SQL Server 2014 :: Indexed View Not Being Used For Partitioned Clustered Column-store Index?

Oct 9, 2015

I am trying to use an indexed view to allow for aggregations to be generated more quickly in my test data warehouse. The Fact Table I am creating the indexed view on is a partitioned clustered columnstore index.

I have created a view with the following code:

ALTER view dbo.FactView
with schemabinding
as
select local_date_key, meter_key, unit_key, read_type_key, sum(isnull(read_value,0)) as [s_read_value], sum(isnull(cost,0)) as [s_cost]
, sum(isnull(easy_target_value,0)) as [s_easy_target_value], sum(isnull(hard_target_value,0)) as [s_hard_target_value]
, sum(isnull(read_value,0)) as [a_read_value], sum(isnull(temperature,0)) as [a_temp], sum(isnull(co2,0)) as [s_co2]
, sum(isnull(easy_target_co2,0)) as [s_easy_target_co2]
, sum(isnull(hard_target_co2,0)) as [s_hard_target_co2], sum(isnull(temp1,0)) as [a_temp1], sum(isnull(temp2,0)) as [a_temp2]
, sum(isnull(volume,0)) as [s_volume], count_big(*) as [freq]
from dbo.FactConsumptionPart
group by local_date_key, read_type_key, meter_key, unit_key

I then created an index on the view as follows:

create unique clustered index IDX_FV on factview (local_date_key, read_type_key, meter_key, unit_key)

I then followed this up by running some large calculations that required use of the aggregation functionality on the main fact table, grouping by the clustered index columns and only returning averages and sums that are available in the view, but it still uses the underlying table to perform the aggregations, rather than the view I have created. Running an equivalent query on the view, then it takes 75% less time to query the indexed view directly, to using the fact table. I think the expected behaviour was that in SQL Server Enterprise or Developer edition (I am using developer edition), then the fact table should have used the indexed view. what I might be missing, for the query not to be using the indexed view?

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Transact SQL :: Getting List Of Clustered Column-store Index In A Database In 2014?

Sep 17, 2015

How can we get the list of clustered columnstore index in a database in sql server 2014

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Clustered Index On Indexed View From ADO.NET

Oct 26, 2005

I have a clustered index on an indexed view in sql server 2000. When I do a simple select in query anaylser from this view I can see from the execution plan in profiler that the clustered index was used to return the data, hence improving performance of the underlying select(this is why I am using the indexed view). However, if I run the query from an asp.net page using the sql provider I can see the call in profiler but the clustered index is not used, hence reducing the performance of the call considerably.If anyone has experienced this please let me know.Cheers 

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Best Way To Build A Partitioned Clustered Column Store

May 19, 2014

I am building three partitioned, clustered column store tables.I was researching whether it was faster to populate a staging table and swap it into the partitioned table or to directly insert into the partitioned table.The first partition for the three tables will have:

Table F: 50M rows, 6 columns wide, partitioned on a date column (1 date, 2 bigint keys, and two varchar columns)
Table D1: 50M rows, 150 columns wide, partitioned on a bigint
Table D2: 19M rows, 300 columns wide, partitioned on a bigint

If build the data that would go into partition 1 in a non partitioned column store, I get these table sizes:

Table F: 476 MB
Table D1: 6,800 MB
Table D2: 5,496 MB

If build the same data directly in the partitioned column store, my table sizes end up being:

Table F: 579 MB
Table D1: 6,800 MB
Table D2: 5,364 MB

That's a 20% difference on Table F, the narrow table.Looking at the row groups, I see 47 identical row groups in partition 1 and the unpartitioned table, but the average "size_in_bytes" is consistently 20% smaller in the unpartitioned table.

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Jun 18, 2015

I have created NONCLUSTERED index on table but my report is taking more time that's why i created columnstore NONCLUSTERED index on the same table but i have one query, if any table have row and column level index(same columns in index) . Which index query will consider.

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May 18, 2015

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Apr 3, 2015

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Hi,

While creating an indexed view with the command :

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there is a check constraint on the policy column of the tables used in this view.

The following error is encountered

Cannot index the view 'test.dbo.account_transactions'. It contains one or more disallowed constructs.

Can anyone help?

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How To Create Non-unique Clustered Indexed View?

May 30, 2008

I'm not able to create indexed views,
which are clustered-indexed on only 1st field.

