Summing Different Combinations Of Selections

May 7, 2008

I am quite new in sql. I am writing a report which takes data of one same column and summing them according to the type as described in another column("TR_1"."TTYPE"). So far I have succeeded to get the sum of only one type at a time (by putting WHERE "TR_1"."TTYPE" = or not equal the desired type). For example: I want to create two columns, one showing the sum of the budget and the other the some of the actuals: here is my SQL instruction (the column "TR_1"."TTYPE" give the record type):
******************************************************************
SELECT SUM("TR_1"."AmountLCU")*-1 "Budget",rtrim("TR_1"."COSTCENTER") "Cost Centre",rtrim("TR_1"."ACCOUNT") "Account Num",rtrim("TR_1"."DONOR") "Donor Num", "TR_1"."AmountLCU"*-1 "Amount","TR_1"."TTYPE", rtrim("TR_1"."ACTIVITY") "Activity Code" FROM "scalaDB"."dbo"."A_GL0601_PREVIOUS" "TR_1"
WHERE NOT ("TR_1"."TTYPE"='' OR "TR_1"."TTYPE"='a' OR "TR_1"."TTYPE"='c') AND NOT ("TR_1"."COSTCENTER"=N'' OR "TR_1"."COSTCENTER"=N'0000') AND (("TR_1"."ACCOUNT">=N'26' AND "TR_1"."ACCOUNT"<N'7100') OR ("TR_1"."ACCOUNT">N'7100' AND "TR_1"."ACCOUNT"<=N'7999'))
GROUP BY "TR_1"."COSTCENTER","TR_1"."ACCOUNT","TR_1"."DONOR","TR_1"."ACTIVITY","TR_1"."AmountLCU","TR_1"."TTYPE"

**********************************************************************
Note: the report is written in Crystal reports and the database is SQL Server (not sure of the version)

Thanks in advance
I.Shaame

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Combinations

Jan 14, 2008

Hi,

I have a table with 2 columns (S.No,Name) with rows
1,Raja
2,Ramu
3,Rane

I need to generate all 2 pair combinations of the names(i,e)

(Raja -Ramu)
(Raja -Rane)
(Ramu -Rane)

Can some one give me a generalized query for this problem?

Thanks,

Prakash.P

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Apr 26, 2006

here is my question

the way our companies are setup are as follows

company A is DatabaseA

Company B is DatabaseB

this was done to ensure company specific data.

now i need to create a proc that runs through DatabaseA gets all the tables, creates DatabaseC and insert all the Tables,Procedures, and data when the user creates a new company in our software interface.

if you could just help me cycle through the objects i can manage the rest.



thanks.

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Oct 12, 2007

I was using the code in this thread (http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=1371094&SiteID=1) to create a console application which can build the SSIS package dynamically and run the package.

I'm not clear on what all could be the possible key / value combinations for the SetComponentProperty Method. From the examples I have seen its either SqlCommand or OpenRowSet. But I'm not sure about the "AccessMode" with values either 0 or 2. Is there any reference where I get more information on these?




Code Block
// Set the custom properties of the source.
srcDesignTime.SetComponentProperty("AccessMode", 2);
srcDesignTime.SetComponentProperty("SqlCommand", "Select * from devdb..empl_karun");



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Feb 23, 2005

Hi,

ok, i'm building a page to display a list of courses, a user rating and 'last visited' date.

I have 3 tables -
course (a list of all courses)
review (a list of all ratings)
visit (user visits to each course)

I've put together an SQL statment that returns everything i need, however its not quite right.
SELECT course.courseID, course.courseName, course.courseURL, avg(review.fldRating) AS fldAverage, visit.visitDate
FROM course


LEFT OUTER
JOIN review
ON course.courseId = review.fldcourseId

LEFT OUTER
JOIN visit
ON course.courseId = visit.courseId and visit.userId = 2

GROUP BY course.courseId, course.courseName, course.courseURL, visit.visitDate
ORDER BY course.courseId, visit.visitDate DESC

The problem lies with the fact that each time a user enters a course a new record is inserted into the visit table - so the visit table will show how many times a user has entered a course and on which dates.

this SQL statment returns something like this:

------------------------------------------------
course1 | 5 stars | 10/02/05
------------------------------------------------
course1 | 5 stars | 03/02/05
------------------------------------------------
course2 | 4 stars | 01/01/05

because the user has entered course 1 twice, the list is now showing 2 course1's - how can I change the statemtent to only select the most recent user visit, but still keep the complete list of courses?

I'm a bit of an SQL novice, so appologies if I've not explained this very well,
Thanks in advance,

-------------
injureFish

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Apr 11, 2006

Hi I am trying to figure out how to use the DISCTINCT function in s SELECT Query for one particular column, but output more that the disctinct column


for example:

table 1

Alan Andrews 1 main st 07465
John Andrews 1 main st 07465
Erick Andrews 1 main st 07465

I want to select by disctinct last name, but on my results I want to see all the other fields as well, and not just the last name. In this case the first name address and zip code.

So is there a way of doing this in SQL?

It does not have to be with the DISCTINCT function, but I need to net down to 1 per last name in a select query.

Thanks in advance!

