Writting Trigger Or Procedure To Delete Duplicate Entries In A Table?

Sep 3, 2007

I am using Sql Server 2000.
I have a customer table with fields - CustId, Name, Address, City, StdCode, Phone.
I used to insert entries in this table from an excel file.
One excel file will contain thousands of customer.
In this table combination of StdCode and Phone should not be repeated.
If I do it in my VB.Net coding.then application gets drastically slow.
So I want to write a procedure or trigger for this.
Here what I will do, I will send all records into database then this trigger or procedure will check for
any existing entry of combination of StdCode and phone. If entry exists then this will delete new entry
or will not allow this new entry.
Is this possible to do using Trigger or stored procedure?

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Here is a sample of some data:

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hello.

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Hi All !

Below is a snippet of MS SQL inside ASP that retieves
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PS I tried to use distinct but with no luck I want just one of each in the example below.

Thanks in Advance!

Scott

==============================

SQL = ""
SQL = "SELECT B.CIMS_MSDS_NUM," & _
"A.COMMODITY_NUMBER, " & _
"B.CIMS_TRADE_NME," & _
"B.CIMS_MFR_NME," & _
"B.CIMS_MSDS_PREP_DTE," & _
"B.APVL_CDE," & _
"COALESCE(C.REGDMATLCD,'?') AS DOTREGD," & _
"COALESCE( D.CIMS_TRADE_SYNM,'NO SYNONYMS') AS SYNONYM, " & _
"A.MSDS_CMDTY_VERIF, " & _
"A.CATALOG_ID " & _
"FROM ( MATEQUIP.VMSDS_CMDTY A " & _
" RIGHT OUTER JOIN MATEQUIP.VCIMS_TRD_PROD_INF B " & _
" ON A.CIMS_MSDS_NUM = B.CIMS_MSDS_NUM " & _
" LEFT OUTER JOIN MATEQUIP.VDOT_TRADE_PROD C " & _
" ON A.CIMS_MSDS_NUM = C.MSDSNUM " & _
" LEFT OUTER JOIN MATEQUIP.VCIMS_TRD_PROD_SYN D " & _
" ON B.CIMS_MSDS_NUM = D.CIMS_MSDS_NUM) "

SQL1 = ""
SQL1 = SQL

SQL = SQL & "WHERE " & Where & " "
==================================

Here is a piece of the problem field, note repeating colors etc.

CCM-PAINTS & COATINGS (1/26/98)F65E36 ORANGE F65W1 GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEF65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEDISAPPROVED BY CCM-PAINTS & COATINGS (1/26/98)F65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65E36 ORANGE F65W1 GLOSS WHITEDISAPPROVED BY CCM-PAINTS & COATINGS (1/26/98)F65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65E36 ORANGE F65W1 GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65A1 WARM GRAY F65L6 TURQUOISEDISAPPROVED BY CCM-PAINTS

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Jan 3, 2007

Hi All,



Below is a snippet of MS SQL inside some VB that retieves
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Below is the SQL and the results from the returned page.


PS I tried to use distinct but with no luck I want just one of each in the example below.

Thanks in Advance!

Scott

==============================

SQL = ""
SQL = "SELECT B.CIMS_MSDS_NUM," & _
"A.COMMODITY_NUMBER, " & _
"B.CIMS_TRADE_NME," & _
"B.CIMS_MFR_NME," & _
"B.CIMS_MSDS_PREP_DTE," & _
"B.APVL_CDE," & _
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"COALESCE( D.CIMS_TRADE_SYNM,'NO SYNONYMS') AS SYNONYM, " & _
"A.MSDS_CMDTY_VERIF, " & _
"A.CATALOG_ID " & _
"FROM ( MATEQUIP.VMSDS_CMDTY A " & _
" RIGHT OUTER JOIN MATEQUIP.VCIMS_TRD_PROD_INF B " & _
" ON A.CIMS_MSDS_NUM = B.CIMS_MSDS_NUM " & _
" LEFT OUTER JOIN MATEQUIP.VDOT_TRADE_PROD C " & _
" ON A.CIMS_MSDS_NUM = C.MSDSNUM " & _
" LEFT OUTER JOIN MATEQUIP.VCIMS_TRD_PROD_SYN D " & _
" ON B.CIMS_MSDS_NUM = D.CIMS_MSDS_NUM) "

SQL1 = ""
SQL1 = SQL

SQL = SQL & "WHERE " & Where & " "
==================================

Here is a piece of the problem field, note repeating colors etc.