I can't even INCLUDED other fields.

I need the entire view to exist as a physical table. (for performance)

Please let me know the work around.


Thanks..

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Jul 23, 2005

I am looking to create a constraint on a table that allows multiplenulls but all non-nulls must be unique.I found the following scripthttp://www.windowsitpro.com/Files/0.../Listing_01.txtthat works fine, but the following lineCREATE UNIQUE CLUSTERED INDEX idx1 ON v_multinulls(a)appears to use indexed views. I have run this on a version of SQLStandard edition and this line works fine. I was of the understandingthat you could only create indexed views on SQL Enterprise Edition?

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SQL Server 2014 :: Error - Cannot Create More Than One Clustered Index On Table

Aug 18, 2015

i have created a fact table which has unique cluster index as below,

CREATE UNIQUE CLUSTERED INDEX [FactSales_SalesID] ON [dbo].[FactSales] (salesid ASC)
WITH (DATA_COMPRESSION = PAGE)
GO
however later when i add CLUSTERED COLUMNSTORE INDEXES :
CREATE CLUSTERED COLUMNSTORE INDEX CSI_FactSales
ON dbo.FactSales WITH (DATA_COMPRESSION = COLUMNSTORE)
GO

it prompts error.

Msg 35372, Level 16, State 3, Line 167 You cannot create more than one clustered index on table 'dbo.FactSales'. Consider creating a new clustered index using 'with (drop_existing = on)' option.

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Aug 8, 2015

I have a view that joins a dozen tables with a million rows added per year by an application. I want to materialize it. The view is always filtered by date first on reports, then there are a few key transaction keys, but then many other fields required to make each row unique. I don't want to add these columns since they are large, many, not used for sorting or filtering, and may not define uniqueness in a future application design. I need a uniqueifier that is application agnostic. I prefer a bigint. So to store the materialized view ideally for reporting, I want to add the following clustered index to materialize the view:

CREATE unique CLUSTERED INDEX idx1
ON [dbo].[myview](myDate, key1, key2, key3, id bigint identity(1,1) NOT NULL)

And I get this error:

Msg 102, Level 15, State 1, Line 3
Incorrect syntax near 'bigint'.

Can I do what I want? If so, how?

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In What Order Does A Clustered Index Store Data?

Mar 26, 2007

Hi

I was going through the book by Kalen Delaney where she has mentioned the following paragpraph in Chapter 7 (Index Internals):

Many documents describing SQL Server indexes will tell you that the clustered index physically stores the data in sorted order. This can be misleading if you think of physical storage as the disk itself. If a clustered index had to keep the data on the actual disk in a particular order, it could be prohibitively expensive to make changes. If a page got too full and had to be split in two, all the data on all the succeeding pages would have to be moved down. Sorted order in a clustered index simply means that the data page chain is logically in order.

Then I read the book on SQL Server 2000 (on Perf Tuning) by Ken England. He says the clustered index stores data in physical order and any insert means moving the data physically. Also the same statement is echoed on the net by many articles.

What is the truth? How are really clustered index stored? What does physical order in the above statement really mean?

Regards

SanjaySi

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Dec 17, 2007

I want to find a way to get partition info for all the tables in all the databases for a server. Showing database name, table name, schema name, partition by (maybe; year, month, day, number, alpha), column used in partition, current active partition, last partition (for date partitions I want to know if the partition goes untill 2007, so I can add 2008)

all I've come up with so far is:






Code Block

SELECT distinct o.name From sys.partitions p
inner join sys.objects o on (o.object_id = p.object_id)
where o.type_desc = 'USER_TABLE'
and p.partition_number > 1

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Aug 22, 2007

We are using partitioned unique indexes on partitioned tables. When the Unique Index is built, should the column the index is partitioned by be the top (leftmost) column in the index? While this violates cardinality, it makes sense (at least to me) that the first thing the query execution would do is figure out which partition(s) contain the result set, then filter from there.

What do you guys think? Is there any documentation on optimizing partitioned indexes?

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SQL Server 2008 :: Put Clustered Index On 8 Column Natural Key Or On Identity Key

Aug 2, 2015

I am extremely new to database design, and I ran into a problem that I know comes up often, however has many opinions...

Basically I have a table that is going to have 50+ columns. The natural key on this table is actually 8 columns wide, 4 of them being Varchar columns by default. (varchar(50)'s).

