IIF Statement - Calculate Value Based On Comparing Current Date To Dates In Fields

Jun 27, 2013

In my table I have the following 4 fields with the associated date field:

Bronze: 11/1/2013
Silver: 5/1/2014
Gold: 11/1/2014
Platinum: 5/1/2015

I am trying to calculate a value based on comparing the current date to the dates in these fields. I am using the below formula. However, using 6/27/2013 as the current date, my formula keeps resulting in "Bronze" when it should result in "Standard" Am I doing something wrong?

=IIf(Date()<[Bronze],"Standard",IIf((Date()>=[Bronze]) And (Date()<[Silver]),"Bronze",IIf(Date()>=[Silver] And Date()<[Gold],"Silver",IIf(Date()>=[Gold] And Date()<[Platinum],"Gold","Platinum"))))

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I am creating a Make Table Query and calculating new fields based on current and prior year-end numbers. If the prior year-end number does not exist (Is Null), I want the use the current rate or calculate the change in rate. I have typed the below in the Field Box:

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However, when running the query, I get the attached error message.

The screenshot will also show how the two tables are joined.

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Sep 28, 2012

The two tables are joined together by a primary and foreign key in the query, . I have not added the actual tables below , as data is senitive - i'm using an example. This join is made using the graphic relationship between the tables.

Table_1 with below column
Mode
6
6
6
6
6
4
4

Primary KEY
0001
0002
0003

[code]....

Initially the pseudo code i'm trying to get to work is;

if table_1.mode = 6 and table_2.type = 06 , then "MATCH" , else "NO_MATCH"

Expr1: IIf(IsNumeric([TABLE_2]![TYPE])="06" And IsNumeric([TABLE_1]![MODE])=6,"MATCH","NO_MATCH") ,

However this calculated field returns incorrect results, i.e. the query returns MATCH for rows that do not match , e.g. mode=6 and type=GL , Previously , when it was returning #Error when trying to match mode=6 and type=GL when it should ideally return "NO_MATCH", which is why I added Isnumeric.

Once I have sorted this out, I would like to achieve this as the calculated field

if table_1.mode = 6 and table_2.type = 06 , then "MATCH" , else "NO_MATCH" or if table_1.mode = 4 and table_2.type = 04 , then "MATCH" , else "NO_MATCH

how I can do this?

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Challenge

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Sep 27, 2012

query is refering to 2 tables

Table_1 with below column
Mode
6
6
6
6
6
4
4

Table_2 with below column

Type
06
GL
PL
04
16

Both tables are joined, and the pseudo code i'm trying to get to work is;

if table_1.mode = 6 and table_2.type = 06 , then "MATCH" , else "NO_MATCH"

I have tried below, but doesn't work.

Expr1: IIf(IsNumeric([TABLE_2]![TYPE])="06" And IsNumeric([TABLE_1]![MODE])=6,"MATCH","NO_MATCH") , returns incorrect results.

Ideally would like this

if table_1.mode = 6 and table_2.type = 06 , then "MATCH" , else "NO_MATCH"

or

if table_1.mode = 4 and table_2.type = 04 , then "MATCH" , else "NO_MATCH

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[ReturnedDate]

DESCRIPTION: If ReturnedDate is null, then calculate the datediff "d" between LDW with Now(), if not, then calculate the datediff "d" between LDW with ReturnDate.

I tried this but it didn't work at all.

Days Absent: Iif(isnull([ReturnedDate],(DateDiff("d",[LDW],Now())),(DateDiff("d",[LDW],[ReturnedDate])))

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