Distance Between Two Points Lat/long
Jan 12, 2008
I have a user defined function, I want to determine the distance between the 2 points. I have it working but i'm having a problem getting to print.
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Code Snippetcreate function dbo.Distance( @lat1 float , @long1 float , @lat2 float , @long2 float)
returns float
as
begin
declare @DegToRad as float
declare @Ans as float
declare @Miles as float
set @DegToRad = 57.29577951
set @Ans = 0
set @Miles = 0
if @lat1 is null or @lat1 = 0 or @long1 is null or @long1 = 0 or @lat2 is
null or @lat2 = 0 or @long2 is null or @long2 = 0
begin
return ( @Miles )
end
set @Ans = SIN(@lat1 / @DegToRad) * SIN(@lat2 / @DegToRad) + COS(@lat1 / @DegToRad ) * COS( @lat2 / @DegToRad ) * COS(ABS(@long2 - @long1 )/@DegToRad)
set @Miles = 3959 * ATAN(SQRT(1 - SQUARE(@Ans)) / @Ans)
set @Miles = CEILING(@Miles)
return ( @Miles )
end
DECLARE @RC float
EXEC Distance '39.943762', '-78.122265', '32.334709', '-96.633546'
PRINT @RC /* in miles */
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Jun 22, 2007
Greetings everyone, I'm posting this thread with the hope that someone will notice it and might offer me a helping hand regarding one of my problems.I have the database named "DBEXAMPLE" with the table MEMB_INFO that contains two important columns that are named cur_points and points where cur_points column contains the total available points that a member can use/spend on a game and the points column stores the total of the points that a member used so far.So as i plan to wipe all data of the database, i need to keep the member login,password and total points that each member purchased.So i will somehow need to update the cur_points column with the total of current cur_points+points columns and then wipe points column.I've personally asked a friend regarding this and he said that this should be something complicated and it might require php also.Really appreciate if someone could help me regarding this.small schema:Database: DBEXAMPLETable: MEMB_INFOColumn cur_points -> total available points that a member can spendColumn points -> total points that the member has already spentColumn memb___id -> member login aka account idTODO -> update cur_points column with the total of cur_points+points columns for each member(buyer)With best regards.
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Jan 21, 2004
Hi
How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL
Help will be appreciated
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Mar 1, 2007
Is there a recommended practice for mirroring in regards to distance? Is it best practice to mirror with both nodes at the same physical location and use another method for failing over to a remote location or can one just put the other node in the mirror a few thousand miles away? I'm suspecting not.
Any comments??
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Mar 18, 2008
Hi,
please, it is possible to know the edit distance used in the fuzzy lookup/grouping.
On this forum I read fuzzy lookup use 4-gram with fix size.
Does exist any document explaining how fuzzy lookup calculate the similarity? In other word, what kind of edit distance, algorithm is used by fuzzy lookup/grouping?
I hope I was enough clear with my poor english.
Thanks All
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Mar 28, 2007
I'm trying to run a dyncamic query that returns all records within a specific distance of a certain point. The longitude and latitude of each record is stored in the database. The query is constructed from two dynamic variables $StartLatitude and $StartLongitude with represent the starting point.
SELECT UserID, ACOS(SIN($StartLatitude * PI() / 180) * SIN(Latitude * PI() / 180) + COS($StartLatitude * PI() / 180) * COS(Latitude * PI() / 180) * COS(($StartLongitude - Longitude) * PI() / 180)) * 180 / PI() * 60 * 1.1515 AS Distance
FROM HPN_Painters
HAVING (Distance <= 150)
It runs fine until I add the 'HAVING (Distance <= 150)' clause, in which I recieve the error: Invalid column name 'Distance' It seems that Distance cannot be referenced in the HAVING clause.
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Jul 23, 2005
I'm looking to find out how I'd go about setting up a database where avisitor to my site could punch in their postal code, and find out how farthey are from another postal code. For example, AutoTrader has this featureI believe to tell you how far the vehicle is from you. Dating sites havethem so you can do proximity searches.Anyone have any ideas where I could start? I'm thinking the post office,but if anyone else has suggestions, I'm open to hear them.Thanks!
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Mar 20, 2007
Various posts have noted that mirroring over distance is not advisable or that either async connections should be used.
Are there any limits/recommendations i.e. if two datacenters are a couple of files part with 10GBs fibre links and <50ms response times would this be acceptable for high-availability mirroring?
