What Are The Maximum Columns That SQL Can Handle?

Mar 7, 2008

What are the maximum columns that SQL can handle?
If I use a table that has about 300 columns and 100,000 records for a web application, Is it going to cause a performance problem?
Have anyone experience in using the size of table like this on web application?

Thank you,
Vi

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How To Handle N-columns In A Table?

Sep 27, 2007

Hi there,
I am trying to create an application that requires n number of columns in table on run time. For example, I want to create a table of products and its properties. For that, I can use master and detail tables, but my problem starts when I get different number of characteristics for different products. Lets say, I have a product that has some colour and size, but for another product, I need expiry date as well and it continues like this. Now I want to know, what I can do to handle this problem. Please help me in this.

Best Regards,
Asif Hameed

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Oct 27, 2007

Hello

I have this newbie question regarding SSIS:

I have a table named People(#Code, Name, eMailList), where the column eMailList has a list of email addresses separated by commas, like "someone@hotmail.com,someone@gmail.com,someone@yahoo.com".

I would like that for each Person, extract the email address info in such a way that I can insert into the following table: EMail(#Code, #ID, Address), where Address has a single email address.

How can I accomplish that?

Thanks a lot.

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Hi,



Does anyone know what is the maximum number of columns allowed in a matrix?



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(col2 + col3) as addcol2,
(col3 + col4) as addcol3,
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Hello friends,

I am sorry to be posting this message in this forum. But thought if anyone does have any idea abt my problem, which i illustrate below.

I want to know what is the maximum number of columns that an INSERT statement can handle?

I have come across a situation where i need to insert 15 values in a table.

INSERT INTO myTable (col1, col2, col3,....., col15) VALUES (v1, v2, v3,...., v15).

Actual statement:

INSERT INTO BillSell (bnumber, stock, qty, price, tprice, seen, bill_id, brokerage, service_tax, brok_st, stt, brok_st_stt, total_cost, total_rate_pu, check)
VALUES ('ICICI 06-12-2004 reshma', 'RELIND', 10, 541.7375183271872, 5417.375183271873, 'no', 2402, 40.2375, 4.92507, 45.162569999999995, 6.771718979089841, 51.934288979089835, 5365.0, 536.5, 'check')


When I call this in Java program, it asks me to check the syntax of the statement as follows :

com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'check) VALUES ('ICICI 06-12-2004 reshma', 'RELIND', 10, 541.7375183271872, 5417.' at line 1

Please make notice that all the data types of the table columns and the values passed in the statement match.

Now the problem is that, when from the above INSERT statement, i remove the last column (i.e. the "check" column and its corresponding value passed i.e. 'check'), the code works fine. I observe here that now there are 14 columns in the statement.

So i need the solutions for this. I cannot move further in the program......

Please help.

Trust in Technology mate .....'Not in Human Beings'

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Hi ,

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Does anybody know if there is a limitation in the number of columns? Or what can cause this error?

Here is the sql:

SELECT DISTINCT FT_TBL.CapId, FT_TBL.Title, FT_TBL.PubMedId, FT_TBL.IssueYear, Rank

FROM ClinicalLiteratureTbl AS FT_TBL,

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Hello

I have this newbie question regarding SSIS:

I have a table named People(#Code, Name, eMailList), where the column eMailList has a list of email addresses separated by commas, like "someone@hotmail.com,someone@gmail.com,someone@yaho o.com".

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DECLARE              
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@ASXCode varchar(5),
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[code]....

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INSERT or UPDATE to this table will fail if the resulting row exceeds the size limit.

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Hi

I'm using service broker and keep getting errors in the log even though everythig is working as expected

SQL Server 2005
Two databases
Two end points - 1 in each database
Two stored procedures:
SP1 is activated when a message enters the sending queue. it insert a new row in a table
SP2 is activated when a response is sent from the receiving queue. it cleans up the sending queue.

I have a table with an update trigger
In that trigger, if the updted row meets a certain condition a dialogue is created and a message is sent to the sending queue.
I know that SP1 and SP2 are behaving properly because i get the expected result.
Sp1 is inserteding the expected data in the table
SP2 is cleaning up the sending queue.

In the Sql Server log however i'm getting errors on both of the stored procs.
error #1
The activated proc <SP 1 Name> running on queue Applications.dbo.ffreceiverQueue output the following: 'The conversation handle is missing. Specify a conversation handle.'

error #2
The activated proc <SP 2 Name> running on queue ADAPT_APP.dbo.ffsenderQueue output the following: 'The conversation handle is missing. Specify a conversation handle.'

