How To Count Particular Text (/) From A Column In A Table?

Jun 16, 2008

I m using SQL Server 2000.

I have Tabel named Topic and have a column name lineage.  lineage has data like following:

/
/
/
/
/
/546707/
/546707/
/546707/43213/


Now I want to get records who has only one "/" in it's crreponding lineage column.

 Can somone tell me how to do that in SQL Server 2000?

Thanks

Khushbu

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For example

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e.g. TABLE2:

e#
--
1
2
3
4
5
5
6
7
7
1
2
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4
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so my TABLE1 should be:

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Code Block
DECLARE @Employee TABLE (ID INT, Date SMALLDATETIME, ShiftID TINYINT)
DECLARE @WantedDate SMALLDATETIME, -- Should be a parameter for SP
@BaseDate SMALLDATETIME,
@NumDays TINYINT
SELECT @WantedDate = '20080301', -- User supplied parameter value
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@NumDays = DATEDIFF(DAY, @BaseDate, DATEADD(MONTH, 1, @BaseDate))

IF @Numdays > 28
BEGIN
SELECT p.ID,
p.[1] , p.[2],p.[3], p.[4], p.[5], p.[6], p.[7], p.[8], p.[9], p.[10], p.[11],
p.[12], p.[13], p.[14], p.[15], p.[16], p.[17], p.[18], p.[19], p.[20], p.[21],
p.[22], p.[23], p.[24], p.[25], p.[26], p.[27], p.[28], p.[29], p.[30], p.[31]
FROM (
SELECT ID,
DATEPART(DAY, Date) AS theDay,
ShiftID
FROM v_Employee
WHERE Date >= @BaseDate
AND Date < DATEADD(MONTH, 1, @BaseDate)
) AS y
PIVOT (
min(y.ShiftID) FOR y.theDay IN ([1], [2], [3], [4], [5], [6], [7],[8] , [9], [10], [11],
[12], [13], [14], [15], [16], [17], [18], [19], [20], [21],
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Code Snippet
CREATE TABLE #Assignment
(CallID INT IDENTITY(1500,1) PRIMARY KEY,
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)
GO
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INSERT #Assignment (AssignmentGroup, Assignee)
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GO

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