INSERT Statement - Autonumbering

Jan 6, 2007

Hi All,
I am having trouble with a simplet INSERT statement. I want to insert a record. The field "dbid" is the primary key and should be autonumbering. What do I need to add to my code?
 
 Dim myconnection As SqlConnection
myconnection = New SqlConnection()
myconnection.ConnectionString = _
ConfigurationManager.ConnectionStrings("infoNoticeDBConnectionString").ConnectionString

Dim strSQL As String = "INSERT INTO users " & _
"(dbid, infoid) VALUES (@dbid, @infoid)"

Dim dbComm As New SqlCommand(strSQL, myconnection)
dbComm.Parameters.Add("infoid", SqlDbType.NVarChar, 50, "@infoid")

dbComm.Parameters.Add("dbid", SqlDbType.UniqueIdentifier, "dbid")

dbComm.Parameters("infoid").Value = gv2.SelectedValue


Try
myconnection.Open()
dbComm.ExecuteNonQuery()
Catch ex As Exception
Response.Write(ex.Message)
Response.End()
Finally
If myconnection.State = ConnectionState.Open Then
myconnection.Close()
End If
End Try

Response.Write("A new record has been added")
Response.End()

End Sub
 Thanks,
 

 

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Hi there,
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Hello

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Greetings All,

I am moving from Foxpro to SQL. I am little confused
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In foxpro it will allow you to set your fields to "autonumber"
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numbers, depending on the application function.

When I try to do this in SQL I can setup my first identity
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One last note, I am still using the Studio Manager
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Apr 9, 2007

Hello
 I have a problem with setting relations properly when inserting data using adonet. Already have searched for a solutions, still not finding a mistake...
Here's the sql management studio diagram :

 and here goes the  code1 DataSet ds = new DataSet();
2
3 SqlDataAdapter myCommand1 = new SqlDataAdapter("select * from SurveyTemplate", myConnection);
4 SqlCommandBuilder cb = new SqlCommandBuilder(myCommand1);
5 myCommand1.FillSchema(ds, SchemaType.Source);
6 DataTable pTable = ds.Tables["Table"];
7 pTable.TableName = "SurveyTemplate";
8 myCommand1.InsertCommand = cb.GetInsertCommand();
9 myCommand1.InsertCommand.Connection = myConnection;
10
11 SqlDataAdapter myCommand2 = new SqlDataAdapter("select * from Question", myConnection);
12 cb = new SqlCommandBuilder(myCommand2);
13 myCommand2.FillSchema(ds, SchemaType.Source);
14 pTable = ds.Tables["Table"];
15 pTable.TableName = "Question";
16 myCommand2.InsertCommand = cb.GetInsertCommand();
17 myCommand2.InsertCommand.Connection = myConnection;
18
19 SqlDataAdapter myCommand3 = new SqlDataAdapter("select * from Possible_Answer", myConnection);
20 cb = new SqlCommandBuilder(myCommand3);
21 myCommand3.FillSchema(ds, SchemaType.Source);
22 pTable = ds.Tables["Table"];
23 pTable.TableName = "Possible_Answer";
24 myCommand3.InsertCommand = cb.GetInsertCommand();
25 myCommand3.InsertCommand.Connection = myConnection;
26
27 ds.Relations.Add(new DataRelation("FK_Question_SurveyTemplate", ds.Tables["SurveyTemplate"].Columns["id"], ds.Tables["Question"].Columns["surveyTemplateID"]));
28 ds.Relations.Add(new DataRelation("FK_Possible_Answer_Question", ds.Tables["Question"].Columns["id"], ds.Tables["Possible_Answer"].Columns["questionID"]));
29
30 DataRow dr = ds.Tables["SurveyTemplate"].NewRow();
31 dr["name"] = o[0];
32 dr["description"] = o[1];
33 dr["active"] = 1;
34 ds.Tables["SurveyTemplate"].Rows.Add(dr);
35
36 DataRow dr1 = ds.Tables["Question"].NewRow();
37 dr1["questionIndex"] = 1;
38 dr1["questionContent"] = "q1";
39 dr1.SetParentRow(dr);
40 ds.Tables["Question"].Rows.Add(dr1);
41
42 DataRow dr2 = ds.Tables["Possible_Answer"].NewRow();
43 dr2["answerIndex"] = 1;
44 dr2["answerContent"] = "a11";
45 dr2.SetParentRow(dr1);
46 ds.Tables["Possible_Answer"].Rows.Add(dr2);
47
48 dr1 = ds.Tables["Question"].NewRow();
49 dr1["questionIndex"] = 2;
50 dr1["questionContent"] = "q2";
51 dr1.SetParentRow(dr);
52 ds.Tables["Question"].Rows.Add(dr1);
53
54 dr2 = ds.Tables["Possible_Answer"].NewRow();
55 dr2["answerIndex"] = 1;
56 dr2["answerContent"] = "a21";
57 dr2.SetParentRow(dr1);
58 ds.Tables["Possible_Answer"].Rows.Add(dr2);
59
60 dr2 = ds.Tables["Possible_Answer"].NewRow();
61 dr2["answerIndex"] = 2;
62 dr2["answerContent"] = "a22";
63 dr2.SetParentRow(dr1);
64 ds.Tables["Possible_Answer"].Rows.Add(dr2);
65
66 myCommand1.Update(ds,"SurveyTemplate");
67 myCommand2.Update(ds, "Question");
68 myCommand3.Update(ds, "Possible_Answer");
69 ds.AcceptChanges();
70