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Mar 27, 2007
I am new to data mining so please excuse my ignorance. Lets assume
- i have created a cluser model
- identified 3 clusters ( a, b, c)
- each record consists of 15 columns
- collecting new records( 15 variables) real time
what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).
ClusterDistance() could be Y but what will be X.
thanks.
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Oct 15, 2015
DECLARE @Latitude NUMERIC(9, 6), @Longitude NUMERIC(9, 6)
DECLARE @MyLatitude NUMERIC(9, 6), @MyLongitude NUMERIC(9, 6)
Set @Latitude = 42.329596;
Set @Longitude = -83.709286;
Set @MyLatitude = 42.430883;
Set @MyLongitude = -82.923642;
Question: How do we calculate the distance in miles between the 2 points.
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Nov 22, 2013
I am trying to write a piece of SQL which gives me a list of enquiries within 10 metre distance of a enquiry.
The idea is to identify possible duplicates.
Table: enquiry
Primary key: enquiry_number
Co-ordinates data fields: enquiry.enquiry_easting and enquiry.enquiry_northing.
I will need to self-search on the same table to find possible enquiries within 10m distance.
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Jun 24, 2005
See here www.merriampark.com/ld.htm for information about the algorithm. This page has a link (http://www.merriampark.com/ldtsql.htm) to a T-SQL implementation by Joseph Gama: unfortunately, that function doesn't work. There is a debugged version in the also-referenced package of TSQL functions (http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=502&lngWId=5), but this still has the fundamental problem that it only works on pairs of strings up to 49 characters.
CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999))
RETURNS int
AS
BEGIN
DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int,
@cv0 varbinary(8000), @cv1 varbinary(8000)
SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0
WHILE @j <= @s2_len
SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1
WHILE @i <= @s1_len
BEGIN
SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1
WHILE @j <= @s2_len
BEGIN
SET @c = @c + 1
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) +
CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END
IF @c > @c_temp SET @c = @c_temp
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1
IF @c > @c_temp SET @c = @c_temp
SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1
END
SELECT @cv1 = @cv0, @i = @i + 1
END
RETURN @c
END
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Jul 20, 2005
I am trying to use the haversine function to find the distance betweentwo points on a sphere, specifically two zip codes in my database. I'mneither horribly familiar with SQL syntax nor math equations :), so Iwas hoping I could get some help. Below is what I'm using and it is,as best as I can figure, the correct formula. It is not however,giving me correct results. Some are close, others don't seem right atall. Any ideas?SET @lat1 = RADIANS(@lat1)SET @log1 = RADIANS(@log1)SET @lat2 = RADIANS(@lat2)SET @log2 = RADIANS(@log2)SET @Dlat = ABS(@lat2 - @lat1)SET @Dlog = ABS(@log2 - @log1)SET @R = 3956 /*Approximate radius of earth in miles*/SET @A = SQUARE(SIN(@Dlat/2)) + COS(@lat1) * COS(@lat2) *SQUARE(SIN(@Dlog/2))SET @C = 2 * ATN2(SQRT(@A), SQRT(1 - @A))/*SET @C = 2 * ASIN(min(SQRT(@A))) Alternative calculation*/SET @distance = @R * @Cthnx,cjrsumner
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Feb 1, 2007
hi everyone:
the report show two tables two matrixs
how can i control the distance between them
I want to set the same distance between the table and matrix
or (table and table )
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Jan 2, 2008
Could I implement a failover cluster solution on the two DBs which are based in two different cities?
Possible?
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Jun 14, 2006
I need to be able to take the latitude and logitude of two locations and compare then to determine the number of miles between each point. It doesn't need to account for elevation, but assumes a flat plane with lat and long.
Does anyone have any algorithms in T-SQL to do this?
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Mar 11, 2014
Given the following example;
declare @CustIfno table (AccountNumber int, StoreID int, Distance decimal(14,10))
insert into @CustIfno values ('1','44','2.145223'),('1','45','4.567834'),
('1','46','8.4325654'),('2','44','7.8754345'),('2','45','1.54654323'),
('2','46','11.5436543'), ('3','44','9.145223'),('3','45','8.567834'),
('3','46','17.4325654'),('4','44','7.8754345'),('4','45','1.54654323'),
('4','46','11.5436543')
How can I show the shortest Distance by AccountID and StoreID. Results would look like this;
AccountNumberStoreID Distance
1 44 2.1452230000
2 45 1.5465432300
3 45 8.5678340000
4 45 1.5465432300
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Mar 28, 2007
This function computes the great circle distance in Kilometers using the Haversine formula distance calculation.
