Transact SQL :: Start Week Of The Month For A Given Week

Jul 23, 2015

I need a Select sentence that return me the first week of the month for a given week.

For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).

I only need give a week number of the year and then returns the week number of the first week of that month.

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T-SQL (SS2K8) :: Get Week Numbers From Dates - Saturday Being Start Of Week

Sep 17, 2015

i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday

CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES

[code]....

The output should look like this

weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000

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Power Pivot :: Cumulative Total For Current Week Days And Previous Week

Nov 30, 2015

We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week. 

I'm trying to produce a line chart with 2 axis:

- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders 

The chart needs two series:

Previous Week. The running count of orders placed that week. 
Current Week. The running count of orders placed this week. 

Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day. 

I have two tables:

Orders TableCalendar Table

The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc. 

My measure for counting orders is simply; # Orders: = countrows[orders].

How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:

- [URL] ...
- [URL] ...

But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.

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SQL Server 2008 :: Get Week Ending Date Given Week Number

Apr 9, 2013

How can I get Saturday's date given the week number?

This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.

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Create A Yesterday, This Week, Last Week Calculated Member

May 23, 2007

Hi all,

I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.

At the moment, I'm doing this:




Code Snippet

create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]

select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?

So I guess there's two questions:

1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)

2)How come the Yesterday member is not returned by the .members function?


Thanks

Greg

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How To Get Week Of The Month?

Apr 19, 2004

This seems like a difficult one ..

I am trying to calculate the number of the week within a month of a given date. in other words, given a date I need to find out whether it's the 1st week or 2nd or 3rd or 4th or 5th week of that given month.

for instance let's call my function "weekOfMonth()":

weekOfMonth(4/19/2004) should return 4 (it's the fourth week of april)
weekOfMonth(4/7/2004) should return 2 (it's the second week of april)
etc ..

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First Day Of Last Week In The Month Of May

Nov 20, 2013

I want to have the first day of last week for the month of may using getdate()

example for this year is : 26th May

I want the format as 2013-05-26

also

I want to add 28 days for that in anther query.

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Once A Week Or Once A Month

Dec 6, 2007

Running a SQL 7 system on a Windows 2000 server using Access 2000 on clientmachines as a front end. System administrator currently reboots the serveronce a month. Yesterday we had some weird thing with the database whereusers were getting ODBC errors when trying to access it. Rebooted theserver, everything was fine. Suggested to the sa that he reboot the serveronce a week. He said he already does it once a month, and that's sufficient.My POV is that: a) doing it once a week might prevent situations such as theone yesterday; b) even without situations like the one yesterday,performance may be degrading over the course of the month, without our beingaware of it, and rebooting once a week might help performance.Any thoughts on this?Thanks!Neil

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How To Stop Week Hours To Continue To Next Week

Jan 29, 2014

I am adding week hrs using while loop , but it can continue next week hrs also.

I can get every week start hrs while update @tem1 table

employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439

My loop statement

while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end

this is the result while executing loop statement .

employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03

How to update only that week hrs , don't continue next week...

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How To Get Data Untill Last Week From The First Week Of The Year

Apr 29, 2008

In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????

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Convert Week Number To Date Of 1st Day Of That Week...

Feb 2, 2008



I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.

Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008

Is there a SQL function that will do this?


Thanks,
Mike

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How Can I Find Week Of Month

Jun 18, 2001

Please provide a function or logic to find week of month..

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Week Split Up For Any Month

Nov 5, 2007

Hi frnds,

Could u pls help me in solving this:

I have a table where i store the Daily details of the stock ( Columns:

Id, Name,Qty,Date)..here in this table it has been populated for the entire year.

I have to get the Sum of the Qty for the Week1,Week2,Week3,Week4,Week5 for all the Stocks(stockid) for any Month given as input.

Pls help me out.

Thanks in Advance
Banu

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Select The Record Per Week In A Month

Mar 7, 2006

Hi,
Support, I have a table order and the field are orderid,customerid,orderdate. What i need to do is that I want customer order list as how many order per week in a month.
Can anyone help me please.
Regards

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Week/Month Date Range

Nov 19, 2001

I need SQL to determine what the date range for the previous week was, ie
Start date 11/11/01 for Last Sunday through 11/17/01 the following Saturday.
The results will populate a drop down box for user queries.
Thanx.

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Datepart Week Month Overlap

Apr 15, 2015

I am writing report to display some IIS site activity, part of the requirement is to produce a trend for user activity for each week of the year.

I have written a stored procedure that uses datepart to split year, month and year week number into separate columns. However the problem I am having is that when a week is split over 2 months I end up with the two entries for the same week but across two months which also splits the count of activity into two rows. So when I produce a line chart in SSRS I end up with a dip due to the week total being split.