and that causes (at line 67):"The INSERT statement conflicted with the FOREIGN KEY constraint
"FK_Question_SurveyTemplate". The conflict occurred in database
"ankietyzacja", table "dbo.SurveyTemplate", column
'id'.
The statement has been terminated.
at System.Data.Common.DbDataAdapter.UpdatedRowStatusErrors(RowUpdatedEventArgs rowUpdatedEvent, BatchCommandInfo[] batchCommands, Int32 commandCount)
at System.Data.Common.DbDataAdapter.UpdatedRowStatus(RowUpdatedEventArgs rowUpdatedEvent, BatchCommandInfo[] batchCommands, Int32 commandCount)
at System.Data.Common.DbDataAdapter.Update(DataRow[] dataRows, DataTableMapping tableMapping)
at System.Data.Common.DbDataAdapter.UpdateFromDataTable(DataTable dataTable, DataTableMapping tableMapping)
at System.Data.Common.DbDataAdapter.Update(DataSet dataSet, String srcTable)
at AnkietyzacjaWebService.Service1.createSurveyTemplate(Object[] o) in J:\PL\PAI\AnkietyzacjaWebService\AnkietyzacjaWebServicece\Service1.asmx.cs:line 397"


Could You please tell me what am I missing here ?
Thanks a lot.
 

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Jan 14, 2008


This problem is being seen on SQL 2005 SP2 + cumulative update 4

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I now need to add an "instead of insert" trigger to the table that is the subject of the insert.

As soon as I add the "instead of insert" trigger, the output clause on the insert statement does not return any data - although the insert completes successfully. As a result I am not able to obtain the identities of the inserted rows

Note that @@identity would return the correct value in the test repro below - but this is not a viable option as the table in question will be merge replicated and @@identity will return the identity value of a replication metadata table rather than the identity of the row inserted into my_table

Note also that in the test repro, the "instead of insert" trigger actually does nothing apart from the default insert, but the real world trigger has additional code.

