Nvarchar Fields With Time Data - Calculate Difference In Hours

Sep 19, 2014

I have two nvarchar fields with time data 12:34:34 and the second one 12:34 I want to calculate the difference in Hours. The first field is called (OTIM) the second field is called (ReportedTime) if the name matters. I tried substring to trim the OTIM, I am unable to make it work.

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Transact SQL :: Getting Time Difference In Hours And Minutes?

Jul 10, 2015

Currently my script is using the below mentioned query to find the time difference.

DATEDIFF(HH,DATEADD(SS,hcreacion,fcreacion) ,DATEADD(SS,hcerrar,fcreacion))

If there is 1 hr 30 minutes time difference, I am getting 2 hours as output. But we need 1.30 as output. is there any way to achieve this?

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Sep 16, 2005

I have written a function that returns the number of Days, Hours and minutes from a given number of minutes. On testinf the results are close but not quite there. Can anyone see where I have gone wrong or is there an easier way of doing this? Code is as follows:

CREATE FUNCTION dbo.GetTimeBetweenLong
(@StartTime DateTime, @EndTime DateTime, @CurrentDate DateTime)
RETURNS VarChar(50) AS
BEGIN
DECLARE @TotalTime Numeric
DECLARE @Minutes Numeric
DECLARE @Hours Numeric
DECLARE @Days Numeric
DECLARE @MinutesInDays Numeric

IF @EndTime IS NULL
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @CurrentDate)
SET @Hours = DATEDIFF(Hour, @StartTime, @CurrentDate) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @CurrentDate) - ((@Days * 24)*60) - (@Hours * 60)
END
ELSE
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @EndTime)
SET @Hours = DATEDIFF(Hour, @StartTime, @EndTime) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @EndTime) - ((@Days * 24)*60) - (@Hours * 60)
END

IF(@Days <0)
BEGIN
SET @Days = @Days - @Days - @Days
END

IF (@Hours < 0)
BEGIN
SET @Hours = @Hours - @Hours - @Hours
END

IF (@Minutes <0)
BEGIN
SET @Minutes = @Minutes - @Minutes - @Minutes
END

RETURN CONVERT(nVarChar(10),@Days) + ' Days, ' + CONVERT(nVarChar(5), @Hours) + ' Hours, ' + CONVERT(nVarCHar(5), @Minutes) + ' Mins'

END

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Oct 9, 2013

i am using this expression to get the time difference between two times.

{%Z.elapsed.time(@AK.VD.depart.date,@AK.VD.depart.time,@AK.VD.depart.date,@DV.VD.arrival.time,"hh.hh")*60} as [LOS (min)]

When Arrival time and depart time both are on same day above expression working to get the diference .

But if arrival date 2013-09-20 00:00:00.000 and arrival time 0800 and depart date 2013-09-21 00:00:00.000 and depart time 0050 when i calculate the time difference(using above expression) between these two i am getting -429.60 which is wrong. i have to get around 990.

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Jul 2, 2015

I have a table like this.

CREATE TABLE Table1
([S_ID] varchar(7), [S_ACTV_CODE] varchar(4), [S_USER] varchar(5), [S_DATETIME] varchar(19), [S_ACT_IND] int)
;
INSERT INTO Table1
([S_ID], [S_ACTV_CODE], [S_USER], [S_DATETIME], [S_ACT_IND])
VALUES
('AAA-111', NULL, 'USER1', '2015-06-15 00:21:06', 0),
('AAA-111', '2', 'USER1', '2015-06-15 00:21:07', 0),

[code]....

Basically I want to calculate the time spent by S_Users on a particular S_ACTV_CODE:

- S_ACTV_CODE_PREV means the previous active records.

- S_START_TIME is the time of S_DATETIME when a S_ACTV_CODE starts

- S_END_TIME is the time before a S_ACTV_CODE changes to another S_ACTV_CODE

- For the first record, S_ACTV_CODE is null, so there is no S_ACTV_CODE_PREV, so S_ACTV_CODE_PREV is NULL

- For the second record S_ACTV_CODE has some value, but S_ACTV_CODE_PREV is NULL for first record. So second record S_ACTV_CODE_PREV is also NULL

- For the last record (means S_ACTV_IND = 1), the user is currently working on it and S_ACTV_CODE is not changed. So S_END_TIME is a open time and we want to keep it as NULL

So the result should be as below:

S_ID S_ACTV_CODE_PREV S_ACTV_CODE_CURR S_USER S_START_TIME
S_END_TIME TIME_SPENT (in Sec)
AAA-111 NULL NULL USER1 2015-06-15 00:21:06
2015-06-15 00:21:07 1
AAA-111 NULL 2 USER1 2015-06-15 00:21:07
2015-06-17 03:20:33 183566
AAA-111 2 4 USER2 2015-06-17 03:20:33

[code]....

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Nov 6, 2006

Hi
Can anyone help me convert a number to give the result in hours and minutes? For example 195 as 3:15 or 210 as 3:30. We are trying to create a report showing hours and minutes worked without having to export to Excel.

I've had a look around the net and this seems to be quite a difficult function in SQL Server.

Any guidance much appreciated.

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Nov 8, 2007

hi Everyone,

I have one query, i want to calculate the business working hours (like from monday to friday 9 to 5 pm and saturday 9 to 2 pm) for the given dates. And also i want to eliminate the public holidays with in the given dates.



If any one was faced the same situation plz help me.




Regards

Venki

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Dec 13, 2007



//Sorry my English!


I have got a two datetime field in my table. Example

startDate EndDate
----------------- ------------------
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Please help

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How can I calculate and return the previous Date at 18:00 Hours?

Here is a miserable attempt:

DECLARE @RunDate SmallDateTime
DECLARE @CurrentDate SmallDateTime
DECLARE @RunDateWoTime SmallDateTime
SET @CurrentDate = GETDATE()

SET @RunDate = DATEADD(day,-1,@CurrentDate)-- AS CurrentDate
SELECT @RunDate AS RunDate

-- Desired Result is the following:

-- 2014-03-03 18:00

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DECLARE @iDAY AS SmallDatetime
SET @iDAY = '2004-08-12 10:05:00'


PRINT @iDAY
PRINT GETDATE()

PRINT GETDATE()-@iDAY
+++++++++++++++
Aug 12 2004 10:05AM
Aug 13 2004 10:05AM
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Dec 8, 2007

Hi All,
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Is there any inbuilt function in SSRS is available to implement this. Or any other way to do this.Please help me with this .Thanks in advance.

With Thanks
M.Mahendra



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SELECT 
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FROM pmt_attendance

o/p
indate   04/18/2015
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declare @siva1 datetime;
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I am having trouble creating a sp for the following situation:

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Truck Period Reading
1 1/31/03 55102
2 1/31/03 22852
1 2/28/03 62148
2 2/28/03 32108
1 3/31/03 69806
2 3/31/03 52763

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TIA,

Rob

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I was thinking something like


Code:

Update #ClaimMaster
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Thanks,

sluggy

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  2015-05-29 7:05:00      AOOze            start

  2015-05-29 7:10:00      AOOze            pqy
  2015-05-29 7:15:00      AOOze            lab
  2015-05-29 7:20:00      AOOze            lmn   

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  2015-05-29 7:35:00      AOOze            stop

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For example:

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thanks

kam

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RETURNS int
AS
BEGIN
declare @i int
Declare @count int

[Code] .....

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