot use cursors as we want to make a view.This is for SQL Server 2000
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Feb 24, 2006
Hi to all,
I want to make an sql query that will subtract two dates and the difference will be number in months.
i have this table TestTable with Fields ACost, Adate, AMonth
my formula is this X = (Now-Adate), should give me number in months
and Y = (ACost/AMonth)
i want to get the product of X and Y, (X*Y).
how can i make this in sql views?
can anyone help me with this?
thanks a lot!
best regards,
saldiboy
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