If you want it in miles, change the average radius of Earth to miles in the function.
create function dbo.F_GREAT_CIRCLE_DISTANCE
(
@Latitude1 float,
@Longitude1 float,
@Latitude2 float,
@Longitude2 float
)
returns float
as
/*
fUNCTION: F_GREAT_CIRCLE_DISTANCE
Computes the Great Circle distance in kilometers
between two points on the Earth using the
Haversine formula distance calculation.
Input Parameters:
@Longitude1 - Longitude in degrees of point 1
@Latitude1 - Latitude in degrees of point 1
@Longitude2 - Longitude in degrees of point 2
@Latitude2 - Latitude in degrees of point 2
*/
begin
declare @radius float
declare @lon1 float
declare @lon2 float
declare @lat1 float
declare @lat2 float
declare @a float
declare @distance float
-- Sets average radius of Earth in Kilometers
set @radius = 6371.0E
-- Convert degrees to radians
set @lon1 = radians( @Longitude1 )
set @lon2 = radians( @Longitude2 )
set @lat1 = radians( @Latitude1 )
set @lat2 = radians( @Latitude2 )
set @a = sqrt(square(sin((@lat2-@lat1)/2.0E)) +
(cos(@lat1) * cos(@lat2) * square(sin((@lon2-@lon1)/2.0E))) )
set @distance =
@radius * ( 2.0E *asin(case when 1.0E < @a then 1.0E else @a end ))
return @distance
end
Edit: corrected spelling
CODO ERGO SUM
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Apr 28, 2008
Hi All,
Does anyone have a Stored Procedure that works perfectly to retrieve all zipcodes within a specified zipcode and distance radius - a zipcode and radius is passed and the Store Procedure result shows all zipcodes that falls within that range.
Thanks in advance
Ade
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Apr 29, 2015
I have the two following locations.
They're both towns in Australia , State of Victoria
Fitzroy,-37.798701, 144.978687
Footscray,-37.799736, 144.899734
After running geography::Point(Latitude, Longitude , 4326) on the latitude and longitude provided for each location, my Geography column for each row is populated with the following:
Fitzroy, 0xE6100000010C292499D53BE642C0A7406667511F6240
Footscray, 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240
In my SQL Query, I have the following which works out the distance between both towns. Geo being my Geography column
DECLARE @s geography = 0xE6100000010C292499D53BE642C0A7406667511F6240 -- Fitzroy
DECLARE @t geography = 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240 -- Footscray
SELECT @s.STDistance(@t)
The result I get is
6954.44911927616
I then looked at formatting this as in Australia we go by KM so after some searching I found two solutions one for Miles and the other KM
So I changed Select statement to look like this
select @s.STDistance(@t)/1000 -- format to KM
My result is then
6.95444911927616
When I go to google maps and do a direction request between the locations provided above it says 10.2km (depending on traffic)
Now I'm new to this spatial data within SQL, why would I get a different result from google maps?
Also I would like to round this number so its easier to use within my where statement so I'm using Ceiling as shown here:
SELECT CEILING(@s.STDistance(@t)/1000)
Is ceiling the correct way to go?
Reason I need to round this is because we are allowing the end user to search by radius so if they pass in 50km I will then say
Where CEILING(@s.STDistance(@t)/1000) < 50
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Nov 19, 2014
I've got a working query which returns all leads within a supplied proximity to a city. I followed a tutorial I googled a couple months ago (can't find it now). It works, but would love others to look the query over (provided DDL and sample data) and tell me if it's as it should be.
Two things I don't like about query:
1. I have to do a UNION to another query that retrieves everything that is in the same city in order to have complete results.
2. very slow to retrieve results (> 1 minute)
Sample DDL: 2 tables
create table dim_lead
(
date_created datetime,
[contact_first_name] varchar(20),
[contact_last_name] varchar(20),
lead_id int,
[Code] .....
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Nov 23, 2006
I know how to create mount point in windows 20003 cluster, I am not sure how
to set it up with SQL 2005 running on the cluster.
Does sql need to be dependant on any of the disks? I have tried looking for
a guide, but cannot find.
current setup active active cluster running. I need to add san space which
will hold the databases. The san will be carved up into drive letters. each
drive letter will hold 3 mount points.
ie.
node 1
J:-2 mount point
k:2 mount point
l:2 mount point
node 2-
r:-2 mount point
s:2 mount point
t:2 mount point
each node would be able to own the disk if the other node failed over.
any help is appreciate. I have tried books online etc.. cannot find a good
step by step.;
thanks
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Mar 12, 2007
HI All,
I use MSSQL as my database and ASP.NET as my front application. I want to display Price value S$23.68.