An example would be week number 14 of this year is split over two months, I think I need to add same week number activity counts together but not sure how to handle this in the stored procedure.

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Week, Month Year Parameter

Jun 10, 2008

My boss would like to see one report with parameter promts. I tried doing this, but I keep getting an error. Can someone help me out here?

Thanks.

WHERE
(@YEAR(CLM_Dout) = YEAR(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND MONTH(CLM_DOUT) = MONTH(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND DATEPART(wk, CLM_DOUT) = DATEPART(wk, GETDATE()))

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Sum By Week / Month / Quarter / Year

Aug 20, 2014

I am trying to group counts by week,month,quarter, year for a particular activity type and I'm having issues.Here's my code so far:

SELECT
distinct
EmailAddressID,
emailaddress,
SUM(CASE WHEN [ActivityDate] >= DATEADD(WEEK, DATEDIFF(WEEK, 0, @DT), 0)
THEN
SUM(CASE WHEN EmailActivityType = 'OPEN' THEN 1 ELSE 0 END) END AS WeekTotalOpens
FROM EmailActivity
WHERE DATEPART(YEAR, [ActivityDate]) = DATEPART(YEAR, @DT)
GROUP BY EmailAddressID,emailaddress
Desired Output:
EmailAddressId EmailAddress WeekTotalOpens MonthTotalOpens etc. then WeekTotalClicks and so on....

SQL doesn't seem to like the sub-aggregate. What is the best way to approach?

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Start Of Week Function

Mar 19, 2005

I wrote the following function to find the start of week date for a given date and a given start day of week.

For example:
If the day passed is Saturday, 2005-03-19, and Sunday is the start of the week, it returns: 2005-03-13 00:00:00.000

If the day passed is Monday, 2005-03-14, and Sunday is the start of the week, it returns: 2005-03-13 00:00:00.000

If the day passed is Monday, 2005-03-14, and Monday is the start of the week, it returns: 2005-03-14 00:00:00.000


Does anyone have a simpler algorithim for start of week that they care to post?


Edit (2006/4/15):
Posted a companion function F_END_OF_WEEK, on this topic:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=64760


There are other Start of Time Period Functions posted here:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=64755


There are other End Date of Time Period Functions here:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=64759





create function dbo.F_START_OF_WEEK
(
@DATEdatetime,
-- Sun = 1, Mon = 2, Tue = 3, Wed = 4
-- Thu = 5, Fri = 6, Sat = 7
-- Default to Sunday
@WEEK_START_DAYint= 1
)
/*
Find the fisrt date on or before @DATE that matches
day of week of @WEEK_START_DAY.
*/
returnsdatetime
as
begin
declare @START_OF_WEEK_DATEdatetime
declare @FIRST_BOWdatetime

-- Check for valid day of week
if @WEEK_START_DAY between 1 and 7
begin
-- Find first day on or after 1753/1/1 (-53690)
-- matching day of week of @WEEK_START_DAY
-- 1753/1/1 is earliest possible SQL Server date.
select @FIRST_BOW = convert(datetime,-53690+((@WEEK_START_DAY+5)%7))
-- Verify beginning of week not before 1753/1/1
if @DATE >= @FIRST_BOW
begin
select @START_OF_WEEK_DATE =
dateadd(dd,(datediff(dd,@FIRST_BOW,@DATE)/7)*7,@FIRST_BOW)
end
end

return @START_OF_WEEK_DATE

end
go

-- Sample function calls

select dbo.F_START_OF_WEEK(getdate(),default) -- Returns Date for Sunday

select dbo.F_START_OF_WEEK(getdate(),1)-- Returns Date for Sunday
select dbo.F_START_OF_WEEK(getdate(),2)-- Returns Date for Monday
select dbo.F_START_OF_WEEK(getdate(),3)-- Returns Date for Tuesday
select dbo.F_START_OF_WEEK(getdate(),4)-- Returns Date for Wednesday
select dbo.F_START_OF_WEEK(getdate(),5)-- Returns Date for Thursday
select dbo.F_START_OF_WEEK(getdate(),6)-- Returns Date for Friday
select dbo.F_START_OF_WEEK(getdate(),7)-- Returns Date for Saturday

select dbo.F_START_OF_WEEK(getdate(),0)-- Returns NULL
select dbo.F_START_OF_WEEK(getdate(),8)-- Returns NULL



Edited 2005/4/9:

I thought I would also post an alternate way of doing the Start of Week instead of using the F_START_OF_WEEK function. These queries demo doing the Start of Week inline in a query, and use a similar algorithm to find the start of week, but the start day of week is hard coded.

