Count Distinct

Mar 23, 2007

hi all,

sometimes, when tables are poorly joined, we have exactly same rows as a result.. so we use distinct.. but how can we count(*) the distinct rows?


select distinct d.docrefid from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'

will return me

docrefid
DC01C06027

but when i try to count(*) only the distinct record, it count all..

select distinct d.docrefid, count(*) from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'
group by d.docrefid

will return me

DocrefId Count
DC01C060272

when i expect

DocrefId Count
DC01C060271




~~~Focus on problem, not solution~~~

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Select Distinct
sum(isnull(cast([Total Count] as float),0))

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Oct 23, 2001

hi!
i am trying to get a count of 3 distinct values , one of them being a datetime - am running into errors - any suggestions are appreciated.


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i am trying to do a distinct on individualid + intakeseq + exitdate,
& then get their count.

Thanks!

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Mar 14, 2007

Hello

for mS SQL 2000

with

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but how can I get the COUNT only ?

something like

SELECT COUNT(SELECT DISTINCT Name, Region
FROM Groups
GROUP BY Name, Region) AS CPT FROM Groups

i must get 254

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Nov 9, 2007

Hi,

I have write down following query ..

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Jul 20, 2006

Hi



I have a table which stores the shift information for employees. The table contains 10 columns as Employeename,Employeeno,month,year,shifttimings etc. If an employee works a day in a particular shift, then a row will be inserted in to the above table for that employee.

Now at the end of the month i wanted to calculate the shift details for each employee for a particular month of a given year like employeename,employeeno, noofdays(countof shiftdays).

Can some body help?



Thanks in Advance!

Santhosh



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Nov 30, 2003

I have an SQL statement that looks like the following:

SELECT [Docs-Entities].entityID, entityName, COUNT([Docs-DocsEntities].filename) AS numDocs
FROM [Docs-Entities] LEFT JOIN [Docs-DocsEntities]
ON [Docs-Entities].entityID = [Docs-DocsEntities].entityID
GROUP BY [Docs-Entities].entityID, entityName

but the problem is that numDocs (the COUNT) is not returning a distinct count. In the DocEntities table, a particular document can actually have multiple entries with the same entityID so that produces inflated numbers for numDocs. But when I do a SELECT DISTINCT on a particular entityID, the results are less and don't match the numDocs number because I only need to list the document one time. This is not a huge issue, but it looks bad on my site.

Is there a way that I can make COUNT count distinctly?

Thanks for the help and I hope I worded that cllearly...

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Aug 17, 2005

I'm struggling to fin a way to use DISTINCT keyword with ROLLUP (or Cube).For example,SELECT employee_city, employee_country, COUNT(DISTINCT employee_name)FROM employeeGROUP BY employee_city, employee_country WITH ROLLUPthat query does not work.Is there a workaround?Thx.

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Jan 28, 1999

hi, I have a table that contain(custname,ordno,ordchange,ordlocation,reaso n)
I want to determine the following:
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here what I wrote as a query, tell me if I am right. I thank you for your help

select custname, COUNT(DISTINCT ordno) ,
COUNT(DISTINCT ordchange) ,
COUNT(DISTINCT ordlocation) ,
COUNT( reason)
from customers a, orders b
where a.custname =b.custname
group by custname

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Aug 30, 2006

Hi,

I want a count of distinct rows in a table through a single query -- is it possible?

eg.

table-

create table ch1 (a int, b int, c int, d int)

insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,3,4,5)

Here distinct row count in a table is 3 which I want to achieve thro a query.

if I do

select count(distinct a) from ch1 it works fine and gives me output as 2.

but this is not working

select count(distinct a,b,c,d) from ch1 - any workaround to find the distinct row count in a table??

Please reply.

Cheers!
Ram.

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Distinct Count Query

Dec 11, 2007

I have a table with following fields
tdate
custcode
prodcode


table is filled with full year data and i want following result

I want count of distinct custcode in every past three months.