The dayatype I used is smallmoney, but it display: S$23.6800. HOw do I control the number of decimals point in the column of MSSQL??
Thanks a lot
Suigion
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May 21, 2008
Dear experts,
Hi, I got a table name Employee, with the following fields
EmployeeID
Name,
ManagerID
ManagerID2,
ManagerID3,
ManagerID4 ..
ManagerID, ManagerID2, ManagerID3, ManagerID4 are all pointing to EmployeeID in the same table.
Now I want to select the all employee records where the manager NAME is like '%Raymond%'. (i.e. any of the four managers name is like '%Raymond%'.
How do I construct the select query? I tried this, but it does not work if there are more than 1 manager named 'Raymond'
DECLARE @Name varchar(50)
SET @Name = '%Raymond%'
DECLARE @EmployeeNumber nvarchar(50)
Select
@EmployeeNumber = EmployeeID
from
Employee
where
[Name] like @Name
SELECT
'HumanResources.Employee' as TableName,
E.[Name] as EmployeeName ,
isnull((Select [Name] from Employee E2 where E2.EmployeeID = E.ManagerID),'') as Manager1,
isnull((Select [Name] from Employee E2 where E2.EmployeeID = E.ManagerID2),'') as Manager2,
isnull((Select [Name] from Employee E2 where E2.EmployeeID = E.ManagerID3),'') as AppraisingManager,
isnull((Select [Name] from Employee E2 where E2.EmployeeID = E.ManagerID4),'') as ModeratingManager,
E.CurrentFlag as Active
FROM
HumanResources.Employee E
WHERE
(E.[ManagerID] = @EmployeeNumber)
or (E.[ManagerID2] = @EmployeeNumber)
or (E.[AppraisingManagerID] = @EmployeeNumber)
or (E.[ModeratingManagerID] = @EmployeeNumber))
Any help is very much appreciated.
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Feb 28, 2008
I understand mount points help scalability in easier maintenance.
By scalability do we mean more than 26 drive letters or it means adding more space to the same mount point letter on with more ease .
Can I add more space to a mountpoint if required later on by adding hard disks .
Also if one can give some pointers to good file group configuration guidelines / storage align partitions , it will be very much helpful
Further I my server CPU has 4 cores , will having 4 filegroups help me in improving system performance.
If SAN has 2 controllers , is it preferred to run data file partition on one controller and log file partition on another.
Thanks in advance.
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May 20, 2008
I have a column in a table with a data type of float.
When I update it to store 7.50, it changes it to 7.5
Is there any way to force it to store 2 decimal points?
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Sep 25, 2007
Hello,
We have a requirement to be able to monitor mount points. The xp_fixeddrives does not support mount point monitoring. Is there another way to do it. Does microsoft working on updating the xp_fixeddrives. Let me know if anyone has any ideas how to monitor mount points.
Thanks
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Sep 9, 2006
Hi,I'm making a rating system that save the results in the database.I have 1 table with 3 columns:1) name2) points3) numberofvotesnow I want to select the 5 names with the best results. In other words the 5 best results when you do (points/numberofvotes)how can I say this in SQL? I hope someone can help me! thnx!
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Aug 14, 2001
Previously I have posted about my problem with transaction logs. Threw my research I have found the truncate log at check point. I have also been lead to think that a check point could be a full back up. I have set this option to true and then performed a full back up. Afterward I have shrank the database to find the transaction log to still be over 43 gigs. Where have I gone astray?
Regards
SeTi_Ni
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Jul 24, 2004
Hi all,
I'm trying to debug storedprocedures in query analyzer from workstation, login with server adminuser.Debugger is not stoping at break points.
any help regarding this will be greatly appreciated.
thanks.
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Aug 14, 2006
I was messing around with backup strategies today at work while contemplating my other db issues.
In doing so, I've made a list of backups that don't truly exist anymore (I deleted the 'backup device' (bleh.bak).
Here's an image, stolen from technet's articles.
http://www.microsoft.com/library/media/1033/technet/images/prodtechnol/sql/2000/maintain/ppc1106_big.gif
See that list of restore points? Mine is full of restore points that have absolutely no meaning in them for a DB I made to test out (testDB).
Is there a way to clean those out?
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