I have added an identity column, (1,1) to the table, however I put the clustered index on the 8 natural keys... My plan is to rebuild the clustered index once nightly when the system isn't in use (after 7 pm).

I know others would say it would be better to have the clustered key on the 1,1 column and then add indexes on the other 8 fields... However I don't quite understand why honestly...

Every single query against this table will use the 8 columns, and will NOT use the Identity column (1,1) because they are calls from other systems that do not know the Identity column....

Therefore if your database is set up for query speed, and every single query has to have a value for 8 columns to get a valid result, does it make sense to put a clustered index over the 8 columns?

If not why? Why is putting a clustered index on an identity column (that will literally never be used in a query) a better solution?

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Partitioned View With Computed Column

Jan 23, 2008

Using SQL Server 2005. Defined partitioned view with computed column. Computed column was a constant varchar. Ran a SELECT. According to Query Execution Plan, SQL did recognize the computed column as the partitioning column and used it to optimize the query.

However MSDN says a computed column cannot be used as the partitioning column.

Could someone from MS clarify?

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Partitioned View && Computed Column..

May 14, 2006

Hello,

please enlighten me regarding an issue with partitioned view... There are 3 tables in my DB of a similar structure:

CREATE TABLE Table1 (value1 varchar(1))
CREATE TABLE Table2 (value1 varchar(1))
CREATE TABLE Table3 (value1 varchar(1))

INSERT INTO Table1 (value1)
SELECT 'a' UNION SELECT 'b' UNION SELECT 'c'

INSERT INTO Table2 (value1)
SELECT 'a' UNION SELECT 'b' UNION SELECT 'c'

INSERT INTO Table3 (value1)
SELECT 'a' UNION SELECT 'b' UNION SELECT 'c'

As sometimes we need to access all data from these tables, a view has been created:

CREATE VIEW AllData AS
SELECT value1, '1' as table_id from Table1
UNION ALL
SELECT value1, '2' as table_id from Table2
UNION ALL
SELECT value1, '3' as table_id from Table3

The problem is that while running a query like

SELECT * from AllData WHERE value1 = 'a' and table_id = '3'

I see a table scan being performed on all 3 tables, not just table3 - i.e optimisation engine doesn't care for my table_id computed column and for that fact that required data is located ONLY in Table3.

Is there any way to force optimiser to consider this column andrrebuild a plan? If not - how can I rebuild a view (I can't modify tables) to achieve that? Maybe create an index for a view?

Thanks in advance. RTFM and search don't seem to clarify this for me...

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Clustered Index On Client_ID+ORderNO+OrdersubNo, If I Create 3 Noncluster Index On Said Column Will It Imporve Performance

Dec 5, 2007



Dear All.

We had Teradata 4700 SMP. We have moved data from TD to MS_SQL SERVER 2003. records are 19.65 Millions.

table is >> Order_Dtl

Columns are:-

Client_ID varchar 10
Order_ID varchar 50
Order_Sub_ID decimal
.....
...
..
.
Pk is (ClientID+OrderId+OrderSubID)

Web Base application or PDA devices use to initiate the order from all over the country. The issue is this table is not Partioned but good HP with 30 GB RAM is installed. this is main table that receive 18,0000 hits or more. All brokers and users are using this table to see the status of their order.

The always search by OrderID, or ClientID or order_SubNo, or enter any two like (Client_ID+Order_Sub_ID) or any combination.

Query takes to much time when ever server receive more querys. some orther indexes are also created on the same table like (OrderDate, OrdCreate Date and Status)

My Question are:-


Q1. IF Person "A" query to DB on Client_ID, then what Index will use ? (If any one do Query on any two combination like Client_ID+Order_ID, So what index will be uesd.? How does MS-SQL SERVER deal with these kind of issues.?

Q2. If i create 3 more indexes on ClientID, ORderID and OrdersubID. will this improve the performance of query.if person "A" search record on orderNo so what index will be used. (Mind it their would be 3 seprate indexes for Each PK columns) and composite-Clustered index is also available.?

Q3. I want to check what indexes has been used? on what search?

Q4. How can i check what table was populated when, or last date of update (DML)?

My Limitation is i Dont Create a Partioned table. I dont have permission to do it.



In Teradata we had more than 4 tb record of CRM data with no issue. i am not new baby in db line but not expert in sql server 2003.