I posted two versions. The first version is simpler, but it has a minor flaw that returns a false result if the start of week would be before 1753/1/1. For the vast majority of applications this would not be a problem. In the second, the algorithm is modified slightly to cause it to overflow if you pick a date that would result in a start of week before 1753/1/1. Note that the F_START_OF_WEEK function returns a NULL in this situation.

The demo queries use the F_TABLE_NUMBER_RANGE that is posted in another thread in order to generate dates to demonstrated the results:
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=47685



-- First demo query for Start of Week
-- Returns bad result if the start of week would be before 1753/1/1
select
DATE,
Sun = dateadd(dd,(datediff(dd,-53684,a.DATE)/7)*7,-53684),
Mon = dateadd(dd,(datediff(dd,-53690,a.DATE)/7)*7,-53690),
Tue = dateadd(dd,(datediff(dd,-53689,a.DATE)/7)*7,-53689),
Wed = dateadd(dd,(datediff(dd,-53688,a.DATE)/7)*7,-53688),
Thu = dateadd(dd,(datediff(dd,-53687,a.DATE)/7)*7,-53687),
Fri = dateadd(dd,(datediff(dd,-53686,a.DATE)/7)*7,-53686),
Sat = dateadd(dd,(datediff(dd,-53685,a.DATE)/7)*7,-53685)
from
(
select
DATE = convert(datetime,number)
from
F_TABLE_NUMBER_RANGE(36524,40000)
) a


-- Second demo query for Start of Week
-- Modified to cause an error instead of returning a bad date
-- if the start of week would be before 1753/1/1
select
DATE,
Sun = dateadd(dd,((datediff(dd,-53684,a.DATE+7)/7)*7)-7,-53684),
Mon = dateadd(dd,((datediff(dd,-53690,a.DATE+7)/7)*7)-7,-53690),
Tue = dateadd(dd,((datediff(dd,-53689,a.DATE+7)/7)*7)-7,-53689),
Wed = dateadd(dd,((datediff(dd,-53688,a.DATE+7)/7)*7)-7,-53688),
Thu = dateadd(dd,((datediff(dd,-53687,a.DATE+7)/7)*7)-7,-53687),
Fri = dateadd(dd,((datediff(dd,-53686,a.DATE+7)/7)*7)-7,-53686),
Sat = dateadd(dd,((datediff(dd,-53685,a.DATE+7)/7)*7)-7,-53685)
from
(
select
DATE = convert(datetime,number)
from
F_TABLE_NUMBER_RANGE(36524,40000)
) a






CODO ERGO SUM

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Start Date Of The Current Week

Feb 17, 2006

Can anyone explain the result of the sql statement

Select DATEADD(wk, DATEDIFF(wk, 6,getdate()), 6)


Can we use this to get the start date of the current week always???

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Start Of The Week Of Current Quarter

Oct 2, 2014

I am trying to always get the start of the week of the current quarter in my criteria

This is the statement for the current quarter
Dateadd(qq, Datediff(qq,0,GetDate()), 0)

This is the statement for the current week
DATEADD(wk, DATEDIFF(wk,0,GETDATE()), 0)

How to calculate from the start of the week of the current quarter...

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Analysis :: SSAS Calculated Members For Each Week Of Month

Jul 6, 2015

I have a date dimension with structure/hierarchy (year - month - wkofmonth - day) & measure count

This works fine when I insert wkofmonth in columns & count in values but when I add another measure it duplicates per week

Product CountWk1(jan) CountWk2(jan) CountWk3(jan) CountWk4(jan) SalesVolume
1            1                        2                  0                         0               1000

Is there something I can do on the structure & do 4 calculated members pending how many weeks in a month, is there a simpler way where the next measure does not calculate by columns field.

If calculated member for each week, how do I do this, any example code?

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DateTime :: To_CHAR :: Change Week Start

Dec 28, 2007

So I need to select and average a whole bunch of data by week. Currently, I group by:


GROUP BY TO_CHAR(m.ENDTIME, 'IW')


and select using


SELECT ... TO_CHAR(m.ENDTIME, 'IW') Week

to summarize by week.

Since the first day of the year was a monday, it sets the weeks as monday-monday. I need to set the weeks to be Thursday 7pm to Thursday 7pm. How can this be achieved? Thanks.

-steve

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Date Of First Day Of Week For Current Week

Jun 6, 2006

seriously now

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Aug 15, 2006

I have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?

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ISO Year Week Day Of Week Function

Jan 18, 2006

Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.

The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.


drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin

declare @YearWeekDayOfWeekvarchar(10)

Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a

return @YearWeekDayOfWeek

end
go


-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.

select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a


Function Test Results:

DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1

(43 row(s) affected)




CODO ERGO SUM

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I can't seem to upload images so here's the link: [URL] ....

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[code]....

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