To run the repro below - select each of the sections below in turn and execute them
1) Create the table
2) Create the trigger
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I need the behaviour to be correct when the trigger is present

Any thoughts would be much appreciated

aero1


/************************************************
1) - Create the table
************************************************/
CREATE TABLE [dbo].[my_table](
[my_table_id] [bigint] IDENTITY(1,1) NOT NULL,
[forename] [varchar](100) NULL,
[surname] [varchar](50) NULL,
CONSTRAINT [pk_my_table] PRIMARY KEY NONCLUSTERED
(
[my_table_id] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF, FILLFACTOR = 70) ON [PRIMARY]
)

GO
/************************************************
2) - Create the trigger
************************************************/
CREATE TRIGGER [dbo].[trig_my_table__instead_insert] ON [dbo].[my_table]
INSTEAD OF INSERT
AS
BEGIN

INSERT INTO my_table
(
forename,
surname)
SELECT
forename,
surname
FROM inserted

END

/************************************************
3) - Do the insert
************************************************/

DECLARE @my_insert TABLE( my_table_id bigint )

declare @forename VARCHAR(100)
declare @surname VARCHAR(50)

set @forename = N'john'
set @surname = N'smith'

INSERT INTO my_table (
forename
, surname
)
OUTPUT inserted.my_table_id INTO @my_insert
VALUES( @forename
, @surname
)

select @@identity -- expect this value in @my_insert table
select * from @my_insert -- OK value without trigger - zero with trigger

/************************************************
4) - Drop the trigger
************************************************/

drop trigger [dbo].[trig_my_table__instead_insert]
go

/************************************************
5) - Re-run insert from 3)
************************************************/
-- @my_insert now contains row expected with identity of inserted row
-- i.e. OK

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Nov 2, 2000

I am trying to do an insert in a particular View...one of the field has got an 'Apostrophe'.(Ex: SQl Server's).
When i do this i get an error. the system does not allow me to insert....
is there any way i can do an Insert with that...???

Thanks

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Feb 2, 2001

How can you insert this statement in a table using Query Analyzer.
(today's date)as single statement.


Thank You,
John

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Nov 17, 2005

How do I
1.) take two seperate columns and combine the data
2.) take that combined data and populate a third column.

Here is an example of what I've been trying to do:

Insert INTO Table_1 (Column1)
Select Column2 + Column3
From Table_1

I continue to get this error message:

Server: Msg 515, Level 16, State 2, Line 1
Cannot insert the value NULL into column 'Column_2', table 'DB1.dbo.Table_1'; column does not allow nulls. INSERT fails.
The statement has been terminated.

If some one could please give me a general script that could do this I would appreciate it. I'm new to using SQL and I'm a little bit lost.

Thanks.

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Sep 29, 2004

I need an insert statement that will grab the maximum of TimeGenerated from the Events table and insert it into LastEventTime in the Host Table. But it has to be inserted based on the relationship of SystemNetName.

For Example,

Host Table
--------------------------------------
SystemNetName LastEventTime
Tweety 9/24/2004
Sylvester 9/25/2004

Events Table
----------------------------------------
SystemNetName TimeGenerated
Tweety 9/24/2004
Tweety 8/26/2004
Sylvester 8/21/2004
Sylvester 9/25/2004
Sylvester 7/5/2004


This is what I had so far but didn't work:
Insert into host(LastEventTime)
Select(Max(TimeGenerated) ) from Events Where
Events.SystemNetName = Host.SystemNetName


Any Ideas?

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Aug 20, 2004

Is is possible to use a Where Clause in a Insert statement in MS SQL? I keep getting a syntax error near 'Where'. Is there something wrong with this?

Insert INTO CPU (CPUNumber, Name, MaxClockSpeed, SystemNetName) Values('CPU2', 'Intel', '2392', 'TWEETY') Where 'CPU2' NOT IN (Select CPUNumber from CPU)

I want to insert into the cpu table as long as what I am inserting is not already in the table.

Desparate.