I am thank u to all who read or reply.

Arshad

Manager Database
Esoulconsultancy.com

(Teradata Master)
10g OCP










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Mar 16, 2001

I have a view named select id,name,state from customer where state ='va'
can I create clustered index on a view (name) if so please provide me with the sql statement.
Thanks
Al

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Nov 14, 2006

the query:

SELECT a.AssetGuid, a.Name, a.LocationGuid
FROM Asset a WHERE a.AssociationGuid IN (
SELECT ada.DataAssociationGuid FROM AssociationDataAssociation ada
WHERE ada.AssociationGuid = '568B40AD-5133-4237-9F3C-F8EA9D472662')

takes 30-60 seconds to run on my machine, due to a clustered index scan on our an index on asset [about half a million rows].  For this particular association less than 50 rows are returned. 

expanding the inner select into a list of guids the query runs instantly:

SELECT a.AssetGuid, a.Name, a.LocationGuid
FROM Asset a WHERE a.AssociationGuid IN (
'0F9C1654-9FAC-45FC-9997-5EBDAD21A4B4',
'52C616C0-C4C5-45F4-B691-7FA83462CA34',
'C95A6669-D6D1-460A-BC2F-C0F6756A234D')

It runs instantly because of doing a clustered index seek [on the same index as the previous query] instead of a scan.  The index in question IX_Asset_AssociationGuid is a nonclustered index on Asset.AssociationGuid.

The tables involved:

Asset, represents an asset.  Primary key is AssetGuid, there is an index/FK on Asset.AssociationGuid.  The asset table has 28 columns or so...
Association, kind of like a place, associations exist in a tree where one association can contain any number of child associations.  Each association has a ParentAssociationGuid pointing to its parent.  Only leaf associations contain assets. 
AssociationDataAssociation, a table consisting of two columns, AssociationGuid, DataAssociationGuid.  This is a table used to quickly find leaf associations [DataAssociationGuid] beneath a particular association [AssociationGuid].  In the above case the inner select () returns 3 rows. 

I'd include .sqlplan files or screenshots, but I don't see a way to attach them. 

I understand I can specify to use the index manually [and this also runs instantly], but for such a simple query it is peculiar it is necesscary.  This is the query with the index specified manually:

SELECT a.AssetGuid, a.Name, a.LocationGuid
FROM Asset a WITH (INDEX (IX_Asset_AssociationGuid)) WHERE
a.AssociationGuid IN (
SELECT ada.DataAssociationGuid FROM AssociationDataAssociation ada
WHERE ada.AssociationGuid = '568B40AD-5133-4237-9F3C-F8EA9D472662')

To repeat/clarify my question, why might this not be doing a clustered index seek with the first query?

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Aug 25, 2015

I had an existing table with lots of indexes.

As a test (fro speed) - I added a non clustered column-store index.

When I run test queries it always ignores my new column-store index. Why?

Should I remove the old indexes, leaving just the column store?

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Jan 4, 2008

I have large table with 10million records. I would like to create clustered or non-clustered index.

What is the quick way to create? I have tried once and it took more than 10 min.

please help.

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SQL Server 2014 :: Column Store Query Reverting To Row Mode With CROSS JOIN

May 20, 2015

I have two inline selects against a table with a nonclustered columnstore on SQL 2014 (12.0.2000). Both execute in batch mode and when I inner-join the two, they continue to execute in batch mode. When I cross join them, one executes in row mode. Below is some SQL to simulate the issue.

-- The purpose of this script is to demonstrate that
-- two queries against a columnstore index that each execute in batch mode
-- will continue to execute in batch mode when inner joined.
-- However, one of the queries will execute in row mode when cross-joined.

-- Create function to return 0 to n rows
IF OBJECT_ID('dbo.IntCount') IS NOT NULL
DROP FUNCTION dbo.IntCount;

[Code] .....

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Apr 21, 2007

I am trying to create a clustered index on a View of a table that has an xml datatype. This indexing ran for two days and still did not complete. I tried to leave it running while continuing to use the database, but the SELECT statements where executing too slowly and the DML statements where Timing out. I there a way to control the server/cpu resources used by an indexing process. How can I determine the completion percentage or the indexing process. How can I make indexing the view with the xml data type take less time?



The table definition is displayed below.



