Find Duplicate Records In Table

Oct 5, 2007

Hello friends,

I have a one problem, i have a table in that some reocrds are duplicate.i want to find which records are duplicate.

for exp. my table is as follows

emp_id              emp_name

1                          aa

2                          bb

3                          cc

1                          aa

3                          cc

3                          cc

and i want the result is like

emp_id              emp_name

1                       aa

1                       aa

3                       cc

3                       cc

3                       cc

 

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Find Duplicate Records

Jan 12, 2000

Hi,

Does anybody know the SQL query to find the duplicate records?

Many Thanks in advance!

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Feb 4, 2003

Hello board,

I was wondering if anyone can tell me an easy way to find duplicate records on sql. The thing is this, at work we have a database (table) which includes tracking numbers, I need a easy way to be able to search this table for duplicate tracking numbers and print them out. I currently access this table to edit some data by using the following path “Start > Programs > Microsoft SQL Server > Enterprise Manager” then work my down the tree to “Databases > Master > Tables” on tables I do a right click and “open table/query”. Any help would be most appreciated. Believe me I’m very “SQL illiterate”

Bill
:confused:

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May 13, 1999

Hi,

As far as I know in SQL Server 6.5 there is no concept called rowid. How can I find duplicate records in a table and delete them.

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Apr 17, 2014

I have this query that I have been using to find duplicate records works great except for now. The logic I am adding is pcs_rreas <> 'NG'. When I add this it does take out the NG, but it also excludes the reocords that have NULL data in this field. I don't want that to happen. How can I fix this? I tried adding (pcs_rreas <> 'NG' or pcs_rreas is null) but nothing is pulling now.

SELECT pcs_id1, pcs_rreas, pcs_lname, pcs_fname, pcs_minit, pcs_degree, pcs_xtyp, pcs_office, pcs_dba, pcs_dob, pcs_sex, pcs_eff, pcs_trm, pcs_spec1, pcs_spec2, pcs_spec3,
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pcs_misc1, pcs_misc2, pcs_newdt, pcs_newby, pcs_chgdt, pcs_chgby, pcs_malp, pcs_pf, pcs_ctl, pcs_sys, pcs_pay, pcs_ann, pcs_bcert, pcs_pass, pcs_w9,
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[code]...

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Jul 28, 2014

How can I pull out duplicate records based on certain fields?

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Jun 11, 2015

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1487   11     2015-05-05 16:33:23   2015-05-05 18:45:26
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Oct 5, 2007

How do i remove duplicate records from a table with a single query without using cursors or anything like that.Sample :tempCol11221P.S The table has only one column  

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Nov 29, 2004

Hello All,

Please show me how to delete duplicate records from a table.


Thanks in Advance

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Feb 9, 2012

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May 16, 2008

Hello,

I need some help on this.
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Gaurish Salunke
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Jul 20, 2005

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Apr 3, 2008

Hi Guyz

say i have a table


10011 NULL NULL Classical NULL
10011 NULL NULL Classical NULL
10004 NULL NULL Classical NULL
10004 NULL NULL Classical NULL
10004 NULL NULL Classical NULL
10005 NULL NULL Classical NULL

i want to eliminate the duplicate records and atable should look like

10011 NULL NULL Classical NULL
10004 NULL NULL Classical NULL
10005 NULL NULL Classical NULL

do we have any simple sql to do it or something complex.
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Jul 6, 2006

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TAI,



barkingdog

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Mar 4, 2008

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Oct 8, 2015

any useful SQL Queries that might be used to identify lists of potential duplicate records in a table?

For example I have Client Database that includes a table dbo.Clients. This table contains various columns which could be used to identify possible duplicate records, such as Surname | Forenames | DateOfBirth | NINumber | PostalCode etc. . The data contained in these columns is not always exactly the same due to differences caused by user data entry; so some records may have missing data from some of the columns and there could be spelling differences too. Like the following examples:

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2 | Smith | John | 06/03/1967 | NULL | SW12 8TQ
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The problem is that whilst it is easy for a human being to review these 3 entries and conclude that they are most likely the same Client entered in to the database 3 times; I cannot find a reliable way of identifying them using a SQL Query.

I've considered using some sort of concatenation to a new column, minus white space and then using a "WHERE column_name LIKE pattern" query, but so far I can't get anything to work well enough. Fuzzy Logic maybe?

the results would produce a grid something like this for the example above:

ID | Surname | Forenames | DuplicateID | DupSurname | DupForenames
1 | Smith | John Raymond | 2 | Smith | John
1 | Smith | John Raymond | 3 | Smith | Jon Raymond
9 | Brown | Peter David | 343 | Brown | Pete D
next batch of duplicates etc etc . . . .

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Nov 15, 2015

I have this table:

id | Name | Age
==================
1 | AAA | 22
1 | AAA | 22
2 | BBB | 33
2 | BBB | 33
2 | BBB | 33
3 | CCC | 44
4 | DDD | 55

I need to delete from this table all the duplicate records and leave only one record. The table will looks like this:

id | Name | Age
==================
1 | AAA | 22
2 | BBB | 33
3 | CCC | 44
4 | DDD | 55

I work with sqlCE for Mobile...

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Apr 29, 2014

I have table 'stores' that has 3 columns (storeid, article, doc), I have a second table 'allstores' that has 3 columns(storeid(always 'ALL'), article, doc). The stores table's storeid column will have a stores id, then will have multiple articles, and docs. The 'allstores' table will have 'all' in the store for every article and doc combination. This table is like the master lookup table for all possible article and doc combinations. The 'stores' table will have the actual article and doc per storeid.