Thanks,
Laura

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Jun 22, 2004

Can someone help me parse this oracle insert statement into SQL Server please?

insert into notify_template (subject, body, priority)
values
(
'
Budgeted time exceeded for task [18040]
',
'
Actual Time exceeds Budgeted time for the following task'
|| chr(10) || chr(10) ||
'Task Name : [18040]
Root Program Name : [18049]
Actual Days : [2000000100]
Budgeted Days : [2000000101]
Estimated Time : [2000000102]'
|| chr(10) || chr(10) ||
' The following resource(s) in the above task have exceeded the budgeted time:'
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' [2000000784]'
|| chr(10) || chr(10) ||
'Click here : [12865]
',
2)

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Jul 16, 2006

hi all

i am writing a trigger that inserts from one table to the next. i have an issue with the table being inserted into have 2 more columns than the one being inserted from. Here is the trigger just in case

CREATE TRIGGER [Insert40801] ON [dbo].[tPA10801]
FOR INSERT

AS

insert into tPA40801
select
intTimesheetKey,
chrTimesheetNumber,
TranID,
intEmployeeKey,
intEmployeeDivKey,
BatchKey,
dtePeriodStartDate,
dtePeriodEndDate,
chrStatus1,
numTotalHrsWorked,
numTotalHrsBilled,
numTotalCosts,
numTotalCharges,
numTotalRecover,
chrSignedID,
dteSignedDate,
chrApprovalID,
dteApprovalDate,
intJobKey,
intPhaseKey,
intTaskKey,
dteDate,
siCstClsificatnDDL,
UpdateCounter,
CompanyID



from tpa10801

now tpa40801 has two extra columns that tpa10801 doesnt. how would i please the sql gods and get the insert statement running? thanks alot

tibor

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Sep 22, 2006

I need to insert over 600 similar records in a table. The only way I know is to write insert into <table> command 600 times. Is there another way which is easier?

Thanks in advance,
Saurav

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Mar 25, 2007

my insert statement got no error but when i check my table the values were not inserted actually.. what maybe the problem?

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Apr 10, 2007

Does anyone see anything wrong with this Insert

INSERT INTO dbo.Report
(LossType, Loss, Area)
SELECT [Loss Type], Loss, Area
FROM dbo.[Main Table]

I keep getting does not alow nulls insert fails

this is the Report Table
CREATE TABLE [Report] (
[Incident Report No] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL ,
[Date] [datetime] NULL ,
[Time] [datetime] NULL ,
[Investigators Name] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Reported by] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Law Enforcement Agency] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Name of Officer] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Evidence Seized] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Associated Reports] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Corrective Action] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL CONSTRAINT [DF_Report_Corrective Action] DEFAULT (N'YES'),
[Comments] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[I/RDocument] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL CONSTRAINT [DF_Report_I/RDocument] DEFAULT (N'SCANNED REPORT'),
[TypeOfIncident] [nvarchar] (300) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Exclusion] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL CONSTRAINT [DF_Report_Exclusion] DEFAULT (N'NO'),
[86_D] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL CONSTRAINT [DF_Report_86_D] DEFAULT (N'NO'),
[Loss] [money] NULL CONSTRAINT [DF_Report_Loss] DEFAULT (0.0000),
[LossType] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Area] [nvarchar] (75) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Action/Incident] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Security/GC] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL CONSTRAINT [DF_Report_Security/GC] DEFAULT (N'GC'),
CONSTRAINT [PK_Report] PRIMARY KEY CLUSTERED
(
[Incident Report No]
) ON [PRIMARY]
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
GO





and the [Main Table]


CREATE TABLE [Main Table] (
[ID] [int] IDENTITY (1, 1) NOT NULL ,
[IR Number] [nvarchar] (100) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL ,
[Date] [datetime] NULL ,
[Inspector] [int] NULL ,
[Area] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Violation] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Violation Type] [int] NULL ,
[Loss] [money] NULL ,
[Loss Type] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Employee] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Guest] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Action] [nvarchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
[Action Type] [int] NULL ,
[Notes] [ntext] COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
CONSTRAINT [PK_Main Table] PRIMARY KEY CLUSTERED
(
[ID]
) ON [PRIMARY]
) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
GO

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hi,

I was wondering how we can insert new records into a table which has records already.

The first col. is an identity col and a primary key.
I have 3000 records and the first col. has unique id but then I need to need to insert new records without inserting all records again.

please let me know if you have any ideas.

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