for example
Result like this

month tjan tfeb tmar tapr tmay ..... tdec

prod1
prod2
.
.
prod5

And data under tmar should be count of distinct custcode of (jan,feb and mar) for corresponding prod code is required.
Under tapr, count of distinct custcode of (feb,mar and apr) for corresponding prod code is required.

Can any1 help me please.

I am using MS SQL 2005 and above table is a big table (approx 10 million records)

Sham

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May 15, 2008

how can i count in sql the number or records taht would be returned if i did

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Oct 14, 2007

hello,
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i get that error:
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here are the table rows, if you need that
CommentID --- UserName --- PictureID --- DateCommented
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Mar 28, 2007

It doesn't seem possibly, but maybe?
Is there a way to have an expression be used, but also benefit from using distinct on a column?

I'm looking for something like:
sum(case when dtEntered > '1-1-2006' then 1 else 0 end)
but also encorporating somehow a distinct count on UserName. So a username showing twice would only count once, and this would only be counted if the record's dtEntered date was greater than Jan 1, 2006.

The reason I'm writing the statement that way is because there are 5 columns which aggregate data by different time periods.

If it's not possible, I will just end up joining to the table multiple times, putting the date filter in the where clause.

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Jul 12, 2004

I am trying to get the below query to work and can't seem to get past this error. Not sure but everywhere I look I think my syntax is right. I am probably missing something obvious but I'm just back from vacation and trying to get in the swing of things. Any help would be appreciated.


Select Distinct(chadcd) as Adjustor, Count (Distinct chclno) as NumberOfCases, Count (Distinct chclno,chwkno)as NumberofClauses
from clmhdr
where chpddt = '20040630'
Group By chadcd
Order by Adjustor

Server: Msg 170, Level 15, State 1, Line 1
Line 1: Incorrect syntax near ',chwkno'.

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Apr 17, 2008

I need a query to return the number of distinct call_num(s) between two timestamps.

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Calls
----------
id_tag(unique id) | status | call_num | entry_id(timestamp)

1 HOLD 0123456789 2008-04-17 05:07:00.080
2 ONSCENE 012345679 2008-04-17 05:10:00.012
3 ENROUTE 321654987 2008-04-19 04:00:00.000

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Feb 19, 2014

Aim- Need to count how many [FDMSAccountNo] fall under a unique parentid

This is my query

SELECT [FDMSAccountNo]
,ParentID
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FDMSAccountNo ParentID
878028271889878028271889
878028272887878028271889
878028273885878028271889

Desired result

Parentid #_of_outlets
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Mar 12, 2007

Hello,

I'm fairly new to SQL as so am looking for help with an ad hoc query. The data in focusing on is from table named APs:

FileNo Type PartNo Completed
6 Northbound 1 03/03/2007
6 Northbound 2 NULL
6 Other 1 NULL
6 Other 2 NULL
20 Proof 0 19/07/2006
20 TCP 0 21/07/2006
24 40-Day 1 16/01/2006
24 40-Day 2 16/03/2006
24 Other 0 NULL
44 Northbound 1 16/01/2006
44 Northbound 2 16/06/2006
44 Northbound 3 16/12/2006
44 Northbound 4 01/01/2007

I've tried variations on a SELECT statement like below but have been unable to find a way to count only those types per fileNo that have all partNo completed (and to count all types per fileNo with a partNo of 0 and a completed date as they have no parts):

SELECT [FileNo], COUNT(DISTINCT [Type]) AS CountOfAPs
FROM APs
WHERE (completed IS NOT NULL)
GROUP BY [File]

Total count should be: 4

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Jul 20, 2005

I want to build query to return how many rows are in this query:select distinct c1, c2 from t1But SQL won't accept this syntax:select count (distinct c1, c2) from t1Does someone know how to count multiple distinct columns? Thanks.--Disclaimer: This post is solely an individual opinion and does not speak onbehalf of any organization.

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Mar 20, 2008

I have a table of users and date when they logged on to a system. I am trying to count how many distinct users logged on for each day of the week. The SQL below works when there's at least a user for each day. But when there is no user for a particular day such as Sunday, I still want it to return "SUN



0 "