CREATE TABLE [dbo].[AuditLogDetails](

[ID] [int] IDENTITY(1,1) NOT NULL,

[RecordID] [int] NOT NULL,

[TableName] [varchar](64) NOT NULL,

[Modifications] [xml] NOT NULL,

CONSTRAINT [PK_AuditLogDetails] PRIMARY KEY CLUSTERED

(

[ID] ASC

)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]

) ON [PRIMARY]



The view definition is displayed below.



ALTER VIEW [dbo].[vwAuditLogDetails] WITH SCHEMABINDING

AS

SELECT P.ID,D.RecordID, dbo.f_GetModification(D.Modifications,P.ID) AS Modifications

FROM dbo.AuditLogParent P

INNER JOIN dbo.AuditLogDetails AS D ON dbo.f_GetIfModificationExist(D.Modifications,P.ID)=1



The definition for UDF f_GetModification



ALTER function [dbo].[f_GetModification]( @Modifications xml,@PID uniqueidentifier )

returns xml

with schemabinding

as

begin

declare @pidstr varchar(100)

SET @pidstr = LOWER(CONVERT(varchar(100), @PID))

return @Modifications.query('/Modifications/modification[@ID eq sql:variable("@pidstr")]')

end





The definition for UDF f_GetIfModificationExist



ALTER function [dbo].[f_GetIfModificationExist]( @Modifications xml,@PID uniqueidentifier )

returns Bit

with schemabinding

as

begin

declare @pidstr varchar(100)

SET @pidstr = LOWER(CONVERT(varchar(100), @PID))

return @Modifications.exist('/Modifications/modification[@ID eq sql:variable("@pidstr")]')

end



The Statement to create the index is below.



CREATE UNIQUE CLUSTERED INDEX [IX_ID_RecordID] ON [dbo].[vwAuditLogDetails]

(

[ID] ASC,

[RecordID] ASC

)WITH (STATISTICS_NORECOMPUTE = OFF, SORT_IN_TEMPDB = OFF, IGNORE_DUP_KEY = OFF, DROP_EXISTING = OFF, ONLINE = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]

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Apr 3, 2002

I have a database where records are Inserted by an external process.
There is no updating or deleting of the data once inserted. The table in
question has a Clustered Index on the Machine_ID (integer) (data is from
manufacturing processes). Each record bears a start and end time. Most
queries involve the Machine, a time span (start time between to points in
time), the Downtime Cause, and the Running Mode.

I want to add an index on the Start Time, the Downtime Cause, and the
Runtime Mode.

My question is: should this new index also contain the Machine_id column
or does the existence of the Clustered Index already on that column negate
its need in the new index?

RC - Dedicated to only creating original mistakes!

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Dec 24, 2014

I have 5 million rows of table, and going to create Non Clustered Index for Datetime values column. Creating Non clustered Index on Datetime value column will affect performance or not.

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May 29, 2007

Want to check my thinking with you folks...

I have a table with a clustered composite index, consisting of 3 columns, which together form a unique key. For illustration, the columns are C1, C2 & C3.

Counts of distinct values for columns are C1 425, C2 300,000 & C3 4,000,000

C3 is effectively number of seconds since 01/01/1970.

The usage of the table is typically, insert a row, do something else, then update it.

Currently, the index columns are ordered C3,C1,C2. Fill factor of 90%.

My thinking is that this composite index is better ordered C1,C2,C3.

My reasoning is that having C3 as the leading column, biases all the inserts towards one side of the indexes underlying B-tree, causing page splits. Also, there'll be a bunch of "wasted" space across the tree, as the values going into C3 only ever get bigger (like an identity), so the space due to the fill factor in lower values never gets used.

Welcome your thoughts.

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Oct 22, 2014

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Sep 18, 2015

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Nov 24, 2015

I created composite clustered index key based on Gender and Salary column 

The Query executed Successfully and <g class="gr_ gr_135 gr-alert gr_tiny gr_spell undefined ContextualSpelling multiReplace" data-gr-id="135" id="135">i</g>

got composite index key id Gender(-), Salary I <g class="gr_ gr_310 gr-alert gr_gramm undefined Grammar only-ins replaceWithoutSep" data-gr-id="310" id="310">want</g> know why Gender(-) display like this?

And Gender is <g class="gr_ gr_391 gr-alert gr_spell undefined ContextualSpelling ins-del multiReplace" data-gr-id="391" id="391">nvarchar</g> (20) 

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