I would appreceiate anybody's help into why i'm getting this. have i set up the stored procs in correctly?

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thanks.

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Jan 18, 2008



We have implemented our service broker architecture using conversation handle reuse per MS/Remus's recommendations. We have all of the sudden started receiving the conversation handle not found errors in the sql log every hour or so (which makes perfect sense considering the dialog timer is set for 1 hour). My question is...is this expected behavior when you have employed conversation recycling? Should you expect to see these messages pop up every hour, but the logic in the queuing proc says to retry after deleting from your conversation handle table so the messages is enqueued as expected?

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I have attached an example of one of the queuing procs below:




Code Block
DECLARE @conversationHandle UNIQUEIDENTIFIER,
@err int,
@counter int,
@DialogTimeOut int,
@Message nvarchar(max),
@SendType int,
@ConversationID uniqueidentifier
select @Counter = 0 -- THIS PART VERY IMPORTANT LOL :)
select @DialogTimeOut = Value
from dbo.tConfiguration with (nolock)
where keyvalue = 'ConversationEndpoints' and subvalue = 'DeleteAfterSec'
WHILE (1=1)
BEGIN
-- Lookup the current SPIDs handle
SELECT @conversationHandle = [handle] FROM tConversationSPID with (nolock)
WHERE spid = @@SPID and messagetype = 'TestQueueMsg';
IF @conversationHandle IS NULL
BEGIN
BEGIN DIALOG CONVERSATION @conversationHandle
FROM SERVICE [InitiatorQueue_SER]
TO SERVICE 'ReceiveTestQueue_SER'
ON CONTRACT [TestQueueMsg_CON]
WITH ENCRYPTION = OFF;
BEGIN CONVERSATION TIMER ( @conversationHandle )
TIMEOUT = @DialogTimeOut
-- insert the conversation in the association table
INSERT INTO tConversationSPID
([spid], MessageType,[handle])
VALUES
(@@SPID, 'TestQueueMsg', @conversationHandle);

SEND ON CONVERSATION @conversationHandle
MESSAGE TYPE [TestQueueMsg] (@Message)

END
ELSE IF @conversationHandle IS NOT NULL
BEGIN
SEND ON CONVERSATION @conversationHandle
MESSAGE TYPE [TestQueueMsg] (@Message)
END
SELECT @err = @@ERROR;
-- if succeeded, exit the loop now
IF (@err = 0)
BREAK;
SELECT @counter = @counter + 1;
IF @counter > 10
BEGIN
-- Refer to http://msdn2.microsoft.com/en-us/library/ms164086.aspx for severity levels
EXEC spLogMessageQueue 20002, 8, 'Failed to SEND on a conversation for more than 10 times. Error %i.'
BREAK;
END
-- We tried on the said conversation, but failed
-- remove the record from the association table, then
-- let the loop try again
DELETE FROM tConversationSPID
WHERE [spid] = @@SPID;
SELECT @conversationHandle = NULL;
END;

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-- GET INFORMATION OF THE JOB
DECLARE @JOBIDAS Char(10)
DECLARE @VRUSERVICEHRSAS Decimal(18,2)
DECLARE @VRUSERVICEMINAS Decimal(18,2)
DECLARE @BILLEDFLATAS Decimal(18,2)
DECLARE @BILLREGRATEAS Decimal(18,2)
DECLARE @MIN_HRSAS Decimal(18,2)

DECLARE @COUNT_GREATER_MINTinyInt
DECLARE @COUNT_LESS_MINTinyInt

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-- PROCESS ONLY RECORDS WHERE THERE IS NO FLAT FEE
IF @BILLEDFLAT = 0
BEGIN
IF @VRUSERVICEMIN BETWEEN 0 AND 15
BEGIN
SET @VRUSERVICEMIN = .25
END
ELSE IF @VRUSERVICEMIN = 15
BEGIN
SET @VRUSERVICEMIN = .25
END
ELSE IF @VRUSERVICEMIN BETWEEN 15 AND 30
BEGIN
SET @VRUSERVICEMIN = .5
END
ELSE IF @VRUSERVICEMIN = 30
BEGIN
SET @VRUSERVICEMIN = .5
END
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BEGIN
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Srain.

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