Query To Avoid Certain Rule

Jun 16, 2014

I have a query that maps all products to some customer levels. In this case levels 0,5,7 and 8

DELETE FROM ProductCustomerLevel
WHERE CustomerLevelID IN (0, 5, 7, 8)
INSERT ProductCustomerLevel
(
ProductID,
CustomerLevelID

[Code] ....

Basically this maps all products in a database to these customer levels so that they get a discount.

I know need to create a new customer level, example number 9. These will only have 1 or 2 products applied to it.

How can I change the SQL above so that it does not map those products already in Customer Level 9 to levels 0,5,7 and 8

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Subqueries Do Not Follow Master Query GROUP BY Rule

Nov 20, 2011

I have a query with 2 subqueries, and no error message is reported, but, my problem is that the 2 subqueries do not follow the GROUP BY rule and show the total instead of by vendor...

Code:
SELECT Table1.agents AS Vendor
, Count(Table1.carS) AS Car_Sold
, Sum(Table1.carP) AS Car_Price
, Count(Table1.busS) AS MortBus_Sold
, Sum(Table1.busP) AS busPRice

[Code] ....

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Oct 30, 2006

Hi,

I have a customer who is using vba to pull a result set from an sql server stored procedure into excel. She wants a calculated column added to the result set that gives:
The number days (datediff) between the end date (autend_dte) on one row and the begin date (autbeg_dte) on the next row for each client (clt_num). The rows are to be ordered by client and begin date. The number should be associated with the second row used to calculate the date diff. The first row for each client will have a date diff of 0.

I could do this using a cursor in the stored procedure or a loop in the vba, but I would prefer to do it with the select, but I don't even know where to start.

See expected results below.


CREATE TABLE #testit (
clt_num int NOT NULL ,
autbeg_dte datetime NULL ,
autend_dte datetime NULL)

INSERT INTO #testit (clt_num, autbeg_dte, autend_dte)
SELECT 510, '2004-09-01 00:00:00.000', '2005-09-30 23:59:00.000' UNION ALL
SELECT 510, '2005-10-01 00:00:00.000', '2006-04-06 23:59:00.000' UNION ALL
SELECT 600, '2006-08-01 00:00:00.000', '2006-11-06 23:59:00.000' UNION ALL
SELECT 2529, '2006-01-13 00:00:00.000', '2006-04-11 23:59:00.000' UNION ALL
SELECT 2529, '2005-11-30 00:00:00.000', '2005-12-12 23:59:00.000' UNION ALL
SELECT 2602, '2006-03-29 00:00:00.000', '2006-05-02 23:59:00.000' UNION ALL
SELECT 2602, '2005-11-12 00:00:00.000', '2006-02-27 23:59:00.000' UNION ALL
SELECT 2602, '2006-05-26 00:00:00.000', '2006-06-12 23:59:00.000' UNION ALL
SELECT 2602, '2006-06-18 00:00:00.000', '2006-06-28 23:59:00.000'

SELECT * FROM #testit
order by clt_num,autbeg_dte

Expected result:

clt_numautbeg_dte autend_dte Days Diff
5102004-09-01 00:00:00.0002005-09-30 23:59:00.0000
5102005-10-01 00:00:00.0002006-04-06 23:59:00.0001
6002006-08-01 00:00:00.000 2006-11-06 23:59:00.000 0
25292005-11-30 00:00:00.0002005-12-12 23:59:00.0000
25292006-01-13 00:00:00.0002006-04-11 23:59:00.00044
26022005-11-12 00:00:00.0002006-02-27 23:59:00.0000
26022006-03-29 00:00:00.0002006-05-02 23:59:00.00030
26022006-05-26 00:00:00.0002006-06-12 23:59:00.00024
26022006-06-18 00:00:00.0002006-06-28 23:59:00.0006


Thanks,

Laurie

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Create table #MyPhoneList
(
AccountID int,
EmailWork varchar(50),
EmailHome varchar(50),
EmailOther varchar(50),

[Code] ....

--> In this table AccountID is uniquee

--> email values could be null or repetetive for work / home / Other (same email can be used more than one columns for accountid)

-- a new column will be created with name as Sourceflag( the value could be work, Home, Other depend on email coming from) then removes duplicates

SELECT AccountID , Email, SourceFlag, ROW_NUMBER() OVER(PARTITION BY AccountID, Email ORDER BY Sourceflag desc) AS ROW
INTO #List
from (
SELECTAccountID
, EmailWorkAS EMAIL
, 'Work'AS SourceFlag
FROM#MyPhoneList (NoLock) eml
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[code]....