What I am wanting to pull is all article, doc combinations that exist in the 'allstores' table, but do not exist in the 'stores' table, per storeid. So if the article/doc combination exists in the 'allstores' table and in the 'stores' table for storeid of 50 does not use that combination, but store 51 does, I want the output of storeid 50, and what combination does not exist for that storeid. I will try this example:

'allstores' 'Stores'
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ALL 0010 001 101 0010 001
ALL 0010 002 101 0010 002
ALL 0011 001 102 0011 002
ALL 0011 002

So I want the query to pull the one from 'allstores' that does not exist in 'stores' which in this case would the 3rd record "ALL 0011 001".

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May 13, 2015

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Is it possible to add another EXCEPT statement after the CTE EXCEPT statement to cover a condition not incorporated in the CTE definition?

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Oct 2, 2007

Hello Everyone:

I am using the Import/Export wizard to import data from an ODBC data source. This can only be done from a query to specify the data to transfer.

When I try to create the tables, for the query, I am getting the following error:




Msg 2714, Level 16, State 4, Line 12

There is already an object named 'UserID' in the database.

Msg 1750, Level 16, State 0, Line 12

Could not create constraint. See previous errors.


I have duplicated this error with the following script:


USE [testing]

IF OBJECT_ID ('[testing].[dbo].[users1]', 'U') IS NOT NULL

DROP TABLE [testing].[dbo].[users1]

CREATE TABLE [testing].[dbo].[users1] (

[UserID] bigint NOT NULL,

[Name] nvarchar(25) NULL,

CONSTRAINT [UserID] PRIMARY KEY (UserID)

)

IF OBJECT_ID ('[testing].[dbo].[users2]', 'U') IS NOT NULL

DROP TABLE [testing].[dbo].[users2]

CREATE TABLE [testing].[dbo].[users2] (

[UserID] bigint NOT NULL,

[Name] nvarchar(25) NULL,

CONSTRAINT [UserID] PRIMARY KEY (UserID)

)

IF OBJECT_ID ('[testing].[dbo].[users3]', 'U') IS NOT NULL

DROP TABLE [testing].[dbo].[users3]

CREATE TABLE [testing].[dbo].[users3] (

[UserID] bigint NOT NULL,

[Name] nvarchar(25) NULL,

CONSTRAINT [UserID] PRIMARY KEY (UserID)

)



I have searched the "2714 duplicate error msg," but have found references to duplicate table names, rather than multiple field names or column name duplicate errors, within a database.

I think that the schema is only allowing a single UserID primary key.

How do I fix this?

TIA

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Mar 29, 2004

I have column A,B and C. I need a query to find the duplicates among these column.
Thanks,
Ravi

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May 28, 2008

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SELECT
*
FROM
table_customer T1
INNER JOIN
table_itemsBought T2
ON
T2.custID = T1.custID
WHERE
price = '100'
OR price = '200';

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Oct 31, 2007

Hi, I have had this problem for a while and have not been able solve it.

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then if patient "A" is admitted again but there admission date is greater than one day they get a code of 2 being for there second admission but will need to loop thru table looking for other admissions and discharges.

The table name is Adm_disc_Match_tbl

Basically what i have 4 fields.
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ur_episode = this wil change for each Hospital (text)
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Discharge_datetime = patient discharge date and time (datetime)

example of data


Code: ( text )
Index_key,ur_episode,Admission_datetime,discharge_ datetime
HERBERT-7/1929,513884-1686900,4/07/2006 10:58,17/07/2006 13:37
HERBERT-7/1929,C023092-1698859,17/07/2006 13:20,24/07/2006 0:30
ELSIE-5/1916,G148445-1720874,8/08/2006 11:00,30/08/2006 10:00
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FREDA-11/1925,G147858-2007408,3/04/2007 10:49,26/04/2007 12:39
FREDA-11/1925,183772-2037727,28/04/2007 17:05,9/05/2007 11:41
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Apr 30, 2004

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BASENO - POSITION - SEQ - PROD -STYL - DESCR - FIELD01 THRU FIELD05 - VALUE01 THRU VALUE05 - FORMTYPE - ANSWER

I have been playing with the following query but can't seem to get it perfect to locate my dups within sql. Can someone help me with the querry?

I'm playing with the following querry.
SELECT
<list of all columns>
FROM
tablename
GROUP BY
<list of all columns>
HAVING
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Can somone possible input my column names into this querry that would possibly get it to locate my dups? I'm missing somehting and not sure what.

Thanks for any help

SQL Newbie

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Oct 17, 2013

I'm using this to find duplicates where a person has the same email but varying firstname and lastnames:

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as t1 inner join [aren1002].[BOOKING]
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The data should be like this:
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Jul 23, 2001

Hello,

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Jan 18, 2000

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Jun 12, 2002

Yes, I know this subject has been exhausted, but I need help in locating the discussion which took place a few months ago.
Sharon relayed to the group a piece of software (expensive) which would help in my particular situation. I grabbed a demo and have gotten the approval for purchase. Unfortunately, I don't have the thread with me at work.

The problem:

Number Fname Lname Age ID
123 John Franklin 43 1
123 Jane Franklin 40 2
123 Jeff Franklin 12 3
124 Jean Simmons 39 4
125 Gary Bender 37 5
126 Fred Johnson 29 6
126 Fred Johnson 39 7
127 Gene Simmons 47 8

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124 Jean Simmons 39 4
125 Gary Bender 37 5
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Thanks

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