Partitioned Tables And Parameters

Apr 18, 2007

Hello all,
I was wondering if anyone else ran into this and if how you got around it.
In a nut shell the SQL optimizer it NOT pruning the additional partitions from the execution plan as would be expected when applying a constraint directly against the partitioned table€™s partition key, Instead its scanning every partition that you have set up in you partition function range.. Yet when you apply the actual value against the table the plan return as expected.



Hmm.... strange......ghost...ooooooo?

I have created a simple test to reproduce:






Code Snippet

CREATE PARTITION FUNCTION [PTFunction](int) AS RANGE LEFT FOR VALUES (1,2,3)

GO

CREATE PARTITION SCHEME [PTDataScheme] AS PARTITION [PTFunction] TO ([PRIMARY], [PRIMARY], [PRIMARY], [PRIMARY])

GO

CREATE TABLE tblPartitionTest(

ID int identity(1,1) ,

PartitionKey int,

Sales money)

ON PTDataScheme(PartitionKey)

GO

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,10.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,20.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,30.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,40.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(1,50.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,10.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,20.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,30.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,40.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(2,50.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,10.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,20.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,30.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,40.00);

INSERT INTO tblPartitionTest(PartitionKey,Sales) VALUES(3,50.00);

set showplan_text on;

-- query using the set value as a constraint

select * from tblpartitiontest

where partitionkey = 2

--show plan text on result:

|--Table Scan(OBJECT:([tblPartitionTest]), WHERE:([tblPartitionTest].[PartitionKey]=(2)) PARTITION ID:((2)))

-- query using the parameter as a constraint

declare @param_partitionkey int

set @param_partitionkey = 2

select * from tblpartitiontest

where partitionkey = @param_partitionkey

--show plan text on result:

|--Table Scan(OBJECT:([tblPartitionTest]), WHERE:([tblPartitionTest].[PartitionKey]=[@param_partitionkey]) PARTITION ID:(RangePartitionNew([@param_partitionkey],(0),(1),(2),(3))))



BTW I have reproduce this in SP 2 as well.



Any thoughts?

Thanks

Eric





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Code Block

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May 8, 2007

From BOL...

CHECK constraints are not needed for the partitioned view to return the correct results. However, if the CHECK constraints have not been defined, the query optimizer must search all the tables instead of only those that cover the search condition on the partitioning column. Without the CHECK constraints, the view operates like any other view with UNION ALL. The query optimizer cannot make any assumptions about the values stored in different tables and it cannot skip searching the tables that participate in the view definition.

Then why am I getting index scans on my partitioning column on tables that fail the search value based on their check constraint?

Not looking for an answer because I know the query optimizer is a fickle b*tch and I did not post any code, but I needed to rant.

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SQL SERVER 2000 Partitioned Views Bug

May 12, 2008

Thanks in advance in reading this post ! I'm facing a situation in sql server 2000 sp4 with partitioned views.

I have a partition views that joins about 10 tables, in each table there is a check constraint.

For example, if a exec a select count(*) from VIEW where col1 = '20080101' , it goes for the table that has data for '20080101' .

If I exec a select col1,col2,col3,col4 from VIEW where col1='20080101', it goes to all tables and make an index seek.

I want the beaviour of query 1, beause it is just looking on 1 table and not one the 10.



Thanks in advance !

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Very Urgent : Bcp Or Dts Data To Partitioned Views

Jan 1, 2004

someone please tell me if i can bcp or dts data in to partition views
it is failing with the error the bulk operation does not support this

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Updating A Partitioned View In A Cursor

Jan 13, 2004

I have a partitioned view defined by a UNTION ALL of member tables. I can update the member tables through the view without any problem. However, when I declare a cursor on this partitioned view and try to update the view using WHERE CURRENT OF, I get an error saying 'The target object type is not updatable through a cursor'. Does anyone know if it's the case that updating a partitioned view through cursor is not supported in SQL Server 2000?

Thanks

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T-SQL (SS2K8) :: Local Partitioned Views

May 13, 2014

SQL 2008R2, Standard on Windows 2008R2 Enterprise.I have implemented a set of local partitioned views to facilitate multi-threading in one of our applications.Testing with SQL and the insert, update, Delete all work fine. However the inserts from SSIS are Bulk and then fail.According to all I have read I should be able to add "instead of Trigger" for the insert and it should work fine. URL....

I have created instead of triggers for insert and delete and again they work fine when I test them with T-SQL but fail in the SSIS package. The error message is that the view is not updateable.

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