Transact SQL :: Getting Last Register From A Query That Use A Group By Clause

I've got this set of registers (just an example) after ordering by the first 3 columns:

value_A value_B value_C ID date
1 2 3 YVIR 29/08/2015
1 2 3 ANTE 27/04/2015
1 2 3 REGO 20/02/2015

I need to get as a final result:

value_A value_B value_C ID date
1 2 3 REGO 29/08/2015

In other words, I need to get, after ordering the result by the date field, the most recent date but at the same time the oldest ID in the list.

I've been trying to do this with the group by clause:

select
value_A, value_B, value_C, min(ID), max(date) -- or max(ID)
from table
group by value_A, value_B, value_C

But in the field ID I'm getting the wrong result because this value is been associated with the alphabetic order.

In access this query involves the function LAST, but in SQL I have not found a good way to perform this. And I am asking because I have seen some possible solution but almost all of them involving the UNION operation, but my problem is, this table can have more than 350.000 registers.

This table is update by some one else, I just can access the information and use it as a source.