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Greetings,

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CustomerOrder
----
ID
CustomerID
StatusID

CustomerOrderDetail
----
ID
Order_ID
StockID
Quantity

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select
cod.*
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'def', 'T456',
'ghi', 'T789',
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Code:


BEGIN

BEGIN
--Query #1 (blah)...
END

WHILE EXISTS (SELECT TOP 1 * FROM #tmpTblPurchaseRaw)
BEGIN
BEGIN
--Query #2 (blah)...
END
BEGIN
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END



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Jan 15, 2007

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Nov 20, 2006

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When I run the below DMX query, I get this error message...

Error (Data mining): the dot expression is not allowed in the context at line 5, column 25. Use sub-SELECT instead.

Thanks in advance...

-Young K



SELECT
t.[AgeGroupName]
, t.[ChildrenStatusName]
, (Predict([Basket Analysis AR].[Training Product], 3)) as [ProductPurchases]
, (PredictProbability([Basket Analysis AR].[Training Product].[ProductName])) as [ProductPurchases]
From
[Basket Analysis AR]
PREDICTION JOIN
OPENQUERY([DM Reports DM],
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[AgeGroupName]
, [ChildrenStatusName]
FROM
[dbo].[DM.BasketAnalysis.Contact]
WHERE isTrainingData = 0
') AS t
ON
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Dec 9, 2007

---------------------------------------
small explain
this fonctin-generate daily shift pattern 1,1,2,2,3,3,4,5,...
(shift=1 morning shift 2=evening shift 3=night ........)
and it work ok
-------------------------------------------------------------------------------------------------
how to do this ?
i want to take this fonctin and add rule
so this functin do this
generate daily shift pattern 1,1,2,2,3,3,4,5,...
now add the new rule !!


if the employee get the shift 2 OR 3 on Thursday !!!
but only if it Thursday !
(the week-end start from Thursday until Sunday morning)

the order for this employee id be 2,2,2 or 3,3,3
i explain
the employee must start the week-end and finish it with the same shift
but only if it start a series 2 OR 3 (2=evening 3=night) ON Thursday .
and after continue
if the employee on Thursday start shift 2=evening than after 2,2,2 3,3,4,5,1,1,2,2,3,3,4,5,..
if the employee on Thursday start shift 3=night than after 3,3,3 4,5,1,1,2,2,3,3,4,5,..
so like this if the employee on Thursday start a series value 2 OR 3 the employee must to end it on the week-end from Thursday until Sunday morning

so my friends
can someone save me
how to do this




Code Block
-- need a list of employee ids with a basedate set to when they start with shift_code=1, unit=1
-- this is a minimal tale to show the format
-- extra columns could be added with other info (e.g. name)
create table empbase (
empid int,
basedate datetime
)
-- fill with test data
insert empbase (empid,basedate) values (12345,'2007/1/1')
insert empbase (empid,basedate) values (88877,'2007/1/5')
insert empbase (empid,basedate) values (98765,'2007/1/20')
insert empbase (empid,basedate) values (99994,'2007/6/5')
go
-------------------------------
create function shifts (
@mth tinyint,
@yr smallint
)
returns
@table_var
table (
empid int,
date datetime,
shift_code int,
unit int)
as
-- generate daily shift pattern 1,1,2,2,3,3,4,5,... changing units 1,2,3,4,... every 30 days.
begin
declare @d1 datetime
declare @d31 datetime
set @d1=convert(datetime,convert(char(8),@yr*10000+@mth*100+1))
set @d31=dateadd(dd,-1,dateadd(mm,1,@d1))
;with n01 (i) as (select 0 as 'i' union all select 1)
,seq (n) as (
select
d1.i+(2*d2.i)+(4*d3.i)+(8*d4.i)+(16*d5.i) as 'n'
from
n01 as d1
cross join
n01 as d2
cross join
n01 as d3
cross join
n01 as d4
cross join
n01 as d5)
,dates (dt) as (
select
dateadd(dd,n,@d1) as 'dt'
from
seq
where
dateadd(dd,n,@d1) <= @d31)
,modval (mod,val) as (
select 0,1 union all
select 1,1 union all
select 2,2 union all
select 3,2 union all
select 4,3 union all
select 5,3 union all
select 6,4 union all
select 7,5)
insert @table_var
select
b.empid,
d.dt,
(select val from modval where mod=(datediff(dd,b.basedate,d.dt) % 8)),
((convert(int,(datediff(dd,b.basedate,d.dt) / 30)) % 4) + 1)
from
empbase b, dates d
where
b.basedate <= d.dt
return
end
go


-- test for various months
select * from shifts(1,2007) order by empid,date
select * from shifts(2,2007) order by empid,date
select * from shifts(3,2007) order by empid,date
select * from shifts(4,2007) order by empid,date
select * from shifts(5,2007) order by empid,date
select * from shifts(12,2007) order by empid,date

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Mar 6, 2006

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Jan 4, 2008



Hi,


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Nov 11, 2006

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1. The application does not belong to us.
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Apr 18, 2012

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CREATE TABLE tick
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Jan 15, 2007

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Below is the paper

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Regards,

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