Alan

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Jul 31, 2004

I want to start with a table that has 4 records:

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-Direct Rep

And I want to end with a table that has every unique combination of these records (the order being reversed would be considered 'unique' in this context)

-Self , Supervisor
-Supervisor , Self
-Self , Peer
-Peer , Self
-Self , Direct Rep
-Direct Rep , Self
-Peer , Direct Rep
-Direct Rep, Peer

How would I do this in an SQL Query? Thanks for your help!

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Jul 9, 2006

The requirement in to write a query which will return top 2 rows (in terms of lst_updt_timestamp column) for every combinations of cust_alias_nm, carrier_cd, acct_nbr columns.

Here I wrote a query which selects top 1 only.
Please help me to write to get the top 2nd along with the top 1st row.

select A.cust_alias_nm_id,
A.carrier_cd_id, A.acct_nbr_id,
sum(A.pd_clm_amt) clm_amt,
sum(A.pd_med_amt) med_amt,
sum(A.pd_exp_amt) exp_amt,
A.lst_updt_timestamp
from bal_load_stg A
group by A.cust_alias_nm_id, A.carrier_cd_id, A.acct_nbr_id, A.lst_updt_timestamp
having A.lst_updt_timestamp
in (
(select max(lst_updt_timestamp) from bal_load_stg B
where
A.cust_alias_nm_id = B.cust_alias_nm_id
and A.carrier_cd_id = B.carrier_cd_id
and A.acct_nbr_id = B.acct_nbr_id))


The output looks like:
cust_alias_nm_id carrier_cd_id acct_nbr_id clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ---------------------------------------- ------------------------------------------------------
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000


The desired output should look like:

cust_alias_nm carrier_cd acct_nbr clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ----------------------------------------
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000
aaa 100 1234567890 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 101 1234567891 400.00 400.00 400.00 2005-05-31 00:00:00.000


All rows present in the table are
cust_alias_nm carrier_cd acct_nbr clm_amt med_amt exp_amt lst_updt_timestamp
---------------- ------------- -------------- ---------------------------------------- ---------------------------------------- ----------------------------------------
aaa 100 1234567890 700.00 700.00 700.00 2005-10-31 00:00:00.000
aaa 100 1234567890 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 102 1234567891 500.00 500.00 500.00 2005-08-31 00:00:00.000
aaa 101 1234567891 500.00 500.00 500.00 2005-07-31 00:00:00.000
aaa 100 1234567890 400.00 400.00 400.00 2005-05-31 00:00:00.000
aaa 101 1234567891 400.00 400.00 400.00 2005-05-31 00:00:00.000





Thanks in advance.

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Sep 6, 2013

How would I write a query to produce all combinations for a situation such as the following?

Suppose I wanted to write a sentence, "This is [adjective] [noun]." where [adjective] comes from the Adjective table and [noun] come from the Noun table.

Adjective table looks like e.g.

ID Adj
1 good
2 so so
3 bad

Noun table looks like e.g.

ID Noun
1 apple
2 orange
3 banana

And the result set would look like

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This is so so apple.
This is bad apple.
This is good orange.
This is so so orange.
This is bad orange.
This is good banana.
This is so so banana.
This is bad banana.

I would take a stab at this myself and post even something that doesn't work...

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Oct 26, 2007

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select count(distinct One, Two) from MyTable

Thanks.

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Mar 29, 2007

Hello,



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Jun 28, 2006

Hi All,

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Using RS 2000

thanx,

99

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Mar 29, 2013

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Code:
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apple
pear
blueberry
apple, pear
apple, blueberry
pear, blueberry
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Jul 23, 2005

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Jan 11, 2008

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Mar 24, 2008

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Aug 27, 2015

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[Code] ...

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1 2
1 3
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2 4
3 4
5 6
5 7
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Jul 2, 2007

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Sep 22, 2006

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Jun 12, 2007

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May 31, 2006

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Jan 11, 2005

Hi,

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@OrderList varchar(500)
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OrderID int
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BEGIN
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I have it working fine for the single or multiple selection, the trouble is that an 'All' selection needs to be in the list box as well, but I can't seem to get it working for this.

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Thanks

My plan is to have the same ability as under the 'Optional' section of this page:

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Aug 25, 2015

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Apr 28, 2008

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Jul 20, 2005

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Apr 30, 2008

Hi,

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Problem:
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Sample input:

Timesheet table
===============
pr_code|ts_hours
QWER.01|6
QWER.01|7
QWER.02|3
QWET.01|2


Project table
=============
pr_code|pr_master
QWER.01|QWER
QWER.01|QWER
QWER.02|QWER
QWET.01|QWET
QWER|QQQQ
QWET|QQQQ
QWEY|QQQQ



Intended output:
For named projects QWER, QWET & QWEY:

QWER|16
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02.01.2013 2.00
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To point I’ve reached myself is a query:

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AND
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As my name shows I am about read to pull my hair out on this and will take any help that I can get.
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a | p | 1
a | n | 1
a | p | 2
b | p | 2

b | p | 2
b | n | 3

I am grouping by first column
a
p 1
n 1
p 2
-------------------
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b
p 2
p 2
n 3
------------------
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n 1
p 2
-------------------
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b
p 2
p 2
n 3
------------------
b 7 7

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I am getting kind of thin in the hair department so I cannot afford to loose any more.



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