SQL Server Data Encryption And Decryption

Feb 19, 2008

Hi.

I have a SQL Server 2000 database that contains information I would like to encrypt. The information is a field inside a table, and I would like to encrypt this information using a key, and decrypt it in my asp.net application using that key and use the decrypted data.

Please tell me how this can be done, or direct me to an article or a link on the subject.

Thanks in advance.

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SQL Security :: Encryption 2005 - User Defined Function For Encryption And Decryption

Oct 7, 2015

I have created two user defined functions for encryption and decryption using passphrase mechanism. When I call encryption function, each time I am getting the different values for the same input. While I searching a particular value, it takes long time to retrieve due to calling decryption function for each row.

best way to encrypt and decrypt using user defined functions.Below is the query which is taking long time.

SELECT ID FROM table WITH (NOLOCK)
                     WHERE dbo.DecodeFunction(column) = 'value'

When I try to use symetric or asymetric encryption, I am not able to put "OPEN SYMETRIC KEY" code in a function. So, I am using PassPhrase mechanism.

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SQL Server 2008 :: Encryption / Decryption On Mirroring Database

May 4, 2015

I have created mirroring... one of the column is encrypted on mirror database and I can see the decrypted result when I do query when I actually logged into server (through remote connection) but when I use the same query through using SSMS from my laptop the query result come as the column is not decrypted,

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RC4 Encryption - Decryption

Dec 12, 2006

This function is used to initialize the seed for the RC4 algorithmCREATE FUNCTION dbo.fnInitRc4
(
@Pwd VARCHAR(256)
)
RETURNS @Box TABLE (i TINYINT, v TINYINT)
AS

BEGIN
DECLARE@Key TABLE (i TINYINT, v TINYINT)

DECLARE@Index SMALLINT,
@PwdLen TINYINT

SELECT@Index = 0,
@PwdLen = LEN(@Pwd)

WHILE @Index <= 255
BEGIN
INSERT@Key
(
i,
v
)
VALUES(
@Index,
ASCII(SUBSTRING(@Pwd, @Index % @PwdLen + 1, 1))
)

INSERT@Box
(
i,
v
)
VALUES(
@Index,
@Index
)

SELECT@Index = @Index + 1
END


DECLARE@t TINYINT,
@b SMALLINT

SELECT@Index = 0,
@b = 0

WHILE @Index <= 255
BEGIN
SELECT@b = (@b + b.v + k.v) % 256
FROM@Box AS b
INNER JOIN@Key AS k ON k.i = b.i
WHEREb.i = @Index

SELECT@t = v
FROM@Box
WHEREi = @Index

UPDATEb1
SETb1.v = (SELECT b2.v FROM @Box b2 WHERE b2.i = @b)
FROM@Box b1
WHEREb1.i = @Index

UPDATE@Box
SETv = @t
WHEREi = @b

SELECT@Index = @Index + 1
END

RETURN
ENDANd this function does the encrypt/decrypt partCREATE FUNCTION dbo.fnEncDecRc4
(
@Pwd VARCHAR(256),
@Text VARCHAR(8000)
)
RETURNSVARCHAR(8000)
AS

BEGIN
DECLARE@Box TABLE (i TINYINT, v TINYINT)

INSERT@Box
(
i,
v
)
SELECTi,
v
FROMdbo.fnInitRc4(@Pwd)

DECLARE@Index SMALLINT,
@i SMALLINT,
@j SMALLINT,
@t TINYINT,
@k SMALLINT,
@CipherBy TINYINT,
@Cipher VARCHAR(8000)

SELECT@Index = 1,
@i = 0,
@j = 0,
@Cipher = ''

WHILE @Index <= DATALENGTH(@Text)
BEGIN
SELECT@i = (@i + 1) % 256

SELECT@j = (@j + b.v) % 256
FROM@Box b
WHEREb.i = @i

SELECT@t = v
FROM@Box
WHEREi = @i

UPDATEb
SETb.v = (SELECT w.v FROM @Box w WHERE w.i = @j)
FROM@Box b
WHEREb.i = @i

UPDATE@Box
SETv = @t
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @i

SELECT@k = (@k + v) % 256
FROM@Box
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @k

SELECT@CipherBy = ASCII(SUBSTRING(@Text, @Index, 1)) ^ @k,
@Cipher = @Cipher + CHAR(@CipherBy)

SELECT@Index = @Index +1
END

RETURN@Cipher
END

Peter Larsson
Helsingborg, Sweden

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Jan 3, 2008

This is related to post :
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=78552

got a issue with this one..im not sure why..

My results are as follows:

Select dbo.fnEncDecRc4('Orange12345', 'Hello123')
Output : ,Mgl
Select dbo.fnEncDecRc4('Orange12345', ',Mgl')
Output : M

i am not able to decrypt it. Any idea why this is hapenning? Does it has to do something with regional settings?

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Jan 24, 2008



Hi,
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Thanks

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Database Security, we are going to use AES 256 Symmetric Encryption. We will be using RSA for Asymmetric Key Encryption, 1024 Bits.

We got the code working for the seond case but for the first, WHEN:

CREATE SYMMETRIC KEY sym_Key WITH ALGORITHM =
AES_256 ENCRYPTION BY ASYMMETRIC KEY asym_Key
GO

THEN:

-- Msg 15314, Level 16, State 1, Line 1
-- Either no algorithm has been specified or the bitlength and the algorithm specified for the key are not available in this installation of Windows.

What can be the way out to be able to create the AES 256 Symmetric key.

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May 4, 2006

Hey I had a table with a column of data encrypted in a format. I was able to decrypt it and then encrypt it using Symmetric keys and then updating the table column with the data. Now, there is a user sp which needs to encrypt the password for the new user and put it in the table. I'm not being able to make it work. I have this so far. Something somewhere is wrong. I dont know where. Please help Thanks. I used the same script to do the encryption initially but that was for the whole column. I need to see the encrypted version of the @inTargetPassword  variable. But it's not working. It doesn't give me an error but gives me wrong data...

 

 

declare @thePassword as varbinary(128)

,@inTargetPassword as varchar(255)

,@pwd3 as varchar(255)

,@theUserId bigint

set @theUserId= 124564

set @inTargetPassword = 'test'

OPEN SYMMETRIC KEY Key1

DECRYPTION BY CERTIFICATE sqlSecurity;

Select @pwd3=EncryptByKey(Key_GUID('Key1')

, @inTargetPassword, 1, HashBytes('SHA1', CONVERT( varbinary, [UserObjectId])))

from table1 where UserObjectId= @theUserId

close symmetric key Key1

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I have got code for single string... but i want to encrypt/decrypt columns and sometimes the whole database...
Can anybody help me out...
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Is there a possibility/way to encrypt a database file so that, if someone else finds/copies the mdf, he/she won't be able to read it.

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Using
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[code]....

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[URL]

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Subject:RijndaelManaged decryption from SQL Server

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Web.config
...

<symmetricCryptoProviders>


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</symmetricCryptoProviders>
...

.cs file
....

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