I learned that you can use GROUP BY ALL and it works but the "ALL" is deprecated beyond SQL 2005.

------------------------------------
SELECT UPPER(LEFT(DATENAME(dw, StartTime), 3)) AS DayOfWeek,
COUNT(DISTINCT UserID) AS NumberOfUser

FROM testUserLoginDuration
WHERE Archived = 0
GROUP BY UPPER(LEFT(DATENAME(dw, StartTime), 3))
ORDER BY
CASE WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'MON' THEN 1
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'TUE' THEN 2
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WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'THU' THEN 4
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--------------
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MON 6
TUE 3
WED 5
THU 3
FRI 2
SAT 1

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Mar 17, 2008

Here is my dataset used by my report definition. The combo of barcode and order id is unique. The 'isDiscountedItem' field indicates if the customer used a coupon to purchased an item at a lower price.

departmentId classId barcode orderId isDiscountedItem
----------------------------------------------------------------------------------------------------------------------
1 1 123 1 True
2 7 456 1 False
1 1 123 2 False
1 1 123 3 True
1 1 789 3 True
2 7 456 3 False
... ... ... ... ...

I want to group my report by department id, class id and barcode. Then, I want to count all distinct order ids for which there was at leat one discounted item.

My report would produce the following output considering the above dataset:






Merchandise Number of customers who used a coupon
--------------------------------------------------------------------------------------------------------------
Department 1 2

Class 1 2

Barcode 123 2
Barcode 789 1
Department 2 0

Class 7 0

Barcode 456 0


I've been looking at a possible solution using hash tables defined in the report code but I would like to find a 'cleaner' solution. Any help would be appreciated.





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Nov 30, 2007

We have a table of students with fields for the ID of the school district and their school name. For example:



DistrictID
StudentName
SchoolName

10001
John Smith
Washington Elementary

10001
Jane Smith
Lincoln Middle

10002
David White
Hill High

...
...
...


I want is a listing with the school district ID, the student name, and the number of schools in the district.

I believe the following statement should give me what I want:

SELECT DistrictID, StudentName, COUNT(DISTINCT SchoolName) OVER (PARTITION BY DistrictID)

FROM StudentData


However, I get the error:

Msg 102, Level 15, State 1, Line 1

Incorrect syntax near 'distinct'.

If I take out the DISTINCT it runs fine, however it counts all the rows as expected, which is not what I want.
If I remove the OVER clause it runs fine, however, it counds the schools across all the districts, which is not what I want.
I can remove the OVER clause and use GROUP BY, but not while also retrieving StudentName.


The SQL 2005 Online Books don't seem to indicate that my statement is invalid. Here are the links just for reference:
Count: http://msdn2.microsoft.com/en-us/library/ms175997.aspx
Over: http://msdn2.microsoft.com/en-us/library/ms189461.aspx

Anyone have an idea one what I'm doing wrong or how to go about getting this information?
Thanks!
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May 22, 2008

Thanks for taking the time to read my post. I greatly appreciate it!

What i'm trying to do is get a distinct count of account numbers within a rolling period. My actual take is rather large but i've created a smaller-like version below. Please reference this table.








Account
Date

1
1/1/08

2
1/2/08

3
1/2/08

2
2/8/08

4
2/9/08

1
2/15/08

1
3/5/08

5
3/6/08

4
3/9/08

3
3/10/08

1
4/1/08

5
4/9/08

2
4/15/08

3
4/26/08

1
5/3/08

2
5/15/08

3
5/29/08

6
5/30/08

Let's say i want to return distinct count of accounts within a 2-month rolling period meaning in February, i'd get a distinct count for accounts in January & February, then in March i'd get a distinct count for February & March, then in April i'd get it for March & April, and so on... my results table would like the table below:








Account
Month

3
1

4
2

5
3

5
4

5
5

I had asked this before but it was a summing equation and not a unique count. I've tried to play with the summing equation to kind of make it work, but i'm starting to get a headache. It's probably so simple!

Here's my previous post: http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=2289509

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The actual result is like:
ID Policy
350235744Credit Cards
350235744PCI
350235744PCI Audit

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