CCM-PAINTS & COATINGS (1/26/98)F65E36 ORANGE F65W1 GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEF65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEDISAPPROVED BY CCM-PAINTS & COATINGS (1/26/98)F65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65E36 ORANGE F65W1 GLOSS WHITEDISAPPROVED BY CCM-PAINTS & COATINGS (1/26/98)F65A2 LIGHT GRAY F65L7 PALE BLUEF65A1 WARM GRAY F65L6 TURQUOISEF65B4 SEMI-GLOSS BLACK F65R1 VERMILIONF65B1 GLOSS BLACK F65N11 RICH BROWNF65A49 ASA #49 GRAY F65M1 MAROONF65A4 MACHINE TOOL GRAY F65L10 BRIGHT BLUEF65L4 DARK BLUEF65L3 LIGHT BLUE V65V100 MIXING CLEARF65H1 IVORY F65Y48 LIGHT YELLOWF65G41 FOREST GREEN F65Y44 LEMON YELLOWF65G40 MEDIUM GREEN F65W100 MIXING WHITEF65G39 LIGHT GREEN F65W4 TINTING WHITEF65G16 SEMI-GLOSS MACHINERY GRE F65W3 CUSTOM WHITEF65E37 INTERNATIONAL ORANGE F65W2 SEMI-GLOSS WHITEF65E36 ORANGE F65W1 GLOSS WHITEF65B50 WR. IRON FLAT BLACK F65R2 TARTAR RED DARKF65A1 WARM GRAY F65L6 TURQUOISEDISAPPROVED BY CCM-PAINTS & COATINGS (1/26/98)F65B1 GLOSS BLACK F65N11

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Error details will be goes to LOG_INVENTORY_ERROR

I have 4 duplicate rows in the Flatfile_Inventory which i have already inserted in the Parent and child table.

Again when i run the query using stored procedure,its tells that all the 4 rows are duplicate and will move to the Log_Inventory_Error.

I need is if i have the duplicate rows in the flatfile_Inventory when i start inserting into the parent and child table the already inserted row have the unique ID i must identify it and delete that row in the both parent and chlid table.And latest row must get inserted into the Parent and child table from Flatfile_Inventory.

-- ===============================================================================================
-- STORED PROCEDURE FOR FLATFILE_INVENTORY
-- ===============================================================================================
USE [IconicMarketing]
---=======================================SALES_CURSUR===========================================
--USE IconicMarketing
--GO
DECLARE
@FileType varchar(50) ,
@ACDealerID varchar(50) ,

[code].....

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Best Method Of Checking For Duplicate Entries In SQL Server

Aug 22, 2007

Here is my situation.  I have a table in my application that pairs users with cars they like.  We'll call this table Favorites.  A user can browse the site and they can designate as many cars they want as favorites.  For example, a user can go to the Honda Accord page and add that as a favorite car and then go to the Toyota Camry page and add that as a favorite car.  However, if he/she goes to that Honda Accord page and tries to click the "Add to Favorites" button again, at the present state of my application, it will just add another entry into the Favorites table with a duplicate pairing.  So, if I were to datalist the table to generate a listing of all favorites belonging to a certain user, he/she may potentially be returned with superfluous duplicate entries.  Not to mention, taking up valuable database space and not looking very professional.
In my Favorites table, the 3 fields are.....favoriteId (set as primary key)userIdcarId
I've been thinking about this for awhile and I've come up with 2 solutions.  I'm a newbie to ASP.NET/programming so I don't have enough insight to make a decision or to even think up of other alternatives.
1) Check proactively by doing a.....SELECT favoriteID FROM Favorites WHERE userId = x and carId = y  (where x and y are variables)If I get a null return, it means I can go ahead and let the user add the car as a favorite in the database.  If I get a valid value, then it means there already exists the same pairing, so I exit out without updating the table.
2) Check reactively by forcing an exception whenever a user tries to enter a duplicate pairing.  I'm not sure how to do this, but perhaps, instead of making "favoriteId" a primary key, perhaps, I can make a primary key pairing of "userId" and "carId".  And by trying to do an insert with a primary key that already exists, we know it won't work since primary keys by definition are unique.
Now, I expect some concurrent users on my site, so I must take into consideration pros and cons of each and determine which is more efficient.  Checking proactively will force a check even if the table does not contain a duplicate pairing of user and car.  However, having a duplicate primary key may be more expensive from a database point of view and may slow down lookups, etc.  Or maybe neither has significant benefits, in which case, I rather go with proactive, since I've already coded it and it works fine.  Or maybe there is a third alternative, which I did not think.  Which method do programmers usually take and which is a better practice?
TIA for your help.

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