SQL Server 2008 :: How To Find Duplicates In A Table As Per Particular Column

Nov 2, 2015

I am having a main table and temptable.

Every sunday, new data will be loaded from temptable to main table. I have to make sure that, duplicates does not get loaded from temptable to maintable.

For example, if last sunday a record gets loaded from temp to main. If this sunday also the same record is present then it means that is a duplicate.

The duplicate is decided on below scenario

select 'CodeChanges: ', count(*) from CodeChanges a, CodeChanges_Temp b
where a.AccountNumber = b.AccountNumber and
a.HexaNumber = b.HexaNumber and
a.HexaEffDate = b.HexaEffDate and
a.HexaId = b.HexaId and

[Code] ...

Yesterday (Sunday) , data from temp got loaded onto maintable but with duplicates.

There is a log which just displays number of duplicates.

Yesterday the log displayed 8 duplicates found. I need to find out the 8 duplicates which got loaded yesterday and delete it off from main table.

There is a column in both tables which is 'creation date and time'. Every Sunday when the load happens this column will have that day's date .

Now i need to find out what are all the duplicates which got loaded on this sunday.

The total rows in temp table is : 363
No of duplicates present is : 8

I used below query to find out the duplicates but it is returning all the 363 rows from the maintable instead of the 8 duplicates.

Select 'CodeChanges: ', * from CodeChanges a where
exists
( Select 1 from CodeChanges_Temp b where
a.HexaNumber = b.HexaNumber and
a.HexaEffDate = b.HexaEffDate and

[Code] ...

Need finding the duplicate records which has creation date time as '2015-11-01 00:00:00.000' and all the above columns mentioned in the query matches.

Example

Few colums only metioned below

creationdateandtime HexaNumber HexaCode
1. 1987-10-01 00:00:00.000 5 3
2. 2015-11-01 00:00:00.000 5 3

So here the second record is duplicate. This is what I am trying to find.

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[code]...

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